I use promises in my website (still learning) and I would like to know if there is a difference between this:
return promise
.then(ctxTransport.getTransportById(idTran, transport))
.then(checkLocking)
.fail(somethingWrong);
and this:
return promise
.then(function () { return ctxTransport.getTransportById(idTran, transport); })
.then(function () { return checkLocking(); })
.fail(somethingWrong);
With the first implementation sometimes I got errors.
var getTransportById = function (transportId, transportObservable, forceRemote) {
// Input: transportId: the id of the transport to retrieve
// Input: forceRemote: boolean to force the fetch from server
// Output: transportObservable: an observable filled with the transport
...
return manager.executeQuery(query)
.then(querySucceeded)
.fail(queryFailed);
function querySucceeded(data) {
transportObservable(data.results[0]);
}
};
function checkLocking() {
var now = new Date();
transport().lockedById(5);
transport().lockedTime(now);
return ctxTransport.saveChanges(SILENTSAVE);
}
function somethingWrong(error) {
var msg = 'Error retreiving data. ' + error.message;
logError(msg, error);
throw error;
}
Thanks.
When passing functions in the promise chain, you're supposed to pass the function names without arguments or the (), or as in the second case, anonymous functions. This is because Q will call it for you with the result/return value of the previous promise resolution.
Therefore, .then(ctxTransport.getTransportById(idTran, transport)) is semantically incorrect, since you're not passing a function, but the return value of ctxTransport.getTransportById.
Related
I'm new to Node/Express and am trying to use Promises to executive successive API calls to Apple's CloudKit JS API.
I'm unclear on how to put the functions in sequence and pass their respective return values from one function to the next.
Here's what I have so far:
var CloudKit = require('./setup')
//----
var fetchUserRecord = function(emailConfirmationCode){
var query = { ... }
// Execute the query
CloudKit.publicDB.performQuery(query).then(function (response) {
if(response.hasErrors) {
return Promise.reject(response.errors[0])
}else if(response.records.length == 0){
return Promise.reject('Email activation code not found.')
}else{
return Promise.resolve(response.records[0])
}
})
}
//-----
var saveRecord = function(record){
// Update the record (recordChangeTag required to update)
var updatedRecord = { ... }
CloudKit.publicDB.saveRecords(updatedRecord).then(function(response) {
if(response.hasErrors) {
Promise.reject(response.errors[0])
}else{
Promise.resolve()
}
})
}
//----- Start the Promise Chain Here -----
exports.startActivation = function(emailConfirmationCode){
CloudKit.container.setUpAuth() //<-- This returns a promise
.then(fetchUserRecord) //<-- This is the 1st function above
.then(saveRecord(record)) //<-- This is the 2nd function above
Promise.resolve('Success!')
.catch(function(error){
Promise.reject(error)
})
}
I get an error near the end: .then(saveRecord(record)) and it says record isn't defined. I thought it would somehow get returned from the prior promise.
It seems like this should be simpler than I'm making it, but I'm rather confused. How do I get multiple Promises to chain together like this when each has different resolve/reject outcomes?
There are few issues in the code.
First: you have to pass function to .then() but you actually passes result of function invocation:
.then(saveRecord(record))
Besides saveRecord(record) technically may return a function so it's possible to have such a statement valid it does not seem your case. So you need just
.then(saveRecord)
Another issue is returning nothing from inside saveRecord and fetchUserRecord function as well.
And finally you don't need to return wrappers Promise.resolve from inside .then: you may return just transformed data and it will be passed forward through chaining.
var CloudKit = require('./setup')
//----
var fetchUserRecord = function(emailConfirmationCode){
var query = { ... }
// Execute the query
return CloudKit.publicDB.performQuery(query).then(function (response) {
if(response.hasErrors) {
return Promise.reject(response.errors[0]);
}else if(response.records.length == 0){
return Promise.reject('Email activation code not found.');
}else{
return response.records[0];
}
})
}
//-----
var saveRecord = function(record){
// Update the record (recordChangeTag required to update)
var updatedRecord = { ... }
return CloudKit.publicDB.saveRecords(updatedRecord).then(function(response) {
if(response.hasErrors) {
return Promise.reject(response.errors[0]);
}else{
return Promise.resolve();
}
})
}
//----- Start the Promise Chain Here -----
exports.startActivation = function(emailConfirmationCode){
return CloudKit.container.setUpAuth() //<-- This returns a promise
.then(fetchUserRecord) //<-- This is the 1st function above
.then(saveRecord) //<-- This is the 2nd function above
.catch(function(error){});
}
Don't forget returning transformed data or new promise. Otherwise undefined will be returned to next chained functions.
