I have created an array in PHP. And I need to get that array into a javascript function. This is what I have tried.
$sql = "SELECT * FROM Questions WHERE Form_ID='$FormID' AND QuestionsDataHave='YES' ORDER BY Questions_ID+0, Questions_ID";
$GetTheValidationRule = mysqli_query($con, $sql);
$ValidatinArray = array();
$J = 0;
while($RowVal = mysqli_fetch_array($GetTheValidationRule)){
$ValidatinArray[$J] = $RowVal['Validation_Type'];
$J++;
}
And This is my javascript code.
$(document).ready(function() {
$("form").submit(function(){
var P= <?php echo json_encode($ValidatinArray); ?>;
var O = P.length;
alert(O);
return false;
});
});
But this gives me an error like this
SyntaxError: syntax error
var P= <br />
Isn't it possible to get the array in this way. Please someone help me.
UPDATE: This is the final out put of my error message
<script>
$(document).ready(function() {
$("form").submit(function(){
alert('AAAAAAAAAAAAAAAAAAA');
var IDsOfTheColumns = document.getElementsByName("DataColumnID[]");
var Data = document.getElementsByName("DataInputValue[]");
var A = IDsOfTheColumns.length;
alert(A);
<br />
<b>Notice</b>: Undefined variable: ValidatinArray in <b>C:\xampp\htdocs\PHIS\CreateTheForm.php</b> on line <b>16</b><br />
var P = null; return false;
});
});
</script>
Sorry for the late response...Try rewriting your document.ready as:
$(document).ready(function() {
$("form").submit(function(){
var P = JSON.parse('<?php echo json_encode($ValidatinArray); ?>');
var O = P.length;
alert(O);
return false;
});
});
The problem is, that in the variable $ValidatinArray is not available in the file, that prints the javascript code. Maybe this manual page helps you:
http://www.php.net/manual/en/language.variables.scope.php
Try this:
<?php
echo ' <script>
$(document).ready(function() {
$("form").submit(function(){
var P= '. json_encode($ValidatinArray) . ';
var O=P.length;
alert(O);
return false;
});
});
</script>';
?>
What you do is simply echo the js using php.
Your tag is coming from the form that you are submitting. check what your form data is before you encode it to verify the output. you can use console.log($("form));
Also using form is not a good idea since if you have more than one form and form is a global name. For forms you should give it a unique form name like "myForm" so that you can target that specific form.
Hope this helps
first of all I recommend that you verify that the variable $ValidatinArray exists and that it is being passed correctly to the file where you are doing the "echo".
the error you show indicates that from the beginning the variable that contains the array does not exist.
if the SQL query is inside a php function check that you are returning the variable.
example
<?php
function GetData(){
// ... here is the code to get the information from the database ...
return $ValidatinArray;
}
$ValidatinArray = GetData();
?>
once you have validated that this array exists we can now see the problem of passing the data to JavaScript:
It all depends on how the structure is, if you have the PHP code and the JavaScript function in the same file you can simply use this method inside the php fil:
// ... php file code
?>
<script>
$(document).ready(function() {
$("form").submit(function(){
// you can use any of the two methods that I leave you here
// Using only json_enconde
var P= <?= json_encode($ValidatinArray) ?>;
// Using json_enconde to pass the array as a string and using JSON.parse to have JavaScript convert it to an object
var P= JSON.parse('<?= json_encode($ValidatinArray) ?>');
var O = P.length;
alert(O);
return false;
});
});
</script>
In case the php file is executed at the moment of opening the page and the file that contains your function in JavaScript is in another file:
You can generate a "global" JavaScript variable from the php code as follows
// ... code php file
?>
<script>
window.variablename = <?= json_encode($ValidatinArray) ?>
</script>
<?php
inside your JS file you can receive the array like this
$(document).ready(function() {
$("form").submit(function(){
var P= window.variablename ;
var O = P.length;
alert(O);
return false;
});
});
PD: using <?= is equivalent to using echo
In php json_encode the array like this:
$inlinejs='';
$inlinejs.='var validatinArray=\''.addslashes(json_encode($ValidatinArray)).'\';'."\n";
$inlinejs.='var validatinArray=eval(\'(\' + validatinArray + \')\');'."\n";
and in javascript:
$(document).ready(function() {
$("form").submit(function(){
<?php echo $inlinejs; ?>
console.log(validatinArray);
});
});
Related
I have a function.php code simple one:
$var = "7000";
and I have another file script.js:
var Price = <?php echo $var ?>;
now it works when this code in the same file.
but when I separate the files its doesn't.
any suggestions?
