I have the following type of string
var string = "'string, duppi, du', 23, lala"
I want to split the string into an array on each comma, but only the commas outside the single quotation marks.
I can't figure out the right regular expression for the split...
string.split(/,/)
will give me
["'string", " duppi", " du'", " 23", " lala"]
but the result should be:
["string, duppi, du", "23", "lala"]
Is there a cross-browser solution?
Disclaimer
2014-12-01 Update: The answer below works only for one very specific format of CSV. As correctly pointed out by DG in the comments, this solution does NOT fit the RFC 4180 definition of CSV and it also does NOT fit MS Excel format. This solution simply demonstrates how one can parse one (non-standard) CSV line of input which contains a mix of string types, where the strings may contain escaped quotes and commas.
A non-standard CSV solution
As austincheney correctly points out, you really need to parse the string from start to finish if you wish to properly handle quoted strings that may contain escaped characters. Also, the OP does not clearly define what a "CSV string" really is. First we must define what constitutes a valid CSV string and its individual values.
Given: "CSV String" Definition
For the purpose of this discussion, a "CSV string" consists of zero or more values, where multiple values are separated by a comma. Each value may consist of:
A double quoted string. (may contain unescaped single quotes.)
A single quoted string. (may contain unescaped double quotes.)
A non-quoted string. (may NOT contain quotes, commas or backslashes.)
An empty value. (An all whitespace value is considered empty.)
Rules/Notes:
Quoted values may contain commas.
Quoted values may contain escaped-anything, e.g. 'that\'s cool'.
Values containing quotes, commas, or backslashes must be quoted.
Values containing leading or trailing whitespace must be quoted.
The backslash is removed from all: \' in single quoted values.
The backslash is removed from all: \" in double quoted values.
Non-quoted strings are trimmed of any leading and trailing spaces.
The comma separator may have adjacent whitespace (which is ignored).
Find:
A JavaScript function which converts a valid CSV string (as defined above) into an array of string values.
Solution:
The regular expressions used by this solution are complex. And (IMHO) all non-trivial regexes should be presented in free-spacing mode with lots of comments and indentation. Unfortunately, JavaScript does not allow free-spacing mode. Thus, the regular expressions implemented by this solution are first presented in native regex syntax (expressed using Python's handy: r'''...''' raw-multi-line-string syntax).
First here is a regular expression which validates that a CVS string meets the above requirements:
Regex to validate a "CSV string":
re_valid = r"""
# Validate a CSV string having single, double or un-quoted values.
^ # Anchor to start of string.
\s* # Allow whitespace before value.
(?: # Group for value alternatives.
'[^'\\]*(?:\\[\S\s][^'\\]*)*' # Either Single quoted string,
| "[^"\\]*(?:\\[\S\s][^"\\]*)*" # or Double quoted string,
| [^,'"\s\\]*(?:\s+[^,'"\s\\]+)* # or Non-comma, non-quote stuff.
) # End group of value alternatives.
\s* # Allow whitespace after value.
(?: # Zero or more additional values
, # Values separated by a comma.
\s* # Allow whitespace before value.
(?: # Group for value alternatives.
'[^'\\]*(?:\\[\S\s][^'\\]*)*' # Either Single quoted string,
| "[^"\\]*(?:\\[\S\s][^"\\]*)*" # or Double quoted string,
| [^,'"\s\\]*(?:\s+[^,'"\s\\]+)* # or Non-comma, non-quote stuff.
) # End group of value alternatives.
\s* # Allow whitespace after value.
)* # Zero or more additional values
$ # Anchor to end of string.
"""
If a string matches the above regex, then that string is a valid CSV string (according to the rules previously stated) and may be parsed using the following regex. The following regex is then used to match one value from the CSV string. It is applied repeatedly until no more matches are found (and all values have been parsed).
Regex to parse one value from valid CSV string:
re_value = r"""
# Match one value in valid CSV string.
(?!\s*$) # Don't match empty last value.
\s* # Strip whitespace before value.
(?: # Group for value alternatives.
'([^'\\]*(?:\\[\S\s][^'\\]*)*)' # Either $1: Single quoted string,
| "([^"\\]*(?:\\[\S\s][^"\\]*)*)" # or $2: Double quoted string,
| ([^,'"\s\\]*(?:\s+[^,'"\s\\]+)*) # or $3: Non-comma, non-quote stuff.
) # End group of value alternatives.
\s* # Strip whitespace after value.
(?:,|$) # Field ends on comma or EOS.
"""
Note that there is one special case value that this regex does not match - the very last value when that value is empty. This special "empty last value" case is tested for and handled by the js function which follows.
