I have a side nav with dots (each of these dots on click scrolls to anchor down the page).
For accessibility purposes, I'd like users to be able to tab through the dots. I have set up a <span> element to wrap the anchors of each dot and the tabindex works fine, however..
I'd like the click event to be fired when they tab on the nav element. ie: If they tab to dot 2 it should imitate a click event so it takes them to that anchor.
Possible?
If I understand correctly, I think that you should be able to solve your problem by listening for the "focus" event on the dots and simulating a click on the dot when you receive it. There are several ways to do this, depending on what frameworks (if any) you are using. For example, if you are working with jQuery and the dots are identified by having the "dot" class:
$('.dot').focus(function(e) {
e.target.click();
}
Here's a small test page that I put together - it seemed to work in both IE10 and Chrome:
<html>
<head>
<script type="text/javascript">
function handleOnLoad() {
var elems = document.getElementsByTagName("span");
var i;
for (i = 0; i < elems.length; ++i) {
elems[i].onfocus = function(event) {
if (event.target) {
event.target.firstChild.firstChild.click();
}
else if (event.srcElement) {
event.srcElement.firstChild.firstChild.click();
}
}
}
}
</script>
</head>
<body onload="handleOnLoad()">
<span class="focus" tabindex="1"><ul class="inactive" tag="scroller">Foo</ul></span>
<span class="focus" tabindex="2"><ul class="inactive" tag="scroller">Bar</ul></span>
<span class="focus" tabindex="3"><ul class="inactive" tag="scroller">Baz</ul></span>
<span class="focus" tabindex="4"><ul class="inactive" tag="scroller">Ban</ul></span>
</body>
</html>
Related
I want to display a <div> block when mouse enters an element
My code so far:
<div class="dropdown">
MEN
<div class="dropdowncontent" id="ddmen" style="margin-left:100px;">
TOPWEAR <br/>
BOTTOMWEAR </br>
FOOTWEAR
</div>
</div>
JavaScript Code:
var ddm=document.getElementById("ddmen")
function ddmenin()
{
ddm.style.display="block";
}
function ddmenout()
{
ddm.style.display="none";
}
But when i hover over <a href="#men"> I cannot click on the links in the <div> with class="dropdowncontent" as the block disappears when i leave the <a href="#men">
I don't understand why this is happening since i have used onmouseover, which is valid even for child elements.
I have tried doing it using css but for some reason the following does not work (Style.css is used in above html)
STYLE.CSS
.dropdowncontent{
display:none;
}
.dropdown:hover .dropdowncontent{display:block;}
Can someone please correct my code to satisfy my needs or has any other simple alternative?
Well, your div link container is not part of a link, so when you move cursor to dropdown menu you leave the link and onmouseout listener does its job.
What you want is to hide the menu when it's not needed anymore. E.g. you clicked on the menu item or you left the menu and didn't return for some time.
To achieve this you can do the following:
Add hiding the menu to click listener on menu items
Add a function that starts some timer as soon as you leave the dropdown button or the menu (so that makes two onmouseout listeners). If you return there, you can reset the timer in onmouseover. When timer is done you can hide the menu.
It can look like this:
const $ = document.querySelector;
let menuTimeoutId;
const menu = $('#ddmen');
function stopMenuTimeoutAndShowMenu() {
if (menuTimeoutId) {
clearTimeout(menuTimeoutId);
menuTimeoutId = null;
}
menu.style.display = 'block';
}
function startMenuTimeout() {
window.menuTimeoutId = setTimeout(() => {
menu.style.display = 'none';
}, 2000); // possible timeout value
}
$('#men, #ddmen').addEventListener('onmouseover', stopMenuTimeoutAndShowMenu);
$('#men, #ddmen').addEventListener('onmouseout', startMenuTimeout);
I think you should use the onmouseover and onmouseout in your <div class="dropdown"> instead. Because, when you go to the div.dropdowncontent you probably invokes the onmouseout event. So the code will be like this:
<div class="dropdown" onmouseover="ddmenin()" onmouseout="ddmenout()">
MEN
<div class="dropdowncontent" id="ddmen" style="margin-left:100px;">
TOPWEAR <br/>
BOTTOMWEAR </br>
FOOTWEAR
</div>
</div>
See if it works ;D
You can try simple CSS changes, that can even help you :
In your Style.css file:
.dropdown .dropdowncontent {
visibility: hidden;
}
.dropdown:hover .dropdowncontent {
visibility: visible;
}
I'm in the process of learning Javascript and I'm trying to create a simple dropdown menu. An example of my desired functionality can be seen on the google homepage in the top menu with the "more" and "settings" dropdown. Specifically when you click off the menu, the menu disappears.
