I have a situation where, in normal CSS circumstances, a fixed div would be positioned exactly where it is specified (top:0px, left:0px).
This does not seem to be respected if I have a parent that has a translate3d transform. Am I not seeing something? I have tried other webkit-transform like style and transform origin options but had no luck.
I have attached a JSFiddle with an example where I would have expected the yellow box be at the top corner of the page rather than inside of the container element.
You can find below a simplified version of the fiddle:
#outer {
position:relative;
-webkit-transform:translate3d(0px, 20px , 0px);
height: 300px;
border: 1px solid #5511FF;
padding: 10px;
background: rgba(100,180,250, .8);
width: 80%;
}
#middle{
position:relative;
border: 1px dotted #445511;
height: 300px;
padding: 5px;
background: rgba(250,10,255, .6);
}
#inner {
position: fixed;
top: 0px;
box-shadow: 3px 3px 3px #333;
height: 20px;
left: 0px;
background: rgba(200,180,80, .8);
margin: 5px;
padding: 5px;
}
<div id="container">
Blue: Outer, <br>
Purple: Middle<br>
Yellow: Inner<br>
<div id="outer">
<div id="middle">
<div id="inner">
Inner block
</div>
</div>
</div>
</div>
How can I make translate3d work with fixed-positioned children?
This is because the transform creates a new local coordinate system, as per W3C spec:
In the HTML namespace, any value other than none for the transform results in the creation of both a stacking context and a containing block. The object acts as a containing block for fixed positioned descendants.
This means that fixed positioning becomes fixed to the transformed element, rather than the viewport.
There's not currently a work-around that I'm aware of.
It is also documented on Eric Meyer's article: Un-fixing Fixed Elements with CSS Transforms.
As Bradoergo suggested, just get the window scrollTop and add it to the absolute position top like:
function fix_scroll() {
var s = $(window).scrollTop();
var fixedTitle = $('#fixedContainer');
fixedTitle.css('position','absolute');
fixedTitle.css('top',s + 'px');
}fix_scroll();
$(window).on('scroll',fix_scroll);
This worked for me anyway.
I had a flickering on my fixed top nav when items in the page were using transform, the following applied to my top nav resolved the jumping/flickering issue:
#fixedTopNav {
position: fixed;
top: 0;
transform: translateZ(0);
-webkit-transform: translateZ(0);
}
Thanks to this answer on SO
In Firefox and Safari you can use position: sticky; instead of position: fixed; but it will not work in other browsers. For that you need javascript.
In my opinion, the best method to deal with this is to apply the same translate, but break children that need to be fixed out of their parent (translated) element; and then apply the translate to a div inside the position: fixed wrapper.
The results look something like this (in your case):
<div style='position:relative; border: 1px solid #5511FF;
-webkit-transform:translate3d(0px, 20px , 0px);
height: 100px; width: 200px;'>
</div>
<div style='position: fixed; top: 0px;
box-shadow: 3px 3px 3px #333;
height: 20px; left: 0px;'>
<div style='-webkit-transform:translate3d(0px, 20px, 0px);'>
Inner block
</div>
</div>
JSFiddle: https://jsfiddle.net/hju4nws1/
While this may not be ideal for some use cases, typically if you're fixing a div you probably could care less about what element is its parent/where it falls in the inheritance tree in your DOM, and seems to solve most of the headache - while still allowing both translate and position: fixed to live in (relative) harmony.
I ran across the same problem. The only difference is that my element with 'position: fixed' had its 'top' and 'left' style properties set from JS. So I was able to apply a fix:
var oRect = oElement.getBoundingClientRect();
oRect object will contain real (relative to view port) top and left coordinates. So you can adjust your actual oElement.style.top and oElement.style.left properties.
I have an off canvas sidebar that uses -webkit-transform: translate3d. This was preventing me from placing a fixed footer on the page. I resolved the issue by targeting a class on the html page that is added to the tag on initialization of the sidebar and then writing a css :not qualifier to state "-webkit-transform: none;" to the html tag when that class is not present on the html tag. Hope this helps someone out there with this same issue!
