Im trying to implement a simple plugin that resize image based on a container.
The problem is , I don't understand why it's not resizing my image when I placed it inside a container
This is the simple plugin demo page i'm trying to replicate
https://dl.dropboxusercontent.com/u/6983010/wserv/imgLiquid/examples/imgLiquid.html
This is my Code
<html>
<head>
<link rel="stylesheet" href="css/float.css">
<script type = "text/javascript" src ="http://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script type = "text/javascript" src ="https://raw.github.com/karacas/imgLiquid/master/src/js/imgLiquid-min.js"></script>
<script type="text/javascript">
$(document).ready(function () {
$(".imgLiquidFill").imgLiquid({fill:true, fadeInTime:500});
$(".imgLiquidNoFill").imgLiquid({fill:false});
});
</script>
</head>
<body>
<div class="container" >
<img src="Creek.jpg"/></div>
</div>
</body>
</html>
My CSS
.container {height: 440px; width: 950px; background:#FFFFFF}
<html>
<head>
<meta http-equiv="Content-Type" content="text/html;charset=utf-8" />
<title>Image</title>
<style>
.container{
background-color:#f7f7f7;
border:2px solid #ccc;
margin:10px;
display:inline-block;
}
.imgLiquid {
display:block;
overflow: hidden;
background:transparent url('http://www.lotienes.com/imagenes/loading.gif') no-repeat center center;
}
.imgLiquid img{
visibility:hidden;
}
</style>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"
type="text/javascript"></script>
<script type="text/javascript"
src="https://raw.github.com/karacas/imgLiquid/master/src/js/imgLiquid-min.js"></script>
<script type="text/javascript">
$(document).ready(function () {
$(".imgLiquidFill").imgLiquid({
fill: true,
fadeInTime:200,
horizontalAlign: "center",
verticalAlign: "top"
});
});
</script>
</head>
<body>
<div class="container">
<span class="imgLiquidFill imgLiquid" style="width:250px; height:250px;">
<a href="/media/Woody.jpg" target="_blank" title="test">
<img alt="" src="/media/Woody.jpg"/>
</a>
</span>
</div>
</body>
</html>
Your changing the codes and you forgot to define the imgLiquidFill and imgLiquid in the class which is very important to make this plugin effective. In modifying the codes make sure you didn't forgot anything. Another thing is you can rename the class but make sure you also rename it in the script to make it the same.
Related
Well i'm new to html/js scripting but i'm working on a project and i want to using hyperlink to show/hide divs
for example if i click on first hyperlink it should show div id:1 only and if i click on second hyperlink it should show 2nd div only.
i managed to find an example of what i need on internet but i have no idea,why whatever i try it doesnot work for me
an example of what i need - my fiddle
and this is my code
<!DOCTYPE html>
<html>
<head>
<style>
#myDIV {
width: 100%;
padding: 50px 0;
text-align: center;
background-color: lightblue;
margin-top:20px;
}
</style>
</head>
<body>
<body>
Click a button to make it visible:<br /><br />
One
Two
Three
Four<br /><br />
<div id="one">One</div>
<div id="two">Two</div>
<div id="three">Three</div>
<div id="four">Four</div><br/><br/>
</body>
<script>
$("div").hide();
// Show chosen div, and hide all others
$("a").click(function (e)
{
//e.preventDefault();
$("#" + $(this).attr("class")).show().siblings('div').hide();
});
</script>
</body>
</html>
so you ned to include JQuery that's what $() is.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<!DOCTYPE html>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<style>
#myDIV {
width: 100%;
padding: 50px 0;
text-align: center;
background-color: lightblue;
margin-top:20px;
}
</style>
</head>
<body>
<body>
Click a button to make it visible:<br /><br />
One
Two
Three
Four<br /><br />
<div id="one">One</div>
<div id="two">Two</div>
<div id="three">Three</div>
<div id="four">Four</div><br/><br/>
</body>
<script>
$("div").hide();
// Show chosen div, and hide all others
$("a").click(function (e)
{
//e.preventDefault();
$("#" + $(this).attr("class")).show().siblings('div').hide();
});
</script>
</body>
</html>
It is Working For me on JSFIDDLE. Add jquery library on your local project.