JavaScript function to parse CSV string:
// Return array of string values, or NULL if CSV string not well formed.
function CSVtoArray(text) {
var re_valid = /^\s*(?:'[^'\\]*(?:\\[\S\s][^'\\]*)*'|"[^"\\]*(?:\\[\S\s][^"\\]*)*"|[^,'"\s\\]*(?:\s+[^,'"\s\\]+)*)\s*(?:,\s*(?:'[^'\\]*(?:\\[\S\s][^'\\]*)*'|"[^"\\]*(?:\\[\S\s][^"\\]*)*"|[^,'"\s\\]*(?:\s+[^,'"\s\\]+)*)\s*)*$/;
var re_value = /(?!\s*$)\s*(?:'([^'\\]*(?:\\[\S\s][^'\\]*)*)'|"([^"\\]*(?:\\[\S\s][^"\\]*)*)"|([^,'"\s\\]*(?:\s+[^,'"\s\\]+)*))\s*(?:,|$)/g;
// Return NULL if input string is not well formed CSV string.
if (!re_valid.test(text)) return null;
var a = []; // Initialize array to receive values.
text.replace(re_value, // "Walk" the string using replace with callback.
function(m0, m1, m2, m3) {
// Remove backslash from \' in single quoted values.
if (m1 !== undefined) a.push(m1.replace(/\\'/g, "'"));
// Remove backslash from \" in double quoted values.
else if (m2 !== undefined) a.push(m2.replace(/\\"/g, '"'));
else if (m3 !== undefined) a.push(m3);
return ''; // Return empty string.
});
// Handle special case of empty last value.
if (/,\s*$/.test(text)) a.push('');
return a;
};
Example input and output:
In the following examples, curly braces are used to delimit the {result strings}. (This is to help visualize leading/trailing spaces and zero-length strings.)
// Test 1: Test string from original question.
var test = "'string, duppi, du', 23, lala";
var a = CSVtoArray(test);
/* Array hes 3 elements:
a[0] = {string, duppi, du}
a[1] = {23}
a[2] = {lala} */
// Test 2: Empty CSV string.
var test = "";
var a = CSVtoArray(test);
/* Array hes 0 elements: */
// Test 3: CSV string with two empty values.
var test = ",";
var a = CSVtoArray(test);
/* Array hes 2 elements:
a[0] = {}
a[1] = {} */
// Test 4: Double quoted CSV string having single quoted values.
var test = "'one','two with escaped \' single quote', 'three, with, commas'";
var a = CSVtoArray(test);
/* Array hes 3 elements:
a[0] = {one}
a[1] = {two with escaped ' single quote}
a[2] = {three, with, commas} */
// Test 5: Single quoted CSV string having double quoted values.
var test = '"one","two with escaped \" double quote", "three, with, commas"';
var a = CSVtoArray(test);
/* Array hes 3 elements:
a[0] = {one}
a[1] = {two with escaped " double quote}
a[2] = {three, with, commas} */
// Test 6: CSV string with whitespace in and around empty and non-empty values.
var test = " one , 'two' , , ' four' ,, 'six ', ' seven ' , ";
var a = CSVtoArray(test);
/* Array hes 8 elements:
a[0] = {one}
a[1] = {two}
a[2] = {}
a[3] = { four}
a[4] = {}
a[5] = {six }
a[6] = { seven }
a[7] = {} */
Additional notes:
This solution requires that the CSV string be "valid". For example, unquoted values may not contain backslashes or quotes, e.g. the following CSV string is NOT valid:
var invalid1 = "one, that's me!, escaped \, comma"
This is not really a limitation because any sub-string may be represented as either a single or double quoted value. Note also that this solution represents only one possible definition for: "Comma Separated Values".
Edit: 2014-05-19: Added disclaimer.
Edit: 2014-12-01: Moved disclaimer to top.
RFC 4180 solution
This does not solve the string in the question since its format is not conforming with RFC 4180; the acceptable encoding is escaping double quote with double quote. The solution below works correctly with CSV files d/l from google spreadsheets.
