We Keep Coding

Why doesn't my form work on mobile devices?

I have a form downloaded from http://reusableforms.com/ that works great on desktop. But the submit button changes to "sending ..." and gets stuck on mobile devices. An error message doesn't display and the page just stops working. What would cause this problem? I am putting my javascript code below. Here is the site for reference: http://jasminew.xyz/flash
$(function()
{
$.ajaxSetup({ cache: false }); // or iPhones don't get fresh data
function after_form_submitted(data)
{
if(data.result == 'success')
{
$('#carouselExampleIndicators').hide();
$('form#reused_form').hide();
$('#success_message').show();
$('#error_message').hide();
}
else
{
$('#error_message').append('<ul></ul>');
jQuery.each(data.errors,function(key,val)
{
$('#error_message
ul').append('<li>'+key+':'+val+'</li>');
});
$('#success_message').hide();
$('#error_message').show();
//reverse the response on the button
$('button[type="button"]', $form).each(function()
{
$btn = $(this);
label = $btn.prop('orig_label');
if(label)
{
$btn.prop('type','submit' );
$btn.text(label);
$btn.prop('orig_label','');
}
});
}//else
}
$('#reused_form').submit(function(e)
{
e.preventDefault();
$form = $(this);
//show some response on the button
$('button[type="submit"]', $form).each(function()
{
$btn = $(this);
$btn.prop('type','button' );
$btn.prop('orig_label',$btn.text());
$btn.text('Sending ...');
});
var formdata = new FormData(this);
$.ajax({
type: "POST",
url: 'handler.php',
data: formdata,
success: after_form_submitted,
dataType: 'json' ,
processData: false,
contentType: false,
cache: false,
});
});
});
EDIT
I have opened remote Safari dev tools and the XHR Post is timing out. I'm not sure what that means.
EDIT
Okay, the problem is that the form stops working if the two upload fields in the form aren't used on iOS. Does anyone know a workaround?

I reviewed your code and would suggest some minor updates:
$(function() {
$.ajaxSetup({
cache: false
}); // or iPhones don't get fresh data
function after_form_submitted(data) {
if (data.result == 'success') {
$('#carouselExampleIndicators').hide();
$('form#reused_form').hide();
$('#success_message').show();
$('#error_message').hide();
} else {
$('#error_message').append('<ul></ul>');
$.each(data.errors, function(key, val) {
$("<li>").html(key + ": " + val).appendTo($('#error_message ul'));
});
$('#success_message').hide();
$('#error_message').show();
//reverse the response on the button
$('button[type="button"]', $form).each(function() {
var $btn = $(this);
var label = $btn.data('orig-label');
if (label) {
$btn.prop('type', 'submit');
$btn.text(label);
$btn.data('orig-label', null);
}
});
}
}
$('#reused_form').submit(function(e) {
e.preventDefault();
var $form = $(this);
//show some response on the button
$('button[type="submit"]', $form).each(function() {
var $btn = $(this);
$btn.prop('type', 'button');
$btn.data('orig-label', $btn.text());
$btn.text('Sending ...');
});
var formdata = new FormData($form[0]);
$.ajax({
type: "POST",
url: 'handler.php',
data: formdata,
success: after_form_submitted,
dataType: 'json',
processData: false,
contentType: false,
cache: false,
});
});
});
I see nothing that is "wrong", just some syntax cleanup. Also this was sort of ambiguous in the creation of FormData, so I switched to a more specific element: $form[0].
I adjusted a few other things to be more jQuery like. All functions the same.
Also, make sure that Ajax URL path is correct. You have:
url: 'handler.php'
Make sure that your can browse to this directly. If the path is not correct, the form will not post properly. It may be better to use a Direct URL Path instead of a relative path.
If you have access to your Web Server or PHP Logs, you can also check there to see if POSTs to your handler.php script are failing in some way. In Safari, you may want to check Network results and see if it provide more response details.
Test it, let me know if it works any better.

Updating div content after form submit without page reload

alright, I have a popup which displays some notes added about a customer. The content (notes) are shown via ajax (getting data via ajax). I also have a add new button to add a new note. The note is added with ajax as well. Now, the question arises, after the note is added into the database.
How do I refresh the div which is displaying the notes?
I have read multiple questions but couldn't get an answer.
My Code to get data.
<script type="text/javascript">
var cid = $('#cid').val();
$(document).ready(function() {
$.ajax({ //create an ajax request to load_page.php
type: "GET",
url: "ajax.php?requestid=1&cid="+cid,
dataType: "html", //expect html to be returned
success: function(response){
$("#notes").html(response);
//alert(response);
}
});
});
</script>
DIV
<div id="notes">
</div>
My code to submit the form (adding new note).
<script type="text/javascript">
$("#submit").click(function() {
var note = $("#note").val();
var cid = $("#cid").val();
$.ajax({
type: "POST",
url: "ajax.php?requestid=2",
data: { note: note, cid: cid }
}).done(function( msg ) {
alert(msg);
$("#make_new_note").hide();
$("#add").show();
$("#cancel").hide();
//$("#notes").load();
});
});
</script>
I tried load, but it doesn't work.
Please guide me in the correct direction.

