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manipulate dynamic input with php mysql and js

I have a table named description:
CREATE TABLE description(
word_id int(11),
word varchar (50),
PRIMARY KEY (word_id)
);
and I try to get all word in this table and for every word I create a checkbox with value and id equal at a value of the word that I get from table description,
if the checkbox is checked, I save his value in var abcd.
<?php
///connection
$get_word = $bdd->query("SELECT * FROM description");
while ($donnees = $get_word->fetch()) {
?>
<input type="checkbox" id="<?php $donnees["word"] ?>" value="<?php $donnees["word"] ?>">
<br>
<script>
$('#<?php $donnees["word"] ?>').on('change', function() {
var abcd= this.checked ? this.value : '';
});
</script>
<?php
}
?>
Now, I want to create a button out of boocle while , if this button is clicked,it must give me the value of checkbox checked.

Here's how you could do it using jQuery. As you already have the PHP logic, my example demonstrates the jQuery code only:
$(document).ready(function() {
'use strict';
$("#getCheckedBoxes").on('click', () => {
$('input[type="checkbox"]').each(function(i, el){
if($(el).is(':checked'))
console.log($(el).val())
})
})
})
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<input type="checkbox" value="Item 1">Item 1
<input type="checkbox" value="Item 2">Item 2
<input type="checkbox" value="Item 3">Item 3
<button id="getCheckedBoxes">Get checked boxes</button>

hope this will solve your problem
PHP code
<?php
///connection
$get_word=$bdd->query("SELECT * FROM description");
while ($donnees = $get_word->fetch()) {
?>
<input type="checkbox" id="myid_<?php $donnees["word"] ?>" onclick="myfunc(<?php $donnees["word"] ?>)" value="<?php $donnees["word"] ?>"><br>
<?php
}
?>
JS CODE
<script>
function myfunc(word){
if(document.getElementById('myid_'+word).checked == true){
var check_val = document.getElementById('myid_'+word).value;
alert(check_val);
}
}
</script>
or you can do this
<script>
function myfunc(word){
if(document.getElementById('myid_'+word).checked == true){
alert(word);
}
}
</script>

add class name such as clickable to your input tag.
after all rendering in php add script that runs when any input with clickable class changed and you can get that tag!
<?php
$get_word=$bdd->query("SELECT * FROM description");
while ($donnees = $get_word->fetch()) { ?>
<input class="clickable" type="checkbox" id="<?php $donnees["word"] ?>" value="<?php $donnees["word"] ?>">
<?php } ?>
<script>
$('.clickable').on('change', function(item) {
console.log(item)
});
</script>

I try this
///connection
$get_word=$bdd->query("SELECT * FROM description");
while ($donnees = $get_word->fetch()) {
?>
<label><?php echo $donnees["word"] ?></label>
<input type="checkbox" id="myid_<?php $donnees["word"] ?>" onclick="myfunc(<?php $donnees["word"] ?>)" value="<?php $donnees["word"] ?>"><br>
<?php
}
?>
<button id="getCheckedBoxes">Get checked boxes</button>
<script type="text/javascript">
$(document).ready(function() {
'use strict';
$("#getCheckedBoxes").on('click', () => {
$('input[type="checkbox"]').each(function(i, el){
if($(el).is(':checked'))
alert($(el).val()) ;
})
})
})
</script>
And the alert message is empty,it don't show the value of checkbox chekced

how to retain drop down values as the value selected after submit

My drop down is showing blank then when i select the value of dropdown the same value is showing, but i have to show dropdown value as select first then when I click on button the respective value should show
I am doing a Php program
<form class="form-horizontal" name="form" method="post" action="<?php $_PHP_SELF?>">
<label for="courseDisp" class="col-sm-2" style="margin-top:10px;">Course : </label>
<?php
$course="SELECT * from course";
$res= $conn->query($course);
if($res->num_rows>0)
{
echo '<select name="courseDisp" id="courseDisp" class="form-control col-sm-3" style="margin-top:8px;display:inline;padding:10px;">';
echo '<option value="0" selected> -- SELECT --</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["course_id"].'>'.$row['shortname'].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>
<label for="yearDisp" class="col-sm-2" style="margin-top:10px;">Year : </label>
<?php
$year="SELECT distinct(year) from syllabus";
$res= $conn->query($year);
if($res->num_rows>0)
{
echo '<select name="yearDisp" id="yearDisp" class="form-control col-sm-3" style="margin-top:8px;display:inline;padding:10px;">';
echo '<option value="0">-- SELECT --</option>';
while($row=$res->fetch_assoc())
{
echo '<option value='.$row["year"].'>'.$row['year'].'</option>';
}
echo '</select>';
} else {
echo "0 result";
}
?>
<script type="text/javascript">
document.getElementById('courseDisp').value = "<?php echo $_POST['courseDisp'];?>";
document.getElementById('yearDisp').value = "<?php echo $_POST['yearDisp'];?>";
<input type="submit" class="btn col-sm-2" style="margin-left:15px;margin-top:10px;width:60px;font-weight:bold;font-size:15px;" value="GO" name="btnGo" id="btnGo" />
</form>

