Array 1:
[ user:{id:1,votes:9}, user:{id:2,votes:3} ]
Array 2:
[ user:{id:1,votes:10}, user:{id:2,votes:5}, user:{id:3,votes:1} ]
Using Node.js, what is the most efficient way to isolate the unique user based on id on it's own?
Using For loops and ForEach loops, I can't figure it out. Underscore is an option, but I still can't figure out a function process. Many thanks.
(I have no control over the way the data comes to me, modifying the array or the object isn't an option sadly)
Try this:
var ids = array1.map(function(u){ return u.id });
var unique = array2.filter(function(u) {
return ids.indexOf(u.id) < 0;
});
Related
I am trying to iterate over an array of array objects to de-dupe and sort the data within each. The function onlyUnique returns unique values in an array. The problem is, it doesn't work as intended.
arr_lists = [arr_1, arr_2, arr_3, arr_4, arr_5, ...]
for (var list_obj of arr_lists) {
list_obj = list_obj.join().split(',').filter(onlyUnique);
list_obj.sort();
Logger.log(list_obj);
}
The logger results show true (i.e. they are what I am looking for), but the original array is unchanged, although I think it should have been updated.
I've tried assigning the filtered array to a new array... nope.
I know that I could add a thousand lines of code to achieve the results, but that seems silly.
I suspect it's something obvious.
You can simply achieve it by using Set data structure to remove the duplicates and Array.sort() compare function to sort the elements in an array.
Live Demo :
const arr_lists = [[2,3,5,6], [7,2,5,3,3], [1,5,3], [4,7,4,7,3], [1,2,3]];
arr_lists.forEach((arr, index) => {
arr_lists[index] = [...new Set(arr)].sort((a, b) => a -b);
})
console.log(arr_lists);
Bit of a lengthy one so those of you who like a challenge (or I'm simply not knowledgeable enough - hopefully it's an easy solution!) read on!
(skip to the actual question part to skip the explanation and what I've tried)
Problem
I have a site that has a dataset that contains an object with multiple objects inside. Each of those objects contains an array, and within that array there are multiple objects. (yes this is painful but its from an API and I need to use this dataset without changing or modifying it.) I am trying to filter the dataset based of the key-value pairs in the final object. However, I have multiple filters being executed at once.
Example of Path before looping which retrieves the key-value pair needed for one hall.
["Hamilton Hall"]["Hire Options"][2].Commercial
After Looping Path of required key-value pair for all halls, not just one (the hall identifier is stored):
[0]["Hire Options"][2].Commercial
Looping allows me to check each hall for a specific key-value pair (kind of like map or forEach, but for an object).
After getting that out of the way back to the question.
How would I go about filtering which of the looped objects are displayed?
What I have Tried
(userInput is defined elsewhere - this happens on a btn click btw)
let results = Object.keys(halls);
for (key of results) {
let weekend = [halls[ `${key}` ][ 'Hire Options' ][4][ 'Weekend function' ]];
if(userInput == weekend) {
outputAll([halls[ `${key}` ]]);
}
}
That filters it fine. However, I run into an issue here. I want to filter by multiple queries, and naturally adding an AND into the if statement doesn't work. I also dont want to have 10 if statements (I have 10+ filters of various data types I need to sort by).
I have recently heard of ternary operators, but do not know enough about them to know if that is the correct thing to do? If so, how? Also had a brief loook at switches, but doesnt seem to look like what I want (correct me if I am wrong.)
Actual Question minus the babble/explanation
Is there a way for me to dynamically modify an if statements conditions? Such as adding or removing conditions of an if statement? Such as if the filter for 'a' is set to off, remove the AND condition for 'a' in the if statement? This would mean that the results would only filter with the active filters.
Any help, comments or 'why haven't you tried this' remark are greatly appreciated!
Thanks!
Just for extra reference, here is the code for retrieving each of the objects from the first object as it loops through them:
(Looping Code)
halls = data[ 'Halls' ];
let results = Object.keys(halls);
for (key of results) {
let arr = [halls[ `${key}` ]];
outputAll(arr);
}
You can use Array.filter on the keys array - you can structure the logic for a match how you like - just make it return true if a match is found and the element needs to be displayed.
let results = Object.keys(halls);
results.filter(key => {
if (userInput == halls[key]['Hire Options'][4]['Weekend function']) {
return true;
}
if (some other condition you want to match) {
return true;
}
return false;
}).forEach(key => outputAll([halls[key]]));
I have an array that is initialized like such var generationObject = [{string:"", score: 0}];
which I then fill dynamically:
for(var i = 0; i < amount_offspring; i++)
{
// "load" text into array and send the string to see if it evolves
generationObject[i].string = evolve(start_text, characters, mutation_rate);
// then score the string
generationObject[i].score = score(target_text, generationObject.string);
}
I then want to sort this array by score. I don't know what's best, to sort it in the for loop or sort the entire array afterwards.
I will then take the string of the highest scoring object and pass it through the function again, recursively.
