Group checkboxes in JSFiddle : Part 1 [closed] - javascript

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I am trying to do group checkboxes by selecting selectAll. Please check JSFiddle for code sample
JSFiddle
<fieldset>
<!-- these will be affected by check all -->
<div><input type="checkbox" ID="checkall1" onclick="CheckAllClick('checkall1');"> Check all</div>
<div><input type="checkbox"> Checkbox</div>
<div><input type="checkbox"> Checkbox</div>
<div><input type="checkbox"> Checkbox</div>
</fieldset>
<fieldset>
<!-- these won't be affected by check all; different field set -->
<div><input type="checkbox" ID="checkall2" onclick="CheckAllClick('checkall2');"> Check all</div>
<div><input type="checkbox"> Checkbox</div>
<div><input type="checkbox"> Checkbox</div>
<div><input type="checkbox"> Checkbox</div>
</fieldset>
function CheckAllClick(id){
alert(id);
$(id).closest('fieldset').find(':checkbox').prop('checked', this.checked);
}
Part 2: Continue


You have some issues in your function: Try this way:
Js
function CheckAllClick(elem) {
$(elem).closest('fieldset').find(':checkbox').prop('checked', elem.checked);
}
Markup
<input type="checkbox" ID="checkall1" onclick="CheckAllClick(this);">Check all</div>
Fiddle
Pass the element in the onclick function as this and access it in your code.
If you can go with jquery approach then:
Add a class to your checkall check boxes
<input type="checkbox" class="checkAll" ID="checkall1" >Check all
With the same code, if you want to make the label click to check the checkbox then just wrap them in label tag, same thing you can do with all the checkboxes by wrapping them in label which generally is a standard way:
<label><input type="checkbox" class="checkAll" ID="checkall1" >Check all<label>
Bind an event handler to a class
$('.checkAll').on('change', function(){
$(this).closest('fieldset').find(':checkbox').prop('checked', this.checked);
})
Fiddle


function CheckAllClick(id){
alert(id);
$(id).closest('fieldset').find(':checkbox').prop('checked', 'checked');
}
The simplest solution is just to changed the checked property to checked seeing as you only selecting inputs you want already
And pass this into your onclick
<div><input type="checkbox" ID="checkall2" onclick="CheckAllClick(this);"> Check all</div>


What you probably want is this.
$('[id^=checkall]').click(function(){
$(this).closest('fieldset').find(':checkbox').not(this).prop('checked', function(i,oldval){
return !oldval;
});
});
Fiddle

Related

Check if all checkboxes are checked on submit [duplicate]

This question already has answers here:
Check if checkbox is checked with jQuery
(26 answers)
Closed 8 years ago.
I have this:
<fieldset id="booom">
<label><INPUT TYPE="checkbox" NAME="a" VALUE="a">something></label>
<label><INPUT TYPE="checkbox" NAME="b" VALUE="b">something></label>
<label><INPUT TYPE="checkbox" NAME="c" VALUE="c">something></label>
</fieldset>
<input type="button" id="answer" value="submit">
How can I check with jQuery if all checkboxes from fieldset 'booom' are unchecked on submit?
So:
if (all checkboxes from parent 'booom' are unchecked) {
alert("something")
}
I found many posts about this but none with an actual simple working sample with a button and an alert box :)
Thanks!

You can use the :checked modifier in a selector.
if ($("#boom :checkbox:checked").length == 0) {
alert("You have to check at least one box");
}

Making certain questions appear on an html form through jQuery?

I'd like to say thanks to the community. You've been a tremendous help so far.
Here's my latest question: I'm designing an online submission form, and one of the questions is a yes/no question with radio buttons. If the lead answers yes, I want a certain question to display. If they answer no, a different question will be displayed instead.
I looked at a few other answers and was able to scrape together some jQuerym but it doesn't seem to be working for me. Here is my javascript and a jsfiddle with the rest of my code.
$(function() {
$('input[type="radio"]').click(function() {
if($(this).attr('id') == 'yes') {
$('#ifyes').show();
} else {
$('#ifno').show();
}
});
});
http://jsfiddle.net/yrktj4kz/
Any help would be appreciated!

Looking at the fiddle, you should use
$('.ifyes').show();
and
$('.ifno').show();
instead.
You were using the id's of the input fields to show the element instead of the class of the wrapping div to which the display: hidden; style was applied.

