Continuing on from: https://stackoverflow.com/questions/16649933/jquery-on-form-change-with-bootstrap-sliders/16650319?noredirect=1
I am currently using the below to capture the ID of a slider and change the content of #log. The problem with this is that is only capture the first slider. I need this to be actioned when any slider is changed.
I've tried using the ID of price on all my sliders, however this doesn't work.
$('#price').each(function(index,value){
$(this).bind('slide', function(){
$("#log").prepend('<p>Changed</p>')
});
});
The reason this doesn't work is because JavaScript conforms with the HTML specification, and the HTML specification states that ID attributes must be unique.
You aren't allowed to have two elements with id="price". Because of this JavaScript will stop searching after it has found the first match. Your .each() loop will only go around once, regardless of how many #price elements are present after the first.
To resolve this, use classes instead. For example:
<div class="price">...</div>
<div class="price">...</div>
<div class="price">...</div>
$('.price').each(function(index,value) { ... });
You will also need to change your #log elements to use classes, too.
$('#price') is id, page include one duplicate id. you need use class
Related
I have common jQuery function and two div tags. Both div tags have different names but both containing elements of identical ids now i want to use this common Jquery function for them both?
I have implemented common function but it's not working for both.
Here's link to my jsfiddle -jsfiddle.net/xS7zF/1/
In my jsfiddle there are two div tags namely example1 and example2 and both tags have elements of identical ids. Function is working fine for first div but not for second.
please help me to sort out this.
Yeah, under the hood, jQuery selection on an ID will use the Document.GetElementById() function implemented by the browser, which is really fast, but (i guess depending on the browser) will stop after it finds the first element, since ID's should be unique and no further searching is needed after the first one is found.
For instance, rename the divs with id="eb" to class="eb" and you can still target specific elements using $("#example1 .eb") and $("#example2 .eb")
UPDATE:
Using your new Fiddle I created this: http://jsfiddle.net/xS7zF/5/
I cleaned up a lot of code and hopefully you can see what I have done. I changed all elements that appear twice from id to class. Now, when you attach an event to an element using $(".classname").click(), it attaches to all the elements. In the handler function where you set HTML and do your show()/hide(), you don't target a specific element using it's ID, but you find it relative to the element that does the event. You can do this using parent(), parentsUntil(), next(), find(), etc. Check jQuery docs for all possibilities. So for instance, the change-handler attaches to all inputs with name=Assets. But instead of doing $("#b1").show(), I go to the parent of the specific input that fires using $(this).parent(). Then I find the element with a class=".b1", which it will only find the one that is next to this specific input and I set the HTML to just that element.
Since there is another input, the same actions happen when THAT input changes, but instead it finds IT's parent, and finds the element with class=".b1" that is next to IT. So both divs with input are contained since they act on elements relative to itself and not across the document.
For extra fun and to show you how flexible this way of programming is, here is a fiddle with the Javascript-code unchanged, but with the exact same question-div copied 8 times. No matter how many times you repeat this, the same code will act on as many divs as you create since everything works relative. http://jsfiddle.net/xS7zF/7/
Hopefully this helps, the rest is up to you!
ID's must be unique, you should not repeat them. You could replace id with class and in the jQuery function do (".ub").each() or manually referencing the object using eq(x). e.g. (".ub").eq(1).
You shouldn't assign same id's to different elements.
You CAN but you SHOULDN'T. Instead of giving the same id, use class
IDs must be unique, try fix this, change to classes.
You can try something like this:
$("div div:first-child")
instead of
$("#eb")
But depends of the rest of your page code. So, change to classes first and use
$(".eb")
when jQuery / javascript find the first ID it would ignore the rest, please read more about it
http://www.w3schools.com/tags/att_global_id.asp
I have some bullet points which I want to show more text below them on clicking them. They are both two separate Ps that are paired together by sharing a common id. So, what I am trying to do below is to find the element with (id_same_as_this.class), so that the element with the class "expand" as well as the id that matches the clicked on P is toggled. Does that make sense?
$(document).ready(function(){
$(".expandable").click(function(){
$(this.attr('id')+"."+"expand").toggle(800);
});
});
I only ask if the above code could be made to work because it would make the expandable bullet points in my web page significantly less code intensive than a lot of the examples I have read about.
$(this.attr('id')+"."+"expand").toggle(800);
Must be
$("#" + this.id +".expand").toggle(800);
You missed the # there. That said, you shouldn't ever have a common ID. By definition IDs are meant to be unique. If you have the same ID on multiple elements, while it may work now on the browsers you try, you have no guarantee it won't break in the next rev of jQuery (or Chrome, or Konqueror, or iOS Safari). There's also no reason to do it. You could just use classes or data-* attributes.
Yes this will work but you need a # before the ID
They are both two separate Ps that are paired together by sharing a common id.
IDs are unique. Two elements can't share a common ID, as that defeats the whole purpose of having a unique identifier. JavaScript assumes that you're using valid HTML, so document.getElementById() will return only the first element with a matching id. By using non-unique IDs, things will start breaking in unpredictable ways:
$('#foo').find('.bar') // Won't search past first #foo
$('#foo .bar') // Will search past first #foo in IE8+
Try restructuring your HTML to make this task easier. Maybe you could do something like this:
<ul id="bullets">
<li>
<h2>Title</div>
<div>Text</div>
</li>
</ul>
And then use a simple event handler:
$('#bullets h2').click(function() {
$(this).next().toggle(800);
});
You don't need id values for this at all (which is good, as from the comments on hungerpain's answer, you're using the same id value on more than one element, which is invalid).
