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Modal only triggered after ajax request

I have two questions about this code. The first is why the modal is not shown before the alert? The second is how can i delay the modal, because the popup is so fast that i can't see nothing in the modal.
$('#myModal').modal('hide');
$(document).ajaxStart(function() {
$('#myModal').modal('show');
}).ajaxStop(function() {
$('#myModal').modal('hide');
//$('#myModal').delay(5000).modal('hide'); does not work
});
$(".generate_report").click(function(event) {
event.preventDefault();
$.post("xls.php", $(".form_report").serialize(), function() {
}).done(function(data) {
alert("should be executed only after modal");
});
});
demo

You can achieve the same with this code:
$(".generate_report").click(function (event) {
event.preventDefault();
$('#myModal').modal('show');
setTimeout(function(){
$.post("xls.php", $(".form_report").serialize(),function(data){
$('#myModal').modal('hide');
alert("after modal");
})
}, 2000);
});
And remove this code
$(document).ajaxStart(function() {
$('#myModal').modal('show');
}).ajaxStop(function() {
$('#myModal').modal('hide');
//$('#myModal').delay(5000).modal('hide'); does not work
});

What this code does is show a modal when the ajax call starts and instantly hide it when its done. You can use a timer to wait a while before closing it.
Also you've nested a callback function in your jQuery.post, but you don't use it which causes confusing code here. Theres no need to use .done() when you're just going to append it to the AJAX function directly. You can just use the callback function here.
$.post("xls.php", $(".form_report").serialize(), function(data) {
alert("should be executed only after modal");
});
But that is just a code styling concern. The done(), success(), fail() methods are used on a jQuery.Deferred promise object, which $.ajax happens to return. And since $.post/$.get are just pointers to $.ajax, they will too.
Secondly, if you want the modal to wait before it closes, you can do this:
var waitTimer;
var timeToWait = 2000; // Time to wait here
var $myModal = $('#myModal');
$myModal.modal('hide');
$(document).ajaxStart(function() {
$myModal.modal('show');
}).ajaxStop(function() {
if (waitTimer) {
clearTimeout(waitTimer);
}
waitTimer = setTimeout(function() {
$myModal.modal('hide');
}, msToWait);
});
The .delay() method you tried to use only works after you've animated something.
Also a quick tip: Cache your jQuery selectors. You're telling jQuery to jump in the DOM 3 times to search for the same element.

how to do jquery once fade out has finished?

I'm trying to fade out a div on a click but also change some css values.
the issue im having is that the values change while the fade out is happening (too early). I need the values to change once the fade out has finished:
<script type="text/javascript">
$('#r_text').click(function() {
$(".box1_d").fadeOut();
$(".box1_c").css("top","0px");
});
</script>
Now when i run that, everything works but just not exactly how i'd like it.. I need the css values to be changed once the fadeout has finished, not while it's still happening.
is this possible?
if so, any ideas how?
thank you.

Use a callback function to modify the .css() as the second parameter to fadeOut(). It will fire when the fade completes.
<script type="text/javascript">
var fadeTime = 500;
$('#r_text').click(function() {
$(".box1_d").fadeOut(fadeTime, function() {
$(".box1_c").css("top","0px");
});
});
</script>

Provided you use jQuery version >= 1.5, you can/should utilize the Deferred object instead of using the callback parameter:
$('#r_text').click((function () {
var animations = {
initial: function () {
return $(".box1_d").fadeOut(1500);
},
following: function () {
return $(".box1_c").css("top","0px").animate({fontSize: '150%'});
},
onDone: function () {
alert('DONE!');
}
};
return function(e) {
$.when(animations.initial())
.pipe(animations.following)
.done(animations.onDone);
e.preventDefault();
};
}()));
JsFiddle of it in action: http://jsfiddle.net/wGcgS/2/

Jquery delay not working

Can someone please tell me why my function is not executing, after my images are displayed?
$("#screen").css("background-image", "url('screens/animated/077.gif')").delay(5000).queue(function() {
$("#screen").css("background-image", "url('screens/animated/078.gif')").delay(5000).queue(function() {
buttonClick(16);
});
});
Don't know why it won't call my buttonClick(16); function.

You could just animate instead dude? animate() you can pass a time to and also it has a callback function, so once the first animation is complete you can run more code, i.e.
$(this).animate(function(){
//Do animation
},1000,function(){
//Animation is complete, do something else like the next animation
$(this).animate(function(){
//Another animation to run once the first is complete
});
});

Because you didn't dequeue.
$("#screen").css("background-image", "url('screens/animated/077.gif')").delay(5000).queue(function () {
$(this).css("background-image", "url('screens/animated/078.gif')").delay(5000).queue(function () {
$(this).dequeue();
buttonClick(16);
}).dequeue();
});

The queue function receives a param that you should call when the next function should run.
Example:
$().queue(function (next) {
// Do what you need
next();
});

jQuery Delaying Queue

I want to delay things like the css from happening but this method wont work. Any ideas on how I can delay tasks.
$(function() {
$('.btn').click(function() {
$('.divOne').animate({"left": "+=400px"}, "fast").delay(800).css("background-color","yellow");
});
});

You can use .queue() to stick it on the default animation (fx) queue, like this:
$('.btn').click(function() {
$('.divOne').animate({"left":"+=400px"}, "fast").delay(800).queue(function(n) {
$(this).css("background-color","yellow");
n(); //call next function in the queue, needed if you animate later!
});
});
You can test it here, all this does is stick it in the fx queue using .queue(function(n)), the n is the next function in the queue, so we're calling it, for example if you didn't do this and added any animation after it, it just wouldn't run, because the next function or .dequeue() isn't called.

