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How can I animate/slide a div into view while moving the contents as opposed to just revealing the contents?

I would like to use the jquery slideUp and slideDown methods, but instead of the effect being one of the contents merely being revealed, as though a screen is being pulled back and forth, I would like the contents themselves to slide into view, as though a hidden panel is being pulled back and forth.

If you want to use jQuery animate check this fiddle: http://jsfiddle.net/cgLy77us/1/
Script:
$(document).ready(function(){
var SlideUpAnimate = function(duration, callback){
var $element = $("#slideUp");
var startPosition = $(window).scrollTop() + $(window).height() + $element.height();
var finishPosition = $element.position().top;
$element.css("top", startPosition + "px").show().animate({
top: finishPosition + "px"
},duration, callback);
};
var SlideDownAnimate = function(duration, callback){
var $element = $("#slideUp");
var finishPosition = $(window).scrollTop() + $(window).height() + $element.height();
var startPosition = $element.position().top;
$element.css("top", startPosition + "px").animate({
top: finishPosition + "px"
},duration, function(){
$element.hide();
callback();
});
};
SlideUpAnimate(1000,function(){
//Some callback code here like:
SlideDownAnimate(1000);
});
});
I think you can adapt to every situation.

making a function works on specific widths

I am trying to make this function works only when the screen size is above 1024px.
//Parallax background image
var velocity = 0.5;
function update(){
var pos = $(window).scrollTop();
$('.parallax').each(function() {
var $element = $(this);
var height = $element.height();
$(this).css('background-position', '40%' + Math.round((height - pos) * velocity) + 'px');
});
};$(window).bind('scroll', update); update();
Here is what I have tried to do:
//Parallax background image
var velocity = 0.5;
$(window).on("ready resize", function() {
if ($(window).width() < 770) {
function update(){
var pos = $(window).scrollTop();
$('.parallax').each(function() {
var $element = $(this);
var height = $element.height();
$(this).css('background-position', '40%' + Math.round((height - pos) * velocity) + 'px');
});
};});$(window).bind('scroll', update); update();
I really don't know what I am doing wrong...

You haven't stated what the problem you're coming across is. If it's "my code doesn't work", then perhaps you should check your syntax first. Your braces are messed up.
//Initialize velocity and empty update function
var velocity = 0.5;
var update = function () {};
//When window is ready (content loaded) OR resized, execute the following function
$(window).on("ready resize", function () {
if ($(window).width() >= 1024) { //Check if window width is 1024px wide or larger
update = function () { //Set update to run this function when executed.
var pos = $(window).scrollTop(); //Get scrollbar position https://api.jquery.com/scrollTop/
//For each element with 'parallax' class, execute the following function
$('.parallax').each(function () {
var $element = $(this); //Get the current parallax-classed element
var height = $element.height(); //Save the current height of this element
//Set the CSS of this parallax-classed element set the background position
$(this).css('background-position', '40% + ' + Math.round((height - pos) * velocity) + 'px');
});
};
} else { //Execute if screen width is < 1024px
update = function () {}; //Set update to do nothing
}
});
//When window is scrolled through, run the update function
$(window).bind('scroll', update);
//update();
Last line is unnecessary, as resize will handle function value, and scroll will handle the execution.
You were missing a + or - within the background-position setting.
So for example, if the result of your Math.round() was "30", then Javascript would interpret that line as $(this).css('background-position', '40%30px'); which obviously would cause issues. I'm sure you wanted it to say something like $(this).css('background-position', '40% + 30px');.

Having issues with mousemove and images in Jquery

How can I make the other images also follow the mouse? Not all at the same time, but when I click on the selected image.
How can I calculate the distance where the mouse moved when I click on the image?
See link below.
HTML:
<div id="squarelocation"></div>
<div class="square 1">1</div>
<div class="square 2">2</div>
<div class="square 3">3</div>
Jquery:
$(document).ready(function () {
var i = true;
$(document).on('click', function () {
$(this)[i ? 'on' : 'off']('mousemove', follow);
i = !i;
});
function follow(e) {
var xPos = e.pageX;
var yPos = e.pageY;
$("#squarelocation").html("The square is at: " + xPos + ", " + yPos + "pixels");
$(".2").offset({
left: e.pageX,
top: e.pageY
});
}
});

I suggest you to bind a click event to the square class like this:
var clickedImage;
$('.square').click(function (e){
initialX = e.pageX;
initialY = e.pageY;
clickedImage = this;
});
and assign the context to a variable, so that you can refer to it whenever you needed. And then in your code, refer to that context instead of the hardcoded '.2':
$(clickedImage).offset({
left: e.pageX,
top: e.pageY
});
This way, the image clicked will be referred to, instead of just '2' following the mouse all the time.
Same for calculating the distance between the clicked origin and the current position, you can save the original spot on clicking the image:
var initialX;
var initialY;
$('.square').click(function (e){
initialX = e.pageX;
initialY = e.pageY;
clickedImage = this;
});
and do the calculation in the 'follow' function, of course how the calculation should be is up to you, but here is an example:
var distanceX = xPos - initialX;
var distanceY = yPos - initialY;
$("#squarelocation").html("The square is at: " + xPos + ", " + yPos + "pixels");
$('#squaredistance').html("Distance from origin: " + distanceX + ", " + distanceY);
Hope this help. jsfiddle: http://jsfiddle.net/FW9jV/1/