Since #skyboyer helped me figure out what was going on, I'll mark their answer as the correct one.
I had to tweak things a little since I needed to pass the returned values to subsequent functions in my promise chain. Here's where I ended up:
exports.startActivation = function(emailConfirmationCode){
return new Promise((resolve, reject) => {
CloudKit.container.setUpAuth()
.then(() => {
return fetchUserRecord(emailConfirmationCode)
})
.then((record) => {
resolve(saveRecord(record))
}).catch(function(error){
reject(error)
})
})
}
I am new to nodejs and using promise and actually this is my first real app with nodejs.
So i have been reading all day and i am a bit confused.
So this is my module :
function User() {
var self = this;
self.users = {};
self.start = function (user, botId) {
return new Promise(function () {
return get(user).then(function (data) {
debug(data);
if (data.botId.indexOf(botId) === false) {
return Repo.UserBotModel.addUser(user.id, botId).then(function () {
data.botId.push(botId);
return data;
});
} else
return data;
});
});
};
self.getDisplayName = function (user) {
if (user.real_name)
return user.real_name;
if (user.last_name)
return user.firstname + ' ' + user.last_name;
return user.first_name;
};
/**
* check if user exist in our database/memory cache and return it,
* otherwise insert in the database and cache it in memory and the return it
* #param user
*/
function get(user) {
return new Promise(function () {
//check if user is loaded in our memory cache
if (self.users.hasOwnProperty(user.id))
return self.users[user.id];
else {
//get from database if exist
return Repo.UserModel.get(user.id).then(function (rows) {
if (rows && rows.length) {
//user exist cache it and resolve
var data = rows[0];
if (data.botId && data.botId.length)
data.botId = data.botId.split(',');
else
data.botId = [];
self.users[user.id] = data;
//------------------------------ code execution reaches here
return data;
}
else {
//user dose not exist lets insert it
return Repo.UserModel.insert(user).then(function (result) {
return get(user);
});
}
});
}
});
}
}
I call the start method witch calls the private get method the call reaches return data;(marked with comment) but then function dose not gets executed in the start method ???
So what am i doing wrong?
UPDATE : Sorry I forgot to mention that I am using bluebird and not the native promise if that makes a difference?
You cannot return from the Promise constructor - you have to call resolve (expected to happen asynchronously). You're not supposed to use the Promise constructor at all here. You can just omit it, and it should work.
The methods from your Repo.UserModel already return promises, so you do not have to create new ones using new Promise.
You can read the values inside those promises using then.
then also provides a way to transform promises. If you return a value in a function passed to then, then will return a new promise that wraps the value you returned. If this value is a promise, it will be awaited.
To convert a value to a promise, you can use Promise.resolve.
Knowing that, you can simplify get like so:
function get(user) {
if (...) {
return Promise.resolve(...)
} else {
return Repo.UserModel.get(...).then(function(rows) {
...
return ...
})
}
}
This version of getwill always return a promise that you can use like so:
get(...).then(function(resultOfGet) {
// process resultOfGet
})
it is a common pattern that we cascade across a list of sources of data with the first success breaking the chain like this:
var data = getData1();
if (!data) data = getData2();
if (!data) data = getData3();
et cetera. if the getDataN() functions are asynchronous, however, it leads us to 'callback hell':
var data;
getData1(function() {
getData2(function () {
getData3(function () { alert('not found'); })
})
});
where the implementations may look something like:
function getData1(callback) {
$.ajax({
url: '/my/url/1/',
success: function(ret) { data = ret },
error: callback
});
}
...with promises I would expect to write something like this:
$.when(getData1())
.then(function (x) { data = x; })
.fail(function () { return getData2(); })
.then(function (x) { data = x; })
.fail(function () { return getData3(); })
.then(function (x) { data = x; });
where the second .then actually refers to the return value of the first .fail, which is itself a promise, and which I understood was chained in as the input to the succeeding chain step.
clearly I'm wrong but what is the correct way to write this?