Maybe use a callback function on the animate. Once the animation is complete use a setTimeout()
$(function() {
$('.btn').click(function() {
$('.divOne').animate({"left": "+=400px"},"fast", function() {
var $elem = $(this);
setTimeout(function() {
$elem.css('background-color','yellow');
}, 800);
})
});
This might not be syntactically perfect.

calling Jquery function from javascript

How can i call a jQuery function from javascript?
//jquery
$(function() {
function my_fun(){
/.. some operations ../
}
});
//just js
function js_fun () {
my_fun(); //== call jquery function
}

Yes you can (this is how I understand the original question).
Here is how I did it. Just tie it into outside context.
For example:
//javascript
my_function = null;
//jquery
$(function() {
function my_fun(){
/.. some operations ../
}
my_function = my_fun;
})
//just js
function js_fun () {
my_function(); //== call jquery function - just Reference is globally defined not function itself
}
I encountered this same problem when trying to access methods of the object, that was instantiated
on DOM object ready only. Works. My example:
MyControl.prototype = {
init: function {
// init something
}
update: function () {
// something useful, like updating the list items of control or etc.
}
}
MyCtrl = null;
// create jquery plug-in
$.fn.aControl = function () {
var control = new MyControl(this);
control.init();
MyCtrl = control; // here is the trick
return control;
}
now you can use something simple like:
function() = {
MyCtrl.update(); // yes!
}

You can't.
function(){
function my_fun(){
/.. some operations ../
}
}
That is a closure. my_fun() is defined only inside of that anonymous function. You can only call my_fun() if you declare it at the correct level of scope, i.e., globally.
$(function () {/* something */}) is an IIFE, meaning it executes immediately when the DOM is ready. By declaring my_fun() inside of that anonymous function, you prevent the rest of the script from "seeing" it.
Of course, if you want to run this function when the DOM has fully loaded, you should do the following:
function my_fun(){
/* some operations */
}
$(function(){
my_fun(); //run my_fun() ondomready
});
// just js
function js_fun(){
my_fun(); //== call my_fun() again
}

var jqueryFunction;
$().ready(function(){
//jQuery function
jqueryFunction = function( _msg )
{
alert( _msg );
}
})
//javascript function
function jsFunction()
{
//Invoke jQuery Function
jqueryFunction("Call from js to jQuery");
}
http://www.designscripting.com/2012/08/call-jquery-function-from-javascript/

<script>
// Instantiate your javascript function
niceJavascriptRoutine = null;
// Begin jQuery
$(document).ready(function() {
// Your jQuery function
function niceJqueryRoutine() {
// some code
}
// Point the javascript function to the jQuery function
niceJavaScriptRoutine = niceJueryRoutine;
});
</script>

jQuery functions are called just like JavaScript functions.
For example, to dynamically add the class "red" to the document element with the id "orderedlist" using the jQuery addClass function:
$("#orderedlist").addClass("red");
As opposed to a regular line of JavaScript calling a regular function:
var x = document.getElementById("orderedlist");
addClass() is a jQuery function, getElementById() is a JavaScript function.
The dollar sign function makes the jQuery addClass function available.
The only difference is the jQuery example is calling the addclass function of the jQuery object $("#orderedlist") and the regular example is calling a function of the document object.
In your code
$(function() {
// code to execute when the DOM is ready
});
Is used to specify code to run when the DOM is ready.
It does not differentiate (as you may think) what is "jQuery code" from regular JavaScript code.
So, to answer your question, just call functions you defined as you normally would.
//create a function
function my_fun(){
// call a jQuery function:
$("#orderedlist").addClass("red");
}
//call the function you defined:
myfun();

I made it...
I just write
jQuery('#container').append(html)
instead
document.getElementById('container').innerHTML += html;

//javascript function calling an jquery function
//In javascript part
function js_show_score()
{
//we use so many javascript library, So please use 'jQuery' avoid '$'
jQuery(function(){
//Call any jquery function
show_score(); //jquery function
});(jQuery);
}
//In Jquery part
jQuery(function(){
//Jq Score function
function show_score()
{
$('#score').val("10");
}
});(jQuery);

My problem was that I was looking at it from the long angle:
function new_line() {
var html= '<div><br><input type="text" value="" id="dateP_'+ i +'"></div>';
document.getElementById("container").innerHTML += html;
$('#dateP_'+i).datepicker({
showOn: 'button',
buttonImage: 'calendar.gif',
buttonImageOnly: true
});
i++;
}

<script>
$.myjQuery = function() {
alert("jQuery");
};
$(document).ready(function() {
alert("Welcome!");
});
function display() {
$.myjQuery();
};
</script>
<input type="button" value="submit" onclick=" display();">
Hope this will work for you!