What is the best way to calculate the time passed since (last) midnight in ms?
Create a new date using the current day/month/year, and get the difference.
var now = new Date(),
then = new Date(
now.getFullYear(),
now.getMonth(),
now.getDate(),
0,0,0),
diff = now.getTime() - then.getTime(); // difference in milliseconds
A bunch of answers so here another:
var d = new Date(), e = new Date(d);
var msSinceMidnight = e - d.setHours(0,0,0,0);
As a function:
function getMsSinceMidnight(d) {
var e = new Date(d);
return d - e.setHours(0,0,0,0);
}
alert(getMsSinceMidnight(new Date()));
Many answers except RobG's (recommended answer), Kolink's and Lai's are wrong here
Let's look closer together
First mistake
OptimusCrime and Andrew D. answers:
As Mala sugested, if the daylight saving correction was applied the nearest midnight, we get incorrect value. Let's debug:
Suppose it's last Sunday of March
The time is fixed at 2 am.
If we see 10 am on the clock, there's actually 11 hours passed from midnight
But instead we count 10 * 60 * 60 * 1000 ms
The trick is played when midnight happens in different DST state then current
Second mistake
kennebeck's answer:
As RobG wrote, the clock can tick if you get the system time twice. We can even appear in different dates sometimes. You can reproduce this in a loop:
for (var i = 0; true; i++) {
if ((new Date()).getTime() - (new Date()).getTime()) {
alert(i); // console.log(i); // for me it's about a 1000
break;
}
}
Third is my personal pitfall you could possibly experience
Consider the following code:
var d = new Date(),
msSinceMidnight = d - d.setHours(0,0,0,0);
msSinceMidnight is always 0 as the object is changed during computation before the substraction operation
At last, this code works:
var d = new Date(),
msSinceMidnight = d.getTime() - d.setHours(0,0,0,0);
Simpler to write, if you don't mind creating two dates.
var msSinceMidnight= new Date()-new Date().setHours(0,0,0,0);
var d=new Date();
// offset from midnight in Greenwich timezone
var msFromMidnightInGMT=d%86400000;
// offset from midnight in locale timezone
var msFromMidnightLocale=(d.getTime()-d.getTimezoneOffset()*60000)%86400000;
var today = new Date();
var d = new Date(today.getFullYear(), today.getMonth(), today.getDate(), 0, 0, 0, 0);
var difference = today.getTime() - d.getTime();
Seconds since midnight would simply be to display the time, but instead of using hours:minutes:seconds, everything is converted into seconds.
I think this should do it:
var now = new Date();
var hours = now.getHours()*(60*60);
var minutes = now.getMinutes()*60;
var seconds = now.getSeconds();
var secSinceMidnight = hours+minutes+seconds;
I am working on a project that requires a time in the future to be set using the Date object.
For example:
futureTime = new Date();
futureTime.setHours(futureTime.getHours()+2);
My questions is; once the future date is set, how can I round to the closest full hour and then set the futureTime var with it?
For example:
Given 8:55 => var futureTime = 9:00
Given 16:23 => var futureTime = 16:00
Any help would be appreciated!
Round the minutes and then clear the minutes:
var date = new Date(2011,1,1,4,55); // 4:55
roundMinutes(date); // 5:00
function roundMinutes(date) {
date.setHours(date.getHours() + Math.round(date.getMinutes()/60));
date.setMinutes(0, 0, 0); // Resets also seconds and milliseconds
return date;
}
The other answers ignore seconds and milliseconds components of the date.
The accepted answer has been updated to handle milliseconds, but it still does not handle daylight savings time properly.
I would do something like this:
function roundToHour(date) {
p = 60 * 60 * 1000; // milliseconds in an hour
return new Date(Math.round(date.getTime() / p ) * p);
}
var date = new Date(2011,1,1,4,55); // 4:55
roundToHour(date); // 5:00
date = new Date(2011,1,1,4,25); // 4:25
roundToHour(date); // 4:00
A slightly simpler way :
var d = new Date();
d.setMinutes (d.getMinutes() + 30);
d.setMinutes (0);
Another solution, which is no where near as graceful as IAbstractDownvoteFactory's
var d = new Date();
if(d.getMinutes() >= 30) {
d.setHours(d.getHours() + 1);
}
d.setMinutes(0);
Or you could mix the two for optimal size.
http://jsfiddle.net/HkEZ7/
function roundMinutes(date) {
return date.getMinutes() >= 30 ? date.getHours() + 1 : date.getHours();
}
As a matter of fact Javascript does this default which gives wrong time.
