I am trying to make for each radio button, when it is clicked on to show the div with more infos about that clicked title, when another radio button is clicked then the to show info about that radio button and hide the other one that was clicked on:
HTML:
<input type="radio" id="1" />
<div class="event1">
content..
</div>
<input type="radio" id="2" />
<div class="event2">
content..
</div>
<input type="radio" id="3" />
<div class="event3">
content..
</div>
jQuery:
var i = 1;
while(i < 10) {
$('.event' + i).hide();
$("#" + i).click(function() {
$('.event' + i).show();
});
i++;
}
HTML
<input type="radio" name="radio" id="1" />
<div class="event">
content.. 1
</div>
<input type="radio" name="radio" id="2" />
<div class="event">
content.. 2
</div>
<input type="radio" name="radio" id="3" />
<div class="event">
content.. 3
</div>
JS
$('input[name=radio]').click(function() {
$('.event').hide();
$(this).next('.event').show();
});
CSS
.event {
display: none;
}
Fiddle
http://jsfiddle.net/UKn6D/
You can try changing your loop with "each"
$(function(){
$("input[type='radio']").each(function(){
$(this).change(function(){
if ($(this).is(':checked'))
$(this).next().show();
else
$(this).next().hide();
});
});
});
It would be preferrable if you assign a class to radio elements to focus specifically on them. Something like "radioElements" should be enough. Or you can also use id with a starter: "radio_1","radio_2" and then use the input[id^='radio_'].
In all the case you can use "each" function.
More deeply, if you want that all other radio "info" cut off change it to:
$(function(){
$("input[type='radio']").each(function(){
$(this).change(function(){
if ($(this).is(':checked')) {
$("input[type='radio']").next().hide();
$(this).next().show();
}
});
});
});
$('input[type="radio"]').on('change', function() {
var id = $(this).attr('id'); //Get the ID from the selected radio button
$('div:visible').hide(); //Hide visible Divs
$('div.event' + id).show(); //Show matched Div
});
You'll want to give the divs an additional class name and update the jQuery code here. You'll also want to make sure to assign a name attribute to the input elements so that they are all part of the same group -- assuming they are.
instead of having a while look like that why not simply have
<div id="input-container">
<input class="clickable" />
<div class="content"></div>
</div>
This will then work with multiple and the jQuery can just be like this
$('#input-container input.clickable').click(function() {
$(this).parent().find('div.content').hide();
$(this).next('div.content').show();
});
I haven't actually tested the above but I believe it should work for you & the reason to have the container ID is just to speed your jQuery up as it is faster to attach via #elementID first
Related
I want an event in which when i click the list tag so the radio button gets checked.
<li class="morning-time">
<div class="morning-icon"></div>
<div class="timeTxt">Morning <span>7am - 12am</span></div>
<div class="checkBox">
<label>
<input type="radio" class="option-input checkbox" id="rbt_Time1" name="rbt_Time" value="1" data-text="Morning 7am - 12am">
<span></span>
</label>
</div>
<div class="clear"></div>
</li>
You will have to include jquery for using the following code:
$(function() {
$('.morning-time').on('click', function(){
$('.option-input', $(this)).prop("checked", true);
});
});
Here, on li(class='morning-time'), the radio(class='option-input') is searched inside(the li tag) and set checked.
You need setAttribute to do so AND to explain the code, radio styled input have a checked attribute. Just set it to true and the input get check.
Here the code :
function CheckMe()
{
var radioInput = document.getElementById("rbt_Time1");
radioInput.setAttribute("checked", "true");
}
I have an input checkbox field and when the checkbox changes (user clicks or unclicks) the div below should toggle. In my style sheet I have the div paypalInputArea as display:none and when the checkbox in clicked, it should toggle, however I can't seem to get it to work. Can anyone see what is wrong with my code?
