I validate the phone number using below code its working fine but i allow char at first time while user entering the values. how i can solve it. . . .
$('.Number').keypress(function () {
$('.Number').keypress(function (event) {
var keycode;
keycode = event.keyCode ? event.keyCode : event.which;
if (!(event.shiftKey == false && (keycode == 46 || keycode == 8 ||
keycode == 37 ||keycode == 39 || (keycode >= 48 && keycode <= 57)))) {
event.preventDefault();
}
});
});
The first character is unrestricted because you have nested keypress handlers. Try this:
$('.Number').keypress(function (event) {
var keycode = event.which;
if (!(event.shiftKey == false && (keycode == 46 || keycode == 8 || keycode == 37 || keycode == 39 || (keycode >= 48 && keycode <= 57)))) {
event.preventDefault();
}
});
Try
$('.Number').keyup(function (event) {
var keycode = event.which;
if (!(event.shiftKey == false && (keycode == 46 || keycode == 8 || keycode == 37 || keycode == 39 || (keycode >= 48 && keycode <= 57)))) {
event.preventDefault();
}
});
Here is a function that will validate the input. It will return true if the value is a number, false otherwise. Numbers are charcode 48 - 57. This function also allows all control characters to return true. (<32)
function isNumber(evt)
{
evt = (evt) ? evt : window.event;
var charCode = (evt.which) ? evt.which : evt.keyCode;
if (charCode > 32 && (charCode < 48 || charCode > 57)) {
return false;
}
return true;
}
Here is a chart of the codes.
<html>
<head>
<title>number validation</title>
<script>
function checkNumber(check)
{
var a = document.getElementById("txt_contact_no").value;
//var x=check.which;
//var x = a.charCode;
var x = a.keyCode;
if(!(a >= 48 || a <= 57))
{
alert("enter only numbers");
return false;
}
else if(a=="" || a==null)
{
alert("field is blank");
return false;
}
// if no is more then the value
/*else if (a.length <= 9)
{
alert("enter minimum 10 characters");
return false;
}*/
alert("done");
return true;
}
</script>
</script>
</head>
<body>
<table>
<form name=form1 method=post action="#">
<tr>
<td>
<b>Subjects</b><input type="text" name="contact_no" id="txt_contact_no" onblur="checkNumber(this)">
</td>
</tr>
<tr>
<td><p id="p1"></p></td>
</tr>
</form>
</table>
</body>
This is the simplest solution for KeyPress Number Events:
$(document).ready(function(){
$(".Number").keypress(function(event){
var keycode = event.which;
if (!(keycode >= 48 && keycode <= 57)) {
event.preventDefault();
}
});
});
Related
$("#chartModal").keypress( function (e) {
if (e.which != 8 && e.which != 0 && e.which != 43 && e.which != 45 && e.which != 46 && (e.which < 48 || e.which > 57)) {
return false;
}
});
This accept +, - & . in between the number, which is not a number.
Try with this
$(document).ready(function () {
$('#chartModal').keypress(function(e) {
var key = e.charCode || e.keyCode || 0;
var keychar = String.fromCharCode(key);
if ( ((key == 8 || key == 9 || key == 46 || key == 35 || key == 36 || (key >= 37 && key <= 40)) && e.charCode==0) /* backspace, end, begin, top, bottom, right, left, del, tab */
|| (key >= 48 && key <= 57) ) { /* 0-9 */
return;
} else {
e.preventDefault();
}
});
});
Here is an example:
$('#chartModal').keypress(function(e){
if (e.which != 8 && e.which != 0 &&e.which!= 43 && e.which!=45 && e.which !=46 &&(e.which < 48 || e.which > 57)) {
return false;
}
var charCode = e.which;
var value=$(this).val();
if(charCode==43 && value.indexOf('+')>=0) //Check whether a + is already there at beginning
return false;
if (charCode == 45 && value.indexOf('-') >= 0)//Check whether a - is already there at beginning
return false;
if (charCode == 46 && value.indexOf('.')!=-1)//Check at least one . is present in the number
return false;
});
Replace #idname with id of input.