I think you are doing it in a wrong way:
your code should look like this
<script type="text/JavaScript">
var valueSelected=document.getElementById('course').value;
alert(valueSelected);// do here according to the need
</script>

This is because there is no $_POST variables present before you submit a form.
$_POST variables can only be 'accessed' whenever a POST form is submitted, so when the form is not submitted, $_POST['course'] will be undefined. If you want to use persistant, but also relative variables, use $_GET.
This can be done the following way:
<script type="text/javascript">
document.getElementById('course').value =<?php echo $_GET['course'];?>";
</script>
(this will cause an error if value is not set, make sure to make exceptions for that, using if statements in PHP)
but the value also needs to be fetched from the URL.
so your url needs to have ?course=<course_value> in it, for example:
https://example.com/index.php?course=Course%201
Click here for more about POST vs GET requests

Instead of setting the value with javascript, you should directly write the selected attribute.
<select name="course">
<?php foreach ($options as $key => $value): ?>
<option value="<?= $key ?>"<?php if ($key == $_POST['course']) echo " selected" ?>>
<?= $value ?>
</option>
<?php endforeach; ?>
</select>
If you have to do this in javascript, keep sure, you use the correct syntax. Your example has a wrong " at the end of the line. Also you should use json_encode, if you want to output vars into javascript. And a last thing - if you don't put this inside the document ready event, the script has to be placed after the select element, which you wan't to manipulate
<select name="course">...</select>
...
<script type="text/javascript">
document.getElementById('course').value = <?= echo json_encode($_POST['course']) ?>;
</script>

Needed to keep the <option value="">-Select-</option>

could not get input field value in jquery

I am creating an input field using foreach loop like this
<?php foreach($data as $key=>$val) { ?>
<td class="table-td-1">
<input readonly class="form-control" name="model[]" id="typename" type="text" value="<?php echo $val['asset']; ?>">
</td>
<?php } ?>
$data is Array
(
[0] => Array
(
[asset_id] => abc-02
[asset_name] => Freezer
)
[1] => Array
(
[asset_id] => xyz-01
[asset_name] => Refrigerator
)
[2] => Array
(
[asset_id] => 300001
[asset_name] => Generator
)
)
and in javascript, I am trying to get the value using this code but it always alerts first value of the input.
<script type="text/javascript">
$(document).ready(function () {
var typename = $('#typename').val();
alert(typename);
});
</script>
i have to disable this input field when value is 'Generator'

Try:
$('[readonly].form-control').each(function(i,e) {
console.log($(e).val());
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<td class="table-td-1">
<input readonly class="form-control" name="model[]" id="typename" type="text" value="1">
<input readonly class="form-control" name="model[]" id="typename" type="text" value="2">
<input readonly class="form-control" name="model[]" id="typename" type="text" value="3">
<input readonly class="form-control" name="model[]" id="typename" type="text" value="4">
<input readonly class="form-control" name="model[]" id="typename" type="text" value="5">
</td>
.val() called once will always produce only one value; .val() docs:
Get the current value of the first element in the set of matched elements .
HTML id attribute is supposed to be unique, try this instead.
<?php
$count = 0;
foreach($data as $key=>$val) {
?>
<td class="table-td-1">
<input readonly class="form-control" name="model[]" id="typename_<?php echo $count++; ?>" type="text" value="<?php echo $val['asset']; ?>">
</td>
<?php } ?>
It'll produce different id attributes for each input, typename_0, typename_1, ..., typename_n, allowing you to for example:
$('[id^="typename_"]').each(function(i,e) {
console.log($(e).val());
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<td class="table-td-1">
<input readonly class="form-control" name="model[]" id="typename_0" type="text" value="1">
<input readonly class="form-control" name="model[]" id="typename_1" type="text" value="2">
<input readonly class="form-control" name="model[]" id="typename_2" type="text" value="3">
<input readonly class="form-control" name="model[]" id="typename_3" type="text" value="4">
<input readonly class="form-control" name="model[]" id="typename_4" type="text" value="5">
</td>
Where [id^="typename_"] is CSS attribute selector, matching all elements with an id attribute starting with typename_.