UPDATE (3/2017)
Parsing single line would be wrong. According to RFC 4180 fields may contain CRLF which will cause any line reader to break the CSV file. Here is an updated version that parses CSV string:
'use strict';
function csvToArray(text) {
let p = '', row = [''], ret = [row], i = 0, r = 0, s = !0, l;
for (l of text) {
if ('"' === l) {
if (s && l === p) row[i] += l;
s = !s;
} else if (',' === l && s) l = row[++i] = '';
else if ('\n' === l && s) {
if ('\r' === p) row[i] = row[i].slice(0, -1);
row = ret[++r] = [l = '']; i = 0;
} else row[i] += l;
p = l;
}
return ret;
};
let test = '"one","two with escaped """" double quotes""","three, with, commas",four with no quotes,"five with CRLF\r\n"\r\n"2nd line one","two with escaped """" double quotes""","three, with, commas",four with no quotes,"five with CRLF\r\n"';
console.log(csvToArray(test));
OLD ANSWER
(Single line solution)
function CSVtoArray(text) {
let ret = [''], i = 0, p = '', s = true;
for (let l in text) {
l = text[l];
if ('"' === l) {
s = !s;
if ('"' === p) {
ret[i] += '"';
l = '-';
} else if ('' === p)
l = '-';
} else if (s && ',' === l)
l = ret[++i] = '';
else
ret[i] += l;
p = l;
}
return ret;
}
let test = '"one","two with escaped """" double quotes""","three, with, commas",four with no quotes,five for fun';
console.log(CSVtoArray(test));
And for the fun, here is how you create CSV from the array:
function arrayToCSV(row) {
for (let i in row) {
row[i] = row[i].replace(/"/g, '""');
}
return '"' + row.join('","') + '"';
}
let row = [
"one",
"two with escaped \" double quote",
"three, with, commas",
"four with no quotes (now has)",
"five for fun"
];
let text = arrayToCSV(row);
console.log(text);
I liked FakeRainBrigand's answer, however it contains a few problems: It can not handle whitespace between a quote and a comma, and does not support 2 consecutive commas. I tried editing his answer but my edit got rejected by reviewers that apparently did not understand my code. Here is my version of FakeRainBrigand's code.
There is also a fiddle: http://jsfiddle.net/xTezm/46/
String.prototype.splitCSV = function() {
var matches = this.match(/(\s*"[^"]+"\s*|\s*[^,]+|,)(?=,|$)/g);
for (var n = 0; n < matches.length; ++n) {
matches[n] = matches[n].trim();
if (matches[n] == ',') matches[n] = '';
}
if (this[0] == ',') matches.unshift("");
return matches;
}
var string = ',"string, duppi, du" , 23 ,,, "string, duppi, du",dup,"", , lala';
var parsed = string.splitCSV();
alert(parsed.join('|'));
I had a very specific use case where I wanted to copy cells from Google Sheets into my web app. Cells could include double-quotes and new-line characters. Using copy and paste, the cells are delimited by a tab characters, and cells with odd data are double quoted. I tried this main solution, the linked article using regexp, and Jquery-CSV, and CSVToArray. http://papaparse.com/ Is the only one that worked out of the box. Copy and paste is seamless with Google Sheets with default auto-detect options.
PEG(.js) grammar that handles RFC 4180 examples at http://en.wikipedia.org/wiki/Comma-separated_values:
start
= [\n\r]* first:line rest:([\n\r]+ data:line { return data; })* [\n\r]* { rest.unshift(first); return rest; }
line
= first:field rest:("," text:field { return text; })*
& { return !!first || rest.length; } // ignore blank lines
{ rest.unshift(first); return rest; }
field
= '"' text:char* '"' { return text.join(''); }
/ text:[^\n\r,]* { return text.join(''); }
char
= '"' '"' { return '"'; }
/ [^"]
Test at http://jsfiddle.net/knvzk/10 or https://pegjs.org/online.
Download the generated parser at https://gist.github.com/3362830.
People seemed to be against RegEx for this. Why?
(\s*'[^']+'|\s*[^,]+)(?=,|$)
Here's the code. I also made a fiddle.
String.prototype.splitCSV = function(sep) {
var regex = /(\s*'[^']+'|\s*[^,]+)(?=,|$)/g;
return matches = this.match(regex);
}
var string = "'string, duppi, du', 23, 'string, duppi, du', lala";
console.log( string.splitCSV() );
.as-console-wrapper { max-height: 100% !important; top: 0; }
Adding one more to the list, because I find all of the above not quite "KISS" enough.
This one uses regex to find either commas or newlines while skipping over quoted items. Hopefully this is something noobies can read through on their own. The splitFinder regexp has three things it does (split by a |):
, - finds commas
\r?\n - finds new lines, (potentially with carriage return if the exporter was nice)
"(\\"|[^"])*?" - skips anynthing surrounded in quotes, because commas and newlines don't matter in there. If there is an escaped quote \\" in the quoted item, it will get captured before an end quote can be found.
