I need your help at a problem of my Wordpress Webpage. My Wordpress-page is an Single-Page-App with 3 different boxes of content. The left and center boxes are static, the right one changes its content by clicking on links of the other boxes. I decided, to load all the content in the right box and show them with the CSS-command visibility. With a combination of pathJS and JS, i want the URL to change by clicking on the links. So far so good - all works fine, but i dont get managed via my JS-Function to remove the shown-class.
My script looks like this:
<script>
function showDetailContent(showid) {
//suche objekt right_id -> was du zeigen willst -> getelementbyid
alert("1");
var id = document.getElementsByClassName('shown');
alert("2");
id.classList.remove('shown');
alert("3");
document.getElementByID("right_" + showid).classList.add('shown');
alert("4");
}
//var c = document.getElementById('content'); -->do the function :)
Path.map("#/?p=<?php the_id();?>").to(function () {
showDetailContent(<?php the_id();?>);
});
Path.listen();
</script>
The alerts are just my way of "debugging". I think its not the best way to debugg, but i am very new in the world of prorgamming and this is kind of easy.
However, the first two alerts are shown, if i activate a link. So the (first) mistake is on the line
id.classList.remove('shown');
Normally, the right-box is hidden, so that only one content is load.
Do you understand my problem till here?
I would appreciate fast help!
Greetings, Yannic! :)
Look at this : http://snipplr.com/view/3561/ to know remove class pure javascript
getElementsByClassName gets multiple elements, try:
var id = document.getElementsByClassName('shown')[0];
Or iterate through them if you want to remove class from all elements with class shown;
Related
I've got a problem where all the dynamic links on my homepage have "#comments" at the end, making it so when the user clicks their screen is annoyingly jolted down to the 'Comments' section each time rather than staying on top.
Example URL:
https://example.com/441447279/amazing-art/#comments
Is there a way to dynamically strip them of the 'comments' part via jQUery?
They're always the SECOND link in a unique class <p class="g1-meta entry-meta entry-byline entry-byline-s entry-byline-with-avatar">
so I was thinking something like
var linkURL = $(".g1-meta.entry-meta.entry-byline.entry-byline-s.entry-byline-with-avatar").find("a").prop('href');
but I don't know how to make it retrieve the SECOND link instead of the 1st.
And I don't know where to go from there... Help appreciated.
Use this
//The key here is to use nth-of-type selector
$(".g1-meta.entry-meta.entry-byline.entry-byline-s.entry-byline-with-avatar").find("a:nth-of-type(2)").each(function(){
let link = $(this).prop('href').replace('#comments','');
$(this).prop('href',link)
})
Or without jQuery
Array.from(document.querySelectorAll('.g1-meta.entry-meta.entry-byline.entry-byline-with-avatar')).forEach(function(node){
let anchorNode = node.querySelectorAll('a')[1];
anchorNode.href= anchorNode.href.replace('#comments','');
})
After much Googling, I resort to the chance at ridicule and moderation on Stack Exchange.
What I am trying to do sounds simple enough. I want to make a <div> id/class that will link automatically create a link to itself via some kind of scripting.
Let me put down some pseudocode, before I make it sound more complicated than it is:
#Let div.link = xxx.html
#Let div.pic = xxx.png/jpg
for div in HTMLdocument:
if div.class == "autolink":
div = "<img src=\"mysite/" + div.pic + ">"
Now, obviously that's Python pseudocode, but I am familiar(ish) with PHP and Javascript. Basically, I want to make the div generate an HTML link without having to actually type out the tags and links for every given div on a web page. I want to be able to type, in my index.html:
<html>
<head></head>
<body>
<div class = "1"></div>
<div class = "2"></div>
</body>
</html>
and then to be presented with a page that has the two divs linked, imaged, and, preferably, formatted.
Like I said, the problem seems simple, but I can't seem to get it to work right, in any language. This seems like a thing that would be very useful for begiiner web designers.
PERSONAL NOTE:
I would preferably like to see a solution in PHP or Javascript, but if you are good with Django and want to show me how to get it done in that, I would be just as grateful!
=========================================
EXAMPLE:
Let's say you have a browser based RPG, and you want to show your player's inventory. The Inventory page would display the items in a players inventory, complete with a link and image, based on whatever was in that user's inventory page. It would look like this (this is VERY rough output, Statements tagged in #these# are not code, and should be interpereted as what they describe):
<h1>User's Inventory:</h1>
<p><div class = "item_1">#Link to page of 'item_1', image of 'item_1'#</div></p>
<p><div class = "item_2">#Link to page of 'item_2', image of 'item_2'#</div></p>
The above would display, roughly, a header that said "User's Inventory", and then display a linked image of item_1, followed by a newline and then a linked image of item_2, where said items would be in a separate file OR a list that lists all the items and their respective links and images.
You can use jquery, and when page dom is loaded, you cycle through each div that has the class autolink and do your manipulations (add your desired html into each div). You can use the id of each div to place data inside. You can use a prefix to that id values for different types of data. For example, im using "inventory_" as a prefix.
<h1>User's Inventory:</h1>
<p><div class = "autolink" id="inventory_item_1">#Link to page of 'item_1', image of 'item_1'#</div></p>
<p><div class = "autolink" id="inventory_item_1">#Link to page of 'item_2', image of 'item_2'#</div></p>
then jquery on document ready:
<script type="text/javascript">
$(document).ready(function ()
{
// define your website here
var mysite = "http://www.example.com/";
// this will cycle through each div with class autolink. using `this` to reffer to each.
