I am trying to figure out an efficient way to remove objects that are duplicates from an array and looking for the most efficient answer. I looked around the internet everything seems to be using primitive data... or not scalable for large arrays. This is my current implementation which is can be improved and want to try to avoid labels.
Test.prototype.unique = function (arr, artist, title, cb) {
console.log(arr.length);
var n, y, x, i, r;
r = [];
o: for (i = 0, n = arr.length; i < n; i++) {
for (x = 0, y = r.length; x < y; x++) {
if (r[x].artist == arr[i].artist && r[x].title == arr[i].title) {
continue o;
}
}
r.push(arr[i]);
}
cb(r);
};
and the array looks something like this:
[{title: sky, artist: jon}, {title: rain, artist: Paul}, ....]
Order does not matter, but if sorting makes it more efficient then I am up for the challenge...
and for people who do not know o is a label and it is just saying jump back to the loop instead of pushing to the new array.
Pure javascript please no libs.
ANSWERS SO FAR:
The Performance Test for the answers below:
http://jsperf.com/remove-duplicates-for-loops
I see, the problem there is that the complexity is squared. There is one trick to do it, it's simply by using "Associative arrays".
You can get the array, loop over it, and add the value of the array as a key to the associative array. Since it doesn't allow duplicated keys, you will automatically get rid of the duplicates.
Since you are looking for title and artist when comparing, you can actually try to use something like:
var arrResult = {};
for (i = 0, n = arr.length; i < n; i++) {
var item = arr[i];
arrResult[ item.title + " - " + item.artist ] = item;
}
Then you just loop the arrResult again, and recreate the array.
var i = 0;
var nonDuplicatedArray = [];
for(var item in arrResult) {
nonDuplicatedArray[i++] = arrResult[item];
}
Updated to include Paul's comment. Thanks!
Here is a solution that works for me.
Helper functions:
// sorts an array of objects according to one field
// call like this: sortObjArray(myArray, "name" );
// it will modify the input array
sortObjArray = function(arr, field) {
arr.sort(
function compare(a,b) {
if (a[field] < b[field])
return -1;
if (a[field] > b[field])
return 1;
return 0;
}
);
}
// call like this: uniqueDishes = removeDuplicatesFromObjArray(dishes, "dishName");
// it will NOT modify the input array
// input array MUST be sorted by the same field (asc or desc doesn't matter)
removeDuplicatesFromObjArray = function(arr, field) {
var u = [];
arr.reduce(function (a, b) {
if (a[field] !== b[field]) u.push(b);
return b;
}, []);
return u;
}
and then simply call:
sortObjArray(dishes, "name");
dishes = removeDuplicatesFromObjArray(dishes, "name");
Basic sort-then-unique implementation, fiddle HERE:
function unique(arr) {
var comparer = function compareObject(a, b) {
if (a.title == b.title) {
if (a.artist < b.artist) {
return -1;
} else if (a.artist > b.artist) {
return 1;
} else {
return 0;
}
} else {
if (a.title < b.title) {
return -1;
} else {
return 1;
}
}
}
arr.sort(comparer);
console.log("Sorted: " + JSON.stringify(arr));
for (var i = 0; i < arr.length - 1; ++i) {
if (comparer(arr[i], arr[i+1]) === 0) {
arr.splice(i, 1);
console.log("Splicing: " + JSON.stringify(arr));
}
}
return arr;
}
It may or may not be the most efficient, and should be entirely scalable. I've added some console.logs so you can see it as it works.
EDIT
In the interest of saving on the space the function used, I did that for loop at the end, but it seems likely that didn't properly find only unique results (depsite it passing my simple jsfiddle test). Please try replacing my for loop with the following:
var checker;
var uniqueResults = [];
for (var i = 0; i < arr.length; ++i) {
if (!checker || comparer(checker, arr[i]) != 0) {
checker = arr[i];
uniqueResults.push(checker);
}
}
return uniqueResults;
I use this function. its not doing any sorting, but produces result. Cant say about performance as never measure it.
var unique = function(a){
var seen = [], result = [];
for(var len = a.length, i = len-1; i >= 0; i--){
if(!seen[a[i]]){
seen[a[i]] = true;
result.push(a[i]);
}
}
return result;
}
var ar = [1,2,3,1,1,1,1,1,"", "","","", "a", "b"];
console.log(unique(ar));// this will produce [1,2,3,"", "a", "b"] all unique elements.