add This on your Head Tag
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
you forget to include $ jquery in you script tag
<!DOCTYPE html>
<html>
<head>
<style>
#myDIV {
width: 100%;
padding: 50px 0;
text-align: center;
background-color: lightblue;
margin-top:20px;
}
</style>
</head>
<body>
<body>
Click a button to make it visible:<br /><br />
One
Two
Three
Four<br /><br />
<div id="one">One</div>
<div id="two">Two</div>
<div id="three">Three</div>
<div id="four">Four</div><br/><br/>
</body>
<script
src="https://code.jquery.com/jquery-1.12.4.min.js"
integrity="sha256-ZosEbRLbNQzLpnKIkEdrPv7lOy9C27hHQ+Xp8a4MxAQ="
crossorigin="anonymous"></script>
<script>
$("div").hide();
// Show chosen div, and hide all others
$("a").click(function (e)
{
//e.preventDefault();
$("#" + $(this).attr("class")).show().siblings('div').hide();
});
</script>
</body>
</html>
You should add jquery in your project.
You can use a CDN
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
OR
you can include your own copy of library in project.
<script src="path/jquery.min.js"></script>
I was testing out a slider I built on a local connection, and it worked great, but then when I tried to upload it to my server, it just stacks the images on top of one another. What are some reasons as to why it would work locally, but not when I take it live?
<html>
<head>
<title>Test</title>
<link rel="stylesheet"; type="text/css"; href="Snoopz2.css";/>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script src="http://malsup.github.com/jquery.cycle.all.js"></script>
</head>
<body>
<script type="text/javascript">
$(document).ready(function() {
$('.slideshow') .cycle({
fx: 'scrollLeft',
delay: -2000,
next: '.button2',
prev: '.button1',
pause: 1
});
});
</script>
<div class="slideshow">
<div class="slide1">
<img src="/Images2/Cavs.jpg" />
</div><!--/slide-->
<div class="slide2">
<img src="/Images2/tiger.jpg" />
</div><!--/slide-->
<div class="slide3">
<img src="/Images2/LandonDonovan.jpg" />
</div><!--/slide-->
</div>
</body>
</html>
here is the CSS:
.slideshow {
width:600px;
height:257px;
margin:0;
padding:0;
position:relative;
overflow:hidden;
}
.slideshow {
margin:0;
padding:0;
width:600px;
height:257px;
float:left;
position:relative;
}
Website that I'm trying to test this on: http://thesnoopz.com/AASliderTest.html
I was able to get the cycle to work by placing the
<script src="http://malsup.github.com/jquery.cycle.all.js"></script>
in the <body> instead of the <head>
unfortunately I'm getting some really weird issues where it only shows up in a small box at the top of screen
http://thesnoopz.com/AASliderTest.html
I want to show the div with id #flower when clicking on the link with id #button but it doesnt work. Heres is the code i wrote.. i made also a jsbin page to show you
any suggestions?
http://jsbin.com/xefanaji/3/
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>JS Bin</title>
</head>
<body>
<div id="front">
<div><p>Button</p></div>
</div>
<div id="flower">
<img src="http://2.bp.blogspot.com/-Gaz8V9dP5O0/UUjtKJPofuI/AAAAAAAALDQ/boET2Ns34aU/s320/blooming-flowers-35.jpg" alt="flower"/>
</div>
<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js">
$(document).ready(
function(){
$("#button").click(function () {
$("#flower").show("slow");
});
});
</script>
</body>
</html>
css
#button{
position:relative;
height:30px;
width:60px;
background-color:lightyellow;
left:40px;
top:40px;
}
#flower{
display:none;
position:relative;
top:-600px;
left:50px;
z-index:0;
}
#front {
z-index:1;
position:relative;
top:100px;
height:600px;
width:100%;
background-color:lightblue;
}
if i am not wrong.. you need to add id to your button ,if (<a ..>Button</a>) is the element you are talking about.
<div><p>Button</p></div>
//-^^^^^^^^^^----here
$("#button").click(function (e) {
e.preventDefault();
$("#flower").show("slow");
});
with CSS you have, i am sure you forget to add id to that a link
well few more thing,
always load script in your <head> section, and you don't need to add src in script tag
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
..
<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
</head>
....
....
<script>
$(document).ready(
function(){
$("#button").click(function () {
$("#flower").show("slow");
});
});
</script>
Try this
<div id="front">
<div><p><a id="button" href="">Button</a></p></div>
</div>
<div id="flower">
<img src="http://2.bp.blogspot.com/-Gaz8V9dP5O0/UUjtKJPofuI/AAAAAAAALDQ/boET2Ns34aU/s320/blooming-flowers-35.jpg" alt="flower"/>
</div>
<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<script>
$(document).ready(
function(){
$("#button").click(function (e) {
e.preventDefault();
$("#flower").show("slow");
});
});
</script>
DEMO
Put the jQuery library in the head section of your document like below
<head>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
</head>
If you need button you can use span instead of anchor e.g.