In most promise libs, you could chain .fail() or .catch() as in #mido22's answer, but jQuery's .fail() doesn't "handle" an error as such. It is guaranteed always to pass on the input promise (with unaltered state), which would not allow the required "break" of the cascade if/when success happens.
The only jQuery Promise method that can return a promise with a different state (or different value/reason) is .then().
Therefore you could write a chain which continues on error by specifying the next step as a then's error handler at each stage.
function getDataUntilAsyncSuccess() {
return $.Deferred().reject()
.then(null, getData1)
.then(null, getData2)
.then(null, getData3);
}
//The nulls ensure that success at any stage will pass straight through to the first non-null success handler.
getDataUntilAsyncSuccess().then(function (x) {
//"success" data is available here as `x`
}, function (err) {
console.log('not found');
});
But in practice, you might more typically create an array of functions or data objects which are invoked in turn with the help of Array method .reduce().
For example :
var fns = [
getData1,
getData2,
getData3,
getData4,
getData5
];
function getDataUntilAsyncSuccess(data) {
return data.reduce(function(promise, fn) {
return promise.then(null, fn);
}, $.Deferred().reject());// a rejected promise to get the chain started
}
getDataUntilAsyncSuccess(fns).then(function (x) {
//"success" data is available here as `x`
}, function (err) {
console.log('not found');
});
Or, as is probably a better solution here :
var urls = [
'/path/1/',
'/path/2/',
'/path/3/',
'/path/4/',
'/path/5/'
];
function getDataUntilAsyncSuccess(data) {
return data.reduce(function(promise, url) {
return promise.then(null, function() {
return getData(url);// call a generalised `getData()` function that accepts a URL.
});
}, $.Deferred().reject());// a rejected promise to get the chain started
}
getDataUntilAsyncSuccess(urls).then(function (x) {
//"success" data is available here as `x`
}, function (err) {
console.log('not found');
});
As a beginner, stumbling across the same problem, I just realized how much simpler this has become with async and await:
The synchronous pattern
var data = getData1();
if (!data) data = getData2();
if (!data) data = getData3();
can now easily be applied to asynchronous code:
let data = await getData1();
if (!data) data = await getData2();
if (!data) data = await getData3();
Just remember to add an async to the function that this code is used in.
I think I have got my head around Parse promise chains, but what I don't understand is how I return my data from the functions (i) back up the promise chain and (ii) back to the calling method of my original JS code.
Using the code below, the first Parse query is called, then a() and finally b() which is all fine. The console.log at each stage are for test purposes and show that the chains have been executed and in order.
I now have 3 questions:
How do I get the data back from function a() and function b() so I can access it in the main function getUserCompetitionTokens()?
How do I return any data from getUserCompetitionTokens() to the main program which has called this Parse code?
What if I want the data from function a() and also from function b() to BOTH be returned to my main program?
function getUserCompetitionTokens(comp_id) {
Parse.initialize("****","****");
currentUser = Parse.User.current();
user_competition = Parse.Object.extend("UserCompetition");
var user_comp_query = new Parse.Query(user_competition);
user_comp_query.equalTo("UserParent", currentUser);
user_comp_query.find().then(a).then(b);
function a(user_comp_results) {
var no_results = user_comp_results.length;
var id = user_comp_results[0].id;
console.log("User Competition Output: " + no_results + " results found, first item id: " + id);
var Competition = Parse.Object.extend("Competition");
var query = new Parse.Query(Competition);
return query.get(comp_id, {
success: function(competition) {
console.log("COMP - " + competition.id);
},
error: function(competition, error) {
console.log(error);
}
});
}
function b(competition) {
var Competition = Parse.Object.extend("Competition");
var query = new Parse.Query(Competition);
query.get(comp_id, {
success: function(competition) {
console.log("COMP 2 - " + competition.id);
},
error: function(competition, error) {console.log(error);}
});
}
}
You don't return :)
I'm sorry, that is just a joke on a technicality: you see, Promises are a way to express asynchronous behaviour. So you can't, strictly saying, grab the return value of a function.
