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jquery, time out another jquery function if a user clicks a div?

I have the following script which fades in multiple divs called 'noti_box'. If a user closes these divs then another div 'advert' fades in in its place.
<script>
$(document).ready(function(){
var animations = [];
$('.noti_box').each(function(i) {
animations.push(
$(this).hide().delay(i * 1000).fadeIn(1500).promise()
);
});
$.when.apply($, animations).done(function () {
time=setInterval(function(){
if ( $('.noti_box:visible').length === 0 ) {
$(".advert").fadeIn("slow");
} },200);
});
});
</script>
this works fine, basically what happens here is my last function is stuck on a loop, where the 'advert' div fades in when 'noti_box' is not visible on the page.
However, now I want a user to click a div called 'icons' and if they do, then this should re-fade in the 'noti_box' divs and fade out the 'advert' div using this code:
<script>
$('.icons').click(function(){
$('.advert').fadeOut('fast');
$('.noti_box).fadeIn('fast');
});
</script>
The problem I have here is the 'advert' div fades in and out again in the blink of an eye, without fading in my 'noti_box' div. This is because my first javascript function is still on a loop and preventing my second script from executing.
So what I need to do, I think is set a time out interval for my first script when a user clicks my div 'icon' and then clear the time out interval once the script has executed and the 'noti_box' divs are once again showing.
Can someone please show me how I would be able to do this as I am brand new to jquery. Thanks

function notiBox(ele){
this.ele=ele;
this.ele.hide().fadeIn('slow');
console.log("I have been born! "+ele);
}
notiBox.prototype={
constructor:notiBox,
advert:function(){
var ele=this.ele;
this.ele.fadeOut('fast',function(){ele.next('.advert').fadeIn('slow');});
},
fadeBack:function(){
var ele=this.ele;
this.ele.next('.advert').fadeOut('slow',function(){ele.fadeIn('slow');});
},
}
$(document).ready(function(){
var timeIn=1;
$('.noti-box').each(function(){
var self=this;
this.timer=setInterval(function(){self.notiBox=new notiBox($(self));clearInterval(self.timer);},1000*timeIn);
timeIn++;
});
$('.icon').click(function(){
$('.noti-box').notiBox.fadeBack();
});
});
Right the above is a 'OOP' based approach to your problem. The only problem you might have with this is that your advert divs are not next to the box div. Sorry I guess your DOM elements and layout. Also my methods my not be correct because it's been so long since I've written something like that. I'll do some tests. In the mean time, could you put up some HTML? So that I can adjust my code :d

How to Initiate Image Fade Out and Fade In with jQuery Function

I have a little jQuery function in my Asp.Net MasterPage that fades an image out after 3 seconds. It works fine, but I'm having difficulty getting it to fade back in. I've tried several things as I'm new using jQuery, and I know there's something I'm doing or not doing. I can't put my finger on it. Here's what I have:
<script src="/Scripts/jquery-2.1.1.js" type="text/javascript"></script>
<script type="text/javascript">
$(document).ready(function (){
setTimeout(function (){
$('#Image1').fadeOut('slow', function(){
$('#Image1').remove();
});
}, 3000);
});
var fadeBack = function () {
$('#Image1').fadeIn();
};
fadeBack();
</script>
Like I said, it fades out with no problem, but I cannot find the right code structure to bring it back in. I'm thinking maybe an If statement block about the opacity is needed?
The real trick is that I want alternate images in 3 boxes I have as seen here:
I have about 12 images total, and just want them to fade one image out, and bring another in. Being more specific, I mean the following:
Column (1): Image1.FadeOut(); Image2.FadeIn(); Image2.FadeOut(); Image3.FadeIn(), and etc.
So for now, I just need help with how to do this in Column One, and I'll see if can string something together to make the other Columns 2 and 3 follow up. The timing would be 3 second for each.
Lastly, could I use an array to store other images which aren't in the Column One box already and call them into the slideshow fade sequence? I appreciate you help for this knowledge, so I can lock this in mind. Thanks.

Use this code, it will hide the image after 3 seconds and after that 1 sec, it will show image back.
$(document).ready(function (){
setTimeout(function (){
$('#Image1').fadeOut('slow');
}, 3000);
setTimeout(function (){
$('#Image1').fadeIn('slow');
}, 4000);
});
if you want like a slideshow use this code
<div class="yourimg_container">
<img src="http://localhost/app/img/off.png" id="Image1"/>
</div>
/* make an array containing your images path (you can fetch images from database using asp.net/php query)*/
var ss= ["http://localhost/app/img/off.png",
"http://localhost/app/img/on.png",
"http://localhost/app/img/slider.png"];
window.setInterval(function(){
slideshow();
}, 3000);
function slideshow(){
var im=$("#Image1").attr("src");
for(i=0;i<ss.length;i++){
if(ss[i]==im){
if(i==ss.length-1) $('#Image1').attr("src",ss[0]);
else $('#Image1').attr("src",ss[i+1]);
}
}
}
additionally you can use other effects like this
function slideshow(){
var im=$("#Image1").attr("src");
for(i=0;i<ss.length;i++){
if(ss[i]==im){
if(i==ss.length-1) {
$('#Image1').fadeOut(500);
$('#Image1').attr("src",ss[0]);
$('#Image1').fadeIn(700);
}
else {
$('#Image1').fadeOut(500);
$('#Image1').attr("src",ss[i+1]);
$('#Image1').fadeIn(700);
}
}
}
}

Your fadeBack() is launched immediately whereas the fadeOut has 3 sec delay. Set a timer for your fadeBack grater than 3 sec and the img will appear.