Here is my html:
<div class="checkbox-row" id="paypalCheckbox">
<input type="checkbox" maxlength="2147483647" value="true" name="paypalPaymentCheckbox" id="paypalPaymentCheckbox" class="checkinput styled" />
<label class="paymentMethodTitle"></label>
</div>
<div class="paypalInputArea">
<isinclude template="includes/paymentmethodsinclude" />
</div>
And here is my jQuery:
$("#paypalCheckbox.checkbox-row .areaExpander").on('change', function() {
$(".paypalInputArea").toggle();
if ($('.paypalInputArea').is(':visible')) {
app.paymentAndReview.setCOContinueBtn(true);
$("#paypalPaymentCheckbox").attr('checked','true');
$('#paypalCheckbox.checkbox-row .areaExpander').addClass('open');
} else {
$("#paypalPaymentCheckbox").removeAttr('checked');
$('#paypalCheckbox.checkbox-row .areaExpander').removeClass('open');
app.paymentAndReview.setCOContinueBtn(false);
}
});
$("#paypalCheckbox.checkbox-row input").attr('checked') && app.paymentAndReview.setCOContinueBtn(true);
$("#paypalCheckbox").on('change', function() {
$(".paypalInputArea").toggle();
if ($('.paypalInputArea').is(':visible')) {
//app.paymentAndReview.setCOContinueBtn(true);
$('#paypalCheckbox.checkbox-row .areaExpander').addClass('open');
} else {
$('#paypalCheckbox.checkbox-row .areaExpander').removeClass('open');
//app.paymentAndReview.setCOContinueBtn(false);
}
});
$("#paypalCheckbox.checkbox-row input").attr('checked') && app.paymentAndReview.setCOContinueBtn(true);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="checkbox-row" id="paypalCheckbox">
<input type="checkbox" maxlength="2147483647" value="true" name="paypalPaymentCheckbox" id="paypalPaymentCheckbox" class="checkinput styled" />
<label class="paymentMethodTitle"></label>
</div>
<div class="paypalInputArea" style="display:none">
blabla
</div>
just replace the line:
$("#paypalCheckbox.checkbox-row .areaExpander").on('change', function() {
with:
$("#paypalCheckbox").on('change', function() {
As you have an ID (which has to be unique) you dont have to use other classes or else to reach it!
you can also remove those lines as the attrribute checked is set as the user clicks on the checkbox
$("#paypalPaymentCheckbox").attr('checked','true');
$("#paypalPaymentCheckbox").removeAttr('checked');
Hope this helps!
It looks like you're missing the class areaExpander from your checkbox
I have two radio buttons each one will toggle different inputs on a form. I've achomplished this using the onclick() function that utilizes hide() but then this require another function with replicated .show() to bring the elements back if the user toggles back and forth. Thought there must be better logic something that is not so redundant, maybe an if toggle value?
Anyways this is what I have:
<labe>
<input type="radio" name="radioReason" onClick="resetPassShow()"> </input
<span class="text">Request profile update (i.e. phone#)</span>
</label>
<label>
<input type="radio" name="radioReason" value="resetPassword" onClick="resetPassRemove;"> </input>
<span class="text">Reset Password or Unlock My Account</span>
</label>
function resetPassRemove(){
$("#prodCategoryLabel").hide();
....
}
function resetPassShow(){
$("#prodCategoryLabel").show();
....
}
Here is the JS Fiddle in action: https://jsfiddle.net/dv5xmw9z/1/
JS
function hideA(x) {
if (x.checked) {
document.getElementById("A").style.visibility = "hidden";
document.getElementById("B").style.visibility = "visible";
}
}
function hideB(x) {
if (x.checked) {
document.getElementById("B").style.visibility = "hidden";
document.getElementById("A").style.visibility = "visible";
}
}
HTML
<input type="radio" onchange="hideB(this)" name="aorb" checked>A |
<input type="radio" onchange="hideA(this)" name="aorb">B
<div id="A">
<br/>A's text</div>
<div id="B" style="visibility:hidden">
<br/>B's text
</div>
use $( ".target" ).toggle(); function.
http://api.jquery.com/toggle/
I get the following HTML of which I have no control:
<div class="form-wrap">
<div class='input-wrap' data-field='start-set'>
<input type='radio' name='participant[0][start-set][value]' value='Information centre' class='participant-form--input-radio'/>
<span>Information centre</span>
<input type='radio' name='participant[0][start-set][value]' value='Terminal' class='participant-form--input-radio'/>
<span>Terminal<span>
</div>
<div class='input-wrap' data-field='delivery'>
...
</div>
</div>
And this might be repeated multiple times in the same page, for different participants.
What needs to be done is to capture the radio input change and if the radio value is 'terminal', to display the sibling div with data-field='delivery'.
I am really bad at front end, so would appreciate any help or guidance.
You can use tree traversal#next() method
$("input[type='radio'].participant-form--input-radio").on('change', function() {
var currentRadio = $(this);
if (currentRadio.val() == "terminal") {
currentRadio.parent().next().show();
}
})
$('input[type=radio]').change(function() {
if ($(this).val() == 'Terminal') {
$(this).parents('.input-wrap').next('[data-field=delivery]').show();
} else {
$(this).parents('.input-wrap').next('[data-field=delivery]').hide();
}
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="form-wrap">
<div class='input-wrap' data-field='start-set'>
<input type='radio' name='participant[0][start-set][value]' value='Information centre' class='participant-form--input-radio' />
<span>Information centre</span>
<input type='radio' name='participant[0][start-set][value]' value='Terminal' class='participant-form--input-radio' />
<span>Terminal<span>
</div>
<div class='input-wrap' data-field='delivery' style="display:none;">
...
</div>
</div>
First, you'll need to bind a change event to your radio button, I've used the name starts with ... selector.
