I have a three divs which slide in, they all have a z-order of 0, they can all slide in at different points and in different orders.
When then are all showing, how do I find out what order the divs are in, I want to be able to slide them back in with a delay on each.
Thanks
I guess your DIV's are slided in by a function of you or of jQuery. You can "override" this function. At this overriding you can put a mechanism that saves for example timestamp for the slided in DIV.
So you'll later be able to find out the order the div's have been shown in.
About overriding JavaScript-/jQuery-functions there are many good entries on Stackoverflow.
For example: Override jQuery functions
Related
I have a site where I want to be able to show or hide a div based on both user input (clicking/tapping a button) and screen size:
a) If the screen width is greater than a certain size, show the div but allow the user to hide it.
b) If the screen with is less than a certain size, hide the div but allow the user to reveal it.
What I'm struggling with is getting these two requirements to interact properly.
I'm using Foundation 5 and jQuery, so both parts of this are possible - Foundation's "show-for-foo-up" handles initial visibility, and there are numerous jQuery functions that allow a div to be toggled between visible and hidden. But what I can't seem to do is find a way to allow a user click to reveal a div that has initially been hidden by Foundation's media query, or a way to do a pure jQuery toggle (ignoring Foundation) that sets the initial visibility according to screen size.
What makes this more complex is that the div contains a form. So I can't simply repeat it in two different divs and toggle between them, as doing that would either mean duplicate element ids or two different forms, both of which aren't possible in this scenario.
Does anyone have any suggestions? I'm open to either a jQuery solution, a Foundation solution or a pure javascript solution, just so long as it works!
Yes, CBroe's comment put me on the right track and my assumption thereafter was correct. All it needs is to use jQuery to alter the class of the div to add or remove the class which uses a media query. Dunno why I didn't think of this before, really.
I'm trying to replicate jQuery slideDown() in GSAP and I'm having trouble working out how jQuery calculates the height of an item which is currently hidden as if it was set to height:auto.
I've tried trawling the code on GitHub but can't find any code which seems to be doing this in jQuery.fn.slideDown or jQuery.fn.animate which it calls.
There are several similar questions on SO and several solutions proposed, all of which seem to have their own problems:
Clone the element, position it off screen and calculate its height. This won't work if the element or any of its child elements have a height set by CSS styles which require the element to be in its original place in the DOM (e.g. an .accordianItem might only be styled if it's inside its .accordian).
Display the item, remove height:0 and quickly calculate the height before hiding the element again and then stating the animation. This might flash the content quickly while calculating the height.
Use visibility:true to show it in place while calculating the height. This would stop the flash and still keep the element in the same position in the DOM for correct height calculation, but it would still push other items below it down because visibility:false items still have a height.
Calculate the height of an item before it's hidden and store it in a data attribute so we know it when we want to open the item later. This won't work if any dynamic content changes the height of the item whilst it's hidden.
jQuery slideDown() "just works" every time so I'd be really interested to know how it works, but I just can't work out where it's doing this. I'm also surprised that GSAP can't do this out of the box, or that nobody has shared a proper solution to this before.
Any help would really be appreciated.
It turns out that if you use $.height() to get the height of an element with display:none it doesn't return 0 as you would expect, it actually sets visibility:hidden, position:absolute etc. and sets display to block to give you the correct height back. I assume this is what's being used internally when doing a slidedown.
This answer helped me a lot.
jQuery: height()/width() and "display:none"
Just to be clear about how this seems to avoid all the problems in my original question. It's basically doing number (3) but avoiding the problem of pushing lower content down the page because it's also set to position:absolute while the height is being calculated. A very simple elegant solution
I'm currently taking a web development class and looking to go beyond the "scope" of the class. I managed to create a jquery slide show in a div, now id like to show case some other features in two other divs, stack them into a single div and and call them via a set of toggles. Any methods or roads that can be suggested?
By stacked I mean three divs, one on top of the other. One of these divs is a jquery slider. I'd like a toggle to show one and hide the other two. I'll try and post code after I make it home from work.