What code do I need to place in the hideMenus function in Javascript to hide the visible uls when a click occurs anywhere on screen?
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta content="text/html; charset=utf-8" http-equiv="Content-Type" />
<title>Untitled 1</title>
<style type="text/css">
a
{
color:blue;
}
.info ul.submenu
{
border: solid 1px #e0e0e0;
background-color: #fff;
position: absolute;
padding: 0;
z-index: 2;
display: none;
}
.info ul.submenu li
{
display: block;
border-top: solid 1px #e0e0e0;
margin: 0px 10px 0 10px;
}
.info ul.submenu li a
{
display: block;
padding: 7px 0px 6px 0;
color: #1177ee;
cursor:pointer;
}
</style>
<script type="text/javascript">
function hideMenus()
{
//TODO
}
function menu(id) {
var myLayer = document.getElementById(id);
myLayer.onblur = function() {
myLayer.style.display = 'none';
};
if (myLayer.style.display == "none" || myLayer.style.display == "") {
myLayer.style.display = "block";
} else {
myLayer.style.display = "none";
}
}
</script>
</head>
<body onclick="hideMenus();">
<div class="info">
Some Text Boom A <a onclick="menu('id1');">Link</a> | More text
<a onclick="menu('id2');">Another Link</a> | more text
<ul id="id1" class="submenu">
<li>A1</li>
<li>A2 This is Long</li>
<li>A3</li>
</ul>
<ul id="id2" class="submenu">
<li>B1</li>
<li>B2</li>
<li>B3</li>
</ul>
</div>
</body>
</html>
I do not want to use jQuery.
It looks like you have a pretty decent setup as-is. You'll likely run into some event bubbling problems (for more info, take a look at PPK's Event Order Article). That seems to be outside of the scope of your current question, so I'll just give you what you asked for:
hideMenus()
{
var uls = document.getElementsByTagName('ul'), i;
for (i = 0; i < uls.length; i++)
{
if (uls[i].className === 'submenu' && uls[i].style.display !== 'none')
{
uls[i].style.display = 'none';
}
}
}
First, we get all the <ul>'s on the page. Then, we loop through all of them, check to see if it's a submenu, and if it's currently displayed. If both are true, then we hide it.
There are a couple faults with this code:
If the uls have more than one class (class="animal submenu"), then it will not hide the menu
It will look through all the <ul>'s on the page. This isn't exactly efficient, but it's the only way to do it without cross-browser support for getElementsByClass.
These aren't huge faults, especially if you're only using this to learn about javascript, and if you closely control your code (i.e. no other developers are working on it). All in all, it's a good stepping stone.
In the future, I'd suggest using addEvent - a fairly common function that allows you to add event handlers to elements without using onclick="...". There are a couple different implementations of it, but they (almost) all work the same from your perspective. Here are links to Dean Edwards's Version and John Resig's Version
Good luck!
Here is more or less the logic we use in our web app for drop down menus:
<html>
<head>
<title></title>
</head>
<body>
<div style="position:relative;width:250px">
<a id="link" href="javascript:" onclick="showDiv(this)">Show menu</a>
<ul id="entries" style="display:none;background:#DEF;padding:0;margin:0">
<li>item 1</li>
<li>item 2</li>
</ul>
<input id="inp" style="position:absolute;left:-30px;width:0" />
</div>
<script>
function showDiv(lnk){
var entries = document.getElementById('entries'),
inp = document.getElementById('inp'),
nh = 'data-nohide';
//show the entries
entries.style.display = 'block';
entries.removeAttribute(nh);
inp.focus();
//if mouse over, can't close it
entries.onmouseover = function(){
this.setAttribute(nh, true);
inp.focus();
};
//if mouse out, can close it
entries.onmouseout = function(){
this.removeAttribute(nh);
};
entries.onclick = function(e){
//code when the user clicks on the menu...
alert((e.target||e.sourceElement).innerHTML);
this.style.display = 'none';
};
//if the user press ESC
inp.onkeyup = function(e){
if(e.keyCode === 27){
this.style.display = 'none';
this.removeAttribute(nh);
}else{
//do something else with other keys(ie:down, up, enter)...
inp.focus();
}
};
//click somewhere else input onblur
inp.onblur = function(){
if(!entries.getAttribute(nh)){
entries.style.display = 'none';
entries = inp = null;
}
};
}
</script>
</body>
</html>
The trick is to use an input field that has the focus, and when it looses it an onblur is triggered and close the menu.
