I have a jQuery script that sends POST data via AJAX to a php file that then creates a table. I have used firebug to check the console and everything gets created properly. On the success: I reload the window and the table isn't displayed.
I know the table html was created properly from the php file because I commented out the reload so I could see exactly what it created) I have lots of things displayed on my page and would like the table in a particular spot. How can I get the table to actually display where I want it to?
<script>
$(document).ready(function () {
$("#stayinfobutton").click(function () {
var id = $('#id').val();
var dataString = {
id: id
};
console.log(dataString);
$.ajax({
type: "POST",
url: "classes/table_auto_guests.php",
data: dataString,
cache: false,
/*success: function(html)
{
window.location.reload(true);
}*/
});
});
});
</script>
The window.location call will reload a new page in the browser window, this will loose the data returned to the ajax call by the server.
Usually the response to Ajax calls is loaded directly into your page, something like:
success: function(html)
{
$('#guestsTable').html(html);
$('userForm').hide();
}
I made up the guestsTable div and userForm names, ;).
The return data may need some coercing to make it into html (I'm assuming your using JQuery), hopefully the php script will set it to html/text in the header, also dataType: html can be passed in the $.ajax({...}) call.
Alternatively, if the classes/table_auto_guests.php returns a full page which you want to load in the browser, Ajax may not be what you are looking for. This post contains code on how to submit the data as a form, and load the result as a new page.
Related
I basically don't seem to understand sending a variable to another page.
I've tried PHP sessions, javascript cookies and ajax POST and GET.
I'm trying to send the innerHTML of a div, with the data created by a jQuery call,
a variable called savedartists. It displays correctly in the console.log on the sending page but the $_POST['savedArtists']
is undefined in the receiving page. I have spent hours looking at different posts on this site but I haven't been able to get it to work.
Any help is appreciated.
<input class="et_pb_button et_pb_button_0 et_pb_bg_layout_light" onClick="savequote();" type="button" id="savedchoices" value="Commander la prestation" >
<script>
function savequote() {
var savedartists = document.getElementById('selectedList').innerHTML;
console.log(savedartists);
$.ajax({
type: "POST",
url: 'example.com/artiste/mise-en-relation/',
data: { savedArtists : savedartists },
success: function(data) {
console.log("success!");
location.href = "example.com/artiste/mise-en-relation/";
}
});
}
</script>
On the receiving page (example.com/artiste/mise-en-relation/)
<?php
if(isset($_POST['savedArtists']))
{
$uid = $_POST['savedArtists'];
echo $uid;
} else {
echo 'zit!';
}
?>
Thanks for your time
Capturing as an answer for future readers...
Fundamentally what's happening here is that two requests are being made to the target page. The first one is the AJAX request:
$.ajax({
type: "POST",
url: 'example.com/artiste/mise-en-relation/',
data: { savedArtists : savedartists },
success: function(data) {
//...
}
});
This is a POST request which contains the data you expect, and works just fine. However, the result of this request is being ignored. That result is available in the success callback, but the code doesn't do anything with it:
console.log("success!");
location.href = "example.com/artiste/mise-en-relation/";
Instead, what the code is doing is performing a redirect. This creates a second request to that same page (though it's essentially irrelevant that it's the same page). This is a GET request and contains no data to send to the server.
At its simplest, you should either use AJAX or redirect the user. Currently you're mixing both.
I want to redirect to the other page.
In that case AJAX is the wrong tool for the job. You may not even need JavaScript at all, unless you want to modify the elements/values of a form before submitting that form. But if all you want is to POST data to another page while directing the user to that page, a plain old HTML form does exactly that. For example:
<form method="POST" action="example.com/artiste/mise-en-relation/">
<input type="text" name="savedArtists">
<button type="submit">Submit</button>
</form>
In this case whatever value the user enters into the <input> will be included in the POST request to example.com/artiste/mise-en-relation/ when the user submits the form.
I am trying to send data from a php page to another php page through JavaScript with ajax and the getting the new page to open with the data that was sent so that the user can print the page.. here is the js snippet processDateP and sourceID2 are entered by user.