const splitFinder = /,|\r?\n|"(\\"|[^"])*?"/g;
function csvTo2dArray(parseMe) {
let currentRow = [];
const rowsOut = [currentRow];
let lastIndex = splitFinder.lastIndex = 0;
// add text from lastIndex to before a found newline or comma
const pushCell = (endIndex) => {
endIndex = endIndex || parseMe.length;
const addMe = parseMe.substring(lastIndex, endIndex);
// remove quotes around the item
currentRow.push(addMe.replace(/^"|"$/g, ""));
lastIndex = splitFinder.lastIndex;
}
let regexResp;
// for each regexp match (either comma, newline, or quoted item)
while (regexResp = splitFinder.exec(parseMe)) {
const split = regexResp[0];
// if it's not a quote capture, add an item to the current row
// (quote captures will be pushed by the newline or comma following)
if (split.startsWith(`"`) === false) {
const splitStartIndex = splitFinder.lastIndex - split.length;
pushCell(splitStartIndex);
// then start a new row if newline
const isNewLine = /^\r?\n$/.test(split);
if (isNewLine) { rowsOut.push(currentRow = []); }
}
}
// make sure to add the trailing text (no commas or newlines after)
pushCell();
return rowsOut;
}
const rawCsv = `a,b,c\n"test\r\n","comma, test","\r\n",",",\nsecond,row,ends,with,empty\n"quote\"test"`
const rows = csvTo2dArray(rawCsv);
console.log(rows);
No regexp, readable, and according to https://en.wikipedia.org/wiki/Comma-separated_values#Basic_rules:
function csv2arr(str: string) {
let line = ["",];
const ret = [line,];
let quote = false;
for (let i = 0; i < str.length; i++) {
const cur = str[i];
const next = str[i + 1];
if (!quote) {
const cellIsEmpty = line[line.length - 1].length === 0;
if (cur === '"' && cellIsEmpty) quote = true;
else if (cur === ",") line.push("");
else if (cur === "\r" && next === "\n") { line = ["",]; ret.push(line); i++; }
else if (cur === "\n" || cur === "\r") { line = ["",]; ret.push(line); }
else line[line.length - 1] += cur;
} else {
if (cur === '"' && next === '"') { line[line.length - 1] += cur; i++; }
else if (cur === '"') quote = false;
else line[line.length - 1] += cur;
}
}
return ret;
}
If you can have your quote delimiter be double quotes, then this is a duplicate of Example JavaScript code to parse CSV data.
You can either translate all single-quotes to double-quotes first:
string = string.replace( /'/g, '"' );
...or you can edit the regex in that question to recognize single-quotes instead of double-quotes:
// Quoted fields.
"(?:'([^']*(?:''[^']*)*)'|" +
However, this assumes certain markup that is not clear from your question. Please clarify what all the various possibilities of markup can be, per my comment on your question.
I've used regex a number of times, but I always have to relearn it each time, which is frustrating :-)
So Here's a non-regex solution:
function csvRowToArray(row, delimiter = ',', quoteChar = '"'){
let nStart = 0, nEnd = 0, a=[], nRowLen=row.length, bQuotedValue;
while (nStart <= nRowLen) {
bQuotedValue = (row.charAt(nStart) === quoteChar);
if (bQuotedValue) {
nStart++;
nEnd = row.indexOf(quoteChar + delimiter, nStart)
} else {
nEnd = row.indexOf(delimiter, nStart)
}
if (nEnd < 0) nEnd = nRowLen;
a.push(row.substring(nStart,nEnd));
nStart = nEnd + delimiter.length + (bQuotedValue ? 1 : 0)
}
return a;
}
How it works:
Pass in the csv string in row.
While the start position of the next value is within the row, do the following:
If this value has been quoted, set nEnd to the closing quote.
Else if value has NOT been quoted, set nEnd to the next delimiter.
Add the value to an array.
Set nStart to nEnd plus the length of the delimeter.
Sometimes it's good to write your own small function, rather than use a library. Your own code is going to perform well and use only a small footprint. In addition, you can easily tweak it to suit your own needs.
Regular expressions to the rescue! These few lines of code properly handle quoted fields with embedded commas, quotes, and newlines based on the RFC 4180 standard.
function parseCsv(data, fieldSep, newLine) {
fieldSep = fieldSep || ',';
newLine = newLine || '\n';
var nSep = '\x1D';
var qSep = '\x1E';
var cSep = '\x1F';
var nSepRe = new RegExp(nSep, 'g');
var qSepRe = new RegExp(qSep, 'g');
var cSepRe = new RegExp(cSep, 'g');
var fieldRe = new RegExp('(?<=(^|[' + fieldSep + '\\n]))"(|[\\s\\S]+?(?<![^"]"))"(?=($|[' + fieldSep + '\\n]))', 'g');
var grid = [];
data.replace(/\r/g, '').replace(/\n+$/, '').replace(fieldRe, function(match, p1, p2) {
return p2.replace(/\n/g, nSep).replace(/""/g, qSep).replace(/,/g, cSep);
}).split(/\n/).forEach(function(line) {
var row = line.split(fieldSep).map(function(cell) {
return cell.replace(nSepRe, newLine).replace(qSepRe, '"').replace(cSepRe, ',');
});
grid.push(row);
});
return grid;
}
const csv = 'A1,B1,C1\n"A ""2""","B, 2","C\n2"';
const separator = ','; // field separator, default: ','
const newline = ' <br /> '; // newline representation in case a field contains newlines, default: '\n'
var grid = parseCsv(csv, separator, newline);
// expected: [ [ 'A1', 'B1', 'C1' ], [ 'A "2"', 'B, 2', 'C <br /> 2' ] ]
Unless stated elsewhere, you don't need a finite state machine. The regular expression handles RFC 4180 properly thanks to positive lookbehind, negative lookbehind, and positive lookahead.
