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Make Regex match to the first occurance

I have a string like this:
*asdasda**asdasdaSD*
And I want to split it into 2 half
*asdasda*
*asdasdaSD*
I'm unsure of how to do this in Regex. This is my current one \*.+\*, but it will match from the start to the end. How can I make it only match the first one it finds?

This should do it.
let answer = '*asdasda**asdasdaSD*'.match(/\*[^*]{1,}\*/g);
// answer[0] equals *asdasda*
Thanks!

Split and grab text before second hyphen

I have the following text string:
test-shirt-print
I want to filter the text string so that it only returns me:
test-shirt
Meaning that everything that comes after the second hyphen should be removed including the hyphen.
I am thinking that the solution could be to split on hyphen and somehow select the two first values, and combine them again.
I am unaware of which functionality is best practice to use here, I also thinking that if it would be possible to use a regular expression in order to be able to select everything before the second hyphen.

You can use split slice and join together to remove everything after the second hyphen
var str = "test-shirt-print";
console.log(str.split("-").slice(0, 2).join('-'))

You can try with String.prototype.slice()
The slice() method extracts a section of a string and returns it as a new string, without modifying the original string.
and String.prototype.lastIndexOf()
The lastIndexOf() method returns the index within the calling String object of the last occurrence of the specified value, searching backwards from fromIndex. Returns -1 if the value is not found.
var str = 'test-shirt-print';
var res = str.slice(0, str.lastIndexOf('-'));
console.log(res);
You can also use split() to take the first two items and join them:
var str = 'test-shirt-print';
var res = str.split('-').slice(0,2).join('-');
console.log(res);

Extract numeric and text parts of a string, in varying formats

I'm trying to put together a RegEx to split a variety of possible user inputs, and while I've managed to succeed with some cases, I've not managed to cover every case that I'd like to.
Possible inputs, and expected outputs
"1 day" > [1,"day"]
"1day" > [1,"day"]
"10,000 days" > [10000,"days"]
Is it possible to split the numeric and text parts from the string without necessarily having a space, and to also remove the commas etc from the string at the same time?
This is what I've got at the moment
[a-zA-Z]+|[0-9]+
Which seems to split the numeric and text portions nicely, but is tripped up by commas. (Actually, as I write this, I'm thinking I could use the last part of the results array as the text part, and concatenate all the other parts as the numeric part?)

var test = [
'1 day',
'1day',
'10,000 days',
];
console.log(test.map(function (a) {
a = a.replace(/(\d),(\d)/g, '$1$2'); // remove the commas
return a.match(/^(\d+)\s*(.+)$/); // split in two parts
}));

This regular expression works, apart from removing the comma from the matched number string:
([0-9,]+]) *(.*)
You cannot "ignore" a character in a returned regular expression match string, so you will just have to remove the comma from the returned regex match afterwards.

Javascript regex match returning a string with comma at the end

Just as the title says...i'm trying to parse a string for example
2x + 3y
and i'm trying to get only the coefficients (i.e. 2 and 3)
I first tokenized it with space character as delimiter giving me "2x" "+" "3y"
then i parsed it again to this statement to get only the coefficients
var number = eqTokens[i].match(/(\-)?\d+/);
I tried printing the output but it gave me "2,"
why is it printing like this and how do i fix it? i tried using:
number = number.replace(/[,]/, "");
but this just gives me an error that number.replace is not a function

What's wrong with this?
> "2x + 3y".match(/-?\d+(?=[A-Za-z]+)/g)
[ '2', '3' ]
The above regex would match the numbers only if it's followed by one or more alphabets.

Match is going to return an array of every match. Since you put the optional negative in a parentheses, it's another capture group. That capture group has one term and it's optional, so it'll return an empty match in addition to your actual match.
Input 2x -> Your output: [2,undefined] which prints out as "2,"
Input -2x -> Your output: [2,-]
Remove the parentheses around the negative.
This is just for the sake of explaining why your case is breaking but personally I'd use Avinash's answer.

Javascript Regex: replacing the last dot for a comma

I have the following code:
var x = "100.007"
x = String(parseFloat(x).toFixed(2));
return x
=> 100.01
This works awesomely just how I want it to work. I just want a tiny addition, which is something like:
var x = "100,007"
x.replace(",", ".")
x.replace
x = String(parseFloat(x).toFixed(2));
x.replace(".", ",")
return x
=> 100,01
However, this code will replace the first occurrence of the ",", where I want to catch the last one. Any help would be appreciated.

You can do it with a regular expression:
x = x.replace(/,([^,]*)$/, ".$1");
That regular expression matches a comma followed by any amount of text not including a comma. The replacement string is just a period followed by whatever it was that came after the original last comma. Other commas preceding it in the string won't be affected.
Now, if you're really converting numbers formatted in "European style" (for lack of a better term), you're also going to need to worry about the "." characters in places where a "U.S. style" number would have commas. I think you would probably just want to get rid of them:
x = x.replace(/\./g, '');
When you use the ".replace()" function on a string, you should understand that it returns the modified string. It does not modify the original string, however, so a statement like:
x.replace(/something/, "something else");
has no effect on the value of "x".

You can use a regexp. You want to replace the last ',', so the basic idea is to replace the ',' for which there's no ',' after.
x.replace(/,([^,]*)$/, ".$1");
Will return what you want :-).

You could do it using the lastIndexOf() function to find the last occurrence of the , and replace it.
The alternative is to use a regular expression with the end of line marker:
myOldString.replace(/,([^,]*)$/, ".$1");

You can use lastIndexOf to find the last occurence of ,. Then you can use slice to put the part before and after the , together with a . inbetween.

You don't need to worry about whether or not it's the last ".", because there is only one. JavaScript doesn't store numbers internally with comma or dot-delimited sets.