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jQuery on click fade in hidden element in while loop

I have a form in while loop which activates when I click on Reply button. This I can do simply but its in while loop and requires a unique ID. With my code its working till now but it works only for the first result. When I click on the other results nothing happens. Even though I have already assigned a unique ID its not working. My code is given below:
jQuery part:
$(document).ready(function() {
$("#reply").on('click', 'a.click', function() {
var rowid = $(this).attr("data-rowid");
$(".reply-comment-holder[data-rowid='" + rowid + "']").fadeToggle(800),
$(this).toggleClass(".reply-comment-holder[data-rowid='" + rowid + "']");
});
});
PHP HTML part:
<?php while($fetch_cmts = $get_cmtq->fetch()){ extract($fetch_cmts); ?>
<div id="reply">Reply</div>
<div class="reply-comment-holder" data-rowid="<?php echo $cmt_id?>" style="display:none;">
<form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>" class="full-width cmtform" id="cmt_form_id_<?php echo $cmt_id?>">
<input type="hidden" name="status_id" value="<?php echo $cmt_id; ?>" id="cmtsid_<?php echo $cmt_id?>" />
<textarea name="comment" placeholder="Give a reply..." class="reply-comment-field commentarea" id="replycomment_<?php echo $cmt_id?>"></textarea>
</form>
</div>
<?php } ?>
Please help with jQuery/Ajax.

HTML
<div class="reply">Reply</div>
<div class="reply-comment-holder" data-rowid="1" style="display:none;">
<form method="post" action="#" class="full-width cmtform" id="cmt_form_id_1">
<input type="hidden" name="status_id" value="1" id="cmtsid_1" />
<textarea name="comment" placeholder="Give a reply..." class="reply-comment-field commentarea" id="replycomment_1"></textarea>
</form>
</div>
<div class="reply">Reply</div>
<div class="reply-comment-holder" data-rowid="2" style="display:none;">
<form method="post" action="#" class="full-width cmtform" id="cmt_form_id_2">
<input type="hidden" name="status_id" value="2" id="cmtsid_2" />
<textarea name="comment" placeholder="Give a reply..." class="reply-comment-field commentarea" id="replycomment_2"></textarea>
</form>
</div>
javascript
$(document).ready(function() {
$(".reply").on('click', 'a.click', function() {
var rowid = $(this).attr("data-rowid");
$(".reply-comment-holder[data-rowid='" + rowid + "']").fadeToggle(800),
$(this).toggleClass(".reply-comment-holder[data-rowid='" + rowid + "']");
});
});
jsbin is listed in comments above.

PHP submit an form only if checkbox checked

I have a form with a check box and an input text. Here is my form:
<form action="index.php?option=com_platiniumchristmas&view=success" method="post">
<label>
<input type="checkbox" name="termsConditions" id="chbx" value="Yes" onclick="foo()" />
<?php echo JText::_( 'COM_PLATINIUMCHRISTMAS_TERMSCONDITIONS_TEXT');?>
</label>
<input type="submit" value="Emitir Voucher" class="btn btn-success" style="float: right" />
<div style="overflow: hidden; padding-right: .5em;">
<input type="text" name="friendName" style="width: 100%;" />
<input type="hidden" name="canal" value="<?php echo $_POST[" canal "]; ?>"/>
</div>
</form>
The idea is only to submit the form if the checked box value is checked. How can I go about this. I have tried using javascript but no success.
The javascript I tried to Use:
<script type=”text/javascript”>
var checkbox = document.getElementById("chbx");
function foo(){
if(checkbox.checked){
alert("meap");
};
};
</script>

You don't need JavaScript at all. Just use the required attribute for the constraint validation API.
<form action="index.php?option=com_platiniumchristmas&view=success" method="post">
<label>
<input type="checkbox" name="termsConditions" id="chbx" value="Yes" required />
<?php echo JText::_( 'COM_PLATINIUMCHRISTMAS_TERMSCONDITIONS_TEXT');?>
</label>
<input type="submit" value="Emitir Voucher" class="btn btn-success" style="float: right" />
<div style="overflow: hidden; padding-right: .5em;">
<input type="text" name="friendName" style="width: 100%;" />
<input type="hidden" name="canal" value="<?php echo $_POST[" canal "]; ?>"/>
</div>
</form>
This will stop the form from submitting unless the checkbox is checked. Do remember, you still need backend validation as always to verify since requests can be forged if enough effort is put into it.

try complete example, it should work.
and then correct your code.
<!DOCTYPE html> <html> <head> <script> function validateForm() {
var x = document.forms["myForm"]["fname"].value;
if (x == null || x == "") {
alert("Name must be filled out");
return false;
} } </script> </head> <body>
<form name="myForm" action="index.php" onsubmit="return validateForm()" method="post"> Name: <input type="text" name="fname"> <input type="submit" value="Submit"> </form>
</body> </html>
Thanks
Amit

$("#form").submit(function(e) {
if(!$('input[type=checkbox]:checked').length) {
alert("Please select the checkbox.");
//stop the form from submitting
return false;
}
return true;
});
<form id='form'>
<div>
<input type="checkbox" name="option-1" id="option-1"> <label for="option-1">Option 1</label>
</div>
<div>
<input type="submit" value="Do thing" >
</div>
</form>
use this