Clone/download code at https://github.com/peterthoeny/parse-csv-js
I have also faced the same type of problem when I had to parse a CSV file.
The file contains a column address which contains the ',' .
After parsing that CSV file to JSON, I get mismatched mapping of the keys while converting it into a JSON file.
I used Node.js for parsing the file and libraries like baby parse and csvtojson.
Example of file -
address,pincode
foo,baar , 123456
While I was parsing directly without using baby parse in JSON, I was getting:
[{
address: 'foo',
pincode: 'baar',
'field3': '123456'
}]
So I wrote code which removes the comma(,) with any other delimiter
with every field:
/*
csvString(input) = "address, pincode\\nfoo, bar, 123456\\n"
output = "address, pincode\\nfoo {YOUR DELIMITER} bar, 123455\\n"
*/
const removeComma = function(csvString){
let delimiter = '|'
let Baby = require('babyparse')
let arrRow = Baby.parse(csvString).data;
/*
arrRow = [
[ 'address', 'pincode' ],
[ 'foo, bar', '123456']
]
*/
return arrRow.map((singleRow, index) => {
//the data will include
/*
singleRow = [ 'address', 'pincode' ]
*/
return singleRow.map(singleField => {
//for removing the comma in the feild
return singleField.split(',').join(delimiter)
})
}).reduce((acc, value, key) => {
acc = acc +(Array.isArray(value) ?
value.reduce((acc1, val)=> {
acc1 = acc1+ val + ','
return acc1
}, '') : '') + '\n';
return acc;
},'')
}
The function returned can be passed into the csvtojson library and thus the result can be used.
const csv = require('csvtojson')
let csvString = "address, pincode\\nfoo, bar, 123456\\n"
let jsonArray = []
modifiedCsvString = removeComma(csvString)
csv()
.fromString(modifiedCsvString)
.on('json', json => jsonArray.push(json))
.on('end', () => {
/* do any thing with the json Array */
})
Now you can get the output like:
[{
address: 'foo, bar',
pincode: 123456
}]
My answer presumes your input is a reflection of code/content from web sources where single and double quote characters are fully interchangeable provided they occur as an non-escaped matching set.
You cannot use regex for this. You actually have to write a micro parser to analyze the string you wish to split. I will, for the sake of this answer, call the quoted parts of your strings as sub-strings. You need to specifically walk across the string. Consider the following case:
var a = "some sample string with \"double quotes\" and 'single quotes' and some craziness like this: \\\" or \\'",
b = "sample of code from JavaScript with a regex containing a comma /\,/ that should probably be ignored.";
In this case you have absolutely no idea where a sub-string starts or ends by simply analyzing the input for a character pattern. Instead you have to write logic to make decisions on whether a quote character is used a quote character, is itself unquoted, and that the quote character is not following an escape.
I am not going to write that level of complexity of code for you, but you can look at something I recently wrote that has the pattern you need. This code has nothing to do with commas, but is otherwise a valid enough micro-parser for you to follow in writing your own code. Look into the asifix function of the following application:
https://github.com/austincheney/Pretty-Diff/blob/master/fulljsmin.js
To complement this answer
If you need to parse quotes escaped with another quote, example:
"some ""value"" that is on xlsx file",123
You can use
function parse(text) {
const csvExp = /(?!\s*$)\s*(?:'([^'\\]*(?:\\[\S\s][^'\\]*)*)'|"([^"\\]*(?:\\[\S\s][^"\\]*)*)"|"([^""]*(?:"[\S\s][^""]*)*)"|([^,'"\s\\]*(?:\s+[^,'"\s\\]+)*))\s*(?:,|$)/g;
const values = [];
text.replace(csvExp, (m0, m1, m2, m3, m4) => {
if (m1 !== undefined) {
values.push(m1.replace(/\\'/g, "'"));
}
else if (m2 !== undefined) {
values.push(m2.replace(/\\"/g, '"'));
}
else if (m3 !== undefined) {
values.push(m3.replace(/""/g, '"'));
}
else if (m4 !== undefined) {
values.push(m4);
}
return '';
});
if (/,\s*$/.test(text)) {
values.push('');
}
return values;
}
While reading the CSV file into a string, it contains null values in between strings, so try it with \0 line by line. It works for me.
stringLine = stringLine.replace(/\0/g, "" );
Try this one.