The mouseover, mouseout are there to prevent the onblur to fire when the user click an item in the menu.
To have a toggle effect like an open/close on the link, I guess 2 links that hide each other are needed.
You can capture a click anywhere if you put onclick on the body.
Because of the javascript event propagation model, if you click anywhere on any element and you don't stop the event from propagating, it will reach body and hide the menus.
So basically this means that you want to capture body onclick and make it to hide the menus so when you click on any area of the page, it will close the menus.
But this hides a bit of unwanted behaviour - when you click on the button to show the menu, the menu will display and quickly after that hide (when the event reaches body). To prevent this, you will want to stop the event from propagating when you click on the button which shows the menu (you can see how this works in the code I posted below). The code shows where you need to touch to make it work nicely.
// this function stops event e or window.event if e is not present from
// propagating to other elements.
function stop_event(e) {
if(!e) {
e = window.event;
}
if (e.stopPropagation) e.stopPropagation();
e.cancelBubble = true;
if (e.preventDefault) e.preventDefault();
e.returnValue = false;
return false;
}
// now you just hide all the menus in your hideMenus
function hideMenus()
{
//pseudocode!
for all visible menus - hide // or if you want you can hide all menus,
// the hidden will remain hidden
}
Now the important part.
function menu(id) {
// your stuff here
stop_event(); // this will stop the event going down to the body
// and hiding it after showing it
// this means it will not flicker like: show-hide
}
And finally on your whole UL element:
//partly pesudocode
ul.onclick = function() { stop_event(); }
To explain again what this does:
1st. You hook your hideMenu function to body.onclick. This means that it will always hide the menus if we don't stop the event.
2nd. When you click the menu button, you show the menu and then we stop the event from going to the body. This way, the body.onclick will not fire and it will not hide the menu right after we opened it.
3rd. The ul.onclick means that the menu will not hide itself when we click on it (though if you want the menu to hide when you click the menu itself, you can remove this part).
I have a number of dropdowns and divs that are hidden when the page loads and can be toggled with a click or mouseover, but some of them flash b/c the JavaScript does not run in time. I have their display initially set to block and then I use JavaScript/prototype to find the element and hide it. I have tried loading these "hider" functions using dom:loaded but there is still flashing. This is an example of a dropdown prototype initialization function. From
http://www.makesites.cc/programming/by-makis/simple-drop-down-menu-with-prototype/:
var DropDownMenu = Class.create();
DropDownMenu.prototype = {
initialize: function(menuElement) {
menuElement.childElements().each(function(node){
// if there is a submenu
var submenu = $A(node.getElementsByTagName("ul")).first();
if(submenu != null){
// make sub-menu invisible
Element.extend(submenu).setStyle({display: 'none'});
// toggle the visibility of the submenu
node.onmouseover = node.onmouseout = function(){
Element.toggle(submenu);
}
}
});
}
};
Is there a better way to hide div's or dropdowns to avoid this flashing?
You always run the risk of flicker when you try to hide elements after page load.
I suggest you give the elements in question an inline style like display:none; or a css class with the same setting.
From the class creation syntax used, I take it that you are using something like Prototype version 1.5.x. Here's my take on how I'd do it with that version (it would be nicer to step up to the latest version, of course):
<script type="text/javascript">
var DropDownMenu = Class.create();
DropDownMenu.prototype = {
initialize: function(menuElement) {
// Instead of using 2 listeners for every menu, listen for
// mouse-ing on the menu-container itself.
// Then, find the actual menu to toggle when handling the event.
