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jQuery actions independent of id

I have a working web page, but I would like to generalize the code. When one clicks a link with e.g. anchor #11 or #12, a div called #t11 or #t12 will open (or close) with this piece of script:
Script
$( "#11" ).click(function() {
$( "#t11" ).toggle();
});
$( "#12" ).click(function() {
$( "#t12" ).toggle();
});
Stripped HTML
<div class="a">
<table>
<tr><td><a id="11">Foo</a></td></tr>
<tr><td>Find out more about Foo</td></tr>
</table>
</div>
<div class="a">
<table>
<tr><td><a id="12">Bar</a></td></tr>
<tr><td>Find out more about Bar</td></tr>
</table>
</div>
<div class="b" id="t11">
<p>More info about Foo</p>
</div>
<div class="b" id="t12">
<p>More info about Bar</p>
</div>
Relevant CSS
.b {
display: none;
}
This is fine, however, with over 20 divs it's getting complicated and difficult to maintain. Is there a way to reduce the code, so every id in <a> will toggle its <div>? I've been struggling with $this but without the result I hoped for.

You can use a selector that will match all appropriate <a> elements, so that your click function will be applied to all of them. Then, you can get the id attribute from your <a> tag using $(this).attr('id'). You can then form a selector that matches the corresponding id of the content you want to toggle, then call the .toggle() method using that selector.
$('.a table tr td a').click(function() {
var id = $(this).attr('id');
var selector = '#t' + id;
$(selector).toggle();
});
.b {
display: none;
}
a:hover {
cursor: pointer;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="a">
<table>
<tr>
<td><a id="11">Foo</a>
</td>
</tr>
<tr>
<td>Find out more about Foo</td>
</tr>
</table>
</div>
<div class="a">
<table>
<tr>
<td><a id="12">Bar</a>
</td>
</tr>
<tr>
<td>Find out more about Bar</td>
</tr>
</table>
</div>
<div class="b" id="t11">
<p>More info about Foo</p>
</div>
<div class="b" id="t12">
<p>More info about Bar</p>
</div>
EDIT
You may also consider adding a class to your actual <a> tags, as mentioned by #Lelio Faieta.
In the above example, if the structure of your html changes, the $('.a table tr td a') selector will break, and the click functionality will be lost.
If, however, you assign a class of, say toggler to each <a> tag, then you can just replace the $('.a table tr td a') selector with $('.toggler') and your click functionality will still work if you change the location of your <a> tags in your html.
$('.toggler').click(function() {
var id = $(this).attr('id');
var selector = '#t' + id;
$(selector).toggle();
});
.b {
display: none;
}
a:hover {
cursor: pointer;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="a">
<table>
<tr>
<td><a id="11" class="toggler">Foo</a>
</td>
</tr>
<tr>
<td>Find out more about Foo</td>
</tr>
</table>
</div>
<div class="a">
<table>
<tr>
<td><a id="12" class="toggler">Bar</a>
</td>
</tr>
<tr>
<td>Find out more about Bar</td>
</tr>
</table>
</div>
<div class="b" id="t11">
<p>More info about Foo</p>
</div>
<div class="b" id="t12">
<p>More info about Bar</p>
</div>

You can use classes to group elements in jquery.
A class is referenced like id but with a dot instead of a dash:
$('.someClass')
where you used to write
$('#anID')
Many objects can share the same class so you can both use classes to target an animation to multiple objects at the same time or to use different element on the DOM to fire an animation

The best way to solve this is by adding a common class to all a tag and performing event with that class.
<a class="atag" id="11">
<a class="atag" id="12">
$(".atag").click(function() {
var id=$(this).attr("id");
$(body).find("#"+id).toggle();
});

How to show different images using .hover() jQuery

I'm gonna try to explain my issue:
I have span elements, each span element have text, when the user hovers it, it should displays an image next to the element, each image is different, I was trying to use jQuery .hover() function, but when I hover on the text it shows me the whole images.
How can I solve it?.
My HTML.
<table>
<tbody>
<tr>
<td style="width: 20%;" class="text-center">
<span class="displayImage">Azotea </span>
<span class="displayImage">Nivel 8 </span>>
</td>
</tr>
</tbody>
</table>
<div class="col-lg-5 text-left">
<img class="displayed" src="images/azotea-n9.jpg" alt="">
<img class="displayed" src="images/test2.jpg" alt="">
</div>
My Code.
$(".displayImage").hover(function(){
$(".displayed").show();
}, function () {
$(".displayed").hide();
});
Thanks!.

You could associate the span with a particular image via a data attribute and id.
$(".displayImage").hover(function(){
// $(this).attr('data-img') == 'azotea' or 'nivel8'
// so we end up with $('#azotea').show(), for example.
$('#' + $(this).attr('data-img')).show();
}, function () {
$('#' + $(this).attr('data-img')).hide();
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
<tbody>
<tr>
<td style="width: 20%;" class="text-center">
<span class="displayImage" data-img='azotea'>Azotea </span>
<span class="displayImage" data-img='nivel8'>Nivel 8 </span>
</td>
</tr>
</tbody>
</table>
<div class="col-lg-5 text-left">
<img class="displayed" src="images/azotea-n9.jpg" alt="azotea" id="azotea">
<img class="displayed" src="images/test2.jpg" alt="nivel 8" id="nivel8">
</div>