Below is Henrique Feijo's answer with ample explanation and an example that you can cut and paste:
Goal: Convert an array of objects that contains duplicate objects (like this one)...
[
{
"id": 10620,
"name": "Things to Print"
},
{
"id": 10620,
"name": "Things to Print"
},
{
"id": 4334,
"name": "Interesting"
}
]
... Into an array of objects without duplicate objects (like this one):
[
{
"id": 10620,
"name": "Things to Print"
},
{
"id": 4334,
"name": "Interesting"
}
]
Explanation provided in the comments:
var allContent = [{
"id": 10620,
"name": "Things to Print"
}, {
"id": 10620,
"name": "Things to Print"
}, {
"id": 4334,
"name": "Interesting"
}]
//Put Objects Into As Associative Array. Each key consists of a composite value generated by each set of values from the objects in allContent.
var noDupeObj = {} //Create an associative array. It will not accept duplicate keys.
for (i = 0, n = allContent.length; i < n; i++) {
var item = allContent[i]; //Store each object as a variable. This helps with clarity in the next line.
noDupeObj[item.id + "|" + item.name] = item; //This is the critical step.
//Here, you create an object within the associative array that has a key composed of the two values from the original object.
// Use a delimiter to not have foo+bar handled like fo+obar
//Since the associative array will not allow duplicate keys, and the keys are determined by the content, then all duplicate content are removed.
//The value assigned to each key is the original object which is along for the ride and used to reconstruct the list in the next step.
}
//Recontructs the list with only the unique objects left in the doDupeObj associative array
var i = 0;
var nonDuplicatedArray = [];
for (var item in noDupeObj) {
nonDuplicatedArray[i++] = noDupeObj[item]; //Populate the array with the values from the noDupeObj.
}
console.log(nonDuplicatedArray)
For those who love ES6 and short stuff, here it's one solution:
const arr = [
{ title: "sky", artist: "Jon" },
{ title: "rain", artist: "Paul" },
{ title: "sky", artist: "Jon" }
];
Array.from(arr.reduce((a, o) => a.set(o.title, o), new Map()).values());
const arr = [
{ title: "sky", artist: "Jon" },
{ title: "rain", artist: "Paul" },
{ title: "sky", artist: "Jon" },
{ title: "rain", artist: "Jon" },
{ title: "cry", artist: "Jon" }
];
const unique = Array.from(arr.reduce((a, o) => a.set(o.title, o), new Map()).values());
console.log(`New array length: ${unique.length}`)
console.log(unique)
The above example only works for a unique title or id. Basically, it creates a new map for songs with duplicate titles.
Below code compares object with JSON as String format and removes duplicates and works fine with simple arrays.
Array.prototype.unique=function(a){
return function(){
return this.filter(a)
}
}(
function(a,b,c){
var tmp=[];
c.forEach(function(el){
tmp.push(JSON.stringify(el))
});
return tmp.indexOf(JSON.stringify(a),b+1)<0
})
If you are using underscore js, it is easy to remove duplicate object.
http://underscorejs.org/#uniq
function remove_duplicates(objectsArray) {
var arr = [], collection = [];
$.each(objectsArray, function (index, value) {
if ($.inArray(value.id, arr) == -1) {
arr.push(value.id);
collection.push(value);
}
});
return collection;
}
Related
So my array looks like this:
let array = [
{"object1":1},
{"object2":2},
{"object3":3}
];
What I want to do is to check, for example, whether or not "object1" exists. The way I would prefer is pure Javascript.
I am doing this for large chunks of data and so my code needs to be something like this:
if ("opensprint1" in array){
console.log("yes, this is in the array");
} else {
console.log("no, this is not in the array");
};
NOTE: I have tried to use the (in) function in JS and the (hasOwnProperty) and neither has worked.
Any ideas?
if ("opensprint1" in array){
That check for the array keys, so it would work with:
if ("0" in array){
But actually you want to check if some of the array elements got that key:
if(array.some( el => "opensprint1" in el))
You're trying to filter an array of objects. You can pass a custom function into Array.prototype.filter, defining a custom search function. It looks like you want to search based on the existence of keys. If anything is returned, that key exists in the object array.
