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get all but last occurrences of a pattern in javascript

Given the following patterns:
"profile[foreclosure_defenses_attributes][0][some_text]"
"something[something_else_attributes][0][hello_attributes][0][other_stuff]"
I am able to extract the last part using non-capturing groups:
var regex = /(?:\w+(\[\w+\]\[\d+\])+)(\[\w+\])/;
str = "profile[foreclosure_defenses_attributes][0][properties_attributes][0][other_stuff]";
match = regex.exec(str);
["profile[foreclosure_defenses_attributes][0][properties_attributes][0][other_stuff]", "[properties_attributes][0]", "[other_stuff]"]
However, I want to be able to get everything but the last part. In other words, everything but [some_text] or [other_stuff].
I cannot figure out how to do this with noncapturing groups. How else can I achieve this?

Something like?
shorter, and matches from the back if you can have more of the [] items.
var regex = /(.*)(?:\[\w+\])$/;
var a = "something[something_else_attributes][0][hello_attributes][0][other_stuff11][other_stuff22][other_stuff33][other_stuff44]".match(regex)[1];
a;
or using replace, though less performant.
var regex = /(.*)(?:\[\w+\])$/;
var a = "something[something_else_attributes][0][hello_attributes][0][other_stuff11][other_stuff22][other_stuff33][other_stuff44]".replace(regex, function(_,$1){ return $1});
a;

If those really are your strings:
var regex = /(.*)\[/;

jquery/javascript how to get rid of blank spaces (replace() not working)

Hi all,
I have a string coming from my database:
var theString = "LNDSH - LONDON SHOPS";
I need to get two variables out of it.
One with the code before the -, and the other one with the sentence after the -.
To do so I do:
var sentence = $.trim(theString.substring((theString.indexOf('-')+1),theString.length));
var code = $.trim(theString.substring(0, theString.indexOf('-')));
var sentence is ok, but I cannot get rid of the spaces before the - in the code variable.
I really need to get rid of those spaces.
Please note that in var sentence I'm doing +1 because it is always one space in between the sentence and the -.
But in the case of the code: I don't know the length of the code and I don't know how many spaces will be before the -
I've tried:
code.replaceAll("\\s+", " ");
But this does not show a thing in my page (no javascript errors either).
I'm using jquery-1.5.1.min and jquery-ui-1.8.14.custom.min
Thanks a lot!

You may use split with regular expression:
var values = "LNDSH - LONDON SHOPS".split(/\s*-\s*/);
console.log(values[0]); // "LNDSH"
console.log(values[1]); // "LONDON SHOPS"

Try this:
variable.replace(/\s/g,'');
Edit: The above will not seperate your strings, it will only remove the white spaces.
To seperate the strings you can do this:
var seperate = theString.split("-", 2);
var LNDSH = seperate[0];
var LONDON_SHOPS = seperate[1];

var theString = "LNDSH - LONDON SHOPS";
var vett = theString.split("-");
var a = vett[0].trim();
var b = vett[1].trim();

var test = theString.split("-");
alert(test[0].trim());
alert(test[1].trim());

Javascript RegExp match & Multiple backreferences

I'm having trouble trying to use multiple back references in a javascript match so far I've got: -
function newIlluminate() {
var string = "the time is a quarter to two";
var param = "time";
var re = new RegExp("(" + param + ")", "i");
var test = new RegExp("(time)(quarter)(the)", "i");
var matches = string.match(test);
$("#debug").text(matches[1]);
}
newIlluminate();
#Debug when matching the Regex 're' prints 'time' which is the value of param.
I've seen match examples where multiple back references are used by wrapping the match in parenthesis however my match for (time)(quarter)... is returning null.
Where am I going wrong? Any help would be greatly appreciated!

