I want to replace the content of my <div id="score_here">10</div>, when I select a value from my drop-down <select id="ansRate" onchange="javascript:add_score(this);">. I have setup my JavaScript function which is shown below, but it doesn't work. What is the problem with this?
<div>
<select id="ansRate" onchange="javascript:add_score(this);">
<option value="0">Answer Rate</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
<option value="10">10</option>
</select>
</div>
<div id="score_here" style="width:100px;height:100px;background-color:yellow;">
81
</div>
<script type="text/javascript">
function add_score(a){
var string = $("#questionScore").text();
var thenum = string.replace( /^\D+/g, '');
var add = $(a).val();
var total = parseInt(thenum) + parseInt(add);
document.getElementByID('score_here').innerHTML = total;
}
</script>
document.getElementById("id")
not
document.getElementByID("id")
should be:
document.getElementById('score_here').innerHTML = total;
:-)
Try this:
document.getElementByID is not the correct syntax, instead try document.getElementById
You can done everything by jQuery.
Just replace this line:
document.getElementByID('score_here').innerHTML = total;
to
$('#score_here').html(total);
Related
var beneficiarioDiv = $('<div class="beneficiario-wrap"><label for="nombre_bene">Nombre y Apellido</label><input type="text" name="nombre_bene" value=""><label for="nombre_bene">Cedula beneficiario</label><div><select name="cedulabene_tipo"><option value="Venezolano" selected>V </option><option value="Extranjero">E </option></select> <input type="text" name="cedulabene_no" value="" maxlength="8"></div><label for="edad_bene">Edad beneficiario</label><input type="text" name="edad_bene" value=""></div>');
$('#beneficiarios').change(function() {
var beneficiarios = $('#beneficiarios :selected').val();
// this gives me the value that the user selected
<div class="beneficiarios-wrapper"></div>
// this is the div where I want to append the number of divs selected by the user
});
<label for="beneficiarios">Cantidad de beneficiarios</label>
<select name="beneficiarios" id="beneficiarios">
<option value="0">0</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
<option value="10">10</option>
</select>
I have been hitting my head cuz I can't think on a way to get this to work ( I'm new with Jquery )
So.. I have a select input field in a form with number options.. I want to check which of the options the user selected and add a DIV the number of times the user selected ( from 0 to 10 ) and if the user selects a number lower than the one he previously chose delete the DIVs previously added and add the ones he now chose (if he selects number 3 add 3 DIVs, if he now selects 2 because he was just mistaken then just show 2 instead of the 3)
I know how to get the number the user selected with the .change event listener and the :selected.val() method.. my problem is appending the divs that number of times the user selected, and deleting them if the user selects a number lower than.
Please i don't know how to make this work!
In your change function, first clear the wrapper and then append the divs in a loop
var beneficiarioDiv = '<div class="beneficiario-wrap"><label for="nombre_bene">Nombre y Apellido</label><input type="text" name="nombre_bene" value=""><label for="nombre_bene">Cedula beneficiario</label><div><select name="cedulabene_tipo"><option value="Venezolano" selected>V </option><option value="Extranjero">E </option></select> <input type="text" name="cedulabene_no" value="" maxlength="8"></div><label for="edad_bene">Edad beneficiario</label><input type="text" name="edad_bene" value=""></div>';
$('#beneficiarios').change(function() {
var beneficiarios = $('#beneficiarios :selected').val();
// this gives me the value that the user selected
$('.beneficiarios-wrapper').empty();
while (beneficiarios--) {
$('.beneficiarios-wrapper').append(beneficiarioDiv);
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<label for="beneficiarios">Cantidad de beneficiarios</label>
<select name="beneficiarios" id="beneficiarios">
<option value="0">0</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
<option value="10">10</option>
</select>
<div class="beneficiarios-wrapper"></div>
You can clear the div on change event. Then use a for loop to append div
const divToAppend = '<div>test</div>';
let number = $('#beneficiarios').val();
$('#beneficiarios').on('change', function () {
$('#placeholder').html('');
number = $(this).val();
for (let i = 0; i < number; i++) {
$('#placeholder').append(divToAppend);
}
});
<label for="beneficiarios">Cantidad de beneficiarios</label>
<select name="beneficiarios" id="beneficiarios">
<option value="0">0</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
<option value="10">10</option>
</select>
<div id="placeholder"></div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
You could just append the divs in a loop:
var b = = $('#beneficiarios :selected').val();
while(b--) {
$(".beneficiarios-wrapper").append("<div>"+b+"</div>")
}
I am trying to change the background colour of my website with local storage. I am using onchange() within the HTML for the colours() function, and the rest is the JavaScript below
var bgcolour;
window.onload = function theme(){
document.body.style.backgroundColor = "red";
localStorage.setItem("bgcolour", 1);
}
function colours(){
localStorage.bgcolour = document.getElementById("party").value;
if (localStorage.bgcolour == '1'){
document.body.style.backgroundColor = "red";
}
}
It does nothing. It doesn't even change, let alone store it as local storage.
I keep missing vital, small parts of code and it feels like I have done it again with this one.
Any help is greatly appreciated!
HTML:
<select name="pnumber" id="party" onchange="colours()">
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
<option value="10">10</option>
<option value="11">11</option>
<option value="12">12</option>
<option value="13">13</option>
<option value="14">14</option>
<option value="15">15 (maximum)</option>
</select>
the code is wrong, you are improperly setting and checking localStorage values. Also, you need to get the value from the node with id party.
var bgcolour;
window.onload = function theme(){
document.body.style.backgroundColor = "red";
localStorage.setItem("bgcolour", 1);
}
var party = document.getElementById('party')
function colours(){
localStorage.setItem('bgcolour', party.value);
if (localStorage.getItem('bgcolour') === '1'){
document.body.style.backgroundColor = "red";
}
else{
document.body.style.backgroundColor = "green";
}
}
<select name="pnumber" id="party" onchange="colours()">
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
<option value="10">10</option>
<option value="11">11</option>
<option value="12">12</option>
<option value="13">13</option>
<option value="14">14</option>
<option value="15">15 (maximum)</option>
</select>
Try this below.