let dateutc="2022-02-17T07:20:00.000Z";
let bd = new Date(dateutc);
console.log(bd.getHours()); // gives me 8!!!!!
it is even wrong for my local time because I am GMT+2 so it should say 9.
moment.js also does it wrong so you need to be VERY carefull
Pass any cycle you want in milliseconds to get next cycle example 1 hours
function calculateNextCycle(interval) {
const timeStampCurrentOrOldDate = Date.now();
const timeStampStartOfDay = new Date().setHours(0, 0, 0, 0);
const timeDiff = timeStampCurrentOrOldDate - timeStampStartOfDay;
const mod = Math.ceil(timeDiff / interval);
return new Date(timeStampStartOfDay + (mod * interval));
}
console.log(calculateNextCycle(1 * 60 * 60 * 1000)); // 1 hours in milliseconds
I've a var example = "05-10-1983"
How I can get the "next day" of the string example?
I've try to use Date object...but nothing...
This would do it for simple scenarios like the one you have:
var example = '05-10-1983';
var date = new Date();
var parts = example.split('-');
date.setFullYear(parts[2], parts[0]-1, parts[1]); // year, month (0-based), day
date.setTime(date.getTime() + 86400000);
alert(date);
Essentially, we create an empty Date object and set the year, month, and date with the setFullYear() function. We then grab the timestamp from that date using getTime() and add 1 day (86400000 milliseconds) to it and set it back to the date using the setTime() function.
If you need something more complicated than this, like support for different formats and stuff like that, you should take a look at the datejs library which does quite a bit of work for you.
You can do the following:
var nextDay;
var example = "05-10-1983";
nextDay = new Date(example);
nextDay.setDate(nextDay.getDate() + 1);
#getDate/#setDate gets/sets the current day of the month (1-31).
After the above is run, nextDay will be set to whatever tomorrow's date is. This will also rollover to the next month / year if it's the end of the month, and even handle leap years. :)
new Date(+new Date('05-10-1983'.replace(/-/g,'/')) + 24*60*60*1000)
The problem with the +86400000 approach is the potential for error when crossing a daylight savings time barrier.
For example, I'm on EST.
If I do this:
var d = new Date("11/04/2012 00:00:00");
var e = new Date(d.getTime() + 86400000);
e is going to be 11/4/2012 23:00:00
If you then extract just the date portion, you get the wrong value. I recently hit upon this issue while writing a calendar control.
this will do it better (and with a flexible offset which will let you do more than 1 day in the future):
function getTomorrow(d,offset) {
if (!offset) { offset = 1 }
return new Date(new Date().setDate(d.getDate() + offset));
}
So
var d = new Date("11/04/2012 00:00:00");
var e = new Date(d.getTime() + 86400000);
doesn't work because of daylight saving barriers. I ran into the same problem. I ended up doing something like this:
function next_day(date) {
var e = new Date(date.getTime() + 24 * 60 * 60 * 1000);
if e.getHours() != date.getHours() {
e = new Date(e.getTime() + (e.getHours() - date.getHours()) * 60 * 60 * 1000)
}
return e;
}
You can use framework called php.js. Google for it. This includes the advanced date functions and more
You can find out day index by getDay() function and create an array of days strings in following manner-
day = new Date(YourDate);
var dayArray = ["Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"];
day = dayArray[day.getDay()+1];
There are leap seconds, leap days, DST, etc., so this can be a tricky problem to solve in all cases.
In my opinion, the best way to address this (without a date library) is to take advantage of the Date constructor overflow feature[1]:
main();
function main() {
var date = uniqueDateParse( '05-10-1983' );
var newDate = nextDay( date );
print( date );
print( newDate );
}
function uniqueDateParse( string ) {
var stringArray = string.split( '-', 3 );
var month = stringArray[ 0 ],
day = stringArray[ 1 ],
year = stringArray[ 2 ];
// Per ISO 8601[2], using Pacific Daylight Time[3].
var dateString = year + '-' + month + '-' + day + 'T00:00:00-07:00';
return new Date( dateString );
}
function nextDay( date ) {
return new Date( date.getFullYear()
, date.getMonth()
, date.getDate() + 1 );
}
function print( object ) {
console.log( object );
}
Links
[1] https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date#Parameters
[2] http://www.w3.org/TR/NOTE-datetime
[3] http://www.timeanddate.com/time/zones/pdt
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Is there an easy way of taking a olain JavaScript Date (e.g. today) and going back X days?
So, for example, if I want to calculate the date 5 days before today.