Not sure what you mean by "stack", but jQuery Accordion might be a simple solution to get what you're looking for.
It also has methods that you could call from other ~buttons~ to trigger to show/hide effect.
You could even make the three divs into a slide show that is triggered by clicking some navigation like forward and back arrows. Look into the Anything Slider.
I need a jQuery scroller to scroll my divs with auto scrolling facility. I am looking for something like jCarousel.
But there are limitations for this. What I want is one which;
1. Scrolls <div>s (or some html elements) and not just images. I may have something like the picture below, to scroll.
It is a text and image combination.
2. It should auto scroll contents
3. The slider should MARQUE continuously and should not rewind to beginning. The slider should not rewind (in the opposite direction) to go for first image/content after the last image/content.
What jcarousel is doing is in autoscroll mode, it shows a set of of images/contents at a time, stop for a while, and then immediately displays the next set. I don't want this and want to autoscroll contents smoothly in a loop. That is, first content should come after last content, in circular loop.
I can provide additional details. just post comments.
Anybody got what I am trying to say and what I want and suggest me a solution?
You can do this without a plugin with some fairly simple jQuery.
See an example here that I put together for another answer:
http://jsfiddle.net/6Dxg6/
Basically, the idea is you clone the contents of a wrapper, and then continually move the contents to the right/left the width of the original content and then reset. Works with any content.
That code even includes hover-stop functionality. Without that, the code is simpler still:
http://jsfiddle.net/qJZtp/1/
I'm creating a custom select plugin. Everything is going great, but the dropdowns (<ul>-objects) are overlapping on each other :(
I understand, that the overlapping order is set after the elements order on page or when they are created. So my question is: What is the method to make the latest opened/shown object (<ul>) on top of the hierarchy?
I just need the correct method. I'm not going to copy the full code, but a little example:
$('#trigger').click(function () {
new_dropdown.slideDown();
});
(A picture is worth of 1000 words)
So lets say, that I open the green select the last.. How can I make it on top of the yellow one?
EDIT
For easier testing I created jsfiddle. For future references I'll post the link: http://jsfiddle.net/hobobne/uZV5p/1/ This is the live demo of the problem at hand.
What you're looking for is the CSS z-index property (higher values put elements at the front).
You could probably just set them in ascending order (e.g. set green one to 1000, yellow to 1001), but if you really need to bring it to the front when clicked, you can change the z-index with javascript
var zindex=100;
$("#trigger").click( function() {
newdropdown.css('z-index', ++zindex);
});
Here's a demo: http://jsfiddle.net/waitinforatrain/Vf7Hu/ (click the red and blue divs to bring to front).
Edit: gilly3's approach is better, and as was mentioned there may be some issues with older versions of IE.
Two ways:
Set a z-index
Setting a z-index will change the default stacking order. You can have a counter that increments and use that to set the z-index of newly stacked items. You may have issues with IE 7 or earlier, though, and those can be fixed by setting the z-index of other items. https://developer.mozilla.org/en/Understanding_CSS_z-index/Adding_z-index
Use absolute positioning, and append the div to the body
If you use absolute positioning, you can append the div to the body and still have it appear below the element. If you append the div to the body, the one last added should be on top, because of the default stacking order.
Give it a class when it is opened, and remove that class from the previously opened ones:
$(".slidedown_active").removeClass("slidedown_active");
$(this).addClass(".slidedown_active");
Then your users can use z-index in their style definition for that class to ensure the active list is always visible.
The reason I don't recommend setting the z-index directly is because you can mess up your users' layout unnecessarily. These kind of overlap issues can be a real headache for a web developer. For a plugin to try to guess at how to resolve overlap issues, without any knowledge of the code or design, would be virtually impossible. Instead, give your users the tools they need to fix the overlap issues themselves. It may be that your users would never encounter overlap issues, so setting the z-index for them would be pointless at best, and potentially harmful.