You should never use same id for several elements.
Update you code for debug, and you'll see that you have an array:
<script type="text/javascript">
$(document).ready(function () {
var typename = $('[name="model[]"]')
.toArray().map(e => e.value);
alert(JSON.stringify(typename));
});
</script>
You should update your php, to set different id for each element drawn in a cycle, i.e:
<?php $i=1;foreach($nomatter as $a) {?>
<input id="typename_<?=$i++?>">
<?php } ?>
So you'll be able to address eash input separately:
var typename = $('#typename_1').val();

Use class instead of duplicate id like this.
<?php foreach($data as $key=>$val) { ?>
<td class="table-td-1">
<input readonly class="form-control clsValue" name="model[]" id="typename" type="text" value="<?php echo $val['asset']; ?>">
</td>
<?php } ?>
And in jquery loop your class and get value using this instant..
$(document).ready(function () {
$( ".clsValue" ).each(function( index ) {
var typename = $(this).val();
alert(typename);
});
});

try this ,
this will call alert function for each input with form-control class
$(document).ready(function () {
$(".form-control").each(function(){
alert($(this).val());
})
});

Set class="typename" instead of id="typename":
<?php foreach($data as $key=>$val) { ?>
<td class="table-td-1">
<input readonly class="form-control" name="model[]" class="typename" type="text" value="<?php echo $val['asset']; ?>">
</td>
<?php } ?>
You can get values like this:
<script type="text/javascript">
$(document).ready(function () {
var typename1 = $('.typename')[0].val();
var typename2 = $('.typename')[1].val();
alert(typename1);
});
</script>

there is a big mistake in your code, you can't use same id for multiple input fields, when the loop run multiple input fields will create with same id, you have to make the id dynamic, you can make the id dynamic by appending some unique value to the id each time you create an input field the use that id to fetch the data.
Please let me know if you need sample code.

pure js approach;
replace id with class;
<?php foreach($data as $key=>$val) { ?>
<td class="table-td-1">
<input readonly class="form-control typename" name="model[]" type="text" value="<?php echo $val['asset']; ?>">
</td>
<?php } ?>
js
window.onload = alertTypeNames();
function alertTypeNames() {
document.getElementsByClassName('typename').map((inputTag) => {
alert(inputTag.value);
return true;
});
}

you fired with your id that's why it's fired only first element value.
this is how you can do that with your current code
$(document).ready(function () {
$('input[name="model[]"]').each(function(){
alert($(this).val());
});
});
However, it's highly recommended that you have to used unique id for each element otherwise used class to do what you want to.

The id attribute specifies a unique id for an HTML element it's not a good practice to use same ID more than once on a page, instead of ID attribute loop the class attribute in jquery.
<script type="text/javascript">
$(document).ready(function () {
$('.common-class').each(function() {
alert($(this).val());
});
});
</script>
<?php $incr_var = 1; ?>
<?php foreach($data as $key=>$val) { ?>
<td class="table-td-1">
<input readonly class="form-control common-class" name="model[]" id="typename<?php echo $incr_var ?>" type="text" value="<?php echo $val['asset']; ?>">
</td>
<?php } ?>

Element id should be unique. And try it inside on event because dynamically adding elements will not grab ready state.
http://api.jquery.com/live/

<?php foreach($data as $key=>$val) { ?>
<td class="table-td-1 status">
<input readonly class="form-control" name="model[]" id="typename" type="text" value="<?php echo $val['asset']; ?>">
</td>
<?php } ?>
And in jquery
$(document).on('change','.status',function(){
var $status = $(this).val();
if($status == 'not_working'){
$(this).closest('tr').find('.reason').removeAttr('disabled');
}
});
reason is class you have to give which input field you want to disable