You could add an 'active' class for the active square. I added an example.
The active square will always be moving until you click to deactivate it.
http://jsfiddle.net/fG6kr/1/
$(document).ready(function () {
var i = true;
$('.square').on('click', function () {
if( $(this).hasClass("active"))
{
$(this).removeClass("active");
$(document).off('mousemove');
}
else
{
$(this).addClass("active");
$(document).on('mousemove', follow);
}
});
function follow(e) {
var xPos = e.pageX;
var yPos = e.pageY;
$("#squarelocation").html("The square is at: " + xPos + ", " + yPos + "pixels");
$('.active').offset({
left: e.pageX,
top: e.pageY
});
}
});

demo
$(function() {
$('.square').click(function(){
$(this).toggleClass('sel');
});
$(document).on('mousemove', function(e){
$(".sel").offset({left: e.pageX+10, top: e.pageY+10});
});
});

Centering Special Javascript Popup, How?

I have this javascript code, lib.js. It manages my every java popup in my site. How ever it is not set to be appear absolutely centered in page, I have tried several css codes for its div. But it did not work. I also tried the famous /2 code but it didnt work or I might have added it to wrong place.
Below is my lib.js:
var currentTime = new Date();
var topP = 0;
$(document, window).keypress(function(e){
if (e.keyCode == 27){
$(".yekbox").fadeOut();
$("#yekbox_overlay").hide();
}
});
$(document).ready(function() {
$(".showme").unbind().hover(
function(e) {
$(".tooltip").remove();
this.t = $(this).next(".description").html();
$(this).append( '<div class="tooltip">' + this.t + '</div>' );
},
function() {
//this.title = this.t;
$(".tooltip").remove();
}
).mousemove(
function(e) {
$(".tooltip").css({
"top" : e.pageY + 20,
"left" : e.pageX + 20
});
}
);
topP = $(this).scrollTop();
//$(".yekbox").css("top", $(window).height()-250 + "px");
//$(".yekbox").css("left", $(window).width()-(440*2) + "px");
$("#yekbox_overlay").css("height", $(window).height());
$(window, document).resize(function(){
topP = $(this).scrollTop();
$(".yekbox").css("marginTop", topP-250 + "px");
if ($(window).width() > 900 ) $(".yekbox").css("left", $(window).width()-(440*2) + "px");
$(".yekbox").css("marginLeft", "auto");
$(".yekbox").css("marginRight", "auto");
$("#yekbox_overlay").css("height", $(window).height());
});
$(window).scroll(function () {
topP = $(this).scrollTop();
$(".yekbox:visible").css("marginTop", topP-250 + "px");
$("#yekbox_overlay:visible").css("height", $(window).height());
});
$(window).bind("scroll",function () {
topP = $(this).scrollTop();
$(".yekbox:visible").css("marginTop", topP-250 + "px");
$("#yekbox_overlay:visible").css("height", $(window).height());
});
$("#yekbox_overlay").click(function(){
$(".yekbox").fadeOut();
$(this).hide();
return false;
});

The JS and HTML code above doesn't help in anything.
In general, if you want a block to be centered to the parent, it should have
A fixed width
margin: auto
If you want a block absolutely centered (position absolute or fixed)
$('#mypopup').css('left', ($(window).width() - $('#mypopup').width()) / 2)

Jquery slider help

ok so i have an interspire shopping cart so its hard to customize..
anyway,
here is a link to my code
http://jsfiddle.net/WTvQX/
im having trouble getting the scroll to work properly...
it works differently on my actual site here...
so i need help... re-doing it or just fixing..
let me kno

You need to add the "relatedLeft" ID to the left button, however try something like this...
Demo: http://jsfiddle.net/wdm954/WTvQX/3/
$('#relatedRight').click(function() {
$('#scool').animate({left: "+=100px"}, 'slow');
});
$('#relatedLeft').click(function() {
$('#scool').animate({left: "-=100px"}, 'slow');
});
You can adjust pixel distance and speed to your liking.
EDIT: Try something like this. The first part finds the width of all the images. Then the animates only fire when the offset is within range.
Demo: http://jsfiddle.net/wdm954/WTvQX/5/
var w = 0;
$('#scroll img').each(function (i, val) {
w += $(this).width();
});
$('#relatedRight').click(function() {
var offset = $('#scroll').offset();
if (offset.left < w) {
$('#scroll').animate({left: "+=100px"}, 'slow');
}
});
$('#relatedLeft').click(function() {
var offset = $('#scroll').offset();
if (offset.left > -w) {
$('#scroll').animate({left: "-=100px"}, 'slow');
}
});
EDIT: One more code option here. This one will stop scrolling sooner (note there are CSS changes here also).
Demo: http://jsfiddle.net/wdm954/WTvQX/7/
var w = 0;
$('#scroll img').each(function (i, val) {
w += $(this).width();
w += parseFloat($(this).css('paddingRight'));
w += parseFloat($(this).css('paddingLeft'));
w += parseFloat($(this).css('marginRight'));
w += parseFloat($(this).css('marginLeft'));
});
$('#scroll').css('width', w + 'px');
$('#relatedRight').click(function() {
var offset = $('#scroll').offset();
if (offset.left < 0) {
$('#scroll').stop().animate({left: "+=100px"}, 'slow');
}
});
$('#relatedLeft').click(function() {
var offset = $('#scroll').offset();
var b = $('#bar').width();
if (offset.left > b-w) {
$('#scroll').stop().animate({left: "-=100px"}, 'slow');
}
});