$(menuElement).observe('mouseout', DropDownMenu.menuToggle);
$(menuElement).observe('mouseover', DropDownMenu.menuToggle);
}
};
DropDownMenu.menuToggle = function (event) {
var menu = DropDownMenu._findMenuElement(event);
if (menu) {Element.toggle(menu);}
};
DropDownMenu._findMenuElement = function (event) {
var element = Event.element(event);
return Element.down(element, 'ul');
}
var toggler = new DropDownMenu('menus');
</script>
And here is some markup to test it with (it may not match yours perfectly, but I think it is similar enough):
<html>
<head>
<title>menu stuff</title>
<style type="text/css ">
/* minimal css */
#menus ul, .menu-type {float: left;width: 10em;}
</style>
</head>
<body>
<h1>Menus</h1>
<div id="menus">
<div class="menu-type">
Numeric
<ul style="display: none;">
<li>1</li><li>2</li><li>3</li><li>4</li>
</ul>
</div>
<div class="menu-type">
Alpha
<ul style="display: none;">
<li>a</li><li>b</li><li>c</li><li>d</li>
</ul>
</div>
<div class="menu-type">
Roman
<ul style="display: none;">
<li>I</li><li>II</li><li>III</li><li>IV</li>
</ul>
</div>
</div>
</body>
</html>
Yoda voice: "Include the prototype.js, I forgot."
Should you want to get rid of inline styling (like I do), give the uls a class like
.hidden {display:none;}
instead, and make the DropDownMenu.menuToggle function do this
if (menu) {Element.toggleClassName(menu, 'hidden');}
instead of toggling the display property directly.
Hope this helps.
Set the display initially to none, then show them as needed. That will get rid of the flashing.
I'm creating a page with an image at the top, and a menu below. When the user clicks on on of the 3 menu buttons, the image slideUp and the page scrolls down so the menu is at the top of the page, then the right .content div fades in. The slideUp should only happen the first time the user clicks on of the buttons.
What the absolute best way to do this with jQuery? (no plugins)
I also need to know how I can't prevent it to fade in the page that is already visible if i click the same button twice?
I'm using rel instead of href, since the href made the page jump, even with return false.
This is what I have so far:
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3/jquery.min.js"></script>
<script type="text/javascript">
$(function(){
imgVisible = true;
$('#mainmenu a').click(function(){
var $activeTab = $(this).attr('rel');
if(!imgVisible){
$('html:not(:animated),body:not(:animated)').animate({scrollTop:$('#mainmenu').offset().top-20},500);
$('.content').hide();
$($activeTab).fadeIn();
} else{
$('#imgholder').slideUp(500,function(){
imgVisible = false;
$('#mainmenu a[rel="'+$activeTab+'"]').click();
});
}
return false;
});
});
</script>
<div id="imgholder"><img src="image.jpg" /></div>
<div id="mainmenu">
<ul>
<li><a rel="#tab1"></a></li>
<li><a rel="#tab2"></a></li>
<li><a rel="#tab3"></a></li>
</ul>
</div>
<div id="container">
<div class="content" id="tab1">
content
</div>
<div class="content" id="tab2">
content
</div>
<div class="content" id="tab3">
content
</div>
</div>
The following code accomplishes what you need:
$('#mainmenu a').click(function(){
var myrel=$(this).attr('rel');
$('.content:not([id='+myrel+'])').hide();
$('#imgholder').slideUp(500,function(){
$('#'+myrel).fadeIn();
});
});
....
<li><a href='#' rel='tab0'></a></li>
I have removed the '#' sign from your rel='' piece ;-)
I am not sure why you would want to scroll the page. When a user clicks on the menu, he/she already has it focused (so it is visible inside the current viewport). But do you have a very large top image? If that is the case, let me know and I will modify the snippet. (Still, it depends on the amount of content below the menu visible when the page first loads.)
Also, for SEO reasons you might want to use the href instead of the rel attribute and create separate content holding pages. The following snippet would remove the navigation action.