Option Menu with 2 Values

I have the following option menu in a form that will insert the fields into a table:
<option value="">select staff</option>
<?php
do {
?>
<option value="<?php echo $row_Staff['Staff_Name']."||".$row_Staff['Email']?>">
<?php echo $row_Staff['Staff_Name']?></option>
<?php
} while ($row_Staff = mysql_fetch_assoc($Staff));
$rows = mysql_num_rows($Staff);
if($rows > 0) {
mysql_data_seek($Categories, 0);
$row_Staff = mysql_fetch_assoc($Staff);
}
?>
</select>
I have 2 fields from source table in value of option from technique explained in How to post two values in an option field?: Staff_Name and Email.
I am trying to insert both fields from the form into a table using:
<input type="hidden" name="Staff_Name" class="form-control" id="Staff_Name" value=<?php
$staff =$_POST['Staff_Data'];
$staff_name = explode("||", $staff);
echo $staff_Name[0];
?> />
and
<input type="hidden" name="Email" class="form-control" id="Email" value=<?php
$staff =$_POST['Staff_Data'];
$email = explode("||", $staff);
echo $email[1];
?> />
Unfortunately, I can see the 2 fields separated by "||" in the table if I insert the option menu value but cannot seem to insert Staff_Name or Email into individual fields. On insert both fields are blank. Any help would be appreciated.

Instead of combine staffname and staffemail in the dropdown value. Please staffname in dropdown value and staffemail in the property of dropdown and onchange of the dropdown set those values in the hidden inputs so you will easily get those values on the form submission.
Please go through below code and let me know if you have any query.
//Dropdown
<select id="ddStaff">
<option value="">select staff</option>
<?php
do { ?>
<option value="<?php echo $row_Staff['Staff_Name']; ?>" staff-email = "<?php echo $row_Staff['Email'];?>">
<?php echo $row_Staff['Staff_Name']?>
</option> <?php
} while ($row_Staff = mysql_fetch_assoc($Staff));
$rows = mysql_num_rows($Staff);
if($rows > 0) {
mysql_data_seek($Categories, 0);
$row_Staff = mysql_fetch_assoc($Staff);
}
?>
</select>
//Input hidden fields to store staff name and staff email
<input type="hidden" id="txtStaffName" name="txtStaffName">
<input type="hidden" id="txtStaffEmail" name="txtStaffEmail">
//Jquery code.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$("#ddStaff").on('change',function(){
var staffName = $(this).val();
var staffEmail = $('option:selected', this).attr('staff-email');
$("#txtStaffName").val(staffName);
$("#txtStaffEmail").val(staffEmail);
});
});
</script>
Please check it on https://jsfiddle.net/z4a0fywp/
For testing purpose I have not made the inputs hidden in the fiddle.

clicking on the select option how to show hidden field using javascript?

I am working on php how to show hidden field?
I have bp_scholarship_enq table in my database and this database i have occupation field i want to add new occupation in my database how i do it?
<script>
function showss(ids)
{
var idss=ids;
if(idss=="other")
document.getElementById(idss).style.display='block';
}
</script>
<?php
echo "<select name='occupation' id='link_block' value='Source' style='width:196%'>
<option>select occupation </otpion>";
$sql = "SELECT * FROM bp_scholarship_enq";
$info = mysql_query($sql);
while ($row = mysql_fetch_array($info))
echo "<option > '" . #$row["occupation"] . "'</option>";
echo '<option onClick="showss('.input_field.')">other</option>';
echo "</select>";
echo '<input type="hidden" name="other" id="input_field" />';
?>

Hidden fields are not meant to be visible. You could use a textbox and set its visiblity to false in css and make visible it on changing the select option.
<input type="text" name="other" id="input_field" style="display:none"/>
<select name='occupation' id='link_block' value='Source' style='width:196%' onChange="showText(this.selectedIndex);">
...............
...............
<option value="other">other</option>
</select>
<script>
function showtext(ind){
var selectBox = document.getElementById('link_block');
if(selectBox.options[ind].value=="other"){
document.getElementById('input_field').style.display = "block";
}else{
document.getElementById('input_field').style.display = "none";
}
}
</script>

Instead of
<input type="hidden" name="other" id="input_field" />
Make it:
<input id="otherOccupation" class="hide" name="other" id="input_field" />
With hide being a class that sets visibility:hidden;
Then have some jquery to remove that class when the user selects "other"
$("#otherOccupation").removeClass("hide")