I want to popup a jQuery dialog when a html checkbox is checked. I'm using following code. But it's not working.
$(document).ready(function () {
$('#chkBoxHelp').click(function () {
if ($(this).is(':checked')) {
$("#txtAge").dialog();
}
});
});
And the html is as below:
<input type="checkbox" id="chkBoxHelp"/>
<div id="txtAge" style="display: none;">Age is something</div>
Please help me.
Also I want to uncheck the checkBox when popup will be closed. Checkbox is in a jQuery popup box. I need to open another popup on checkbox checked.
Thanks in Advance.
You can use open and close methods and close event.
Code:
$(document).ready(function () {
$('#chkBoxHelp').click(function () {
if ($(this).is(':checked')) {
$("#txtAge").dialog({
close: function () {
$('#chkBoxHelp').prop('checked', false);
}
});
} else {
$("#txtAge").dialog('close');
}
});
});
Demo: http://jsfiddle.net/IrvinDominin/V9zMx/
Try this, also closing if the checkbox is clicked again.
$(document).ready(function () {
var the_checkbox = $('#chkBoxHelp');
the_checkbox.click(function () {
if ($(this).is(':checked')) {
$("#txtAge").dialog({
close: function () {
the_checkbox.prop('checked', false);
}
});
} else {
$("#txtAge").dialog('close');
}
});
});
Demo here
Related
I'm Trying to popup an alert when a button is clicked using jQuery but for some reason its not working.
$(document).ready(function () {
$("#find").click(function () {
alert("Hi");
});
});
Here is the link to code:Weather
Kindly let me what I'm I doing wrong.
You should try this instead.
$(function(){
$("#find").on('click',function () {
alert("Hi");
});
});
I have a hidden div which will be shown on a button click and hide when i click every where else in page.
Now the problem is here:
Inside my div I have datepickers whenever I click on next/prev or select date,div slides up. How can I prevent that?
The code is here:
$(document).click(function(evt) {
if(evt.target.id!='btn' )
if($('#div').is(':visible')) {
$('#div').slideUp();
}
});
$("#div").click(function(e) {
e.stopPropagation();
return false;
});
$('#btn').click(function () {
if($('#div').is(':visible')) {
$('#div').slideUp();
}
else{
//initialize controls
$('#div').slideDown();
}
});
Update:
jsfiddle added.
Please check my js fiddle
I have added date picker id #ui-datepicker-div" for stop propagation, and it's worked.
$(document).click(function(evt) {
if(evt.target.id!='btn' )
if($('#div').is(':visible')) {
$('#div').slideUp();
}
});
$( "#datepicker" ).datepicker();
$("#div, #ui-datepicker-div").click(function(e) {
e.stopPropagation();
return false;
});
$('#btn').click(function () {
if($('#div').is(':visible')) {
$('#div').slideUp();
}
else{
//initialize controls
$('#div').slideDown();
}
});
you have to slideUp your required div if you click anywhere in your document body except your button 'btn', your div itself AND div children:
$(document).click(function(e) {
if ( e.target.id != 'btn' && e.target.id != 'div' && !$('#div').find(e.target).length) {
if($('#div').is(':visible')) {
$('#div').slideUp();
}
}
});
In your document.ready you made mistake in if block, I modified it as
if(evt.target.id!='btn' ){
if($('#div').is(':visible')) {
$('#div').slideDown();
}
}
Also try to avoid using id as 'btn' as it this id or class will make confusion if you use more css in your design
Here is another version of the same problem. Use some common class for those elements that wouldn't hide your div. Hope it will help you:
HTML :
<html>
<body>
<div id="container" style="display:none">
<input type="date" class="prevent-click">
</div>
<button onclick="display()" class="prevent-click">click</button>
</body>
</html>
JS :
var display = function () {
$("#container").toggle();
$("body").off("click").on("click", function (event) {
if ($(event.target).hasClass("prevent-click")) {
return;
}
$("#container").hide();
});
}
I want to do a simple function in Jquery: when a button is clicked show the input text, when it's clicked again- hide the input text.
<div>
<div id="btnNewGroup">New Group</div>
<input type="text" id="newGroup" style="display:none" />
</div>
and this is the scrupt section:
$(document).ready(function () {
$("#btnNewGroup").click(function () {
if ($("#newGroup").hide()) {
$("#newGroup").show();
}
else {
$("#newGroup").hide()
}
});
});
when I click the button the text input is showing, when I click it again I want the input text to be hidden, but nothing happens.
You can use toggle() to show / hide
Live Demo
$("#btnNewGroup").click(function () {
$("#newGroup").toggle();
});
The problem with the condition you have is that you are hiding the element instead of checking if it is hidden. You can is with :hidden like is(':hidden') to check if element is hidden.
if ($("#newGroup").is(':hidden')) {
$("#newGroup").show();
else
$("#newGroup").hide();
if ($("#newGroup").hide())
The hide function does not return a boolean value so you can't use it in an if statement. It returns a jQuery object which is always true so your second block never gets hit.