function parseCSV(csv) {
let quotes = [];
let token = /(?:(['"`])([\s\S]*?)\1)|([^\t,\r\n]+)\3?|([\r\n])/gm;
let text = csv.replace(/\\?(['"`])\1?/gm, s => s.length != 2 ? s : `_r#${quotes.push(s) - 1}`);
return [...text.matchAll(token)]
.map(t => (t[2] || t[3] || t[4])
.replace(/^_r#\d+$/, "")
.replace(/_r#\d+/g, q => quotes[q.replace(/\D+/, '')][1]))
.reduce((a, b) => /^[\r\n]$/g.test(b)
? a.push([]) && a
: a[a.length - 1].push(b) && a, [[]])
.filter(d => d.length);
}
Use the npm library csv-string to parse the strings instead of split: https://www.npmjs.com/package/csv-string
This will handle the comma in quotes and empty entries
This one is based on niry's answer but for semicolon:
'use strict';
function csvToArray(text) {
let p = '', row = [''], ret = [row], i = 0, r = 0, s = !0, l;
for (l of text) {
if ('"' === l) {
if (s && l === p) row[i] += l;
s = !s;
} else if (';' === l && s) l = row[++i] = '';
else if ('\n' === l && s) {
if ('\r' === p) row[i] = row[i].slice(0, -1);
row = ret[++r] = [l = '']; i = 0;
} else row[i] += l;
p = l;
}
return ret;
};
let test = '"one";"two with escaped """" double quotes""";"three; with; commas";four with no quotes;"five with CRLF\r\n"\r\n"2nd line one";"two with escaped """" double quotes""";"three, with; commas and semicolons";four with no quotes;"five with CRLF\r\n"';
console.log(csvToArray(test));
Aside from the excellent and complete answer from ridgerunner, I thought of a very simple workaround for when your backend runs PHP.
Add this PHP file to your domain's backend (say: csv.php)
<?php
session_start(); // Optional
header("content-type: text/xml");
header("charset=UTF-8");
// Set the delimiter and the End of Line character of your CSV content:
echo json_encode(array_map('str_getcsv', str_getcsv($_POST["csv"], "\n")));
?>
Now add this function to your JavaScript toolkit (should be revised a bit to make crossbrowser I believe).
function csvToArray(csv) {
var oXhr = new XMLHttpRequest;
oXhr.addEventListener("readystatechange",
function () {
if (this.readyState == 4 && this.status == 200) {
console.log(this.responseText);
console.log(JSON.parse(this.responseText));
}
}
);
oXhr.open("POST","path/to/csv.php",true);
oXhr.setRequestHeader("Content-type", "application/x-www-form-urlencoded; charset=utf-8");
oXhr.send("csv=" + encodeURIComponent(csv));
}
It will cost you one Ajax call, but at least you won't duplicate code nor include any external library.
Ref: http://php.net/manual/en/function.str-getcsv.php
You can use papaparse.js like the example below:
<!DOCTYPE html>
<html lang="en">
<head>
<title>CSV</title>
</head>
<body>
<input type="file" id="files" multiple="">
<button onclick="csvGetter()">CSV Getter</button>
<h3>The Result will be in the Console.</h3>
<script src="papaparse.min.js"></script>
<script>
function csvGetter() {
var file = document.getElementById('files').files[0];
Papa.parse(file, {
complete: function(results) {
console.log(results.data);
}
});
}
</script>
</body>
</html>
Don't forget to include papaparse.js in the same folder.
According to this blog post, this function should do it:
String.prototype.splitCSV = function(sep) {
for (var foo = this.split(sep = sep || ","), x = foo.length - 1, tl; x >= 0; x--) {
if (foo[x].replace(/'\s+$/, "'").charAt(foo[x].length - 1) == "'") {
if ((tl = foo[x].replace(/^\s+'/, "'")).length > 1 && tl.charAt(0) == "'") {
foo[x] = foo[x].replace(/^\s*'|'\s*$/g, '').replace(/''/g, "'");
} else if (x) {
foo.splice(x - 1, 2, [foo[x - 1], foo[x]].join(sep));
} else foo = foo.shift().split(sep).concat(foo);
} else foo[x].replace(/''/g, "'");
} return foo;
};
You would call it like so:
var string = "'string, duppi, du', 23, lala";
var parsed = string.splitCSV();
alert(parsed.join("|"));
This jsfiddle kind of works, but it looks like some of the elements have spaces before them.
I am so close to getting this, but it just isn't right.
All I would like to do is remove the character r from a string.
The problem is, there is more than one instance of r in the string.
However, it is always the character at index 4 (so the 5th character).
Example string: crt/r2002_2
What I want: crt/2002_2
This replace function removes both r
mystring.replace(/r/g, '')
Produces: ct/2002_2
I tried this function:
String.prototype.replaceAt = function (index, char) {
return this.substr(0, index) + char + this.substr(index + char.length);
}
mystring.replaceAt(4, '')
It only works if I replace it with another character. It will not simply remove it.
Any thoughts?
var mystring = "crt/r2002_2";
mystring = mystring.replace('/r','/');
will replace /r with / using String.prototype.replace.