As pointed out by GrumpyCrouton in his comment to you, variables out of one file can be read in another by including them
<?php
include('file1.php'); // include the file where the variable is defined
<script>
var Price = <?= json_encode($var) ?>; // in javascript code export the variable to js usign json
</script>
It is always safe to use json_encode and dump the variable directly into js no need to encapsulate it any more then that, I would add a semicolon at the end but that is more of a personal preference in this day and age.
Create a script called price.php with the following content:
<?php
header("Content-type: text/javascript"); // As suggested by Mark Eriksson
$var = "7000";
?>
const PRICE = <?php echo $var; ?>;
Now you can reference this JavaScript block on any HTML page:
<script src="price.php"></script>
You will have a global JavaScript variable (constant) called PRICE.
Do you need variable prices? No problem, you can pass a value as a parameter, for example:
<script src="price.php?price=8500"></script>
And in your price.php, you change it to:
<?php
$var = $_GET["price"];
?>
const PRICE = <?php echo $var; ?>;
Your HTML page still gets a constant named PRICE.
Well, if you want to access some PHP variables, then you need to use AJAX.
Its quite simple.
Do this inside function.php file
<?php
$var = "7000";
// Put your price into array to form it into JSON format further
$data = ["price" => $var];
return json_encode($data);
And following in your JS file.
let xhr = new XmlHttpRequest();
xhr.open('get', 'function.php', true);
xhr.onload = function() {
if (this.status == 200) {
var data = JSON.parse(this.response);
// Your final result
var Price = data.price;
}
}
xhr.send();
Hiii Everyone,
<script src="../../record/recordmp3.js?id=<?php echo $_GET['id'];?>&&test_no=<?php echo $_GET['test_no'];?>"></script>
<script type="text/javascript" data-my_var_1="some_val_1" data-my_var_2="some_val_2" src="/js/somefile.js"></script>
And I tried to get that passing value in recordmp3.js is
var student_id = this_js_script.attr('data-my_var_1');
var test_no = this_js_script.attr('data-my_var_2');
And also by
var student_id = "<?php echo $_GET['id'];?>";
var test_no = "<?php echo $_GET['test_no'];?>";
And my value is not passing correctly.Instead only '0' is passing In my index page I have some PHP variable value I need to pass that value to recordmp3.js file.Please help me to solve this issue.Thank you so much in advance.
I tried like below its working fine
<script src="../../record/recordmp3.js"></script>
<script type="text/javascript">
MYLIBRARY.init(["<?php echo $id; ?>", "<?php echo $test_no; ?>"]);
MYLIBRARY.helloWorld();
</script>
var MYLIBRARY = MYLIBRARY || (function(){
var _args = {}; // private
return {
init : function(Args) {
_args = Args;
// some other initialising
},
helloWorld : function() {
window.id= _args[0];
window.test_no= _args[1];
}
};
}());
You need to convert these values to json array. You cannot directly assign the php values to JavaScript variables.
Hope this answer is useful. Please let me know if you find any difficulties on converting to json value.
.js files don't execute and compile the php files,so in order to access the php variables in javascript the file should be .php.
script.php
<?php
$foo = 'Hello cool';
?>
<script>
var foo ='<?php echo $foo ?>';
console.log(foo);
</script>
i hope this example will solve your issue
When I am using changing php variables to JavaScript variables, I am getting "expression expected" error from PhpStorm.
I cannot change the extension of the file to something.js.php because I am already using blade template so it should be blade.php
<!DOCTYPE html>
<html>
<body>
<?php $myVar = 5;?>
<script type="text/javascript">
var myJavascriptVar = <?php echo $myVar; ?>;
var myJavascriptSecondVar = {{$myVar;}};
alert(myJavascriptVar + myJavascriptSecondVar);
</script>
</body>
</html>
I have added a sample html page for more clarification. In PhpStrom the
var myJavascriptVar = <?php echo $myVar; ?>;
and
var myJavascriptSecondVar = {{$myVar;}};
statements gives expression expected error.