You can try two things:
$(document).ready(function () {
$("#btnNewGroup").click(function () {
if ($("#newGroup").is(":visible")) {
$("#newGroup").hide();
}
else {
$("#newGroup").show()
}
});
});
Or a simple toggle:
$(document).ready(function () {
$("#btnNewGroup").click(function () {
$("#newGroup").toggle();
});
});
Additionally, when working with selectors multiple times it's a good idea to cache the element - otherwise jQuery tries to find the element each time you try:
$(document).ready(function () {
$("#btnNewGroup").click(function () {
var $newGroup = $("#newGroup"); // Cache it here
if ($newGroup.is(":visible")) {
$newGroup.hide();
}
else {
$newGroup.show()
}
});
});
use .toggle() for hide and show alternatively in jquery
$("#btnNewGroup").click(function () {
$("#newGroup").toggle();
});
Demo
Use .toggle() function
$("#btnNewGroup").click(function () {
$("#newGroup").toggle()
});
Or use :visible pseudo selector with is()
Demo
$(document).ready(function () {
$("#btnNewGroup").click(function () {
if ($("#newGroup").is(":visible")) {
$("#newGroup").hide();
}
else {
$("#newGroup").show()
}
});
});
Note :hide() function does not return boolean value. Use is(:visible) or is(:hidden)
You need to change
if ($("#newGroup").hide()) {
to (just one possible solution)
if ($("#newGroup").css('display')=='none') {
Because $("#newGroup").hide() will always return true.
And here are the full code:
$(document).ready(function () {
$("#btnNewGroup").click(function () {
if ($("#newGroup").css('display')=='none') {
$("#newGroup").show();
}
else {
$("#newGroup").hide()
}
});
});
Have a look at the .toggle() function within the API.
http://api.jquery.com/toggle/
document.getElementById("username").style.display='block';
MY PROBLEM
jQuery(document).ready(function () {
if ($('input.pokazkontakt').prop(':checked')) {
$(this).parent().nextAll('.pkbox:first').css('display', 'block');
} else {
$(this).parent().nextAll('.pkbox:first').css('display', 'none');
}
$('input.pokazkontakt').click(function () {
$(this).parent().nextAll('.pkbox:first').toggle('fast');
});
});
Demo
2nd part of JS is working (toogle), but i want to check first if checkbox is checked and hide the div or show. Where is a problem?
Try this:
jQuery(document).ready(function () {
$('input.pokazkontakt').each(function(){
if ($(this).is(':checked')) {
$(this).parent().nextAll('.pkbox:first').css('display', 'none');
} else {
$(this).parent().nextAll('.pkbox:first').css('display', 'block');
}
});
$('input.pokazkontakt').click(function () {
$(this).parent().nextAll('.pkbox:first').toggle('fast');
});
});
Use your logic reversely when you set display:none and display:block.
Use .is to check for checked state.
Use .each to iterate all your checkboxes
DEMO
You can use .is()
if($('input.pokazkontakt').is(':checked'))
instead of if($('input.pokazkontakt').prop(':checked'))
Demo
CODE:
<script type="text/javascript">
$(document).ready(function() {
$('.show_or_hide_link_clicker').click(function() {
$(".the_box_to_show").fadeIn(400);
});
});
</script>
When show_or_hide_link_clicker is clicked the_box_to_show is shown. How do I hide it if show_or_hide_link_clicker is clicked again or when the user clicks away?
Update: This is what I am doing now: http://jsfiddle.net/nFbnr/
Question: How can i remove the double click requirement ot show the div?
jQuery Toggle is what you're looking for.
$('.the_box_to_show').toggle();
When clicking anywhere, check if the element was on the propagation path. If not, the user clicked outside of it so you can hide it.
$(document).click(function(e) {
if ($(e.target).closest(".the_box_to_show").size() === 0) {
$(".the_box_to_show").hide();
}
});
http://jsfiddle.net/vdHAu/
$(document).click(function(e) {
if (!$(e.target).is(".the_box_to_show")) {
$(".the_box_to_show").hide();
}
});
$('.show_or_hide_link_clicker').click(function() {
$(this).hide();
$(".the_box_to_show").fadeIn(400);
});
An another way without delegate event to document level:
you have to set attribute tabindex to the box and CSS outline for style
http://jsfiddle.net/GV56b/
$(document).ready(function () {
$('.show_or_hide_link_clicker').click(function () {
$(this).hide();
$(".the_box_to_show").fadeIn(400, function () {
this.focus()
});
});
$(".the_box_to_show").on('blur',function(){
$(this).hide();
$('.show_or_hide_link_clicker').fadeIn(400);
});
});
check this out
$('.show_or_hide_link_clicker').click(function() {
$(this).hide();
$(this).addClass('active);
$(".the_box_to_show").fadeIn(400);
});
$(document).on('click', 'html', function(){
$(".the_box_to_show").fadeOut(400);
});
$(document).on('click', '.active', function(e){
e.stopPropagation();
});