<!DOCTYPE html>
<html>
<link rel="stylesheet" href="https://www.w3schools.com/w3css/4/w3.css">
<body>
<button class = 'w3-button w3-red w3-hover-black w3-btn' onclick = "setBackground('#e60000')">Red</button>
<button class = 'w3-button w3-blue w3-hover-black w3-btn' onclick = "setBackground('#004de6')">Blue</button>
<button class = 'w3-button w3-green w3-hover-black w3-btn' onclick = "setBackground('#00802b')">Green</button>
<button class = 'w3-button w3-yellow w3-hover-black w3-btn' onclick = "setBackground('#e6e600')">Yellow</button>
<script>
function setBackground(color)
{
localStorage.setItem("name", color);
window.location.href = 'http://localhost/Ritabrata/localStorage.html'; //reload the page to effect the change.
}
if(localStorage.name) //Accessing name variable of localStorage.
{
document.body.style.background = localStorage.name;
}
</script>
</body>
</html>
You seem to have some issues with setting and getting values from local-storage. Below is how it is done.
// Store
localStorage.setItem("lastname", "Smith");
// Retrieve
document.getElementById("result").innerHTML = localStorage.getItem("lastname");
I believe something is wrong with your HTML. See this plunk. I copy pasted all of your javascript and I'm assuming your HTML is something like this:
<input type="text" id="party" onchange="colours()" />
You will notice that the background is originally gray, then putting a value "1" in the textbox will make the background red.
I've a dropdown
<select id="ddl1">
<option value="0">number</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
</select>
now what i'm doing is as soon as user clicks on ddl1 i change its default value to 4 like this
$(function () {
var defaultValue = "4";
$('#ddl1').click(function () {
var select_val = $('#ddl1').val();
if (select_val == "0")
$('#ddl1').val(defaultValue);
});
});
but now the problem is when user tries to select the default option of dropdown i.e number, option 4 is selected. Any ideas how to fix this?
The problem is when the user just clicks on dropdown -> option4 must be selected and when user clicks on option number -> option number must be selected instead of option 4.
Not sure why you're doing that but focusin or focus events can help you achieve that as follows:
$(function() {
$('#ddl1').on('focusin', function() {
this.value != 0 || $(this).val( 4 );
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<select id="ddl1">
<option value="0">number</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
</select>
You should call this function on change, not click - else, like you said, as soon as you click an option is selected.
$('#ddl1').change(function () {
DEMO
Edit: You should use a class to give the feel of the default option, you don't actually want it set to selected EACH time the user clicks:
<select id="ddl1">
<option value="0">number</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4" class="default">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
</select>
.default {
color: blue;
}
is this what you're looking for? http://jsfiddle.net/swm53ran/84/
$(function () {
var defaultValue = "4";
var count = 0;
$('#ddl1').click(function () {
if (count < 1) {
$('#ddl1').val(defaultValue);
count++;
}
});
});
I have a dropdown that will change with respect to the first value (i.e from_value).
What I'm trying to do is. There will be numbers from 1 to 10.
So if the first value is selected as 2, then the second value (i.e to_value) should be populated with 2 to 10 in the dropdown.
Below is my code and I'm not sure to run the loop here. Could someone help me in running the loop and do my task.
In other words - If the first drop down is selected with value 2, then the second dropdown should populate with 2,3,4,5,6,7,8,9,10
If the first dropdown is selected with 8, then the second dropdown should show 8,9,10
$("#from_value").change(function(){
var from_value = $("#from_value").val();
$("div.to_value").html('<label>To Value</label><select name="to_value" id="to_value"><option>'+ from_value +'</option></select>');
});
try
HTML
<select id="from_value">
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
<option value="10">10</option>
</select>
<select id="to_value">
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
<option value="10">10</option>
</select>
JS
$("#from_value").change(function () {
var val = +this.value;
$("#to_value option").hide();
$("#to_value option:gt(" + val + "),#to_value option:eq(" + val + ")").show();
$("#to_value").val(val);
});
DEMO
Hope you are getting value in from_value.
Then you could try this
$("#from_value").change(function() {
var from_value = $("#from_value").val();
var opts = '';
for(var i = from_value; from_value <=10; i++)
{
opts = opts+'<option>' + i + '</option>';
}
$("div.to_value").html('<label>To Value</label><select name="to_value" id="to_value">' + opts + '</select>');
});
This is a weird one but our developer is away and my client is having a web site presentation tomorrow.
On a web page one drop-down has the values below. Is there a way using script/css our designer can hide the replicated values and just show 1-9 once? Thanks so much.
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
Try this:
var usedNames = {};
$("select > option").each(function () {
if(usedNames[this.text]) {
$(this).remove();
} else {
usedNames[this.text] = this.value;
}});
Working Demo
you can remove the dups using jQuery like below:
var found = [];
$("select option").each(function() {
if($.inArray(this.value, found) != -1) $(this).remove();
found.push(this.value);
});
Keep an array of found values, if value not found in array, add it .push(), if found, its a dupe, .remove() it.
You can use :gt() selector:
$('select option:gt(8)').hide();
try this ....
$('select option').each(function(i)){
if(i >= 9)
$(this).remove();
});