$(".autolink").each(function () {
// we get for div with id="inventory_item_1" ...
var mylink = $(this).attr('id').replace("inventory_",""); // ... a value item_1
var myimagesrc = $(this).attr('id').replace("inventory_","image_"); // ... image_item_1
$(this).html('<img src="'+mysite+'images/'+myimagesrc+'.jpg">');
// the above will add html code of this format:
// <img src="http://www.example.com/images/image_item_1.jpg">
});
});
</script>
try it here:
http://jsfiddle.net/5APhT/2/
I'll give a sample in php. Here is an example if you already have a set of links to use
<?php
//Create a multidimensional array to store all you need to create links
$links['1'][]="http://www.yahoo.com";
$links['1'][]="yahoo.com";
$links['2'][]="http://www.facebook.com";
$links['2'][]="yahoo.com";
$links['3'][]="http://www.google.com";
$links['3'][]="yahoo.com";
foreach($links as $class => $innerArray){
$link=innerArray[0];
$linktext=innerArray[1];
echo "<div class='$class'><a href='$link'>$linktext</a></div>";
}
?>
This creates the divs for you so you don't have to add them in advance.
You can add images in the same manner
AJAX content is being rendered with a remoteLink function inside the form to populate a accordion (just a little background info).
The function attatchEmail(test) which is being called on the double-click of each paragraph content of the JQuery Accordion widget. This is what happens running the function... Screenshot of 1st alert & Screenshot of 2nd alert.
Is it not possible to select the paragraph and get the contents from the paragraph like below?
(I have tried changing .val to .html and .text. I have also tried $('#'+testingID))
_form.GSP
function attatchEmail(test) {
$(document).ready(function()
{
var testingID = test.id;
alert(testingID);
var testingValue = $(testingID).val();
alert(testingValue);
});
};
_contactListAjax.GSP
<g:each in="${contactList}" status = "i" var="contact">
<h3>${contact.contactSurname +', '+ contact.contactForename}</h3>
<div><p id="contact${contact.id}" ondblclick="attatchEmail(this)">${'Email: '+contact.email}</p></div>
</g:each>
Run out of avenues to explore, I'm sure I've done something simple like this before perfectly fine :/
See two screenshots please for better insight, thanks
Well, it looks like you're using jQuery but it also looks like you're not really buying into the jQuery methodology. Mixing behavior with markup is not really considered a good practice these days, especially when using a library like jQuery. I'm not sure of your exact issue but I would recommend changing it to something like the following:
<g:each in="${contactList}" status = "i" var="contact">
<h3>${contact.contactSurname +', '+ contact.contactForename}</h3>
<div><p class="contact-email" data-id="${contact.id}">${'Email: '+contact.email}</p></div>
</g:each>
$(function() {
$("body").on("dblclick", ".contact-email", attachEmail);
});
function attatchEmail(event) {
var $element = $(event.target);
var id = $element.data("id");
};
This should help fix any issues with dynamic rendering because of the way the jQuery on function works.
I am creating two divs:
var div_day=document.createElement("div");
var div_dateValue=document.createElement("div");
I then want to add div_day to an existing calendar div and div_dateValue to div_day:
$('#calendar').append(div_day)
$(div_day).append(div_dateValue);
div_day gets added to calendar, but div_dateValue does not get added to div_day, and the script stops there. No errors in the console but it is in a loop and should have more div_days (each with a unique id). I am new to jquery so any help is appreciated.
In my search I have found how to add divs, but not to add a dynamically created div to another dynamically created div.
Thanks for your help!
Kevin
div_day.appendChild(div_dateValue)
$('#calendar').append(div_day)
Something else must be going on (even with your missing semi-colon). Your example works fine here:
http://jsfiddle.net/P4rh5/
But, instead of creating divs with straight javascript, you can do it with jQuery:
var div_day = $("<div>");
var div_dateValue = $("<div>");
$('#calendar').append(div_day);
$(div_day).append(div_dateValue);
Of course, you could do this in a single step:
$('#calendar').append("<div><div></div></div>");
$('<div><div></div></div>').appendTo("#calendar");
Try this and mark it as answer if it helps
I am trying to create an image gallery, I am using numbers instead of left/right arrows. At the moment, I am trying to get it working with only 2 image (i.g 2 numbers)
this is the html . the id page, is the highlighted number
<div class="grid_1 pagelink" id="page"><p>1</p></div>
<div class="grid_1 pagelink"><p>2</p></div>
the first time the page loads, the code below works. so when I click on link 2 the the code bellow runs fine. But then I want the same code to be triggered when I click back on the first link; but when I do that, the page refreshes by ignoring the code bellow:
$('.pagelink').live('click', function(e){
e.preventDefault();
var frame = $(this).text() - 1;
var frames = 240 * frame;
// $('#gal').animate({marginLeft:'500px'},'slow');
$('#gal').animate({marginLeft: "+="+frames+'px'},'slow');
$(this).attr('id', 'page').removeClass('pagelink');
$('#page').addClass('pagelink').removeAttr('id','page');
// $('#book').animate({ left: '50' });
})
I thought that the .live() would do that for me but it is not working.
I hope you could help
thank you
Previous, this is because you are removing the class of link "pagelink" which were used to map the clicked event.
Also, use another class instead of id(#page) to identify the #page link, id might be problem if its already assign to other link. like
$(this).removeClass('pagelink').addClass('page');
$('.page').addClass('pagelink').removeClass('page');
live should work fine. i think you have a bug in your code, and its probably here:
$(this).attr('id', 'page').removeClass('pagelink');
$('#page').addClass('pagelink').removeAttr('id','page');
what exactly are you trying to accomplish with this code?
when you click on page2, the you set the div's id to be page, but now you have 2 elements with an id of page, and when you select that id, you get the first one (ie page1), but you still remove the class pagelink from page2
in other words, the bug is that at some point you will have 2 elements with the same id (and ids must be unique btw) so when you select that id with $('#page') you always get the first one