However, you are already grabbing the results of each step correctly... You just didn't realize you can use it yourself.
The answer is to use your own then handler.
user_comp_query.find().then(a).then(b).then(function(results){
console.log(results); // Hooray!
});
However, keep in mind that a Promise might fail. That's why it's important to pass a second handler, which will be called whenever there is an error.
var handleSuccess = function (results) {};
var handleFailure = function (error) {};
var parsePromise = user_comp_query.find().then(a).then(b);
parsePromise.then(handleSuccess, handleFailure);
I'm trying to get my head around promises in JavaScript. I feel like I know what a promise is. However, I don't understand how to use them. In an attempt to learn, I decided to query a database from Node.js. In my code, I have one JavaScript file called test.js. Test.js looks like this:
Test.js
'use strict';
module.exports = function (app) {
var customerService = require('customer.js')(app);
var getCustomerTest = function() {
customerService.getCustomer(1).then(
function (customer) { console.log(customer); },
function (error) { console.log(error); }
);
};
};
Customer.js
'use strict';
module.exports = function(app) {
var _ = require('lodash');
var db = require('db');
return {
getCustomer: function(customerID) {
try {
console.log('querying the database...');
var database = db.connect(CONNECTION_STRING);
database.query('select * from customers where [ID]="' + customerID + '", function(error, result, response) {
if (error) {
// trigger promise error
} else {
// This throws an exception because displayMessage can't be found.
this.displayMessage('Success');
// trigger promise success
}
});
} catch (ex) {
// trigger promise error
}
},
displayMessage: function(message) {
console.log(new Date() + ' - ' + message);
}
};
};
I'm struggling trying to setup the promise in getCustomer. Especially since the call to the database call happens asynchronously. I feel like my call to customerService.getCustomer is the correct approach. However, once inside of getCustomer, I have two issues:
How do I setup / return my promise?
Why can't I call displayMessage after the database query is done? How do I do this?
Thank you JavaScript whiz!
"Why can't I call displayMessage after the database query is done"
You are getting the error because this is not referencing the object that contains getCustomer and displayMessage. This is because you are in a callback function and the context has changed.
You need to save a reference to the correct context and use that to access displayMessage
getCustomer: function(customerID) {
//saving the context
var that = this;
try {
...
database.query('select * from customers where [ID]="' + customerID + '", function(error, result, response) {
...
// Now use it here to call displayMessage
that.displayMessage('Success');
...
}
});
} catch (ex) {
...
}
},
"How do I setup / return my promise?"
You will need a promise library (unless you plan to make your own). For this I will show the use of the q library
There are a couple ways of doing this, but I will show the use of deferreds.
The basic process is:
Create a deferred object in a function that will call an async function/method.
Return the promise object
Set the appropriate callbacks for then/fail/fin etc on the promise object.
In the callback of the async function resolve or reject the deferred, passing any arguments that will be needed in the callbacks.
The appropriate callbacks that were set in step 2 will then be called in order.
Code
var Q = require("q");
...
getCustomer:{
var deferred = Q.defer(),
database = db.connect(CONNECTION_STRING);
database.query("some query", function(error, result, response) {
if(error){
//Anything passed will be passed to any fail callbacks
deferred.reject(error);
} else {
//Anything passed will be passed to any success callbacks
deferred.resolve(response);
}
});
//Return the promise
return deferred.promise;
}
...
customerService.getCustomer(1).then(function (customer) {
console.log(customer);
}).fail(function (error) {
console.log(error);
}).done();
The q library has quite a few helpful api functions. Some help with getting promises with Node async functions. Read the Adapting Node section of the readme to see how it is done.
JSFiddle Demo demonstrating in browser use of q