$('#mainmenu a').each(function(){
var myhref = $(this).attr('href');
$(this).attr('href','#').attr('rel',myhref);
}).click(function(){
var myrel=$(this).attr('rel');
$('.content:not([id='+myrel+'])').hide();
//....etc
I think this is a great example of what your looking for: Organic Tabs
var imgVisible = true;
var $activeTab, $lastTab;
var $mainmenu = $('#mainmenu');
var offset = $mainmenu.offset().top - 20;
$mainmenu.find('a').click(function() {
$activeTab = $($(this).attr('rel'));
if (!imgVisible) {
// dont fire any events if already open
if ($lastTab.attr('id') == $activeTab.attr('id')) return false;
$lastTab.fadeOut('normal', function() {
$activeTab.fadeIn(500, function() {
$lastTab = $activeTab;
});
});
} else {
$('#imgholder').slideUp(500, function() {
imgVisible = false;
window.scrollTo(0, offset);
$activeTab.fadeIn(500, function() {
$lastTab = $activeTab;
});
});
}
return false;
});
I highly suggest adding <a href="#"> as this will not make the page jump when done properly and will ensure validation on your anchor links. Someone let me know if I missed something, it can be resolved quickly (or you can do it for me if you have an optimization or improvement).
I wanted to have some radio buttons that disabled when the mouse went over and enabled again when it went out (just for fun).
<form>
<input type="radio" name="rigged" onMouseOver="this.disabled=true" onMouseOut="this.disabled=false">
</form>
When the mouse goes on it it does what it should be when it goes back off the button wont re-enable. Also, how do I make it default to enable so that when you refresh the page it doesn't stay disabled.
Thanks in advance.
You could achieve the same effect by wrapping your radio buttons in a div tag and setting the onmouseover and onmouseout events.
<div id="container" onmouseout="this.disabled=false" onmouseover="this.disabled=true">
<input name="rigged" type="radio">
</div>
The above solution only works in IE, for a solution that works in FireFox do the following.
<script type="text/javascript">
function toggleDisabled(el) {
try {
el.disabled = el.disabled ? false : true;
}
catch(E){
}
if (el.childNodes && el.childNodes.length > 0) {
for (var x = 0; x < el.childNodes.length; x++) {
toggleDisabled(el.childNodes[x]);
}
}
}
</script>
*This javaScript function was borrowed from here: Enable or disable DIV tag and its inner controls using Javascript
<div id="container" onmouseover="toggleDisabled(this)" onmouseout="toggleDisabled(this)">
<input name="rigged" type="radio">
</div>
The inputs do not fire the mouseout events because they are disabled.
So you have to wrap it in a div and catch the div's events.
If you want pure javascript, use Phaedrus's example "toggleDisabled" script.
If you want jQuery and not-so-newbie friendly:
<html>
<head>
<title>Page</title>
<script src="jquery-1.3.2.min.js"></script>
<script>
$(function() {
function toggleDisabled(d) {
var disable = d;
this.disableChildren = function() { $(this).children().each(function() { this.disabled = d; }); }
}
$("form .radios").hover(new toggleDisabled(true).disableChildren, new toggleDisabled(false).disableChildren);
});
</script>
</head>
<body>
<form>
<div class="radios">
<input type="radio" name="rigged" value="1"/> Item One<br />
<input type="radio" name="rigged" value="2"/> Item Two<br />
<input type="radio" name="rigged" value="3"/> Item Three<br />
<input type="radio" name="rigged" value="4"/> Item Four
</div>
</form>
</body>
</html>
I had a similar problem with wanting an image to expose, and then go regular when the mouse left the image. I was using jQuery and ended up hooking into mouseenter and mouseout, instead of the events you are using. You might want to try those.
$('#rigged').mouseenter(function() {
$(this).disabled = true;
}).mouseout(function() {
$(this).disabled = false;
});
Something like that.
Again, that's using jQuery.
(You'll have to give the input radio button the id 'rigged')
I think when it's becoming disabled, it's not going to fire any events.
You could try a few things.
On mouseover, make an invisible div overlay the radio box. This will make it impossible to use. Then on the mouseout of this invisible div, remove the div.
You could play with mouse x and y coords, and see if they overlay your radio elements. This isn't an optimal solution though.
Markup for the first, in jQuery, would go something like this
$('#rigged').after('<div id="overlay" style="display: none;"></div>'); // make this the size of the radio button and/or associated label (if present). also, maybe with absolute and relative positioning, make sure it will overlap the radio element
$('#rigged').bind('mouseover', function() {
$('#overlay').show();
});
$('#overlay').live('mouseout', function() {
$(this).hide();
});
You'll need to adapt this to work with multiple elements.