Alternatively you could use regex with a global flag (as suggested by Erik Reppen & Sagar Gala, below) to replace all occurrences with
mystring = mystring.replace(/\/r/g, '/');
EDIT:
Since everyone's having so much fun here and user1293504 doesn't seem to be coming back any time soon to answer clarifying questions, here's a method to remove the Nth character from a string:
String.prototype.removeCharAt = function (i) {
var tmp = this.split(''); // convert to an array
tmp.splice(i - 1 , 1); // remove 1 element from the array (adjusting for non-zero-indexed counts)
return tmp.join(''); // reconstruct the string
}
console.log("crt/r2002_2".removeCharAt(4));
Since user1293504 used the normal count instead of a zero-indexed count, we've got to remove 1 from the index, if you wish to use this to replicate how charAt works do not subtract 1 from the index on the 3rd line and use tmp.splice(i, 1) instead.
A simple functional javascript way would be
mystring = mystring.split('/r').join('/')
simple, fast, it replace globally and no need for functions or prototypes
There's always the string functions, if you know you're always going to remove the fourth character:
str.slice(0, 4) + str.slice(5, str.length)
Your first func is almost right. Just remove the 'g' flag which stands for 'global' (edit) and give it some context to spot the second 'r'.
Edit: didn't see it was the second 'r' before so added the '/'. Needs \/ to escape the '/' when using a regEx arg. Thanks for the upvotes but I was wrong so I'll fix and add more detail for people interested in understanding the basics of regEx better but this would work:
mystring.replace(/\/r/, '/')
Now for the excessive explanation:
When reading/writing a regEx pattern think in terms of: <a character or set of charcters> followed by <a character or set of charcters> followed by <...
In regEx <a character or set of charcters> could be one at a time:
/each char in this pattern/
So read as e, followed by a, followed by c, etc...
Or a single <a character or set of charcters> could be characters described by a character class:
/[123!y]/
//any one of these
/[^123!y]/
//anything but one of the chars following '^' (very useful/performance enhancing btw)
Or expanded on to match a quantity of characters (but still best to think of as a single element in terms of the sequential pattern):
/a{2}/
//precisely two 'a' chars - matches identically as /aa/ would
/[aA]{1,3}/
//1-3 matches of 'a' or 'A'
/[a-zA-Z]+/
//one or more matches of any letter in the alphabet upper and lower
//'-' denotes a sequence in a character class
/[0-9]*/
//0 to any number of matches of any decimal character (/\d*/ would also work)
So smoosh a bunch together:
var rePattern = /[aA]{4,8}(Eat at Joes|Joes all you can eat)[0-5]+/g
var joesStr = 'aaaAAAaaEat at Joes123454321 or maybe aAaAJoes all you can eat098765';
joesStr.match(rePattern);
//returns ["aaaAAAaaEat at Joes123454321", "aAaAJoes all you can eat0"]
//without the 'g' after the closing '/' it would just stop at the first match and return:
//["aaaAAAaaEat at Joes123454321"]
And of course I've over-elaborated but my point was simply that this:
/cat/
is a series of 3 pattern elements (a thing followed by a thing followed by a thing).
And so is this:
/[aA]{4,8}(Eat at Joes|Joes all you can eat)[0-5]+/
As wacky as regEx starts to look, it all breaks down to series of things (potentially multi-character things) following each other sequentially. Kind of a basic point but one that took me a while to get past so I've gone overboard explaining it here as I think it's one that would help the OP and others new to regEx understand what's going on. The key to reading/writing regEx is breaking it down into those pieces.
Just fix your replaceAt:
String.prototype.replaceAt = function(index, charcount) {
return this.substr(0, index) + this.substr(index + charcount);
}
mystring.replaceAt(4, 1);
I'd call it removeAt instead. :)
For global replacement of '/r', this code worked for me.
mystring = mystring.replace(/\/r/g,'');
This is improvement of simpleigh answer (omit length)
s.slice(0, 4) + s.slice(5)
let s = "crt/r2002_2";
let o = s.slice(0, 4) + s.slice(5);
let delAtIdx = (s, i) => s.slice(0, i) + s.slice(i + 1); // this function remove letter at index i
console.log(o);
console.log(delAtIdx(s, 4));
let str = '1234567';
let index = 3;
str = str.substring(0, index) + str.substring(index + 1);
console.log(str) // 123567 - number "4" under index "3" is removed
return this.substr(0, index) + char + this.substr(index + char.length);
char.length is zero. You need to add 1 in this case in order to skip character.
Maybe I'm a noob, but I came across these today and they all seem unnecessarily complicated.
