I wish to check if at least one checkbox checked before submission of a form, here is my code:
<script type="text/javascript">
function validate() {
if (document.getElementById('checking').checked) {
alert("checked");
} else {
alert("You didn't check it! Let me check it for you.")
}
}
</script>
<?php foreach (..... ) : ?>
<form name="frm1" id="frm1" method="post" action="next.php" >
...
<input type="checkbox" value="" class="chk" id="checking"/>
...
....
</form>
I did like that but it seems dosn't work for me,I see the message but at the same time it make submission also that not enought to verify atleast one checkbox is checked?
Onclick is firing both events, the validation and the submit. You could put the submitting part inside the validation script for instance and only submit the form, if your validation was successful.
EDIT: posting a more complete code sample
<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
</head>
<body>
<script type="text/javascript">
function validate() {
if ($('#checking').is(':checked')) {
$('#frm1').submit();
} else {
alert("You didn't check it! Let me check it for you.");
$('#checking').attr('checked', true);
}
}
</script>
<form name="frm1" id="frm1" method="post" action="next.php" >
<input type="checkbox" value="" class="chk" id="checking"/>
<img src="/submit.png">
</form>
</body>
</html>
Also, you should consider also adding server side validation, if none exist yet, since a user can easily change the HTML/JavaScript on your page on runtime with tools like FireBug for instance and submit data that's not valid anyway.
I'd suggested in my original answer that you'd need "something like ...".
Here is what should be a full working solution. The trick that needed to be added was that validate should return a true/false so that we can decide whether or not to submit the form.
<script type="text/javascript">
function validate() {
if (document.getElementById('checking').checked) {
alert("checked");
return true;
} else {
alert("You didn't check it! Let me check it for you.")
return false;
}
}
</script>
<form name="frm1" id="frm1" method="post" action="next.php" >
<input type="checkbox" value="" class="chk" id="checking"/>
</form>
Original Answer:
You probably need something in your click handler that is more like
if (validate()) { $(this).closest('form').submit(); }
This should make the submission wait until the alert is closed.
If you want the form to not submit if the checkbox thing didn't happen, then you could return true/false from validate() and the same would work.
Related
My research is pointing me to Ajax and/or JQuery, but I wanted to ask to make sure I understand and move in the right direction.
I've been looking to use a javascript onclick function to create a popup(alert) asking to confirm that I want to proceed and show the changes I'm about to make.
I hoped that I could use PHP $_POST or GET to echo the change in the popup/alert window. However without the page refresh it appears I can't do this, but looking for a confirmation? Should I be looking for Ajax to do this? Any thoughts/suggestions would likely give me a head start as php/ajax is sort of foreign to me.
Sample code:
<script>
function clicked() {
if (confirm('Do you want to submit? <?php if(isset($_POST['city'])){$city = $_POST['city'];echo $city;}?>'))
{
yourformelement.submit();
} else {
return false;
}
}
</script>
</head>
<form action="output.php" method="post">
<input name="city">
<input type="submit" onclick="clicked();" value="Button" />
</form>
</html>
You can get the input value with jQuery before submitting:
<form action="output.php" method="post" id="form">
<input name="city" id="city_input">
<input type="submit" value="Button" />
</form>
<script>
$('#form').submit(function(e) {
e.preventDefault();
let cityInputVal = $('#city_input').val();
if (confirm('Do you want to submit ' + cityInputVal + '?'))
{
this.submit();
} else {
return false;
}
});
</script>
The preventDefault() function stops the form submission and therefore, page refresh.
I am trying to write a very simple jQuery function which will have two main properties. The first one will be to check if the field is empty or not. The second one will be if the field is not empty to execute a form which will lead to a PHP coded page. I am very new to jQuery and I will be very grateful if someone can point where exactly is my mistake. Thank you in advance.
function Captcha() {
$('#Button').click(function() {
if ($("#Field").val().length == 0) {
alert("Please fill the box");
return false;
} else {
alert("Your code is saved");
return true;
}
});
}
$(document).ready(function() {
Captcha();
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form action="success.php" id="Alpha" method="post" onsubmit="return Captcha();">
<input id="Field" type="text" placeholder="Enter key here">
<button id="Button" type="submit" form="Alpha">Confirm</button>
</form>
Don't work with the button's click event, work with the form's submit event because a form can be submitted via the keyboard and therefore the button can be circumvented.
You can see a working version here (Stack Overflow prevents submit code from working in the snippet environment below.)
$(function() {
$('#Alpha').on("submit", function() {
if ($("#Field").val().length == 0) {
alert("Please fill the box");
return false;
} else {
alert("Your code is saved");
return true;
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form action="success.php" id="Alpha" method="post" onsubmit="return Captcha();">
<input id="Field" type="text" placeholder="Enter key here">
<button id="Button" type="submit" form="Alpha">Confirm</button>
</form>
You would want to validate the form fields when you actually submit the form. When you click on the button you are still in the process of triggering the submit.
Try changing this:
$('#Button').click(function() {
Into this:
$('#Alpha').on('submit', function() {
See if that helps.