There is a function $('#Image1').remove(); Applied. It mean once fade over, the html block will be removed. Then you can't access the object. Because fade in and fade out accessing same id #Image1. So comment the line. It may work.

Changing the order of events in Jquery

So I created some pop-up code that will contain specific information from each link clicked in the pop-up. When closed, the content in the pop-up div gets deleted. Here is my code:
var $content = $('#popupcontent');
var $window = $('#popupwindow');
$('.open').click(function(){
//alert('runnning');
var a = $(this).contents('span');
$content.append(a);
$window.fadeIn(300);
});
$('.close').click(function(){
//alert('running');
var a = $content.contents('span');
$window.fadeOut(300);
$('#popupcontent span').remove();
});
My issue is that it is somehow removing the content before fading out, so the viewer can then see that the pop-up container goes blank. How can I make it so that it will surely fade out first and then remove the content? Here is a Jsfiddle to illustrate that: http://jsfiddle.net/kAdQK/4/

You may want to utilize the complete call back argument for the fadeout method, to remove the element once fadeout is completed. With your current code it will start the fadeout animation and then immediately remove the content without waiting for fadeout animation to complete, hence you get the visual effect that you are seeing now. Using the callback you make sure that it gets executed once the animation is complete.
$window.fadeOut(300, function () {
$('#popupcontent span').remove();
});
Syntax
.fadeOut( [duration ] [, complete ] )
Fiddle

You can use the animation complete to remove your element after the fadeout ends.
The following code will ensure that #popupcontent is removed only after it's faded out
$window.fadeOut('slow', function() {
$('#popupcontent span').remove();
});

Just use a setTimeout();
$window.fadeOut(300);
setTimeout(function(){
$('#popupcontent span').remove();},2000);
Example Here

How do I add images inside my JavaScript to display Pause and Play icons?

I am trying to use two images to act as play and pause buttons for my tutorial script. How do I replace the "Start" and "Stop" inside my JavaScript with two images instead?
Here is my JavaScript:
$(document).ready(function(){
fadeLoop()
function fadeLoop() {
var counter = 0,
divs = $('.fader').css('visibility','visible').hide(),
dur = 100;
function showDiv() {
$("div.fader").fadeOut(dur) // hide all divs
.filter(function(index) {
return index == counter % divs.length;
}) // figure out correct div to show
.delay(dur) // delay until fadeout is finished
.fadeIn(dur); // and show it
counter++;
}; // function to loop through divs and show correct div
showDiv(); // show first div
return setInterval(function() {
showDiv(); // show next div
}, 4 * 1000); // do this every 7 seconds
};
$(function() {
var interval;
$("#start").click(function() {
if (interval == undefined){
interval = fadeLoop();
$(this).val("Stop");
}
else{
clearInterval(interval);
$(this).val("Start");
interval = undefined;
}
});
});
});
and here is my Fiddle: Fiddle!!

Instead of changing the text value of the element, change the CSS class name. Have two different classes, each using a background image.

Instead of a button, just set the onclick event for an image in your markup. Then you could modify the image with the attr JQuery function:
$(this).attr('src', '[path to my image]');
I couldn't get your JSFiddle to load, but seeing some markup would probably be helpful.
Edit:
I checked back again, and the JSFiddle seems to be up now. The input at the bottom of your markup should either be a div or an img tag. If you use an img tag, use the code above to modify the source image on the click event.
A div might be better since you can preload the background images. In the case of a div you can set the background image with two CSS classes:
.start {
background-image: url('start.png');
}
.stop{
background-image: url('stop.png');
}
Then you need to remove the start class and add the stop class or vice versa:
$(this).removeClass('start');
$(this).addClass('stop');
If you modify the CSS stop selector and make it ".start.stop" you can even just remove and add the stop class instead of having to worry about removing and adding the start class as well.

Image load by jQuery

We have image and links in separate blocks.
When link is clicked, its href attribute puts to src of the image.
What I'm trying to do:
If image is not already loaded (not cached) {
fadeOut previous image {
fadeIn loader {
load image (when animation of loader ends) {
fadeOut loader {
fadeIn image
}
}
}
}
} else (if image is cached, do not show loader) {
fadeOut previous image {
fadeIn new image
}
}
Here is what I have: http://jsfiddle.net/EvXJr/13/
First part works, don't know how to code the second (else) part.
Please help.

The dirty way would be to assign ids to loaded images, if there is no element with such id on a page - show loader, else just animate image.
Example:
html:
<div id="container">
</div>
js:
$('#container').delegate('a', 'click', function () {
var sel_id = this.id;
if (!document.getElementById('img_' + this.id)) {
//create image with id like: sel_id = 'img_' + this.id
} else {
//just show image
}
});

Why don't you just keep track of what HREFs you have loaded with a javascript array that you have loaded and if your HREF can be found in the loaded array just take out the loader related functions.

Couldn't get the jsfiddle to load but if I understand correctly I would just set the background image of the element that holds the images to a loading gif then you don't have to worry about fading in and out a loader. If an image is already cached it will load so quickly you will never see the loading gif. And if it isn't and takes a while to load the user will see the loading gif and using the function below the image will fade in nicely once loaded.
And if you want to perform a function once an image has loaded use
$("img").load(function(){
//do stuff once image has loaded.
//for example
$(this).fadeIn("slow");
});