Try something like this:
var d = new Date();
d.setDate(d.getDate()-5);
Note that this modifies the date object and returns the time value of the updated date.
var d = new Date();
document.write('Today is: ' + d.toLocaleString());
d.setDate(d.getDate() - 5);
document.write('<br>5 days ago was: ' + d.toLocaleString());
var dateOffset = (24*60*60*1000) * 5; //5 days
var myDate = new Date();
myDate.setTime(myDate.getTime() - dateOffset);
If you're performing lots of headachy date manipulation throughout your web application, DateJS will make your life much easier:
http://simonwillison.net/2007/Dec/3/datejs/
It goes something like this:
var d = new Date(); // today!
var x = 5; // go back 5 days!
d.setDate(d.getDate() - x);
I noticed that the getDays+ X doesn't work over day/month boundaries. Using getTime works as long as your date is not before 1970.
var todayDate = new Date(), weekDate = new Date();
weekDate.setTime(todayDate.getTime()-(7*24*3600000));
If you want it all on one line instead.
5 days from today
//past
var fiveDaysAgo = new Date(new Date().setDate(new Date().getDate() - 5));
//future
var fiveDaysInTheFuture = new Date(new Date().setDate(new Date().getDate() + 5));
5 days from a specific date
var pastDate = new Date('2019-12-12T00:00:00');
//past
var fiveDaysAgo = new Date(new Date().setDate(pastDate.getDate() - 5));
//future
var fiveDaysInTheFuture = new Date(new Date().setDate(pastDate.getDate() + 5));
I wrote a function you can use.
function AddOrSubractDays(startingDate, number, add) {
if (add) {
return new Date(new Date().setDate(startingDate.getDate() + number));
} else {
return new Date(new Date().setDate(startingDate.getDate() - number));
}
}
console.log('Today : ' + new Date());
console.log('Future : ' + AddOrSubractDays(new Date(), 5, true));
console.log('Past : ' + AddOrSubractDays(new Date(), 5, false));
I find a problem with the getDate()/setDate() method is that it too easily turns everything into milliseconds, and the syntax is sometimes hard for me to follow.
Instead I like to work off the fact that 1 day = 86,400,000 milliseconds.
So, for your particular question:
today = new Date()
days = 86400000 //number of milliseconds in a day
fiveDaysAgo = new Date(today - (5*days))
Works like a charm.
I use this method all the time for doing rolling 30/60/365 day calculations.
You can easily extrapolate this to create units of time for months, years, etc.
get moment.js. All the cool kids use it. It has more formatting options, etc. Where
var n = 5;
var dateMnsFive = moment(<your date>).subtract(n , 'day');
Optional! Convert to JS Date obj for Angular binding.
var date = new Date(dateMnsFive.toISOString());
Optional! Format
var date = dateMnsFive.format("YYYY-MM-DD");
A few of the existing solutions were close, but not quite exactly what I wanted. This function works with both positive or negative values and handles boundary cases.
function addDays(date, days) {
return new Date(
date.getFullYear(),
date.getMonth(),
date.getDate() + days,
date.getHours(),
date.getMinutes(),
date.getSeconds(),
date.getMilliseconds()
);
}
Without using the second variable, you can replace 7 for with your back x days:
let d=new Date(new Date().getTime() - (7 * 24 * 60 * 60 * 1000))
I made this prototype for Date so that I could pass negative values to subtract days and positive values to add days.
if(!Date.prototype.adjustDate){
Date.prototype.adjustDate = function(days){
var date;
days = days || 0;
if(days === 0){
date = new Date( this.getTime() );
} else if(days > 0) {
date = new Date( this.getTime() );
date.setDate(date.getDate() + days);
} else {
date = new Date(
this.getFullYear(),
this.getMonth(),
this.getDate() - Math.abs(days),
this.getHours(),
this.getMinutes(),
this.getSeconds(),
this.getMilliseconds()
);
}
this.setTime(date.getTime());
return this;
};
}
So, to use it i can simply write:
var date_subtract = new Date().adjustDate(-4),
date_add = new Date().adjustDate(4);
I like doing the maths in milliseconds. So use Date.now()
var newDate = Date.now() + -5*24*3600*1000; // date 5 days ago in milliseconds
and if you like it formatted
new Date(newDate).toString(); // or .toUTCString or .toISOString ...
NOTE: Date.now() doesn't work in older browsers (eg IE8 I think). Polyfill here.
UPDATE June 2015
#socketpair pointed out my sloppiness. As s/he says "Some day in year have 23 hours, and some 25 due to timezone rules".