Create a function to call the ajax and get the data from ajax.php then just call the function whenever you need to update the div:
<script type="text/javascript">
$(document).ready(function() {
// create a function to call the ajax and get the response
function getResponse() {
var cid = $('#cid').val();
$.ajax({ //create an ajax request to load_page.php
type: "GET",
url: "ajax.php?requestid=1&cid=" + cid,
dataType: "html", //expect html to be returned
success: function(response) {
$("#notes").html(response);
//alert(response);
}
});
}
getResponse(); // call the function on load
$("#submit").click(function() {
var note = $("#note").val();
var cid = $("#cid").val();
$.ajax({
type: "POST",
url: "ajax.php?requestid=2",
data: {
note: note,
cid: cid
}
}).done(function(msg) {
alert(msg);
$("#make_new_note").hide();
$("#add").show();
$("#cancel").hide();}
getResponse(); // call the function to reload the div
});
});
});
</script>

You need to provide a URL to jQuery load() function to tell where you get the content.
So to load the note you could try this:
$("#notes").load("ajax.php?requestid=1&cid="+cid);

Ajax Form Cannot Prevent Page Reload with event.preventDefault();

I have the following code which is supposed submit a form via Ajax without having to reload the page:
$( document ).on('submit', '.login_form', function( event ){
event.preventDefault();
var $this = $(this);
$.ajax({
data: "action=login_submit&" + $this.serialize(),
type: "POST",
url: _ajax_login_settings.ajaxurl,
success: function( msg ){
ajax_login_register_show_message( $this, msg );
}
});
});
However for some reason, despite the event.preventDefault(); function which is supposed to prevent the form from actually firing, it actually does fire.
My question is, how do I prevent the above form from reloading the page?
Thanks

don't attach a listener on document instead use a on click handler on the submit button and change the type to button.
<button id="form1SubmitBtn">Submit</button>
$('#form1SubmitBtn').click(function(){
//do ajax here
});
Happy Coding !!!

for instance you can write like this
$(".login_form").on('submit', function( event ){
var $this = $(this);
$.ajax({
data: "action=login_submit&" + $this.serialize(),
type: "POST",
url: _ajax_login_settings.ajaxurl,
success: function( msg ){
ajax_login_register_show_message( $this, msg );
}
});
event.preventDefault();
});

You can use jquery and ajax to do that. Here is a nice piece code below that doesn't refresh the page but instead on submit the form gets hidden and gets replaced by a thank you message. The form data is sent to an email address using sendmail.php script.
Assuming your form has 3 input fields - name, email and message.
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.3/jquery.min.js"></script>
<script type="text/javascript">
jQuery(function() {
jQuery("#button").click(function() {
var name=jQuery('#name').val();
var email=jQuery('#email').val();
var message=jQuery('#message').val();
var dataString = 'name='+ name + '&email=' + email + '&message=' + message;
jQuery.ajax({
type: "POST",
url: "sendmail.php",
data: dataString,
success: function() {
jQuery('#contact_form').html("<div id='message'></div>");
jQuery('#contactForm').hide();
jQuery('#message').html("<h2>Contact Form Submitted!</h2>")
.append("<p>Thank you for your submission. We will be in touch shortly.</p>").hide()
.fadeIn(1500, function() {
});
}
});
return false;
});
});
</script>
On top of your form tag just add this to display the thank you message.
<div id='message'></div>
Enjoy coding!!!!!!!