$("#PrintShelf").click(function() {
$.ajax({
type: "POST",
url: "print2.php",
dataType: "json",
data: ({processDate: $('#processDateP').val(), sourceID: $('#sourceID2').val()}),
success: function(data){
if('#sourceID2' != null ){
window.open('print2.php');
}
}
});
});
I want this to open the file PHP file print2.php, but it either opens the file with no data if i move window.open outside of success function or it sends the data and the page popluates correctly (can see using firebug) but does not open the window..I have run just the print2.php file alone with dummy values and it works and prints.
Thanks in advance
Okay, so I searched the web as much as I could and I couldn't find the solution on my problem. I also typed the question and searched for an answer as I saw similar questions to mine. Didn't help. I tried numerous solutions.
Well I have an index page that loads includes/data.php which loads the data from database and echo the .js format that is then loaded by function and display data on the page, so I have at the end of my index.php something like this:
<script type="text/javascript" src="includes/data.php"></script>
On the same index page I have a form that inserts data to database. If you refresh the page I will see refreshed includes/data.php along with new data I just inputted.
I am trying to implement AJAX so that when I click on the button I insert the data to database (already achieved this) and to refresh content of includes/data.php and index.php so it shows data right away without refreshing the index.php. This is my AJAX code:
$('#addtocal').submit( function() {
$.ajax({
url : $(this).attr('action'),
type : $(this).attr('method'),
data : $(this).serialize(),
success : function( data ) {
// This is the part where I am stuck.
},
error : function(){
$(".error").fadeIn(2000);
$(".error").fadeOut(2000);
}
});
return false;
});
Just to mention that #calendar is where main jquery function is loading the html content based on the info from /includes/data.php. Thank you in advance for any help you can provide and let me know if you need any other information from me in order to better assist me.
P.S. I saw many suggested using .load() to load content from includes/data.php but that is not working in my case as the content from includes/data.php needs to serve other jquery function that creates html on the fly and and place it in #calendar
I got it to work. What I did I inser aditional $.ajax inside the $.ajax and on completion and I called again again the jquery that uses /includes/data.php
so the code would be something like this:
$('#addtocal').submit( function() {
$.ajax({
url : $(this).attr('action'),
type : $(this).attr('method'),
data : $(this).serialize(),
success : function( data ) {
$.ajax({
url: "../includes/data.php",
dataType: "script",
cache: true
}).done(function() {
// Here I called other jquery function that uses ../includes/data.php
});
},
error : function(){
$(".error").fadeIn(2000);
$(".error").fadeOut(2000);
}
});
return false;
});
Thanks for your help anyway #Half Crazed gave me a clue so I get the $.getScript function and saw the way to call .js again so I tried and it worked.
How can I get the html of a certain html element which is located on a different site?
Solution:
$.ajax({
url: 'somefile.html',
success: function(data) {
data=$(data).find('div#id');
$('#mydiv').html(data);
alert('Done.');
}
});
You can use $.load with an appended container
The .load() method, unlike $.get(), allows us to specify a portion of
the remote document to be inserted.
$('#result').load('ajax/test.html #container');
Make a ajax call to a php or any other file , use CURL or other tools to grab the page you want and extract the div and echo it and then when you get back the html just put it inside a div in your page
$.ajax({
url: 'somefile.html',
success: function(data) {
data=$(data).find('div#id');
$('#mydiv').html(data);
alert('Done.');
}
});
Here you go:
$('#div_id_in_your_page').load('ajax_page.html #required_div');
For class:
$('.div_class_in_your_page').load('ajax_page.html #required_div');
One way is:
send an ajax call to a server side script
this script fetches the remote page and returns HTML as a response. (generally JSON is preferred)
your page finally gets access to the html.
you can also use like this.
$.ajax({
url:"page2.html",
success:function(response){
$("#currentDIV").html(response);
},error:function(){
alert("error");
}
});
I am calling an ajax script to fetch a content of a page and then replace the current contents with the fetched one. One problem I am facing is that there is a javascript on the fetched page which doesnt get rendered and is treated as text. How do I make sure that the javascript gets loaded?
write javascript(fetched page) code in main page.
for example:
$.ajax({
url: "your fetched page url",
dataType: "html",
type: 'POST',
data: "your data",
success: function(data){
$("#result").html(data); //call back div
//put your javascript code from fetched page here
}
});