Try to apply opposite transform to the child element:
<div style='position:relative; border: 1px solid #5511FF;
-webkit-transform:translate3d(0px, 20px , 0px);
height: 100px; width: 200px;'>
<div style='position: fixed; top: 0px;
-webkit-transform:translate3d(-100%, 0px , 0px);
box-shadow: 3px 3px 3px #333;
height: 20px; left: 0px;'>
Inner block
</div>
</div>
Add a dynamic class while the element transforms.$('#elementId').addClass('transformed').
Then go on to declare in css,
.translat3d(#x, #y, #z) {
-webkit-transform: translate3d(#X, #y, #z);
transform: translate3d(#x, #y, #z);
//All other subsidaries as -moz-transform, -o-transform and -ms-transform
}
then
#elementId {
-webkit-transform: none;
transform: none;
}
then
.transformed {
#elementId {
.translate3d(0px, 20px, 0px);
}
}
Now position: fixed when provided with a top and z-index property values on a child element just work fine and stay fixed until the parent element transforms. When the transformation is reverted the child element pops as fixed again. This should easen the situation if you are actually using a navigation sidebar that toggles open and closes upon a click, and you have a tab-set which should stay sticky as you scroll down the page.
One way to deal with this is to apply the same transform to the fixed element:
<br>
<div style='position:relative; border: 1px solid #5511FF;
-webkit-transform:translate3d(0px, 20px , 0px);
height: 100px; width: 200px;'>
<div style='position: fixed; top: 0px;
-webkit-transform:translate3d(0px, 20px , 0px);
box-shadow: 3px 3px 3px #333;
height: 20px; left: 0px;'>
Inner block
</div>
</div>
I am new to web developing, and forgive me if this is very naive question but I am facing an issue where I have a row which has 7 images basically certification that My company has. They all are different size and color and doesnt look good together.
I am trying to make them all look same size and responsive.
So far I have used:
clip: rect(0px,60px,200px,0px);
but this just cuts the images, so I need some other solution which can fix this
My first image is 250*100px whereas other is 250*250px likewise I have 7 images all different size so I have set max-width:250px; height:auto; and this is how it look now:
CSS:
.ribbon img{
height:150px;
margin: 2px 2px 2px 2px;
}
.ribbon img:hover{
border: solid 1px black;
-moz-box-shadow: 0 0 10px #ccc;
-webkit-box-shadow: 0 0 10px #ccc;
box-shadow: 0 0 10px black;
}
.ribbon{
vertical-align:center;
}
What I am trying to get is those first to image should come in center I have tried vertical-align:middle but doesn't work and the PCGS image is full size 250*250 so it is the problem
You could try img { height: 250px; } to makes all img with the same height, browser will handle the width onscale if you leave the width not set
Edit 1 -
If you want they have the same width, you may replace the height with width that setup the value you want, please try this example, https://jsfiddle.net/e7wv86pc/
img { width: 14%; }
You can also use css property background-size set to cover, and set the images using css background-image property like this:
.image {
width: 250px;
height: 250px;
background-repeat: no-repeat;
background-size: cover;
background-position: center;
}
.i1 {
background-image: url("http://ia.media-imdb.com/images/M/MV5BMjE4NDMwMzc4Ml5BMl5BanBnXkFtZTcwMDg4Nzg4Mg##._V1_UY317_CR6,0,214,317_AL_.jpg");
}
.i2 {
background-image: url("http://feelgrafix.com/data_images/out/20/932835-gerard-butler.jpg");
}
<div class="image i1"></div>
<div class="image i2"></div>
I was wondering if there is a way to make the hover area bigger than the image?
For example, I have an image that is 72px x 61px and when I hover over it, it changes to a different image. What I would like to know is if I can hover outside the image but still trigger the change in the image.
Sorry if this is confusing, I tried to post an image but since I just signed up I am not able to.
This is a working example, just hover in the gray colored region
.outer {
border: 1px solid;
padding: 60px;
width: 300px;
background-color: #ddd;
}
.outer:hover>img {
content: url('http://docs.gimp.org/en/images/filters/examples/color-taj-sample-colorize.jpg');
}
<div class="outer">
<img src="http://goo.gl/7VYJyX" />
</div>
Yes. Put it in a container (<div>, <a>, whatever), add padding to the container (to increase the area).