Your regex is literally looking for timequarterthe and splitting the match (if it finds one) into the three backreferences.
I think you mean this:
var test = /time|quarter|the/ig;

Your regex test simply doesn't match the string (as it does not contain the substring timequarterthe). I guess you want alternation:
var test = /time|quarter|the/ig; // does not even need a capturing group
var matches = string.match(test);
$("#debug").text(matches!=null ? matches.join(", ") : "did not match");

javascript split with regex

I would like to split characters into array using javascript with regex
foo=foobar=&foobar1=foobar2=
into
foo, foobar=,
foobar1, foobar2=
Sorry for not being clear, let me re describe the scenario.
First i would split it by "&" and want to post process it later.
str=foo=foobar=&foobar1=foobar2=
var inputvars=str.split("&")
for(i=0;i<inputvars.length;i++){
var param = inputvars[i].split("=");
console.log(param);
}
returns
[foo,foobar]
[]
[foobar1=foobar2]
[]
I tried to use .split("=") but foobar= got splited out as foobar.
I essentially want it to be
[foo,foobar=]
[foobar1,foobar2=]
Any help with using javascript to split first occurence of = only?

/^([^=]*)=(.*)/.exec('foo=foobar=&foobar1=foobar2=')
or simpler to write but using the newer "lazy" operator:
/(.*?)=(.*)/.exec('foo=foobar=&foobar1=foobar2=')

from malvolio, i got to conclusion below
var str = 'foo=foobar=&foobar1=foobar2=';
var inputvars = str.split("&");
var pattern = /^([^=]*)=(.*)/;
for (counter=0; counter<inputvars.length; counter++){
var param = pattern.exec(inputvars[counter]);
console.log(param)
}
and results (which is what i intended)
[foo,foobar=]
[foobar1,foobar2=]
Thanks to #malvolio hint of regex
Cheers

Remove everything after a certain character

Is there a way to remove everything after a certain character or just choose everything up to that character? I'm getting the value from an href and up to the "?", and it's always going to be a different amount of characters.
Like this
/Controller/Action?id=11112&value=4444
I want the href to be /Controller/Action only, so I want to remove everything after the "?".
I'm using this now:
$('.Delete').click(function (e) {
e.preventDefault();
var id = $(this).parents('tr:first').attr('id');
var url = $(this).attr('href');
console.log(url);
}

You can also use the split() function. This seems to be the easiest one that comes to my mind :).
url.split('?')[0]
jsFiddle Demo
One advantage is this method will work even if there is no ? in the string - it will return the whole string.

var s = '/Controller/Action?id=11112&value=4444';
s = s.substring(0, s.indexOf('?'));
document.write(s);
Sample here
I should also mention that native string functions are much faster than regular expressions, which should only really be used when necessary (this isn't one of those cases).
Updated code to account for no '?':
var s = '/Controller/Action';
var n = s.indexOf('?');
s = s.substring(0, n != -1 ? n : s.length);
document.write(s);
Sample here

var href = "/Controller/Action?id=11112&value=4444";
href = href.replace(/\?.*/,'');
href ; //# => /Controller/Action
This will work if it finds a '?' and if it doesn't

May be very late party :p
You can use a back reference $'
$' - Inserts the portion of the string that follows the matched substring.
let str = "/Controller/Action?id=11112&value=4444"
let output = str.replace(/\?.*/g,"$'")
console.log(output)

It works for me very nicely:
var x = '/Controller/Action?id=11112&value=4444';
var remove_after= x.indexOf('?');
var result = x.substring(0, remove_after);
alert(result);

If you also want to keep "?" and just remove everything after that particular character, you can do:
var str = "/Controller/Action?id=11112&value=4444",
stripped = str.substring(0, str.indexOf('?') + '?'.length);
// output: /Controller/Action?

You can also use the split() method which, to me, is the easiest method for achieving this goal.
For example:
let dummyString ="Hello Javascript: This is dummy string"
dummyString = dummyString.split(':')[0]
console.log(dummyString)
// Returns "Hello Javascript"
Source: https://thispointer.com/javascript-remove-everything-after-a-certain-character/

if you add some json syringified objects, then you need to trim the spaces too... so i add the trim() too.
let x = "/Controller/Action?id=11112&value=4444";
let result = x.trim().substring(0, x.trim().indexOf('?'));

Worked for me:
var first = regexLabelOut.replace(/,.*/g, "");

It can easly be done using JavaScript for reference see link
JS String
EDIT
it can easly done as. ;)
var url="/Controller/Action?id=11112&value=4444 ";
var parameter_Start_index=url.indexOf('?');
var action_URL = url.substring(0, parameter_Start_index);
alert('action_URL : '+action_URL);