Here's a simpler (to me) approach to removing whatever you want from a string.
function removeForbiddenCharacters(input) {
let forbiddenChars = ['/', '?', '&','=','.','"']
for (let char of forbiddenChars){
input = input.split(char).join('');
}
return input
}
Create function like below
String.prototype.replaceAt = function (index, char) {
if(char=='') {
return this.slice(0,index)+this.substr(index+1 + char.length);
} else {
return this.substr(0, index) + char + this.substr(index + char.length);
}
}
To replace give character like below
var a="12346";
a.replaceAt(4,'5');
and to remove character at definite index, give second parameter as empty string
a.replaceAt(4,'');
If it is always the 4th char in yourString you can try:
yourString.replace(/^(.{4})(r)/, function($1, $2) { return $2; });
It only works if I replace it with another character. It will not simply remove it.
This is because when char is equal to "", char.length is 0, so your substrings combine to form the original string. Going with your code attempt, the following will work:
String.prototype.replaceAt = function (index, char) {
return this.substr(0, index) + char + this.substr(index + 1);
// this will 'replace' the character at index with char ^
}
DEMO
You can use this: if ( str[4] === 'r' ) str = str.slice(0, 4) + str.slice(5)
Explanation:
if ( str[4] === 'r' )
Check if the 5th character is a 'r'
str.slice(0, 4)
Slice the string to get everything before the 'r'
+ str.slice(5)
Add the rest of the string.
Minified: s=s[4]=='r'?s.slice(0,4)+s.slice(5):s [37 bytes!]
DEMO:
function remove5thR (s) {
s=s[4]=='r'?s.slice(0,4)+s.slice(5):s;
console.log(s); // log output
}
remove5thR('crt/r2002_2') // > 'crt/2002_2'
remove5thR('crt|r2002_2') // > 'crt|2002_2'
remove5thR('rrrrr') // > 'rrrr'
remove5thR('RRRRR') // > 'RRRRR' (no change)
If you just want to remove single character and
If you know index of a character you want to remove, you can use following function:
/**
* Remove single character at particular index from string
* #param {*} index index of character you want to remove
* #param {*} str string from which character should be removed
*/
function removeCharAtIndex(index, str) {
var maxIndex=index==0?0:index;
return str.substring(0, maxIndex) + str.substring(index, str.length)
}
I dislike using replace function to remove characters from string. This is not logical to do it like that. Usually I program in C# (Sharp), and whenever I want to remove characters from string, I use the Remove method of the String class, but no Replace method, even though it exists, because when I am about to remove, I remove, no replace. This is logical!
In Javascript, there is no remove function for string, but there is substr function. You can use the substr function once or twice to remove characters from string. You can make the following function to remove characters at start index to the end of string, just like the c# method first overload String.Remove(int startIndex):
function Remove(str, startIndex) {
return str.substr(0, startIndex);
}
and/or you also can make the following function to remove characters at start index and count, just like the c# method second overload String.Remove(int startIndex, int count):
function Remove(str, startIndex, count) {
return str.substr(0, startIndex) + str.substr(startIndex + count);
}
and then you can use these two functions or one of them for your needs!
Example:
alert(Remove("crt/r2002_2", 4, 1));
Output: crt/2002_2
Achieving goals by doing techniques with no logic might cause confusions in understanding of the code, and future mistakes, if you do this a lot in a large project!
The following function worked best for my case:
public static cut(value: string, cutStart: number, cutEnd: number): string {
return value.substring(0, cutStart) + value.substring(cutEnd + 1, value.length);
}
The shortest way would be to use splice
var inputString = "abc";
// convert to array and remove 1 element at position 4 and save directly to the array itself
let result = inputString.split("").splice(3, 1).join();
console.log(result);
This problem has many applications. Tweaking #simpleigh solution to make it more copy/paste friendly:
function removeAt( str1, idx) {
return str1.substr(0, idx) + str1.substr(idx+1)
}
console.log(removeAt('abbcdef', 1)) // prints: abcdef
Using [index] position for removing a specific char (s)
String.prototype.remplaceAt = function (index, distance) {
return this.slice(0, index) + this.slice(index + distance, this.length);
};
credit to https://stackoverflow.com/users/62576/ken-white
So basically, another way would be to:
Convert the string to an array using Array.from() method.
Loop through the array and delete all r letters except for the one with index 1.
Convert array back to a string.
let arr = Array.from("crt/r2002_2");
arr.forEach((letter, i) => { if(letter === 'r' && i !== 1) arr[i] = "" });
document.write(arr.join(""));
In C# (Sharp), you can make an empty character as '\0'.
Maybe you can do this:
String.prototype.replaceAt = function (index, char) {
return this.substr(0, index) + char + this.substr(index + char.length);
}
mystring.replaceAt(4, '\0')
Search on google or surf on the interent and check if javascript allows you to make empty characters, like C# does. If yes, then learn how to do it, and maybe the replaceAt function will work at last, and you'll achieve what you want!
Finally that 'r' character will be removed!