let array = [{
"object1": 1
},
{
"object2": 2
},
{
"object3": 3
}
];
const filterByKey = (arr, keyName) =>
array.filter(obj => Object.keys(obj).includes(keyName)).length > 0;
console.log(filterByKey(array, 'object1'));
console.log(filterByKey(array, 'object5'));
That is roughly equivalent to:
let array = [{
"object1": 1
},
{
"object2": 2
},
{
"object3": 3
}
];
const filterByKey = (arr, keyName) => {
// iterate each item in the array
for (let i = 0; i < arr.length; i++) {
const objectKeys = Object.keys(arr[i]);
// take the keys of the object
for (let j = 0; j < objectKeys.length; j++) {
// see if any key matches our expected
if(objectKeys[i] === keyName)
return true
}
}
// none did
return false;
}
console.log(filterByKey(array, 'object1'));
console.log(filterByKey(array, 'object5'));
This might help you
let array = [
{"object1":1},
{"object2":2},
{"object3":3}
];
let targetkey = "opensprint1";
let exists = -1;
for(let i = 0; i < array.length; i++) {
let objKeys = Object.keys(array[i]);
exists = objKeys.indexOf(targetkey);
if (exists >= 0) {
break;
}
}
if (exists >= 0) {
console.log("yes, this is in the array");
} else {
console.log("no, this is not in the array");
}
let array = [
{ "object1": 1 },
{ "object2": 2 },
{ "object3": 3 }
];
let checkKey = (key) => {
var found = false;
array.forEach((obj) => {
if (!(obj[key] === undefined)) {
found = true;
array.length = 0;
}
});
return found;
}
console.log(checkKey("object2"));
In this case, I think one of the most efficient way is to do a for and break like:
let array = [
{"object1":1},
{"object2":2},
{"object3":3}
];
exist = false;
for(let i = 0; i<array.length; i++){
if("object1" in array[i]){
exist = true;//<-- We just know the answer we want
break;//<-- then stop the loop
}
}
console.log(exist);
When iteration finds a true case, stops the iteration. We can't perform a break in .map, .filter etc. So the number of iterations are the less possible. I think this is also the case of .some()
I'm new to JavaScript and I'm really lost here. Here is some data produced by PHP json_encode() (and limited to most pertinent keys) :
[
{
"product_option_id":"229",
"product_option_value":
[
{
"product_option_value_id":"21",
"option_value_id":"51",
"price":"1,22 €",
"price_prefix":"+"
},
{
"product_option_value_id":"22",
"option_value_id":"52",
"price":false,
"price_prefix":"+"
},
{
"product_option_value_id":"23",
"option_value_id":"53",
"price":"2,42 €",
"price_prefix":"+"
}
],
"option_id":"14",
"type":"radio",
"value":""
},
{
"product_option_id":"228",
"product_option_value":
[
{
"product_option_value_id":"19",
"option_value_id":"49",
"price":"1,22 €",
"price_prefix":"+"
},
{
"product_option_value_id":"20",
"option_value_id":"50",
"price":"2,42 €",
"price_prefix":"+"
}
],
"option_id":"13",
"type":"select",
"value":""
}
]
I need to access price and price_prefix values (in JavaScript) knowing product_option_id and product_option_value_id.
How do I do that ? Should I go for a loop ?
Update :
Thanks for replies. Unless I missed something, it appears that in my case arrays (as ugly as they may be…) are much more efficient than all the proposed solutions (I'll try another approach, formatting a JSON object corresponding to my needs with PHP rather than using the "default" one, but it's off topic here). Though I'm not fond of adding libraries and it's a bit slower than most other solutions, I'll accept Matt's solution because it really seems to make life easier as far as JSON access is concerned. But it should be noted that Yeldard and Barmar's (almost cloned) solutions are faster than other propositions.
lodash would make this easier and neater. It provides _.find or _.filter depending on if your id's are unique or not.
var record = _.find( data_structure, {
"product_option_id": "229"
})
if ( !record ) throw new Error("Record not found");
var value = _.find( record.product_option_value, {
"product_option_value_id":"22"
})
if ( !value ) throw new Error("Value not found");
console.log( "price[%s] prefix[%s]", value.price, value.price_prefix )
Demo
For more complex data selection, you might want to look at sift.js. It's based on mongodb's query system.