I want to allow only one . in textfield, with backspace, left and right arrow.
I found this this link.
only allow numbers, backspace, delet, left arrow and right arrow keys in textbox
I addded one more validation in above code, so that user can add only . in textfield, but it's not working.
JS
function validateQty(event) {
var key = window.event ? event.keyCode : event.which;
if (event.keyCode == 8 || event.keyCode == 46 || event.keyCode == 37 || event.keyCode == 39 ) {
if($(this).val().indexOf('.') == -1)
return true;
else
return false;
}
else if ( key < 48 || key > 57 ) {
return false;
}
else return true;
};
JSFiddle
The problem as I see it is that in the line if($(this).val().indexOf('.') == -1), the this is the Window object not the input control.
Try adding an ID to the input control and reference the same in the code as:
function validateQty(event) {
var key = window.event ? event.keyCode : event.which;
if (event.keyCode == 8 || event.keyCode == 46 || event.keyCode == 37 || event.keyCode == 39 ) {
if($('#IdofInputControl').val().indexOf('.') == -1)
return true;
else
return false;
}
else if ( key < 48 || key > 57 ) {
return false;
}
else return true;
};
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="text" ID="IdofInputControl" onkeypress='return validateQty(event);'>
And your validation should work!
function isNumber(evt) {
evt = (evt) ? evt : window.event;
var charCode = (evt.which) ? evt.which : evt.keyCode;
if (charCode > 31 && (charCode < 48 || charCode > 57)&&(evt.which != 46 || $('#refAmount').val().indexOf('.') != -1)) {
return false;
}
return true;
}
You can use following code with some modifications of keys which you want to use or not.
jQuery("#YourSelector").keypress(function (evt) {
var charCode = (evt.which) ? evt.which : evt.keyCode;
if (charCode != 46 && charCode > 31 && (charCode < 43 || charCode > 57)){
return false;
}else{
return true;
}
});
On html I have one input box in which I just want to enter numeric values. I used following function:
function allowNumbersOnly(event,locale) {
if(locale=='en' && (event.keyCode==190 || event.keyCode==110)){
return true;
}
else if(locale=='nl' && (event.keyCode==188 || event.keyCode==190 || event.keyCode==110)){
return true;
}
if(event.keyCode==189 || (event.keyCode==109) ){
return true;
}
var key = event.charCode || event.keyCode || 0;
// allow backspace, tab, delete, arrows, numbers and keypad numbers ONLY
if (
key == 8 ||
key == 9 ||
key == 46 ||
(key >= 37 && key <= 40) ||
(key >= 48 && key <= 57) ||
(key >= 96 && key <= 105)){
}else{
event.preventDefault();
}
}
This code works fine. But when I am pressing shift key+ any number from keyboard then special character gets entered. Can anyone tell me how to solve this issue?
Try the following function
function isNumber(evt) {
evt = (evt) ? evt : window.event;
var charCode = (evt.which) ? evt.which : evt.keyCode;
if (charCode > 31 && (charCode < 48 || charCode > 57)) {
return false;
}
return true;
}
If you are using HTML5 just try
<input type="number">
Try like this:
function blockspecialcharacter(e) {
var key= document.all ? key= e.keyCode : key= e.which;
return ((key > 64 && key < 91) || (key> 96 && key< 123) || key== 8 || key== 32 || (key>= 48 && key<= 57));
}
Check demo here
shiftKey event attribute returns a Boolean value that indicates whether or not the "SHIFT" key was pressed
if (event.shiftKey==1)
{
alert("The shift key was pressed!")
}
else
{
alert("The shift key was NOT pressed!")