To expand on that, the answer above will have daylightsaving inaccuracies in the case where you want to calculate the LOCAL day 5 days ago in a timezone with daylightsaving changes and you
assume (wrongly) that Date.now() gives you the current LOCAL now time, or
use .toString() which returns the local date and therefore is incompatible with the Date.now() base date in UTC.
However, it works if you're doing your math all in UTC, eg
A. You want the UTC date 5 days ago from NOW (UTC)
var newDate = Date.now() + -5*24*3600*1000; // date 5 days ago in milliseconds UTC
new Date(newDate).toUTCString(); // or .toISOString(), BUT NOT toString
B. You start with a UTC base date other than "now", using Date.UTC()
newDate = new Date(Date.UTC(2015, 3, 1)).getTime() + -5*24*3600000;
new Date(newDate).toUTCString(); // or .toISOString BUT NOT toString
split your date into parts, then return a new Date with the adjusted values
function DateAdd(date, type, amount){
var y = date.getFullYear(),
m = date.getMonth(),
d = date.getDate();
if(type === 'y'){
y += amount;
};
if(type === 'm'){
m += amount;
};
if(type === 'd'){
d += amount;
};
return new Date(y, m, d);
}
Remember that the months are zero based, but the days are not. ie new Date(2009, 1, 1) == 01 February 2009, new Date(2009, 1, 0) == 31 January 2009;
Some people suggested using moment.js to make your life easier when handling dates in js. Time has passed since those answers and it is noteworthy, that the authors of moment.js now discourage its use. Mainly due to its size and lack of tree-shaking-support.
If you want to go the library route, use an alternative like Luxon. It is significantly smaller (because of its clever use of the Intl object and support for tree-shaking) and just as versatile as moment.js.
To go back 5 days from today in Luxon, you would do:
import { DateTime } from 'luxon'
DateTime.now().minus({ days: 5 });
function addDays (date, daysToAdd) {
var _24HoursInMilliseconds = 86400000;
return new Date(date.getTime() + daysToAdd * _24HoursInMilliseconds);
};
var now = new Date();
var yesterday = addDays(now, - 1);
var tomorrow = addDays(now, 1);
See the following code, subtract the days from the current date. Also, set the month according to substracted date.
var today = new Date();
var substract_no_of_days = 25;
today.setTime(today.getTime() - substract_no_of_days* 24 * 60 * 60 * 1000);
var substracted_date = (today.getMonth()+1) + "/" +today.getDate() + "/" + today.getFullYear();
alert(substracted_date);
I have created a function for date manipulation. you can add or subtract any number of days, hours, minutes.
function dateManipulation(date, days, hrs, mins, operator) {
date = new Date(date);
if (operator == "-") {
var durationInMs = (((24 * days) * 60) + (hrs * 60) + mins) * 60000;
var newDate = new Date(date.getTime() - durationInMs);
} else {
var durationInMs = (((24 * days) * 60) + (hrs * 60) + mins) * 60000;
var newDate = new Date(date.getTime() + durationInMs);
}
return newDate;
}
Now, call this function by passing parameters. For example, here is a function call for getting date before 3 days from today.
var today = new Date();
var newDate = dateManipulation(today, 3, 0, 0, "-");
Use MomentJS.
function getXDaysBeforeDate(referenceDate, x) {
return moment(referenceDate).subtract(x , 'day').format('MMMM Do YYYY, h:mm:ss a');
}
var yourDate = new Date(); // let's say today
var valueOfX = 7; // let's say 7 days before
console.log(getXDaysBeforeDate(yourDate, valueOfX));
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.2/moment.min.js"></script>
The top answers led to a bug in my code where on the first of the month it would set a future date in the current month. Here is what I did,
curDate = new Date(); // Took current date as an example
prvDate = new Date(0); // Date set to epoch 0
prvDate.setUTCMilliseconds((curDate - (5 * 24 * 60 * 60 * 1000))); //Set epoch time
I like the following because it is one line. Not perfect with DST changes but usually good enough for my needs.
var fiveDaysAgo = new Date(new Date() - (1000*60*60*24*5));
Using Modern JavaScript function syntax
const getDaysPastDate = (daysBefore, date = new Date) => new Date(date - (1000 * 60 * 60 * 24 * daysBefore));
console.log(getDaysPastDate(1)); // yesterday
A easy way to manage dates is use Moment.js
You can use add. Example
var startdate = "20.03.2014";
var new_date = moment(startdate, "DD.MM.YYYY");
new_date.add(5, 'days'); //Add 5 days to start date
alert(new_date);
Docs http://momentjs.com/docs/#/manipulating/add/
for me all the combinations worked fine with below code snipplet ,
the snippet is for Angular-2 implementation ,
if you need to add days , pass positive numberofDays , if you need to substract pass negative numberofDays
function addSubstractDays(date: Date, numberofDays: number): Date {
let d = new Date(date);
return new Date(
d.getFullYear(),
d.getMonth(),
(d.getDate() + numberofDays)
);
}
I get good mileage out of date.js:
http://www.datejs.com/
d = new Date();
d.add(-10).days(); // subtract 10 days
Nice!