var records = sift({
"product_option_id": "229",
"product_option_value": {
$elemMatch: {
"product_option_value_id": "22"
}
}
},
data_structure
)
you can do like this
for(var i in jsonData) {
var item = jsonData[i];
if(item.product_option_id == 229) {
for(var j in item.product_option_value){
var item1 = item.product_option_value[j];
if(item1.product_option_value_id == 21) {
//your item here
break;
}
}
break;
}
}
This should do it:
var productOptionId = 229;
var productOptionValue = 22;
var matchingOuter = yourData.filter(function(i){
return i.product_option_id === productOptionId;
})[0];
if (matchingOuter) {
var matchingInner = matchingOuter.product_option_value.filter(function(i){
return i.product_option_value === productOptionValue;
})[0];
}
If a matching item exists it will be assigned to matchingInner
Following would do:
function getProductValues(products, product_option_id, product_option_value_id) {
if (!product_option_id || !product_option_value_id) {
return;
}
return products.filter(function(product) {
return +product.product_option_id === product_option_id;
}).map(function (product) {
var option_values = product.product_option_value;
return option_values.filter(function (option) {
return +option.option_value_id === product_option_value_id;
})[0] || [];
})[0] || [];
}
Usage:
getProductValues(data, 229, 51)
Result:
{product_option_value_id: "21", option_value_id: "51", price: "1,22 €", price_prefix: "+"}
Use filter on the main array to grab the right object, filter again on the option_value_id, then map on the returned array to get a single price/prefix object. map and filter both return arrays which is why you see the code picking up the first element ([0]) in a couple of places.
function getData(data, options) {
return data.filter(function (product) {
return product.product_option_id === options.id;
})[0].product_option_value.filter(function (details) {
return details.product_option_value_id === options.optionId;
}).map(function(el) {
return { price: el.price, prefix: el.price_prefix }
})[0];
}
getData(data, { id: '229', optionId: '23' }); // { price: "2,42 €", prefix: "+" }
DEMO
Use nested loops to search through the main array and the sub-arrays, looking for the matching element.
function find_product(product_option_id, product_option_value_id) {
for (var i = 0; i < products.length; i++) {
var product = products[i];
if (product.product_option_id == product_option_id) {
for (var j = 0; j < product.product_option_value.length; j++) {
var value = product.product_option_value[j];
if (value.product_option_value_id == product_option_value_id) {
return { price: value.price, price_prefix: value.price_prefix }
}
}
}
}
}
Yes, you need to enumerate through the array and find your items:
Here is the working code which outputs price_prefix and price of product with product_option_id = 228 and product_option_value_id = 19. You can replace these values with your own.
for (var i = 0; i < obj.length; i++) // Enumerate through array
{
var item = obj[i];
if (item.product_option_id === "228") // Filtering items by product_option_id
{
// When necessary product_option_id found
for (var j = 0; j < item.product_option_value.length; j++) // Enumerate through its products
{
var productItem = item.product_option_value[j];
if (productItem.product_option_value_id === "19") // Filtering by product_option_value_id
{
// here it is. productItem is found! do whatever you want with it
alert(productItem.price_prefix + " " + productItem.price);
}
}
}
}
Working JSFiddle demo.
$.each(constructions, function(i,v) {
if ($.inArray(v.name, map[ii].buildings) == -1) {//stuff}
};
Where constructions is an array of objects, each with a unique name. map[ii].buildings is an array containing some of these objects. I want to iterate each object in constructions, checking if its name parameter appears in the objects of map[ii].buildings.
The above code works if the each element in the map[ii].buildings array is just the text string of the object name, but not if the element is the entire object.. close, but no dice >.<
Try using $.grep() instead of $.inArray(); you can specify a function to do the filtering for you.
