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JS: Finding next key in json

I have the following json:
{0: "2", 1: "2", $$hashKey: "object:35", undefined: "1"}
Currently I am trying to get its key-value with the below code:
var data = JSON.stringify(row);
var result = $.parseJSON(data);
$.each(result, function (k, v) {
//display the key and value pair
console.log(k, v);
});
The above code works fine and I can get my key-value from it.
Now what I am trying to get is the next key-value pairs within the $.each loop.
For example if in the loop the current key is "0" I want to get the next key "1" in the same call itself. If in the loop the current key is "1" I want to get the next key "$$hashKey" along with their values.
Is it possible to do so? I am open to code changes above if required.

You can use Object.keys to get the keys to an array, then run through it with a forEach to have access to the keys index. Important to note that objects are unordered, so your key order one time may differ from the next time:
var keys = Object.keys(obj);
keys.forEach(function(key, index) {
var nextIndex = index + 1;
if (nextIndex === keys.length) return; //out of bounds
var nextKey = keys[nextIndex];
});
Edit: As pointed out by the comments - if you want the keys in the same order each time, call .sort() on your keys array with your desired sort logic.

Understanding now that the goal is to retrieve keys in the order they appear in JSON, a couple of thoughts:
(1) if you control the source of the object ("row" in the OP code), don't represent it as an object. instead use an array of key-value pairs: [[0, "2"], [1, "2"], [$$hashKey, "object:35"], [undefined, "1"]].
otherwise, (2) roll your own JSON parser that returns an array of key-value pairs for an object. This post looks to be a sensible start. Or, you can vastly simplify the task if you are able to make certain assumptions about the values, for example, say you know that all values are strings...
// parse a string representing an object, returning an array of key-value pairs.
// assumes values are strings that do not contain commas or colons
function myProbablyNegligentlySimpleJSONParse(string) {
let trimmed = string.trim().slice(1, -1);
let components = trimmed.split(',');
return components.map(kvString => {
let kv = kvString.split(':');
return [ kv[0].trim(), kv[1].trim() ];
});
}
forEach passes the current index to the iterator function, so that int can be used to look ahead or behind in the iteration.
var data = '{0: "2", 1: "2", $$hashKey: "object:35", undefined: "1"}';
let result = myProbablyNegligentlySimpleJSONParse(data);
result.forEach(function (pair, index) {
let [k, v] = pair; // now k and v are your key and value
console.log(`key is ${k} value is ${v}`)
if (index < result.length-1) {
let [nextK, nextV] = result[index+1];
console.log(`next key is ${nextK} next value is ${nextV}`);
}
});

You could turn your object into an iterable and which will return the next [key, value] pair each time you call next on the iterator:
function makeIterable(o) {
o[Symbol.iterator] = () => {
var keys = Object.keys(o);
var i = 0;
return {
next() {
var done = false;
var value = [keys[i + 1], o[keys[i + 1]]];
if (i >= (keys.length - 1)) {
done = true;
}
i++;
return {
value,
done
}
}
};
}
}
var jsonStr = '{ "0": "2", "1": "2", "$$hashKey": "object:35", "undefined": "1" }';
var obj = JSON.parse(jsonStr);
makeIterable(obj);
var itr = obj[Symbol.iterator]();
while (true) {
var item = itr.next();
if (item.done) {
break;
}
console.log(item.value);
}

JavaScript - Filter <key,value> Object by key

I am looking for a short and efficient way to filter objects by key, I have this kind of data-structure:
{"Key1":[obj1,obj2,obj3], "Key2":[obj4,obj5,obj6]}
Now I want to filter by keys, for example by "Key1":
{"Key1":[obj1,obj2,obj3]}

var object = {"Key1":[1,2,3], "Key2":[4,5,6]};
var key1 = object["Key1"];
console.log(key1);

you can use the .filter js function for filter values inside an object
var keys = {"Key1":[obj1,obj2,obj3], "Key2":[obj4,obj5,obj6]};
var objectToFind;
var keyToSearch = keys.filter(function(objects) {
return objects === objectToFind
});
The keyToSearch is an array with all the objects filter by the objectToFind variable.
Remember, in the line return objects === objectToFind is where you have to should your statement. I hope it can help you.