Pages loaded by AJAX from the PHP back-end

What I'm tring to do is to load information from different pages, without having to refresh the whole main page...
Could you tell me how to adapt this code for loading files with different names (like about.html and project.html?
Note: this code is made just for loading 'page_.html' files.
var default_content="";
$(document).ready(function(){
checkURL();
$('ul li a').click(function (e){
checkURL(this.hash);
});
default_content = $('#pageContent').html();
setInterval("checkURL()",250);
});
var lasturl="";
function checkURL(hash)
{
if(!hash) hash=window.location.hash;
if(hash != lasturl)
{
lasturl=hash;
if(hash=="")
$('#pageContent').html(default_content);
else
loadPage(hash);
}
}
function loadPage(url)
{
url=url.replace('#page','');
$('#loading').css('visibility','visible');
$.ajax({
type: "POST",
url: "load_page.php",
data: 'page='+url,
dataType: "html",
success: function(msg){
if(parseInt(msg)!=0)
{
$('#pageContent').html(msg);
$('#loading').css('visibility','hidden');
}
}
});
}
Here is the php file:
if(!$_POST['page']) die("0");
$page = (int)$_POST['page'];
if(file_exists('pages/page_'.$page.'.html'))
echo file_get_contents('pages/page_'.$page.'.html');
else echo 'There is no such page!';

You can make multiple ajax requests this is the jquery load method:
$( "#result" ).load( "ajax/test.html", function() {
alert( "Load was performed." );
});
do that 2x and your well off!
Keep in mind for this to work you'll need the jquery library.
I was doing a similar thing on my site here is my code:
window.setInterval("check()",60000);
//request information notice is inside a function called check() (it's not required to put inside function I only do this if I will be making the same request multiple time throughout the program)
function check() {
var request = $.ajax({
url: "file.php",
type: "POST",
dataType: "html"
});
request.done(function(msg) {
//when request is done:
$(".wheretoputnewdata").html(msg);
});
request.fail(function(jqXHR, textStatus) {
//if request failed do this:
alert( "Request failed: " + textStatus );
});
}

Replace this line
if(file_exists('pages/page_'.$page.'.html'))
with this
if(file_exists('pages/'.$page.'.html'))

How to pass extra parameter in jquery post request from outside click event?

Hi i have jquery request like below ,
$('#filterForm').submit(function(e){
e.preventDefault();
var dataString = $('#filterForm').serialize();
var class2011 = document.getElementById("2011").className;
//var validate = validateFilter();
alert(dataString);
if(class2011=='yearOn')
{
dataString+='&year=2011';
document.getElementById("2011").className='yearOff';
}
else
{
document.getElementById("2011").className='yearOn';
}
alert (dataString);
$.ajax({
type: "POST",
url: "myServlet",
data: dataString,
success: function(data) {
/*var a = data;
alert(data);*/
}
});
and my Form is like ,
<form method="post" name="filterForm" id="filterForm">
<!-- some input elements -->
</form>
Well, I am triggering jquery submit on submit event of a form ,(it's working fine)
I want pass one extra parameter inside form which is not in above form content but it's outside in page
it's like below
[Check this image link for code preview][1]
So how can i trigger above event , on click of , element with class yearOn ( check above html snippet ) and class yearOff , with additional parameter of year set to either 2011 or 2010

$(document).ready(function () {
$('#filterForm').submit(function (e) {
e.preventDefault();
var dataString = $('#filterForm').serialize();
if ($("#2011").hasClass('yearOn')) {
dataString += '&year=2011';
$("#2011").removeClass('yearOn').addClass('yearOff');
}
else {
$("#2011").removeClass('yearOff').addClass('yearOn');
}
$.ajax({
url: "/myServlet",
type: "POST",
data: dataString,
success: function (data) {
/*var a = data;
alert(data);*/
}
});
});
});

1.) If you are using jQuery already, you can use the $.post() function provided by jquery. It will make your life easier in most cases.
2.) I have always had a successful post with extra parameters this way:
Build you extra parameters here
commands={
year:'2011'
};
Combine it with your form serialize
var dataString=$.param(commands)+'&'+$("#filterForm").serialize();
Perform your post here
$.post("myServlet",data,
function(data) {
/*var a = data;
alert(data);*/
}
);
OR use $.ajax if you really love it
$.ajax({
type: "POST",
url: "myServlet",
data: dataString,
success: function(data) {
/*var a = data;
alert(data);*/
}
In the end, here is the full code the way you are doing it now
$('#filterForm').submit(function(e){
e.preventDefault();
var class2011 = document.getElementById("2011").className;
//var validate = validateFilter();
alert(dataString);
if(class2011=='yearOn') {
dataString+='&year=2011';
document.getElementById("2011").className='yearOff';
} else {
document.getElementById("2011").className='yearOn';
}
commands={
year:'2011'
};
var dataString=$.param(commands)+'&'+$("#filterForm").serialize();
alert (dataString);
$.ajax({
type: "POST",
url: "myServlet",
data: dataString,
success: function(data) {
/*var a = data;
alert(data);*/
}
});