Instead of checking for -1, you check whether the array that $.grep() returns has length == 0
Simple example: (would be easier if you posted the code / example of what "constructions" objects look like)
var constructions = [{
Name: "Mess hall",
SqFt: 5000
}, {
Name: "Infirmary",
SqFt: 2000
}, {
Name: "Bungalow",
SqFt: 2000
}, {
Name: "HQ",
SqFt: 2000
}];
var buildings = [{
Name: "Infirmary",
SqFt: 2000
}, {
Name: "HQ",
SqFt: 2000
}];
// found buildings will be list of items in "constructions" that is not in "buildings"
var foundBuildings = $.grep(constructions, function (constructionsItem) {
return $.grep(buildings, function (buildingsItem) {
return buildingsItem.Name === constructionsItem.Name
}).length == 0; // == 0 means "not in", and > 0 means "in"
});
// this just renders the results all pretty for ya
$.each(foundBuildings, function (idx, item) {
$("#output").append("<div>" + item.Name + "</div>");
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id='output'></div>
Example jsFiddle: http://jsfiddle.net/eLeuy9eg/3/
The non-jQuery way of doing this would be to use filter. Something like this:
// pass in an array and the key for which you want values
// it returns an array of those values
function getValues(arr, key) {
return arr.map(function (el) { return el[key]; });
}
function notFoundIn(arr, arr2) {
// grab the names of the buildings
var buildings = getValues(arr2, 'name');
// grab the names from the construction objects and filter
// those that are not in the building array
return getValues(arr, 'name').filter(function (el) {
return buildings.indexOf(el) === -1;
});
}
notFoundIn(constructions, buildings); // eg [ "one", "three" ]
DEMO
You could even add a new method to the array prototype. With this one you can use either simple arrays, or arrays of objects if you pass in a key. Note in this example I've replaced map and filter with loops that perform the same functions, but faster (see comments):
function getValues(arr, key) {
var out = [];
for (var i = 0, l = arr.length; i < l; i++) {
out.push(arr[i][key]);
}
return out;
}
if (!Array.prototype.notFoundIn) {
Array.prototype.notFoundIn = function (inThisArray, key) {
var thisArr = key ? getValues(this, key) : this;
var arrIn = key ? getValues(inThisArray, key) : inThisArray;
var out = [];
for (var i = 0, l = thisArr.length; i < l; i++) {
if (arrIn.indexOf(thisArr[i]) === -1) {
out.push(thisArr[i]);
}
}
return out;
}
}
constructions.notFoundIn(buildings, 'name');
[1, 2, 3].notFoundIn([2]); // [1, 3]
DEMO
Here's what I have in mind:
Given an array of objects:
[
{
"name": "Kirk",
"count": 1
},
{
"name": "Spock",
"count": 1
},
{
"name": "Kirk",
"count": 1
}
]
I am trying to get:
[
{
"name": "Kirk",
"count": 2
},
{
"name": "Spock",
"count": 1
}
]
I am wondering if there's already an algorithm, perhaps combining some higher order functions to achieve this. I could do this easily with loops, but I am looking for a way to solve it using higher order functions. If someone could point me to what I should use to achieve this, it would be great. Again, I'm looking for something as elegant as possible (two maps and a filter would not be a big improvement from loops).
This is my current solution and I'm looking for something better (and by better I mean more expressive):
function mergeDuplicates(input) {
var output = [];
var existingItem = null;
input.forEach(function (inputItem) {
existingItem = _.find(output, function (outputItem) {
return inputItem.name === outputItem.name;
});
existingItem ? existingItem.count += 1 : output.push({
name: inputItem.name,
count: 1
});
existingItem = null;
});
return output;
}
To make line #10 more clear: in the original array, count might be either non-existing or 1, hence I set it to 1.
I think the best way would be to hash each object if it does not already exist, and delete the ones that you found already hashed in your structure. This way, you'd be checking the existence of each object only 1 (depends on your hash scheme).
Just a function if you would like to use.
function merge(arr) {
for(var o = {}, i; i=arr.shift(); o[i.name] = i.count + (o[i.name] || 0));
for(i in o) arr.push({name:i, count:o[i]});
}
Calling :
var myArray = [{"name":"Kirk","count":1},
{"name":"Spock","count":1},
{"name":"Kirk","count":1}];
merge(myArray);
// myArray is now : [{"name":"Kirk","count":2}, {"name":"Spock","count":1}]
You can use reduce which is actually a fold.
a.reduce(function(p, c) {
var n = c.name;
if (p[n])
p[n].count++;
else
p[n] = c;
return p;
}, {})
will give you a object with "Kirk" and "Spock" as the key, what you want as values.
I know this is an old question, but I couldn't resist trying to solve it. Instead of two maps and a filter, we use a sort and then a reduce. This was a fun one to sort out :-)
function mergeDuplicates(list, prop, cb){
return list.sort(function(a,b){
if(a[prop] < b[prop]){ return -1;}
if(a[prop] > b[prop]){return 1;}
return 0;
}).reduce(function(acc, item, index, array){
if(index > 0 && array[index-1][prop] === item[prop]){
cb(acc[acc.length-1], item);
return acc;
}else{
var newItem = Object.assign({}, item);
cb(newItem);
acc.push(newItem);
return acc;
}
}, []);
}
Then use it like this:
var newList = mergeDuplicates(list, "name", function(item, dup){
if(dup){
item.count++;
}else{
item.count = 1;
}
});
EDIT: Here's another take at it using reduce and using an object as a hashmap to store duplicates (similar to some of the other answers). This one uses ramdajs
const mergeDups = (cb, prop, list) => R.pipe(
R.reduce((acc, item) => (
R.has(item[prop], acc) ?