That's a bug (incomplete inter-language handling) in PhpStorm.
https://youtrack.jetbrains.com/issue/WI-24968
https://youtrack.jetbrains.com/issue/WI-25739
possibly some another (from "Related" list) as well
Watch those tickets (star/vote/comment) to get notified on any progress. Right now they are not assigned to any specific future versions.
Here are two workarounds:
1. function
function blade(_)
{
return _;
}
var data = blade({{ $data }});
// or ES6 arrow function
var data = (_ => _)({{ $data }});
2. array
var data = [{{ $data }}].pop();
// or
var data = [{{ $data }}][0];
I have an HTML form generated by php which has a dropdown of voucherproviders.
I want to select the provider and have this populate the form for editing.
Here is my JQuery code:
$(document).ready(function() {
$(document).on('change','#id_voucherprovider',function(){
var voucher_providers = <?php echo json_encode($voucher_providers); ?>;
//The value I have got from the drop down is....
var value = $('#id_voucherprovider option:selected').val();
var vendortext = $('#id_voucherprovider option:selected').text();
//so the voucher provider is
alert(vendortext);
$('.ftext input').val(vendortext);
$("textarea#id_vendornotes").val(voucher_providers[value]);
});
});
voucherproviders is not being passed into the JQuery despite the echo json_encode($voucher_providers); code working when inline with the php code.
It seems to return a null array. Can anyone see what is wrong?
Many Thanks
Dave
var voucher_providers = <?php echo json_encode($voucher_providers); ?>;
json_encode returns a string, unless it is parsed it will not be usable. Use JQuery .parseJSON and you should have better results. :)
var jsonString = <?php echo json_encode($voucher_providers); ?>;
var voucher_providers = $.parseJSON(jsonString);
try this (note the quotes):
var voucher_providers = JSON.parse('<?php echo json_encode($voucher_providers); ?>');
parse your json ex: obj = JSON.parse(data);
Hi please check the json format at below site:-
http://jsonlint.com/
and check if this is fine.
i am trying to fetch JavaScript variable "i" in my PHP Code within a JavaScript function in the below code, I find problem in retrieving records, either first record or the last record repeats instead of all records in database.. can you guys help me out ?
Thanks
<?php
$query21 = $mysqli->query("SELECT * FROM register");
$nr = mysqli_num_rows($query21);
while ($row = mysqli_fetch_assoc($query21)) {
$results[] = $row;
}
?>
<script language="javascript" type="text/javascript">
var intervalID = 0;
var time = 10;
MsgPop.displaySmall = true;
MsgPop.position = "bottom-right";
$(document).ready(function(){
var test = MsgPop.open({
Type: "success",
AutoClose: true,
Content: "Welcome to MsgPop!"});
MsgPop.live();
});
function showMessages(){
var n = '<?php
echo $nr;
?>';
var i = 0;
while (i < n){
var name = '<?php
echo $results[i]['name'];
?>';
MsgPop.open({
Type: "success",
Content: name,
AutoClose: false});
i++;
}
</script>
First you have to create a php file which return same array. File contain
$query21 = $mysqli->query("SELECT * FROM register");
$nr = mysqli_num_rows($query21);
while ($row = mysqli_fetch_assoc($query21)) {
$results[] = $row;
}
echo json_encode($results);
exit;
Now you have to call this file using ajax from your javascript code.
$.ajax({
type: "POST",
url: "sql.php", //your file url
})
.done(function (data) {
//you get your array data(json format)
});
now you get that array in ajax response in json format and you can do anything with this data.
Impossible: PHP is a server side language that runs only at server. but javascript is a client side script it only run at your browser only. Php only gives response depends on your requests. The roll of php is end at server. But the javascript work with your response only, that is javascript can work at browser only.
You could try using AJAX, or else it isn't happening. Like said PHP is server-side only... Good luck!
PHP cannot fetch javascript variables. You should try another strategy.
At the server side (PHP), try to store $resuts in a javascript variable.
var results = '<?php echo json_encode($results); ?>';
Then at the browser side, try to access the data with javascript functions.
var name = results[i]['name'];