I try don´t change your html
https://jsfiddle.net/luarmr/hjreda3r/
I add a little css as well for hide the elements from the origin
$(".displayImage").hover(
function(el){
var image = $(this).data('ref');
$(".displayed:nth-child(" + image + ")").show();
}, function () {
$(".displayed").hide();
}
);

I would suggest you to better use css3 instead of jquery, cos jquery slows down productivity of your site on mobile gadgets, so maybe you should look here enter link description here

You need to find common ground between your span & image and without adding anything extra in your markup, that would be the index value of each of them. Obviously, this solution that I recommend below is entirely dependant on the order with which you lay out your HTML.
Take a look at this solution I posted for a similar problem.
So basically, your code should become something like this:
$(".displayed").hide();
$(".displayImage").hover(function(){
$(".displayed").eq($(this).index()).show();
},function(){
$(".displayed").eq($(this).index()).hide();
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<table>
<tbody>
<tr>
<td style="width: 20%;" class="text-center">
<span class="displayImage">Azotea </span>
<span class="displayImage">Nivel 8 </span>
</td>
</tr>
</tbody>
</table>
<div class="col-lg-5 text-left">
<img class="displayed" src="https://dl.dropboxusercontent.com/u/45891870/Experiments/Codepen/PIXI/0.4/images/JS.jpg" alt="">
<img class="displayed" src="https://dl.dropboxusercontent.com/u/45891870/Experiments/Codepen/PIXI/0.4/images/PIXI.jpg" alt="">
</div>
Hope it helps in some way.
T

Making a menu appear and disappear by clicking the same icon

I'm trying to make a standard hamburger icon on a phone show a menu when clicked and make the menu disappear when clicked again. What I have does make the menu appear but not disappear when clicked again. This code doesn't seem to be doing it:
Javascript/Jquery:
<script>
function show( elem )
{
var n=$(elem).is(":visible");
if (n==false){
$('#'+elem).show();
}
if (n==true) {
$('#'+elem).hide();
}
}
</script>
HTML/PHP
<table align="center"><tr><td><img src="images/hamburger.png"> </td></tr></table>
<div id="link1" class="dynamic_link" style="display:none">
<?php
phoneMenu();
?>
</div>

Try utilizing .toggle()
// added `foodicon` `id` to `img`,
// removed `onclick` from `html`
$("#foodicon").on("click", function() {
$("#link1").toggle()
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js">
</script>
<table align="center">
<tr>
<td>
<a href="#">
<!-- assign `foodicon` `id` to `img` -->
<img id="foodicon" src="http://lorempixel.com/100/100/food">
</a>
</td>
</tr>
</table>
<div id="link1" class="dynamic_link" style="display:none">
food menu
</div>

jQuery last child selector

This is not working and I don't know why. I have tried it in the console it works, but when I change my js codes it does not work.
$('#recipe-table td:last-child').width();
How can I get it the correct way?
this is the html
<div id="div-lists">
<div id="div-recipe-table">
<table class="" id="recipe-table" cellspacing="0" cellpadding="0">
<tbody>
<tr class="recipe-list" data-ng-repeat="recipe in recipe_data" ng-click="recipe_click(recipe.CodeListe,recipe.Name)">
<td id="td-img{{recipe.CodeListe}}">
<center>
<span id="img{{recipe.ID}}X">
<a id="{{recipe.ID}}" href="javascript:void(0);">
<img ng-if="recipe.Pictures !==''" fallback-src="images/default.png" ng-src="{{recipe.Pictures}}" class="images" id="img{{recipe.ID}}"/><img ng-if="recipe.Pictures===''" class="images" src="images/default.png" id="img1"/>
</a>
</span>
</center>
</td>
<!-- I want to get The width of this <td> -->
<td class="recipes">
<div id="div-recipe-name">
<strong>{{recipe.Name}}</strong></div>
</td>
<!-- Until here
I already tried using $('.recipes').width(); but it returns 0 -->
</tr>
</tbody>
</table>
</div>
<div id="div-list-loading"></div>
<div id="div-list-noresults">{{ui_translation.UIT[171610]}}</div>
</div>
</div>

Try the following:
$('#recipe-table td:last').width();
From the jQuery Docs
While :last matches only a single element, :last-child can match more
than one: one for each parent.
Since you have already tried $('.recipes').width(); does the following provide you any results:
$('.recipes').each(function (index, elem) {
alert($(this).width());
});

Try below jQuery
You can use .last() method constructs a new jQuery object from the last element in that set.
$('#recipe-table td').last().width();
JSFIDDLE DEMO

Can`t seem to make the selector select right

<div class="form_div">
<form name="first" class="dirs" method="post" action="">
<table>
<tr>
<td>
<img src="path..." class="info">
<div class="tip">
<p>Some text</p>
</div>
</td>
</tr>
</table>
</form>
</div>
<script type="text/javascript">
$(document).ready(function() {
$(".info").tip({ effect : 'slide'});
});
</script>
I want to select the div with the class tip and img tag class info from the div > form > table > tr > td. But i can't select it with the function i have in the script.
The selector doesn't find the img tag and the div with the class tip.
Am i going wrong somewhere?

Use this :
$(".info, .tip")
Its a multiple selector.
And look at .slideDown(), .slideUp() and .slideToggle()

Try to put your javascript code at the top of the body