$('input[name^=participant]').on('change', function() {
Alternatives are:
$('input:radio') /* all radiobuttons */
$('.form-wrap input:radio') /* all radiobuttons inside .form-wrap */
$('.participant-form--input-radio') /* class selector */
After that we need to find the element we want to show and hide. I prefer to travel up the tree to the elements parent and the find the child we are looking for
$(this).closest('.form-wrap').find('[data-field="delivery"]')
Then I use toggle(statement) to either hide or show it. The statement in this case will be "is the value 'Terminal'"
.toggle( $(this).val() == 'Terminal' )
All together, it looks like this:
$(function() {
$('input[name^=participant]').on('change', function() {
$(this).closest('.form-wrap').find('[data-field="delivery"]').toggle( $(this).val() == 'Terminal' );
});
});
[data-field="delivery"] { display: none; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="form-wrap">
<div class='input-wrap' data-field='start-set'>
<input type='radio' name='participant[0][start-set][value]' value='Information centre' class='participant-form--input-radio' />
<span>Information centre</span>
<input type='radio' name='participant[0][start-set][value]' value='Terminal' class='participant-form--input-radio' />
<span>Terminal</span>
</div>
<div class='input-wrap' data-field='delivery'>
...
</div>
</div>
I want to display a div on each button click and also want to hide the other all divs how I can do it.
HTML
<div id=a style="display:none">1</diV>
<div id=b style="display:none">2</diV>
<div id=c style="display:none">3</diV>
<div id=d style="display:none" >4</diV>
<input type=button value=1 id=w>
<input type=button value=2 id=x>
<input type=button value=3 id=y>
<input type=button value=4 id=z>
jQuery
$('#w').live('click', function () {
$('#a').css('display', 'block');
});
$('#x').live('click', function () {
$('#b').css('display', 'block');
});
$('#y').live('click', function () {
$('#c').css('display', 'block');
});
$('#z').live('click', function () {
$('#d').css('display', 'block');
});
http://jsfiddle.net/6UcDR/
In your JSFiddle, you are using jQuery 1.7.2. If you are using this version in your real app, you should not be using $.live(), but use $.on() instead - the former is deprecated in favour of the latter.
The simplest and cleanest way to solve your problem would be to wrap both your buttons and divs in containers, and use $.index() to associate a button with a div:
<div class="showThese">
<div id="a" style="display:none">1</div>
<div id="b" style="display:none">2</div>
<div id="c" style="display:none">3</div>
<div id="d" style="display:none" >4</div>
</div>
<div class="buttons">
<input type="button" value="1" id="w">
<input type="button" value="2" id="x">
<input type="button" value="3" id="y">
<input type="button" value="4" id="z">
</div>
Note that your attributes must be quoted, as in the above HTML.
Then, in JavaScript, you only need to bind one delegated event to the buttons container. I'll use $.on() in this case:
$('div.buttons').on('click', 'input', function() {
var divs = $('div.showThese').children();
divs.eq($(this).index()).show().siblings().hide();
});
Here is a demo.
The above method does away with having to use IDs and other attributes, however you will need to be careful if you want other elements in the containers, as $.index() will begin to fail if you do.
Just start by hiding all other div's, then showing the one you want to be shown.
$('#w').live('click', function(){
$('div').hide();
$('#a').show();
});
If understand you correctly, it should be just setting the display:none for the divs before showing your specific div.
$('#w').live('click', function(){
$('div').css('display','none');
$('#a').css('display','block');
});
$('#x').live('click', function(){
$('div').css('display','none');
$('#b').css('display','block');
});
$('#y').live('click', function(){
$('div').css('display','none');
$('#c').css('display','block');
});
$('#z').live('click', function(){
$('div').css('display','none');
$('#d').css('display','block');
});
live is deprecated, use on
$('input').on('click', function(){
var index = $(this).index();
$('div').hide().eq(index).show();
});
example from jQuery.com:
function notify() { alert("clicked"); }
$("button").on("click", notify);
Check the demo http://jsfiddle.net/6UcDR/2/ Is this the thing that you want to achieve.
Try this jQuery-
$('#w').click(function(){
$('#a').show()
$('#b,#c,#d').hide()
});
$('#x').click(function(){
$('#b').show();
$('#a,#c,#d').hide()
});
$('#y').click(function(){
$('#c').show();
$('#b,#a,#d').hide()
});
$('#z').click(function(){
$('#d').show();
$('#b,#c,#d').hide()
});
Add a class to all the divs u want to show or hide
eg:
<div id=a class="hide" style="display:none">1</diV>
And then add the following statement to each onclick function
$('.hide').css('display','none'); /* Replace .hide with whatever class name u have chosen*/
To see the answer in action: http://jsfiddle.net/6UcDR/1/