Whenever I press the submit button it just submits the form and doesn't seem to run the checkSubmit function. Everything I've looked at in other examples suggests my code is correct. Is there something missing or wrong with the way I'm calling it?
<script language="javascript" type="text/javascript">
function checkSubmit() {
alert("This is an alert!");
if (document.getElementById("userID").value.length <1) {
alert("Please enter a User ID.");
return false;
}
else {
alert(document.getElementById("userID").value.length)
return true;
}
</script>
<form name="submitform1" method="POST" action="http://127.0.0.1/MyFile.php" onsubmit="return checkSubmit();">
Enter User ID: <input id="userID" name="userID" type=text size="25"/><br />
<input type="submit" name="submit" onclick="this.form.onsubmit();" value="Submit" >
</form>
<br />
Your code is missing the closing curly bracket for the checkSubmit() function for one.
In your HTML change the remove the onsubmit handler from the form element and change the onclick attribute on the submit button to call the function:
onclick="checkSubmit(event);"
Then, in your function, prevent the form from submitting, do your checks, then submit the form.
function checkSubmit(e) {
e.preventDefault();
// do checks
document.submitform1.submit();
}
I've got a JS problem. My validation seems to be working, checking that the user inputs a valid number which isn't zero, but the form is still submitting. I have seen this question asked many times but I can't find a solution that works for me. Any ideas would be great.
My Javascript
function checkNotZero()
{
var theNumber = document.getElementById("theNumber").value;
var str = /^\+?[1-9]\d*$/.test(theNumber);
if ( str == false ) {
alert('You have not entered a valid number');
return false;
} else {
document.getElementById('numberCheck').submit();
}
}
My HTML
<form action="/next.php" method="post" id="numberCheck">
<input type="text" id="theNumber" value="0">
<button id="submitButton" OnClick="checkNotZero();">Add to Basket</button>
</form>
Use an <input type="submit"> for the submit button.
Validate on the form's submit event rather than some onclick. Forms can get submitted in other ways than just clicking a button (for instance, pressing "enter", or procedurally through code).
Prefer .addEventListener to attributes for attaching events to elements. Use preventDefault() to prevent form submission.
Hi for the above requirement of 'validating form' java script validation should be done
when the form gets submitted. follow the below approach, form will not get submitted
until and unless the validation is correct.
<html>
<head>
<script type="text/javascript">
function checkNotZero()
{
var theNumber = document.getElementById("theNumber").value;
var str = /^\+?[1-9]\d*$/.test(theNumber);
if ( str == false ) {
alert('in');
alert('You have not entered a valid number');
return false;
} else {
document.getElementById('numberCheck').submit();
}
}
</script>
</head>
<body>
<form action="/next.php" method="post" id="numberCheck" onsubmit="return
checkNotZero()">
<input type="text" id="theNumber" value="0">
<button id="submitButton">Add to Basket</button>
</form>
</body>
</html>
the only change is <form action="/next.php" method="post" id="numberCheck"
onsubmit="return checkNotZero()">
do not use onclick event in submit button.
I have been battling for the past two days with the evil onbeforeunload function in JavaScript. I have a function that warns the user when they are about to close a page.
However before the page close I would like to submit the form using JavaScript's .submit().
This is my code:
function setPopUpWindow(submitForm){
window.onbeforeunload = function () {
if (submitForm == false ) {
//alert("It worked"); --This code gets called so I know it works
document.getElementById("CancelScripting").submit();
//return "Unsaved Data would be lost";
}
}
}
In my html I have two buttons, one is (supposed to) trigger the .submit() and the other will just ignore it.
<body>
<form action=tett.html id="popUpForm" method=POST>
<script>setPopUpWindow();</script>
<input type="submit" id="submit_button" onclick="setPopUpWindow(true);">
<input class=b1 type=submit id="CancelScripting" style="visibility:hidden" value="CancelScripting" >
</body>
The `setPopWindow value for the second input is not defined so it would be false.
For some reason the submit is not working well.
------------------------Edit to my question-----------------------------------------------
I would like to submit the form even if the user leaves the page by closing the X button on their window. This is the reason why I have the hidden button... Looks like people misunderstood my question.
The only thing you can do is to ask the user if they really want to leave the page:
<head>
<script type="text/javascript">
var submitForm = false;
window.onbeforeunload = function () {
if(submitForm == false){
return 'You have an unfinished form ...';
}
}
function setPopUpWindow(type){
submitForm = true;
}
</script>
</head>
<body>
<form action="" method="post" name="SubmitForm" id="SubmitForm">
<input type="submit" id="submit_button" onclick="setPopUpWindow(true);">
</form>
</body>
I think that what you want to do is submit the form rather than the button by doing something like:
document.forms["formId"].submit();
where formId is the id of the form.
Also, I dont see anywhere in your code where your form is but your buttons should be inside of form tags.
For example, it should look like this:
<body>
<script>setPopUpWindow();</script>
<form id="formId" action="" method="post">
<input type="submit" id="submit_button" onclick="setPopUpWindow(true);">
<input class=b1 type=submit id="CancelScripting" style="visibility:hidden" value="CancelScripting" >
</form>
</body>