Just do this:
$(document).ready(function(){
$(".expandable").click(function(){
$(this).find(".expand").toggle(800);
});
});
That will find the element with the class expand within the expandable that was clicked. No relying on unspecified behavior of selectors.
If you really need that data on the expandable, just put it in a data-* attribute. So instead of this invalid structure:
<!-- INVALID -->
<div id="foo27" class="expandable">
<div class="expand">...</div>
</div>
<div id="foo27" class="expandable">
<div class="expand">...</div>
</div>
Do this
<!-- VALID -->
<div data-id="foo27" class="expandable">
<div class="expand">...</div>
</div>
<div data-id="foo27" class="expandable">
<div class="expand">...</div>
</div>
Use the above code to do the expansion. If you need the value, use .attr("data-id") or .data("id") to get it.
I have a site that has multiple divs with the same id name. I want to set a mouseleave function for all of the divs that have this id. In my $(document).ready function I have this code...
$('#my_post_container').mouseleave(function(e)
{
hideSnippet();
});
My hideSnippet() function is correct, but doing this only set the mouseleave function for the first time that a div comes up of id my_post_container. Is there a way to set the mouseleave function to all divs with this id?
I have a site that has multiple divs with the same id name.
Then you need to fix that. You must not have more than one element with the same id. id values must be unique on the page.
You probably want to use class instead, at which point your code is basically fine:
$('.my_post_container').mouseleave(function(e)
{
hideSnippet();
});
...although it coudl be shortened a bit if hideSnippet doesn't care what arguments it gets, doesn't care about this, and doesn't return false:
$('.my_post_container').mouseleave(hideSnippet);
It is invalid HTML to have multiple objects with the same id. As such, you cannot use normal selectors to find them all and you should fix your HTML to not do that.
The #1 suggestion is to fix the HTML so it does not have multiple objects with the same ID. Use a class name and you can then select them all with getElementsByClassName() or querySelectorAll() or with jQuery selectors as in:
$('.my_post_container')
If you insist on having multiple objects with the same id (a bad choice), then you will have to somewhat manually iterate over all possible objects that could have that id.
$("div[id='my_post_container']");
But, this is pretty darn inefficient because the browser can't use any of the built-in selector engine logic and it could break in the future if jQuery decides to optimize this. You really ought to switch to using class names.
You can not have multiple elements on the same page with the same id. Use a class instead, as shown here:
HTML:
<div class="my_post_container">...</div>
<div class="my_post_container">...</div>
<div class="my_post_container">...</div>
jQuery:
$('.my_post_container').mouseleave(function(e)
{
hideSnippet();
});
First of all there should not be any div elements with same ID name.. first we should solve that by keeping class name same.
then on mouse leave and enter part..
$(".testClass").on({
mouseenter : function() {
$(this).css({"background-color" : "blue"});
},
mouseleave : function() {
$(this).css({"background-color" : "green"});
}
});
this should work.. will add a js sample http://jsfiddle.net/meVc6/
and the same thing can be achived using css too..
just add css .testClass:hover { background-color:blue}
I'm making a site, and the html is displayed through php with data fetched from a database.
I have a foreach() function, so all of the things displayed have the same DIV ID's.
It ends up being like 4 DIVs with the same ID (#content), so the PHP works fine, but I have a jQuery script and when I call the jQuery("#content").hide(); it only hides ONE of the DIV's not all of them, and I want it to hide all of them. Is there something else I have to do?
Thanks.
You should use a class (.class_name), not an id--only one DOM element may have a given ID, otherwise it's invalid HTML. It's reasonable for an ID selector to return only a single element.
IDs on elements on a page should be unique. So every HTML tag you specify should have a different ID. If you want to hide all of a certain element, it might be suitable to add a class to the elements you wish to hide?
e.g.
<div class="divToHide">Content...</div>
<div class="divToHide">Content...</div>
<div class="divToHide">Content...</div>
Then your jquery would be:
$(".divToHide").hide();
That's simply because you cannot have more than one element with a specified ID. IDs are and must be unique. Only one single element with the same element may exist in a DOM.
Failing to follow this rule may result in broken scripts and other horrors.
You can use classes for this purpose.
an ID can only be used ONCE in HTML! because its a id and a id should always be Unique
I've got 3 tabs. Each of them have a div called optional, apart from other elements.
optional is initially hidden using Javascript, I dun wanna use CSS ( this is so if js is disabled, the div won't be hidden at all ).
So I use this to hide optional
$(function(){
$('#optional').hide();
});
Now, this works just fine on the first tab but won't hide on the next two tabs. They've all got the same code, no naming conflicts and no javascript errors reported.
Any idea what I'm doing wrong?
$(function(){
$('div.optional').hide();
});
Classname instead of id, since IDs are required to be unique. By the DOM/JS, if not html.
Edited: to change ...('.optional')... to ...('div.optional')... which should reduce the time it takes the function to work (since it's looking through only one set of tags <div> rather than all of them, examining them for their class-name.