If what you're doing is in JS, attach the hover handler to the container instead of the image.
If you're doing CSS, something like this should be helpful:
.container:hover img{
/* styles for img when .container is hovered*/
}
Is this what you are going for. her is my fiddle https://jsfiddle.net/pdjoh1dy/1/
HTML
<div id="hover-example">
<div id="img-holder">
</div>
</div>
CSS
#hover-example{width: 500px; height: 500px; border-style: solid;}
#img-holder{margin: 25%; width: 50%; height: 50%; background-color: blue;}
#hover-example:hover > #img-holder{
background-color: red;
margin: 10%;
width: 80%;
height: 80%;
}
You could also set the image to display: block and add padding, if it does not mess with your layout.
How can we apply a circle mask to a non-square image and still maintain the original image's aspect ratio, ie. prevent the image from being squashed? The image should still fill the entire circle.
A CSS-only solution is preferred, otherwise jQuery/Javascript can be used.
JSFiddle Example: http://jsfiddle.net/vxLmrm0o/
.photo {
position: absolute;
z-index: 999;
width: 160px;
height: 160px;
background: #ccc;
border: 3px solid #fff;
border-radius: 80px;
-webkit-border-radius: 80px;
-moz-border-radius: 80px;
top: 0px;
position: relative;
overflow:hidden;
text-align:center;
}
.photo-bg {
width: 100%;
padding: 40px 0 40px 0;
text-align: center;
background: #ccc;
}
Could you use a wrapper, and then set overflow:hidden? With the wrapper object being set relatively, and img absolutely, you could come up with something like:
.wrapper{
height:200px;
width:200px;
border-radius:50%;
overflow:hidden;
background: rgba(0,0,0,0.5);
text-align:center;
position:relative;
}
img {
position:absolute;
width: 400px;
top:0;
left:0;
}
<div class="wrapper">
<img src="http://media.bestofmicro.com/R/O/464964/original/Facebook-logo-PSD.jpg" class="photo" />
</div>
If that's the overall outcome you're looking for.
I've noticed in your example you've set:
width: 160px;
height: 160px;
Which is going to bring a change to your aspect ratio.
By setting only one of these values, the other will be set to 'auto', meaning it will scale to your correct aspect ratio.
example 1
but alas! This isn't right!
I see you've prefixed the border-radius property, and set it to 80px;
I would see this as a bit of overkill, since vendor prefixes for this aren't really necessary. see here
Instead, you could set it to 50%, and use the non-prefixed version:
border-radius: 50%;
But you've still got this 'rectangle' issue. So instead, you could use a wrapper to solve this:
example 2
This still has a few issues, the likes of top:0; is actually pointless since it was set on a position:relative and so bears no importance/use for this (it can only be used on other position types, for example absolute;)
finishing this off and tiding it up, you could be left with this:
DEMO
Or as my snippet shows above, you could 're write' it to this:
DEMO
I have an image slider. In order to have a shoother view I want to show image edges feathered when rolling.
I have tried to use box-shadow property but it did not help me. It is possible to feather image edges using an image editor. But I do not want that.
I have added an additional <div class="insetShadow"> next to <img>.
<div class="item">
<img src="images/01.jpg" alt="" />
<div class="insetShadow"></div>
</div>
.insetShadow
{
width: 100%;
height: 100%;
top:0;
left:0;
position:relative;
box-shadow: inset 0px 0px 13px 5px #fff;
z-index: 20;
}
.carousel img
{
width: auto;
height: 300px;
max-height: 300px;
margin: 0 auto;
position: relative;
z-index: 19;
}
box-shadow is not applicable to img element when inset feature enabled.
In the up-left picture you may see the actual view and in the bottom-right desired view.
Is there any other css solution for that or any jQuery plugin?
Try using a spread radius of at least half of the blur radius:
box-shadow: inset 0 0 12px 6px #fff;
Demo
You can use this generator to mess up with the box-shadow properly. It's just CSS and attach it to the slideshow element with jQuery.
Check this and work around!