I have updated your code
HTML:
<li>
<label for="coverage">K. Do you have current coverage?</label>
<input type="radio" name="choice" class="radio-toggle" data-target=".ifyes" data-target-group=".ifdiv" /> Yes
<input type="radio" name="choice" class="radio-toggle" data-target=".ifno" data-target-group=".ifdiv" /> No
</li>
<li>
<div class="ifyes ifdiv">
<label for="ifyes">When does the policy expire?</label>
<input type="text" id="ifyes" name="ifyes" value="" />
</div>
<div class="ifno ifdiv">
<label for="ifno">When do you need the policy to take effect?</label>
<input type="text" id="ifno" name="ifno" value="" />
</div>
</li>
and JS:
$(document).ready(function(){
$('.radio-toggle').click(function() {
$($(this).data('targetGroup')).hide();
$($(this).data('target')).show();
});
});
Obviously you need to call the jQuery library.
This is the complete and updated fiddle: http://jsfiddle.net/yrktj4kz/1/
Note that i'm using html data attribute to optimize the js code.

jQuery autoselect radiobox is not working

I cannot get my jquery code to auto select a radiobox.
Here is my html:
<div class="formField rsform-block rsform-block-existingcustomer" style="margin-bottom: -22px;">
<!--<input name="form[existingCustomer]" type="radio" value="Yes" id="existingCustomer0" /><label for="existingCustomer0">Yes</label><input checked="checked" name="form[existingCustomer]" type="radio" value="No" id="existingCustomer1" /><label for="existingCustomer1">No</label><br/>
<span id="component100" class="formNoError">Please tell us if you're an existing customer.</span>-->
Are you an existing client?<br>
<label for="existingCustomer0" class="radio"><span class="icon"></span><span class="icon-to-fade"></span>Yes
<input name="form[existingCustomer]" type="radio" value="Yes" id="existingCustomer0" class="addRadio">
</label>
<label for="existingCustomer1" class="radio checked"><span class="icon"></span><span class="icon-to-fade"></span>No
<input checked="checked" name="form[existingCustomer]" type="radio" value="No" id="existingCustomer1" class="addRadio" style="display:none;">
</label>
</div>
and here is a snippet of the jQuery code that is supposed to do it:
if(aaid) {
var num_one = aaid;
jQuery('input[value="Yes"]').prop('checked', true);
Does anyone see the problem? I am trying to autoselect the "yes" checkbox, so that it will activate the next part which is create a dropdown menu.
Thanks in advance! :)

Try this:
$(document).ready(function () {
$('input:radio[name="form[existingCustomer]"][value="Yes"]').attr('checked',true);
//OR
$('input:radio[name="form[existingCustomer]"][value="Yes"]').prop('checked',true);
});
Example

I see a couple issues with your code here.
1. input hmtl does not have proper ending/end tag
2. not sure why you wrap it around the label
3. Be sure to put your jquery code in document ready so that it checks the radiobox when the page is loaded.
4. in you html code, you are pre-setting the No radio to be checked. Is that on purpose? It looks like you set it to no and then using jquery to set it back to yes.
Anyway, try attr instead of prop. Something like this.
$('input:radio[value="Yes"]').attr('checked', true);

Group checkboxes in JSFiddle: Part2 [closed]

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Questions must demonstrate a minimal understanding of the problem being solved. Tell us what you've tried to do, why it didn't work, and how it should work. See also: Stack Overflow question checklist
Closed 9 years ago.
Improve this question
Group checkboxes in JSFiddle : Part 1
After solving Part 1 for Global Checkbox for All Check/Uncheck. I have couple other issues to solve.
If I unchecked any of the items from list. Automatically Global (Check all) should be unchecked.
If I checked all of items individually. Automatically Global (Check all) should be checked. like this.
Code
<fieldset>
<!-- these will be affected by check all -->
<div><input type="checkbox" ID="checkall1"> Check all</div>
<div><input type="checkbox"> Checkbox</div>
<div><input type="checkbox"> Checkbox</div>
<div><input type="checkbox"> Checkbox</div>
</fieldset>
<fieldset>
<!-- these won't be affected by check all; different field set -->
<div><input type="checkbox" ID="checkall2"> Check all</div>
<div><input type="checkbox"> Checkbox</div>
<div><input type="checkbox"> Checkbox</div>
<div><input type="checkbox"> Checkbox</div>
</fieldset>
JS
$('[id^=checkall]').click(function(){
$(this).closest('fieldset').find('input').not(this).prop('checked',this.checked);
});
JSFiddle

Register a callback which will check whether all the checkboxes in the current group is checked or not
$('input[id^=checkall]').click(function(){
$(this).closest('fieldset').find('input').not(this).prop('checked',this.checked);
});
$(':checkbox').not('[id^=checkall]').click(function(){
var all = $(this).closest('fieldset').find('[id^=checkall]');
var chks = $(this).closest('fieldset').find('input').not(all);
all.prop('checked', chks.length == chks.filter(':checked').length);
})
Demo: Fiddle