Website includes this beauty:
Datejs doesn’t just parse strings, it slices them cleanly in two
If you want to both subtract a number of days and format your date in a human readable format, you should consider creating a custom DateHelper object that looks something like this :
var DateHelper = {
addDays : function(aDate, numberOfDays) {
aDate.setDate(aDate.getDate() + numberOfDays); // Add numberOfDays
return aDate; // Return the date
},
format : function format(date) {
return [
("0" + date.getDate()).slice(-2), // Get day and pad it with zeroes
("0" + (date.getMonth()+1)).slice(-2), // Get month and pad it with zeroes
date.getFullYear() // Get full year
].join('/'); // Glue the pieces together
}
}
// With this helper, you can now just use one line of readable code to :
// ---------------------------------------------------------------------
// 1. Get the current date
// 2. Subtract 5 days
// 3. Format it
// 4. Output it
// ---------------------------------------------------------------------
document.body.innerHTML = DateHelper.format(DateHelper.addDays(new Date(), -5));
(see also this Fiddle)
To calculate relative time stamps with a more precise difference than whole days, you can use Date.getTime() and Date.setTime() to work with integers representing the number of milliseconds since a certain epoch—namely, January 1, 1970. For example, if you want to know when it’s 17 hours after right now:
const msSinceEpoch = (new Date()).getTime();
const fortyEightHoursLater = new Date(msSinceEpoch + 48 * 60 * 60 * 1000).toLocaleString();
const fortyEightHoursEarlier = new Date(msSinceEpoch - 48 * 60 * 60 * 1000).toLocaleString();
const fiveDaysAgo = new Date(msSinceEpoch - 120 * 60 * 60 * 1000).toLocaleString();
console.log({msSinceEpoch, fortyEightHoursLater, fortyEightHoursEarlier, fiveDaysAgo})
reference
function daysSinceGivenDate (date) {
const dateInSeconds = Math.floor((new Date().valueOf() - date.valueOf()) / 1000);
const oneDayInSeconds = 86400;
return Math.floor(dateInSeconds / oneDayInSeconds); // casted to int
};
console.log(daysSinceGivenDate(new Date())); // 0
console.log(daysSinceGivenDate(new Date("January 1, 2022 03:24:00"))); // relative...
First arg is the date to start with and second is how mush day you want to increase or reduce to the date
example (1)- pass -1 to reduce date by one day
example (2)- pass 1 to increase date by one day
const EditDay = (date: Date, num: number): Date => {
return new Date(date.getTime() + num * 24 * 60 * 60 * 1000)
}
When setting the date, the date converts to milliseconds, so you need to convert it back to a date:
This method also take into consideration, new year change etc.
function addDays( date, days ) {
var dateInMs = date.setDate(date.getDate() - days);
return new Date(dateInMs);
}
var date_from = new Date();
var date_to = addDays( new Date(), parseInt(days) );
You can using Javascript.
var CurrDate = new Date(); // Current Date
var numberOfDays = 5;
var days = CurrDate.setDate(CurrDate.getDate() + numberOfDays);
alert(days); // It will print 5 days before today
For PHP,
$date = date('Y-m-d', strtotime("-5 days")); // it shows 5 days before today.
echo $date;
Hope it will help you.
I converted into millisecond and deducted days else month and year won't change and logical
var numberOfDays = 10;//number of days need to deducted or added
var date = "01-01-2018"// date need to change
var dt = new Date(parseInt(date.substring(6), 10), // Year
parseInt(date.substring(3,5), 10) - 1, // Month (0-11)
parseInt(date.substring(0,2), 10));
var new_dt = dt.setMilliseconds(dt.getMilliseconds() - numberOfDays*24*60*60*1000);
new_dt = new Date(new_dt);
var changed_date = new_dt.getDate()+"-"+(new_dt.getMonth()+1)+"-"+new_dt.getFullYear();
Hope helps