You can create a new object based on some custom filter criteria by using a combination of Object.keys and the array .reduce method. Note this only works in es6:
var myObject = {"Key1":["a","b","c"], "Key2":["e","f","g"]}
function filterObjectByKey(obj, filterFunc) {
return Object.keys(obj).reduce((newObj, key) => {
if (filterFunc(key)) {
newObj[key] = obj[key];
}
return newObj;
}, {});
}
const filteredObj = filterObjectByKey(myObject, x => x === "Key1")
console.log(filteredObj)

Not sure what exactly are you trying to achieve, but if you want to have a set of keys that you would like to get the data for, you have quite a few options, one is:
var keys = ['alpha', 'bravo'];
var objectToFilterOn = {
alpha: 'a',
bravo: 'b',
charlie: 'c'
};
keys.forEach(function(key) {
console.log(objectToFilterOn[key]);
});

Underscore: How to return all values by array with keys

I have big object with a lot of key : value, and I have array with some keys from this object.
How to return values of this keys(array) by underscore?
I try some like this, but it's bull**
_.find(objectwithkeysandvalues , function(value){
return _.intersection(value,arraywithekeys)
});

You don't need Underscore for this task. Instead, you can use the map function to create a new array that contains the values specified by the keys in the old array:
var myValues = keys.map(function (key) {
return myObject[key]
});

You only need to map each value from your keys array to yourBigObject[value].
In Underscore this would look like this :
var keys = [ ... ]; // Keys from your big object
var obj = { ... }; // Your big object
var values = _.map(keys, function(value, index) {
return obj[value];
});
See this fiddle for experimenting.

Here's a solution using upcoming EcmaScript 7 Array Comprehensions available today via Babel.js.
Try it: Array Comprehensions Example.
ES7:
var obj = {
"key1": 1,
"key2": 2,
"key3": 3
}
var arr = ["key1"];
var values = [for(key of arr) obj[key]];
console.log(values);

Sorting a JavaScript object by property name

I've been looking for a while and want a way to sort a Javascript object like this:
{
method: 'artist.getInfo',
artist: 'Green Day',
format: 'json',
api_key: 'fa3af76b9396d0091c9c41ebe3c63716'
}
and sort is alphabetically by name to get:
{
api_key: 'fa3af76b9396d0091c9c41ebe3c63716',
artist: 'Green Day',
format: 'json',
method: 'artist.getInfo'
}
I can't find any code that will do this. Can anyone give me some help?

UPDATE from the comments:
This answer is outdated. In ES6 objects keys are now ordered. See this question for an up-to-date answer
By definition, the order of keys in an object is undefined, so you probably won't be able to do that in a way that is future-proof. Instead, you should think about sorting these keys when the object is actually being displayed to the user. Whatever sort order it uses internally doesn't really matter anyway.
By convention, most browsers will retain the order of keys in an object in the order that they were added. So, you could do this, but don't expect it to always work:
function sortObject(o) {
var sorted = {},
key, a = [];
for (key in o) {
if (o.hasOwnProperty(key)) {
a.push(key);
}
}
a.sort();
for (key = 0; key < a.length; key++) {
sorted[a[key]] = o[a[key]];
}
return sorted;
}

this function takes an object and returns a sorted array of arrays of the form [key,value]
function (o) {
var a = [],i;
for(i in o){
if(o.hasOwnProperty(i)){
a.push([i,o[i]]);
}
}
a.sort(function(a,b){ return a[0]>b[0]?1:-1; })
return a;
}
The object data structure does not have a well defined order. In mathematical terms, the collection of keys in an object are an Unordered Set, and should be treated as such.
If you want to define order, you SHOULD use an array, because an array having an order is an assumption you can rely on. An object having some kind of order is something that is left to the whims of the implementation.

Just use sorted stringify() when you need to compare or hash the results.

// if ya need old browser support
Object.keys = Object.keys || function(o) {
var result = [];
for(var name in o) {
if (o.hasOwnProperty(name))
result.push(name);
}
return result;
};
var o = {c: 3, a: 1, b: 2};
var n = sortem(o);
function sortem(old){
var newo = {}; Object.keys(old).sort().forEach(function(k) {new[k]=old[k]});
return newo;
}
// deep
function sortem(old){
var newo = {}; Object.keys(old).sort().forEach(function(k){ newo[k]=sortem(old[k]) });
return newo;
}
sortem({b:{b:1,a:2},a:{b:1,a:2}})

Here is a one-liner for you.
Array.prototype.reduce()
let data = {
method: 'artist.getInfo',
artist: 'Green Day',
format: 'json',
api_key: 'fa3af76b9396d0091c9c41ebe3c63716'
};
let sorted = Object.keys(data).sort().reduce( (acc, currValue) => {
acc[currValue] = data[currValue];
return acc;
}, {});
console.log(sorted);
Good luck!!