So what would be a good way to go about this sort function? I've seen some here use this
generationObject.sort(function(a, b) {
return (a.score) - (b.score);
});
But I'm not sure if .sort is still supported? This didnt seem to work for me though.
generationObject is an array, not an object, so score(target_text, generationObject.string); could be the problem, as .string will be undefined. (Did you mean generationObject[i].string?)
Try building your array like this:
var generationObject = []
for(var i = 0; i < amount_offspring; i++)
{
evolved_string = evolve(start_text, characters, mutation_rate)
generationObject.push({
string: evolved_string,
score: score(target_text, evolved_string)
})
}
And then Array.prototype.sort should do the trick.
You should write your sorting logic outside the for loop, since if you put it inside, the object array will be sorted N times, where N being the iterations of your loop. The following are two ways to do it-
By using sort() function- To clarify your question, sort() is still supported across almost all the browsers. If you are still concerned about the browser compatibility, you can check the MDN documentation to see the list of supported browsers.
generationObject = generationObject.sort(function(a, b) {
return parseInt(a.score) - parseInt(b.score);
});
By using underscorejs-
In underscore, you can take advantage of the sortBy() function.
Returns a (stably) sorted copy of list, ranked in ascending order by the results of running each value through iteratee. iteratee may also be the string name of the property to sort by (eg. length).
You can simply do this in underscorejs-
generationObject = _.sortBy(generationObj, 'score');
i am trying to remove some items in an json object list, the ones that have a specific group. My JSON looks like this.
var events = [
{"id":"19","name":"sports","group":"1"},
{"id":"20","name":"school","group":"2"},
{"id":"21","name":"fun","group":"1"}
]
I tried this
for(var i in events)
if(events[i].group == deleted_group)
events.splice(i, 1);
But the problem of this, is that if i have to remove more items, it bugs out. Is there another easy way to to this ? I am open for sugestion even using underscore.js .
Thank you in advance, Daniel!
Try this
var events = [
{"id":"19","name":"sports","group":"1"},
{"id":"20","name":"school","group":"2"},
{"id":"21","name":"fun","group":"1"}
]
console.log(_.reject(events, function(event){ return event.group == '1'; }));
When you're using the "splice" function to remove elements from the array inside a for loop,
you need to shift your current index back when removing an item since the array is reindexed.
Also take a look at the array functions like "filter" for a more convenient way, read more on MDN.
You can use delete operator to delete objects (https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/delete):
delete events[0]
The problem with delete is, that in your array, as a value of events[0] it will leave undefined.
So another way (the way I would choose for your simple example) is to just rewrite the array:
var temp_events = [];
for(var i in events)
if(events[i].group != deleted_group)
temp_events[temp_events.length] = events[i];
events = temp_events;
Executing splice in a for loop has complexity n^2 (where n is number of elements). Rewriting has linear complexity.
Is it possible to turn a column of a multidimensional array to row using JavaScript (maybe Jquery)? (without looping through it)
so in the example below:
var data = new Array();
//data is a 2D array
data.push([name1,id1,major1]);
data.push([name2,id2,major2]);
data.push([name3,id3,major3]);
//etc..
Is possible to get a list of IDs from data without looping? thanks
No, it is not possible to construct an array of IDs without looping.
In case you were wondering, you'd do it like this:
var ids = [];
for(var i = 0; i < data.length; i++)
ids.push(data[i][1]);
For better structural integrity, I'd suggest using an array of objects, like so:
data.push({"name": name1, "id": id1, "major":major1});
data.push({"name": name2, "id": id2, "major":major2});
data.push({"name": name3, "id": id3, "major":major3});
Then iterate through it like so:
var ids = [];
for(var i = 0; i < data.length; i++)
ids.push(data[i].id);
JavaScript doesn't really have multidimensional arrays. What JavaScript allows you to have is an array of arrays, with which you can interact as if it was a multidimensional array.
As for your main question, no, you would have to loop through the array to get the list of IDs. It means that such an operation cannot be done faster than in linear time O(n), where n is the height of the "2D array".
Also keep in mind that arrays in JavaScript are not necessarily represented in memory as contiguous blocks. Therefore any fast operations that you might be familiar with in other low level languages will not apply. The JavaScript programmer should treat arrays as Hash Tables, where the elements are simply key/value pairs, and the keys are the indices (0, 1, 2...). You can still access/write elements in constant time O(1) (at least in modern JavaScript engines), but copying of elements will often be done in O(n).
You could use the Array map function which does the looping for you:
var ids = data.map(function(x) { return x[1] });
Unfortunately, like everything else on the web that would be really nice to use, INTERNET EXPLORER DOESN'T SUPPORT IT.
See this page for details on how the map function works:
https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Array/map
The good news it that the link above provides some nice code in the "Compatibility" section which will check for the existence of Array.prototype.map and define it if it's missing.
You don't need anything special- make a string by joining with newlines, and match the middle of each line.
var data1=[['Tom Swift','gf102387','Electronic Arts'],
['Bob White','ea3784567','Culinarey Arts'],
['Frank Open','bc87987','Janitorial Arts'],
['Sam Sneer','qw10214','Some Other Arts']];
data1.join('\n').match(/([^,]+)(?=,[^,]+\n)/g)
/* returned value: (Array)
gf102387,ea3784567,bc87987
*/