This question already has answers here:
How to get the last character of a string?
(15 answers)
Closed 8 years ago.
I know there are methods to remove characters from the beginning and from the end of a string in Javascript. What I need is trim a string in such a way that only the last 4 characters remain.
For eg:
ELEPHANT -> HANT
1234567 -> 4567
String.prototype.slice will work
var str = "ELEPHANT";
console.log(str.slice(-4));
//=> HANT
For, numbers, you will have to convert to strings first
var str = (1234567).toString();
console.log(str.slice(-4));
//=> 4567
FYI .slice returns a new string, so if you want to update the value of str, you would have to
str = str.slice(-4);
Use substr method of javascript:
var str="Elephant";
var n=str.substr(-4);
alert(n);
You can use slice to do this
string.slice(start,end)
lets assume you use jQuery + javascript as well.
Lets have a label in the HTML page with id="lblTest".
<script type="text/javascript">
function myFunc() {
val lblTest = $("[id*=lblTest]");
if (lblTest) {
var str = lblTest.text();
// this is your needed functionality
alert(str.substring(str.length-4, str.length));
} else {
alert('does not exist');
}
}
</script>
Edit: so the core part is -
var str = "myString";
var output = str.substring(str.length-4, str.length);
Related
This question already has answers here:
Split by Caps in Javascript
(4 answers)
Closed 8 years ago.
What's the best way to have a function that takes in a phrase of the form fooBar and returns the words foo bar?
My current approach of iterating over all characters to find a capitalized letter and then splitting on that index seems suboptimal is there a better way?
Thanks!
Your approach is the good one, that is exactly what split function does with this pattern: (?=[A-Z])
var resultArray = mystring.split(/(?=[A-Z])/);
The pattern uses a lookahead assertion (?=...) that means followed by.
Note: if you want to make lowercase all items of the result array, you can map the array like this:
resultArray = resultArray.map(function (x){ return x.toLowerCase(); });
The answer here suffices: Split by Caps in Javascript
Basically use a regex that looks for caps and does a split. To be complete the function is
function splitFooBar() {
var fb = fooBar.split(/(?=[A-Z])/);
fbString = fb.length > 1? fb[0] + " " + fb[1].substr(0, 1).toLowerCase() + fb[1].substr(1): fb[0];
return fbString;
}
try this
var re = /([A-Z])/g;
var str = 'fooBar fooBar fooBarww oldWman ';
var subst = ' $1';
var result = str.replace(re, subst);
result = result.toLowerCase();
console.log(result)
alert(result)
This question already has answers here:
How do I replace all occurrences of a string in JavaScript?
(78 answers)
Closed 8 years ago.
I'm trying to remove the euro sign from my string.
Since the string looks like this €33.0000 - €37.5000, I first explode to string on the - after I try to remove the euro sign.
var string = jQuery('#amount').val();
var arr = string.split(' - ');
if(arr[0] == arr[1]){
jQuery(this).find('.last').css("display", "none");
}else{
for(var i=0; i< arr.length; i++){
arr[i].replace('€','');
console.log(arr[i]);
}
}
When I try it on my site, the euro signs aren't removed, when I get the string like this
var string = jQuery('#amount').val().replace("€", "");
Only the first euro sign is removed
.replace() replace only the fisrt occurence with a string, and replace all occurences with a RegExp:
jQuery('#amount').val().replace(/€/g, "")
Try using a regular expression with global replace flag:
"€33.0000 - €37.5000".replace(/€/g,"")
First get rid of the € (Globally), than split the string into Array parts
var noeur = str.replace(/€/g, '');
var parts = noeur.split(" - ");
The problem with your first attempt is that the replace() method returns a new string. It does not alter the one it executes on.
So it should be arr[i] = arr[i].replace('€','');
Also the replace method, by default, replaces the 1st occurrence only.
You can use the regular expression support and pass the global modifier g so that it applies to the whole string
var string = Query('#amount').val().replace(/€/g, "");
var parts = /^€([0-9.]+) - €([0-9.]+)$/.exec(jQuery('#amount').val()), val1, val2;
if (parts) {
val1 = parts[1];
val2 = parts[2];
} else {
// there is an error in your string
}
You can also tolerate spaces here and there: /^\s*€\s*([0-9.]+)\s*-\s*€\s*([0-9.]+)\s*$/
This question already has answers here:
How can I get query string values in JavaScript?
(73 answers)
Closed 8 years ago.
I have the following string and I'm trying to retrieve the string between two symbols
http://mytestdomain.com/temp-param-page-2/?wpv_paged_preload_reach=1&wpv_view_count=1&wpv_post_id=720960&wpv_post_search&wpv-women-clothing[]=coats
I need to retrieve wpv-women-clothing[] or any other string between the last & and the last = in the URL
Should I use regex for this or is there a function in Javascript/jQuery already well suited for this?
Thanks
var str = "http://mytestdomain.com/temp-param-page-2/?wpv_paged_preload_reach=1&wpv_view_count=1&wpv_post_id=720960&wpv_post_search&wpv-women-clothing[]=coats";
var last =str.split('&').pop().split('=')
console.log(last[0]) // wpv-women-clothing[]
jsFiddle example
Split the string on the ampersands (.split('&')), take the last one (.pop()), then split again on the = (.split('=')) and use the first result last[0].
.*&(.*?)=.*
This should do it.
See demo.
http://regex101.com/r/lZ5bT3/1
Group index 1 contains your desired output,
\&([^=]*)(?==[^&=]*$)
DEMO
> var re = /\&([^=]*)(?==[^&=]*$)/g;
undefined
> while ((m = re.exec(str)) != null) {
... console.log(m[1]);
... }
wpv_post_search&wpv-women-clothing[]
Can you try:
var String = "some text";
String = $("<div />").html(String).text();
$("#TheDiv").append(String);
This question already has answers here:
Regex exec only returning first match [duplicate]
(3 answers)
Closed 8 years ago.
This regex in JavaScript is returning only the first real number from a given string, where I expect an array of two, as I am using /g. Where is my mistake?
/[-+]?[0-9]*\.?[0-9]+/g.exec("-8.075090 -35.893450( descr)")
returns:
["-8.075090"]
Try this code:
var input = "-8.075090 -35.893450( descr)";
var ptrn = /[-+]?[0-9]*\.?[0-9]+/g;
var match;
while ((match = ptrn.exec(input)) != null) {
alert(match);
}
Demo
http://jsfiddle.net/kCm4z/
Discussion
The exec method only returns the first match. It must be called repeatedly until it returns null for gettting all matches.
Alternatively, the regex can be written like this:
/[-+]?\d*\.?\d+/g
String.prototype.match gives you all matches:
var r = /[-+]?[0-9]*\.?[0-9]+/g
var s = "-8.075090 -35.893450( descr)"
console.log(s.match(r))
//=> ["-8.075090", "-35.893450"]
This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
How do I split a string, breaking at a particular character?
I have a string in following format
part1/part2
/ is the delimiter
now I want to get split the string and get part 1. How can I do it?
result = "part1/part2".split('/')
result[0] = "part1"
result[1] = "part2
split the string and get part 1
'part1/part2'.split('/')[0]
var tokens = 'part1/part2'.split('/');
var delimeter = '/';
var string = 'part1/part2';
var splitted = string.split(delimeter);
alert(splitted[0]); //alert the part1
var result = YourString.split('/');
For your example result will be an array with 2 entries: "part1" and "part2"