ES5 Compatible:
function sortByKey(obj) {
var keys = Object.keys(obj);
keys.sort();
var sorted = {};
for (var i = 0; i < keys.length; i++) {
var key = keys[i];
sorted[key] = obj[key];
}
return sorted;
}

This should be used with caution as your code shouldn't rely on Object properties order. If it's just a matter of presentation (or just for the fun !), you can sort properties deeply like this :
function sortObject(src) {
var out;
if (typeof src === 'object' && Object.keys(src).length > 0) {
out = {};
Object.keys(src).sort().forEach(function (key) {
out[key] = sortObject(src[key]);
});
return out;
}
return src;
}

Getting the first index of an object

Consider:
var object = {
foo: {},
bar: {},
baz: {}
}
How would I do this:
var first = object[0];
console.log(first);
Obviously, that doesn’t work because the first index is named foo,
not 0.
console.log(object['foo']);
works, but I don’t know it’s named foo. It could be named anything. I just want the first.

Just for fun this works in JS 1.8.5
var obj = {a: 1, b: 2, c: 3};
Object.keys(obj)[0]; // "a"
This matches the same order that you would see doing
for (o in obj) { ... }

If you want something concise try:
for (first in obj) break;
alert(first);
wrapped as a function:
function first(obj) {
for (var a in obj) return a;
}

they're not really ordered, but you can do:
var first;
for (var i in obj) {
if (obj.hasOwnProperty(i) && typeof(i) !== 'function') {
first = obj[i];
break;
}
}
the .hasOwnProperty() is important to ignore prototyped objects.

This will not give you the first one as javascript objects are unordered, however this is fine in some cases.
myObject[Object.keys(myObject)[0]]

If the order of the objects is significant, you should revise your JSON schema to store the objects in an array:
[
{"name":"foo", ...},
{"name":"bar", ...},
{"name":"baz", ...}
]
or maybe:
[
["foo", {}],
["bar", {}],
["baz", {}]
]
As Ben Alpert points out, properties of Javascript objects are unordered, and your code is broken if you expect them to enumerate in the same order that they are specified in the object literal—there is no "first" property.

for first key of object you can use
console.log(Object.keys(object)[0]);//print key's name
for value
console.log(object[Object.keys(object)[0]]);//print key's value

There is no way to get the first element, seeing as "hashes" (objects) in JavaScript have unordered properties. Your best bet is to store the keys in an array:
var keys = ["foo", "bar", "baz"];
Then use that to get the proper value:
object[keys[0]]

ES6
const [first] = Object.keys(obj)

Using underscore you can use _.pairs to get the first object entry as a key value pair as follows:
_.pairs(obj)[0]
Then the key would be available with a further [0] subscript, the value with [1]

I had the same problem yesterday. I solved it like this:
var obj = {
foo:{},
bar:{},
baz:{}
},
first = null,
key = null;
for (var key in obj) {
first = obj[key];
if(typeof(first) !== 'function') {
break;
}
}
// first is the first enumerated property, and key it's corresponding key.
Not the most elegant solution, and I am pretty sure that it may yield different results in different browsers (i.e. the specs says that enumeration is not required to enumerate the properties in the same order as they were defined). However, I only had a single property in my object so that was a non-issue. I just needed the first key.

You could do something like this:
var object = {
foo:{a:'first'},
bar:{},
baz:{}
}
function getAttributeByIndex(obj, index){
var i = 0;
for (var attr in obj){
if (index === i){
return obj[attr];
}
i++;
}
return null;
}
var first = getAttributeByIndex(object, 0); // returns the value of the
// first (0 index) attribute
// of the object ( {a:'first'} )

To get the first key of your object
const myObject = {
'foo1': { name: 'myNam1' },
'foo2': { name: 'myNam2' }
}
const result = Object.keys(myObject)[0];
// result will return 'foo1'

Based on CMS answer. I don't get the value directly, instead I take the key at its index and use this to get the value:
Object.keyAt = function(obj, index) {
var i = 0;
for (var key in obj) {
if ((index || 0) === i++) return key;
}
};
var obj = {
foo: '1st',
bar: '2nd',
baz: '3rd'
};
var key = Object.keyAt(obj, 1);
var val = obj[key];
console.log(key); // => 'bar'
console.log(val); // => '2nd'

My solution:
Object.prototype.__index = function(index)
{
var i = -1;
for (var key in this)
{
if (this.hasOwnProperty(key) && typeof(this[key])!=='function')
++i;
if (i >= index)
return this[key];
}
return null;
}
aObj = {'jack':3, 'peter':4, '5':'col', 'kk':function(){alert('hell');}, 'till':'ding'};
alert(aObj.__index(4));