<span class="button">Button</span>
then add a little styling
.button {
font-size: 12px;
color: #333;
}
.button:hover {
color: #ddd;
}
and then put this script just before </body> tag
<script>
$(function() {
$(".button").click(function () {
$("#flower").show("slow");
});
});
</script>
You could use the revised jQuery below to accomplish this, the reason your code isnt working is because your link doesnt have the id button set.
$('#front a:first').on('click',function(e){
e.preventDefault();
$('#flower').show();
})
You are missing id #button for that link.
<a id="button" href="">Button</a>
So this could be a possibly very simple problem but I'm having a mind block at the moment. I'm trying to integrate this code with my website, but due to the image being a background layer I can't have it appear above other elements on the page.
So is there a way to code the background-image within the HTML instead of CSS so it can be given a z-index property so it stacks on-top of other elements?
The code is as follows below in it's simplest form
(Left out something, should work now).
<!DOCTYPE HTML>
<html>
<head>
<meta charset="utf-8">
<title>Test</title>
<link href="home%20css.css" rel="stylesheet" type="text/css"/>
<script src="http://code.jquery.com/jquery-1.8.2.min.js" type="text/javascript"></script>
<script src="http://static.tumblr.com/jvojroo/DIamwjvp3/jquery.caroufredsel-6.2.0-packed.js" type="text/javascript"></script>
<script src="https://raw.github.com/jasonenglish/jquery-flex/master/jquery.flex.js"></script>
<script type="text/javascript">
$(function() {
$(".button0").flex();
});
</script>
<style type="text/css">
.button0 {
position:relative;
width:850px;
min-height:300px;
}
.button0 a {
width:100px;
height:100px;
position:absolute;
background-repeat:no-repeat;
background-position:center;
}
[bb=a] {background-image: url(http://farm8.staticflickr.com/7013/6448917381_0b754e86fb_z.jpg);
position: absolute;
z-index: 100;
}
/* [bg=b] {background-image:url(http://farm9.staticflickr.com/8156/7362866426_bf285ebd45.jpg);background-size:300px auto;}
[bg=c] {background-image:url(http://farm6.staticflickr.com/5117/7410370290_0935419fc3.jpg);}
[bg=d] {background-image:url(http://farm8.staticflickr.com/7262/7419245080_bb752ed1d6.jpg);}
[bg=e] {background-image:url(http://farm8.staticflickr.com/7003/6468321069_3375be3073_z.jpg);background-size:auto 280px;}
[bg=f] {background-image:url(http://farm8.staticflickr.com/7220/7342556872_46cddaf9b0.jpg);background-size:auto 280px;}
[bg=g] {background-image:url(http://farm9.staticflickr.com/8021/7322604950_348c535903.jpg);background-size:auto 200px;}
[bg=h] {background-image:url(http://farm8.staticflickr.com/7076/7286717012_6e6b450243.jpg);}
[bg=i] {background-image:url(http://farm8.staticflickr.com/7129/7452167788_a3f6aa3104.jpg);background-size:auto 200px;}
[bg=j] {background-image:url(http://farm8.staticflickr.com/7153/6480022425_a8d419e663_z.jpg);background-size:auto 280px;}
[bg=k] {background-image:url(http://farm8.staticflickr.com/7225/7269592732_c4b7918626.jpg);background-size:auto 280px;} */
</style>
<body>
<div class="button0">
<a bb="a" style="left:0px;top:0px;width:10%;height:140px;" width="145%" height="140"></a>
<!--<a bg="b" style="left:260px;height:100px;top:0px;width:125px;" width="250" height="175">B</a>
<a bg="c" style="left:395px;height:250px;top:0px;width:75px;" width="125" height="350">C</a>
<a bg="d" style="left:480px;height:75px;top:0px;width:75px;" width="175" height="150">D</a>
<a bg="e" style="left:565px;height:125px;top:0px;width:200px;" width="200" height="250">E</a>
<a bg="f" style="left:480px;height:200px;top:85px;width:75px;" width="150" height="225">F</a>
<a bg="g" style="left:0px;height:100px;top:135px;width:75px;" width="305" height="150">G</a>
<a bg="h" style="left:260px;height:75px;top:110px;width:125px;" width="200" height="200">H</a>
<a bg="i" style="left:85px;height:140px;top:135px;width:165px;" width="200" height="140">I</a>
<a bg="j" style="left:565px;height:150px;top:135px;width:75px;" width="125" height="275">J</a>
<a bg="k" style="left:650px;height:75px;top:135px;width:75px;" width="75" height="200">K</a> -->
</div>
</body>
First, set your background using the body background tag:
<body background="http://farm8.staticflickr.com/7013/6448917381_0b754e86fb_z.jpg" id=bkgrnd>
Then, use a script to set the z-index:
<script>
function changeStackOrder()
{
document.getElementById("bkgrnd").style.zIndex="1";
}
</script>
Thanks ALOT guys! I've got it working now, thank you!