}
so you can exit from your function if shift is pressed using value of event.shiftKey
// in your code
function allowNumbersOnly(event,locale) {
if (event.shiftKey==1) {
return false;
} // RETURN if shift key got clicked.
if (locale=='en' && (event.keyCode==190 || event.keyCode==110)) {
return true;
}
else if (locale=='nl' && (event.keyCode == 188 ||
event.keyCode == 190 ||
event.keyCode == 110)) {
return true;
}
if (event.keyCode==189 || (event.keyCode==109)) {
return true;
}
var key = event.charCode || event.keyCode || 0;
// allow backspace, tab, delete, arrows, numbers and keypad numbers ONLY
if (key == 8 ||
key == 9 ||
key == 46 ||
(key >= 37 && key <= 40) ||
(key >= 48 && key <= 57) ||
(key >= 96 && key <= 105)) {
}
else {
event.preventDefault();
}
}
Try this:
function blockSpecialChars(e){
var e = e || window.event;
var k = e.which || e.keyCode;
var s = String.fromCharCode(k);
return !/^[\\\"\'\;\:\>\|~`!##\$%^&*\(\)]$/i.test(s);
}
Add or remove the special characters from the above code to make it as you need.
I am using following javascript code which I think should only allow numbers, backspace, delet, left arrow and right arrow keys in textbox, but it is also allowing alphabets. I don't know why?
function validateQty(event) {
var key = window.event ? event.keyCode : event.which;
if (event.keyCode == 8 || event.keyCode == 46
|| event.keyCode == 37 || event.keyCode == 39) {
return true;
}
else if ( key < 48 || key > 57 ) {
return false;
}
else return true;
};
Calling this function as
<input type="text" onkeypress='validateQty(event)'>
No doubt your code is correct but you missed "return" keyword in textbox.
<input type="text" onkeypress='return validateQty(event);'>
You can see the code here
<input type="text" class="form-control" id="dompetku_msisdn" name="dompetku_msisdn" placeholder="Phone Number" aria-describedby="helpBlock" onkeydown='return (event.which >= 48 && event.which <= 57) || event.which == 8 || event.which == 46 || event.which == 37 || event.which == 39' required /> </input>
function isNumberKey(evt)
{
var charCode = (evt.which) ? evt.which : event.keyCode
if (charCode > 31 && (charCode < 48 || charCode > 57))
return false;
return true;
}
<HTML>
<HEAD>
</HEAD>
<BODY>
<input id="txtChar" onkeypress="return isNumberKey(event)" type="text" name="txtChar" maxlength="10">
</BODY>
</HTML>
const validateQty = (event) => {
var key = window.event ? event.keyCode : event.which;
console.log(event);
if (event.keyCode === 8 || event.keyCode === 46
|| event.keyCode === 37 || event.keyCode === 39) {
return true;
} else if (key < 48 || key > 57) {
return false;
} else { return true; }
};
<input type="text" onkeydown='return validateQty(event);'>
I modified his code a bit, so you can just add a class to an input
$(".numberonly").keydown(function(e){
// Number Only
if (e.keyCode == 8 || e.keyCode == 46
|| e.keyCode == 37 || e.keyCode == 39) {
return true;
}
else if ( e.keyCode < 48 || e.keyCode > 57 ) {
e.preventDefault();
}
});
add class to an input
<input type="text" class="numberonly" />
I have text boxes which only allow to enter numeric values. I handled it using a JavaScript. But it doesn't allow me to enter dot and tab movement. I need those two as well. How to change this code to enter dot symbol and tab movement.
function CheckNumeric(e) {
if (window.event) // IE
{
if ((e.keyCode < 48 || e.keyCode > 57) & e.keyCode != 8) {
event.returnValue = false;
return false;
}
}
else // Fire Fox
{
if ((e.which < 48 || e.which > 57) & e.which != 8) {
e.preventDefault();
return false;
}
}
this code is tested and works..this may help u..!!
<script type="text/javascript">
function onlyDotsAndNumbers(txt, event) {
var charCode = (event.which) ? event.which : event.keyCode
if (charCode == 46) {
if (txt.value.indexOf(".") < 0)
return true;
else
return false;
}
if (charCode > 31 && (charCode < 48 || charCode > 57))
return false;
return true;
}
> <asp:TextBoxID="txt1"runat="server"onkeypress="return onlyDotsAndNumbers(this,event)"/>