You lose the context in your code. try:
<script type=”text/javascript”>
function foo(){
var checkbox = document.getElementById("chbx");
if(checkbox.checked){
alert("meap");
};
};
</script>

multi form ajax php social comment system

I have a lot of these forms that I post with PHP. They are under every article in my page, but when I submit the form with these ajax functions it only sends to the first form of the page. Why? I want send these form separately what am I doing wrong?
<script type="text/javascript" >
$(function() {
$(".submit").click(function()
{
var name = $("#name").val();
var comment = $("#comment").val();
var post_id = $("#post").val();
var dataString = 'name='+ name + '&comment=' + comment+ '&post_id=' + post_id;
if(name=='' || comment=='')
{
alert('Please Give Valid Details');
}
else
{
$("#flash").show();
$("#flash").fadeIn(400).html('<img src="images/loading.gif" />Loading Comment...');
$.ajax({
type: "POST",
url: "commenti.php",
data: dataString,
cache: false,
success: function(html){
$("ol#update").append(html);
$("ol#update li:last").fadeIn("slow");
$("#flash").hide();
}
});
}return false;
});
});
<script>
<ol id="update" class="timeline">
</ol>
<div id="flash"></div>
<div >
<form action="#" method="post">
<input type="hidden" id="post" value="<?php echo $post_id; ?>"/>
<input type="hidden" id="name" value="<?php echo $username; ?>"/>
<textarea id="comment"></textarea><br />
<input type="submit" class="submit" value=" Submit Comment " />
</form>
</div>
<ol id="update" class="timeline">
</ol>
<div id="flash"></div>
<div >
<form action="#" method="post">
<input type="hidden" id="post" value="<?php echo $post_id; ?>"/>
<input type="hidden" id="name" value="<?php echo $username; ?>"/>
<textarea id="comment"></textarea><br />
<input type="submit" class="submit" value=" Submit Comment " />
</form>
</div>
<ol id="update" class="timeline">
</ol>
<div id="flash"></div>
<div >
<form action="#" method="post">
<input type="hidden" id="post" value="<?php echo $post_id; ?>"/>
<input type="hidden" id="name" value="<?php echo $username; ?>"/>
<textarea id="comment"></textarea><br />
<input type="submit" class="submit" value=" Submit Comment " />
</form>
</div>

First of all, as has been said in the comments, don't use repetead IDs. If you don't intend to use Ids as a unique identifier, use classes.
<ol class="timeline update">
<div id="flash"></div>
<div >
<form action="#" id="form" method="post">
<input type="hidden" class="post" value="<?php echo $post_id; ?>"/>
<input type="hidden" class="name" value="<?php echo $username; ?>"/>
<textarea class="comment"></textarea><br />
<input type="submit" class="submit" value=" Submit Comment " />
</form>
</div>
</ol>
In your javascript code, you are trying to get the id name with var name = $('#name'), right? What name?
Also, try to send your requeste with an array rather than a string.
Something like this:
$(".submit").click(function()
{
var name = $(this).parents('form:input.name').val();
var comment = $(this).parents('form:input.comment').val();
var post_id = $(this).parents('form:input.post').val();
var data = {'name': name,
'comment': comment,
'post_id':post_id},
$.ajax({
type: "POST",
url: "commenti.php",
data: data,
success: function(html){
//do stuff
}
}
Access your variable in PHP with $_POST['varName'];
Hope it helps.

.change not reacting as dynamic as expected

I'm new to javascript, I'm using jquery, this is my html with php code:
<form action="" method="POST" enctype="multipart/form-data">
<h1>Quantity 1</h1>
<input id="btn1" type="number" name="cantpag" value="<?php echo $cp; ?>">
<h1>Quantity 2</h1>
<input id="btn2" type="number" name="cantreinv" value="<?php echo $cr; ?>">
<input type="submit">
</form>
Here is my JS:
<script>
$(document).ready(function(){
$(document).on('change','#btn1',function(){
alert('works');
});
});</script>
When I change the value of "#btn1", nothing happens immediately, instead, I must press tab or somwhere else to have the alert show up. Is there any way for this to be instant, as in, just adding or removing a number from the input field triggers the alert?

$(document).ready(function(){
$(document).on('input','#btn1',function(){
alert('works');
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form action="" method="POST" enctype="multipart/form-data">
<h1>Quantity 1</h1>
<input id="btn1" type="number" name="cantpag" value="<?php echo $cp; ?>">
<h1>Quantity 2</h1>
<input id="btn2" type="number" name="cantreinv" value="<?php echo $cr; ?>">
<input type="submit">
</form>
The input event should work better. The change event on certain elements require a blur to register.

Auto submit login form and start session

I am trying to auto submit login form by using javascript but it cannot start session and redirect to same page but when i am try to submit same form without javascript it working.
I need to submit form automatically. Any suggestion?
<?php include('_header.php'); ?>
<form id="my_form" method="post" action="index.php" name="loginform">
<label for="user_name"><?php echo WORDING_USERNAME; ?></label>
<input id="user_name" type="text" value="something" name="user_name" required />
<label for="user_password"><?php echo WORDING_PASSWORD; ?></label>
<input id="user_password" type="hidden" value="something1" name="user_password" />
<input type="checkbox" id="user_rememberme" name="user_rememberme" value="1" />
<label for="user_rememberme"><?php echo WORDING_REMEMBER_ME; ?></label>
<input type="submit" name="login" value="<?php echo WORDING_LOGIN; ?>" />
</form>
<script type="text/javascript">
function submitForm() {
document.getElementById('my_form').submit();
}
window.onload = submitForm;
</script>
<?php echo WORDING_REGISTER_NEW_ACCOUNT; ?>
<?php echo WORDING_FORGOT_MY_PASSWORD; ?>
<?php include('_footer.php'); ?>

If you want to autosubmit your form upon page visit you simply put this code after your form:
<script>
document.getElementById('my_form').submit();
</script>

the problem is that you are submiting form over and over again, try this, check if form has already been submited and if not submit a form otherwise skip submition
<script type="text/javascript">
function submitForm() {
document.getElementById('my_form').submit();
}
<?php if(!isset($_REQUEST['login']) ) : ?> window.onload = submitForm; <?php endif ?>
</script>