R.assoc(item[prop], cb(acc[item[prop]], item), acc) :
R.assoc(item[prop], cb(item), acc)
), {}),
R.values
)(list);
const cb = (i, d) => ( !R.isNil(d) ?
R.assoc('count', i.count + 1, i) :
R.assoc('count', 1, i) )
mergeDups(cb, 'name', items);
Here it is in the repl on Ramda's site
Try this better i'll useful resolve your issues
cleanup(arrayOfObj, 'name');
function cleanup(arr, prop) {
var new_arr = [];
var lookup = {};
for (var i in arr) {
lookup[arr[i][prop]] = arr[i];
}
for (i in lookup) {
new_arr.push(lookup[i]);
}
return new_arr;
}
Yet another version using reduce function:
var items =
[
{
"name": "Kirk",
"count": 1
},
{
"name": "Spock",
"count": 1
},
{
"name": "Kirk",
"count": 1
}
];
var filtered = items.reduce(function(prev, current,index){
if(!(current.name in prev.keys)) {
prev.keys[current.name] = index;
prev.result.push(current);
}
else{
prev.result[prev.keys[current.name]].count += current.count;
}
return prev;
},{result: [], keys: []}).result;
document.getElementById("output").innerHTML = JSON.stringify(filtered,null,2);
<pre id='output' />
I have an array of objects as follows within my server side JS:
[
{
"Company": "IBM"
},
{
"Person": "ACORD LOMA"
},
{
"Company": "IBM"
},
{
"Company": "MSFT"
},
{
"Place": "New York"
}
]
I need to iterate through this structure, detect any duplicates and then create a count of a duplicate is found along side each value.
Both of the values must match to qualify as a duplicate e.g. "Company": "IBM" is not a match for "Company": "MSFT".
I have the options of changing the inbound array of objects if needed. I would like the output to be an object, but am really struggling to get this to work.
EDIT: Here is the code I have so far where processArray is the array as listed above.
var returnObj = {};
for(var x=0; x < processArray.length; x++){
//Check if we already have the array item as a key in the return obj
returnObj[processArray[x]] = returnObj[processArray[x]] || processArray[x].toString();
// Setup the count field
returnObj[processArray[x]].count = returnObj[processArray[x]].count || 1;
// Increment the count
returnObj[processArray[x]].count = returnObj[processArray[x]].count + 1;
}
console.log('====================' + JSON.stringify(returnObj));
For example:
counter = {}
yourArray.forEach(function(obj) {
var key = JSON.stringify(obj)
counter[key] = (counter[key] || 0) + 1
})
Docs: Array.forEach, JSON.stringify.
Object.prototype.equals = function(o){
for(var key in o)
if(o.hasOwnProperty(key) && this.hasOwnProperty(key))
if(this[key] != o[key])
return false;
return true;
}
var array = [/*initial array*/],
newArray = [],
ok = true;
for(var i=0,l=array.length-1;i<l;i++)
for(var j=i;j<l+1;j++)
{
if(!array[i].equals(array[j]))
newArray.push(array[i]);
}
We are required to write a JavaScript function that takes in one such array of objects. The function creates and return a new array in which no objects are repeated (by repeated we mean objects having same value for "Country" property.)
Moreover, the function should assign a count property to each object that represents the number of times they appeared in the original array.
const arr = [
{
"Country": "BR",
"New Lv1−Lv2": "#N/A"
},
{
"Country": "BR",
"New Lv1−Lv2": "#N/A"
},
{
"Country": "",
"New Lv1−Lv2": "test"
}];
const convert = (arr) => {
const res = {};
arr.forEach((obj) => {
const key = `${obj.Country}${obj["New Lv1−Lv2"]}`;
if (!res[key]) {
res[key] = { ...obj, count: 0 };
};
res[key].count += 1;
});
return Object.values(res);
};
console.log(convert(arr));
know more
With ES6, one can use Array#reduce with an object to store the counts.
let counts = arr.reduce((acc, curr)=>{
const str = JSON.stringify(curr);
acc[str] = (acc[str] || 0) + 1;
return acc;
}, {});
Demo
To create a new array without duplicates, a Set can be used with Array#filter.
let set = new Set;
let res = arr.filter(x => {
const str = JSON.stringify(x);
return !set.has(str) && set.add(str);
});
Demo