I have a hopefully easy question:
This: http://jsfiddle.net/gSAjV/2/
is what I want to achieve, but I can't seem to get it working.
I'm all new to javascript, so I'm not sure how to properly put the script in the html document.
I have tried the <script type="text/javascript"> and others, but it just doesn't work.
So i wondered if anyone would take the time to put it in a html document and get it working, and ofcourse posting the entire code. I would be very greatfull!
my doc:
<html>
<head>
<style>
.parentDiv{
border:1px solid black;
padding:10px;
width: 80px;
margin:5px;
display:relative;
}
.childDiv{
border:1px solid blue;
height: 50px;
margin:10px;
}
</style>
<script type='text/javascript'>
$('.childDiv').click(function(){
$(this)
.css('background-color','#00ff66')
.siblings()
.css('background-color','#ffffff');
});
</script>
</head>
<body>
<div id="divParent1" class="parentDiv">
Group 1
<div id="child1" class="childDiv">
Child 1
</div>
<div id="child2" class="childDiv">
Child 2
</div>
</div>
<div id="divParent2" class="parentDiv">
Group 2
<div id="child1" class="childDiv">
Child 1
</div>
<div id="child2" class="childDiv">
Child 2
</div>
</div>
</body>
</html>
Put this somewhere in your html file:
<script type="text/javascript">
$(document).ready(function() {
$('.childDiv').click(function(){
$(this).parent().find('.childDiv').css('background-color','#ffffff');
$(this).css('background-color','#ff0000');
});
});
</script>
You can put it more or less anywhere, but just before the </body> tag would be a good place.
And as #MarkK has rightly pointed out, you need to reference the jQuery library itself.
This goes between <head> and </head>:
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script>
In jsfiddle, you can right-click on the Results pane and View Source. This will give you the exact html that produces the result.
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=UTF-8">
<title> - jsFiddle demo</title>
<script type='text/javascript' src='http://code.jquery.com/jquery-1.4.4.min.js'></script>
<link rel="stylesheet" type="text/css" href="/css/normalize.css">
<link rel="stylesheet" type="text/css" href="/css/result-light.css">
<style type='text/css'>
.parentDiv{
border:1px solid black;
padding:10px;
width: 80px;
margin:5px;
display:relative;
}
.childDiv{
border:1px solid blue;
height: 50px;
margin:10px;
}
</style>
<script type='text/javascript'>//<![CDATA[
$(window).load(function(){
$('.childDiv').click(function(){
$(this).parent().find('.childDiv').css('background-color','#ffffff');
$(this).css('background-color','#ff0000');
});
});//]]>
</script>
</head>
<body>
<div id="divParent1" class="parentDiv">
Group 1
<div id="child1" class="childDiv">
Child 1
</div>
<div id="child2" class="childDiv">
Child 2
</div>
</div>
<div id="divParent2" class="parentDiv">
Group 2
<div id="child1" class="childDiv">
Child 1
</div>
<div id="child2" class="childDiv">
Child 2
</div>
</div>
</body>
</html>
You just need to import jQuery (the library that contains the $ functions). This is simple, just add
<script src="http.//ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script>
to your HTML, before your other script.
<html>
<head>
<!--inclue jquery - change the path 'src'. the default is jquery.js is on the same location of this html-->
<script type="text/javascript" src="jquery.js"></script>
<sript type="text/javascript">
jQuery().ready(function($){
$('.childDiv').click(function(){
$(this).parent().find('.childDiv').css('background-color','#ffffff');
$(this).css('background-color','#ff0000');
});
});
</script>
</head>
<body>
<!--the content paste your html here-->
</body>
</html>