Jquery to Make 2 Sets of Radio Buttons Mirror Eachother

I am trying to setup two sets of radio buttons that will function simultaneously. In other words whenever Male is checked on the top, I would like Male at the bottom to be automatically checked. (and vice versa) If user scrolls down and clicks female then the one at the top should be checked. No matter which radio the user clicks both radio sets should always have the same value checked. Please advise on the most practical way to accomplish this. My main focus is Javascript or Jquery but I have spent several hours trying to come up with something to no avail. Please advise. Thanks! :)
<div class="top">
<input type="radio" name="sex" value="Male" /> Male<br />
<input type="radio" name="sex" value="Female" checked="checked" /> Female<br />
</div>
<div>Random Content</div>
<div class="bottom">
<input type="radio" name="sex2" value="Male" /> Male<br />
<input type="radio" name="sex2" value="Female" checked="checked" /> Female<br />
</div>

Attach to the change event and selecting all other radio buttons which have the same beginning of the name and are of equal value but which are not the current one.
$("input[name^='sex']").change(function(){
var $otherRadioButtons = $("input[name^='sex'][value='" + this.value + "']").not(this);
$otherRadioButtons.prop('checked', $(this).prop('checked'));
});
The above is not using any clever caching of the selectors which you can add yourself.
Basically, whenever a radio button changes it's checked value the code will select all other radio buttons with the same value (male/female) which also start with the same name (sex????) and set their checked property to the same value as the current one.
I hope this makes sense. See a working demo below.
DEMO - Changing radio buttons in a set.
Edit
I just noticed.. I am using jquery 1.3.2 and upgrading isnt an option
at the moment. You don't happen to have a 1.3.2 alternative do you?
For jQuery version 1.3.2 use the attr method instead of the prop method:
$("input[name^='sex']").change(function(){
var $otherRadioButtons = $("input[name^='sex'][value='" + this.value + "']").not(this);
$otherRadioButtons.attr('checked', $(this).attr('checked'));
});
DEMO - Changing radio buttons in a set using jQuery 1.3.2.

Just add an onclick listener to both sets. Like this:
document.getElementById("male1").onclick=clickMale;
document.getElementById("male2").onclick=clickMale;
document.getElementById("female1").onclick=clickFemale;
document.getElementById("female2").onclick=clickFemale;
function clickMale(){
document.getElementById("male1").checked=true;
document.getElementById("male2").checked=true;
}
function clickFemale(){
document.getElementById("female1").checked=true;
document.getElementById("female2").checked=true;
}
And add IDs to the radio buttons ("male1", "male2", "female1", "female2")

Since you mentioned it, Zove's answer in jQuery would be something like this, if you prefer:
$("#male1").click(clickMale);
$("#male2").click(clickMale);
$("#female1").click(clickFemale);
$("#female2").click(clickFemale);
function clickMale(){
$("#male1").attr('checked', true);
$("#male1").attr('checked', true);
}
function clickFemale(){
$("#female1").attr('checked', true);
$("#female2").attr('checked', true);
}
You don't need jQuery for something this simple, but if you're using it elsewhere, it's best to be consistent.

It might make sense, to share a class for both male / female inputs, e.g. 'js-male' or 'js-female'). This saves some code. for instance you could do:
$('.js-male').change(function() {
$('.js-male').attr('checked', $(this).attr('checked'));
});
$('.js-female').change(function() {
$('.js-female').attr('checked', $(this).attr('checked'));
});
There might be more elegant ways to deal with the whole situation so. Do you really want the inputs to have different names ('male', 'male2'), which means that your server receives two different params? If you give both radio button groups the same names, only the value of the last one will be sent to the server, anyway, if you mirror the radio buttons anyway, this doesn't really matter.
Demo

Just change the location of your jQuery source and this will work right out of the box.
<html>
<head>
<script src="jquery-1.7.1.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$("#male1, #male2").live("click", function(){
$("#male1").attr("checked", $("#male2").attr("checked"));
$("#male2").attr("checked", $("#male1").attr("checked"));
});
$("#female1, #female2").live("click", function(){
$("#female1").attr("checked", $("#female2").attr("checked"));
$("#female2").attr("checked", $("#female1").attr("checked"));
});
});
</script>
</head>
<body>
<div class="top">
<input id="male1" type="radio" name="sex" value="Male" /> Male<br />
<input id="female1" type="radio" name="sex" value="Female" checked="checked" /> Female<br />
</div>
<div>Random Content</div>
<div class="bottom">
<input id="male2" type="radio" name="sex2" value="Male" /> Male<br />
<input id="female2" type="radio" name="sex2" value="Female" checked="checked" /> Female<br />
</div>
</body>
</html>

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