I need a regular expression for replacing multiple forward slashes in a URL with a single forward slash, excluding the ones following the colon
e.g. http://link.com//whatever/// would become http://link.com/whatever/
I think this should work: /[^:](\/+)/ or /[^:](\/\/+)/ if you want only multiples.
It wont match leading // but it looks like you're not looking for that.
To replace:
"http://test//a/b//d".replace(/([^:]\/)\/+/g, "$1") // --> http://test/a/b/d
Working Demo
As you already accepted an answer. To show some more extend of matching and controlling the matches, this might help you in the future:
var url = 'http://link.com//whatever///';
var set = url.match(/([^:]\/{2,3})/g); // Match (NOT ":") followed by (2 OR 3 "/")
for (var str in set) {
// Modify the data you have
var replace_with = set[str].substr(0, 1) + '/';
// Replace the match
url = url.replace(set[str], replace_with);
}
console.log(url);
Will output:
http://link.com/whatever/
Doublets won't matter in your situation. If you have this string:
var url = 'http://link.com//om/om/om/om/om///';
Your set array will contain multiple m//. A bit redundant, as the loop will see that variable a few times. The nice thing is that String.replace() replaces nothing if it finds nothing, so no harm done.
What you could do is strip out the duplicates from set first, but that would almost require the same amount of resources as just letting the for-loop go over them.
Good luck!
result = subject.replace(/(?<!http:)\/*\//g, "/");
or (for http, https, ftp and ftps)
result = subject.replace(/(?<!(?:ht|f)tps?:)\/*\//g, "/");
The original accepted answer does a sufficient job at replacing, but not for matching. And the currently accepted answer matches the character before duplicate slashes, also not good for matching.
Using a negative lookbehind to exclude the protocol from the match (?<!:), and a curly bracket quantifier to match 2 to infinite slashes \/{2,} does the job to both match and replace.
(?<!:)\/{2,}
let str = 'https://test.example.com:8080//this/is//an/exmaple///';
document.write('Original: ' + str + '<br><br>');
document.write('Matches: ' + str.match(/(?<!:)\/{2,}/g) + '<br><br>');
document.write('Replaced: ' + str.replace(/(?<!:)\/{2,}/g, '/'));
Related
I want to replace a text after a forward slash and before a end parantheses excluding the characters.
My text:
<h3>notThisText/IWantToReplaceThis)<h3>
$('h3').text($('h3').text().replace(regEx, 'textReplaced'));
Wanted result after replace:
notThisText/textReplaced)
I have tried
regex = /([^\/]+$)+/ //replaces the parantheses as well
regex = \/([^\)]+) //replaces the slash as well
but as you can see in my comments neither of these excludes both the slash and the end parantheses. Can someone help?
A pattern like /(?<=\/)[^)]+(?=\))/ won't work in JS as its regex engine does not support a lookbehind construct. So, you should use one of the following solutions:
s.replace(/(\/)[^)]+(\))/, '$1textReplaced$2')
s.replace(/(\/)[^)]+(?=\))/, '$1textReplaced')
s.replace(/(\/)[^)]+/, '$1textReplaced')
s.replace(/\/[^)]+\)/, '/textReplaced)')
The (...) forms a capturing group that can be referenced to with $ + number, a backreference, from the replacement pattern. The first solution is consuming / and ), and puts them into capturing groups. If you need to match consecutive, overlapping matches, use the second solution (s.replace(/(\/)[^)]+(?=\))/, '$1textReplaced')). If the ) is not required at the end, the third solution (replace(/(\/)[^)]+/, '$1textReplaced')) will do. The last solution (s.replace(/\/[^)]+\)/, '/textReplaced)')) will work if the / and ) are static values known beforehand.
You can use str.split('/')
var text = 'notThisText/IWantToReplaceThis';
var splited = text.split('/');
splited[1] = 'yourDesireText';
var output = splited.join('/');
console.log(output);
Try Following: In your case startChar='/', endChar = ')', origString=$('h3').text()
function customReplace(startChar, endChar, origString, replaceWith){
var strArray = origString.split(startChar);
return strArray[0] + startChar + replaceWith + endChar;
}
First of all, you didn't define clearly what is the format of the text which you want to replace and the non-replacement part. For example,
Does notThisText contain any slash /?
Does IWantToReplaceThis contain any parentheses )?
Since there are too many uncertainties, the answer here only shows up the pattern exactly matches your example:
yourText.replace(/(\/).*?(\))/g, '$1textReplaced$2')
var text = "notThisText/IWantToReplaceThis";
text = text.replace(/\/.*/, "/whatever");
output : "notThisText/whatever"`
I am trying to fix this since yesterday and believe I am missing something very simple.
I wrote a regex to match ANY ONE of the three IP address format:
Pattern to match : X.X.X.X OR X.X.X.X/X.X.X.X OR X.X.X.X-X.X.X.X
Regex:
/^(([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\/([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5]))|(([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\-([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5]))|(([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5]))$/
Problem:
The regex matches the above 3 formats but the problem is with the alternation symbol - the behaviour is like the regex stops once the match is found.
Example: 1.1.1.1/1.1.1.1 - Once this match is found it does not check after that.
i.e: 1.1.1.1/1.1.1.1 - Valid
But 1.1.1.1/1.1.1.1(...anything after this is also recognized as valid which should not be the case...)
Question:
How do I make it to match only one of the 3 alternatives as it is. I tried a bit with word boundaries (\b) as well, but I am not sure if that is what is needed.
Any help appreciated.
Try this regex:
(^(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)$)|(^(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)[\/-](?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)$)
You can test it using the following link for verification.
https://regex101.com/r/fC6uS3/1
The problem is that alternation has the lowest precedence of all the regex constructs. Your regex matches either:
^X.X.X.X/X.X.X.X // anchored at start only
or
X.X.X.X-X.X.X.X // not anchored
or
X.X.X.X$ // anchored at end only
You can fix it by adding another set of parentheses around everything but the anchors:
^(your regex)$
Im not sure if you want to match more than one, but if that is the case then remove "^" from the beginning and "$" from the end and also make it globally search like this:
/(([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\/([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5]))|(([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\-([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5]))|(([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5])\.([01]?\d\d?|2[0-4]\d|25[0-5]))/g
Hope this helps
You can probably shorten your regex to:
^(((([0-2][0-5][0-6])|(\d{1,2}))\.){3}((([0-2][0-5][0-6])|(\d{1,2}))))([/-](((([0-2][0-5][0-6])|(\d{1,2}))\.){3}(([0-2][0-5][0-6])|(\d{1,2}))))*$
If you are running it with javascript you would surround with /.../
var pattern = new RegExp(/^(((([0-2][0-5][0-6])|(\d{1,2}))\.){3}((([0-2][0-5][0-6])|(\d{1,2}))))([/-](((([0-2][0-5][0-6])|(\d{1,2}))\.){3}(([0-2][0-5][0-6])|(\d{1,2}))))*$/);
var testCases = {};
//should work
testCases['testCaseA'] = '1.2.3.4';
testCases['testCaseB'] = '1.2.3.4/1.256.3.4';
testCases['testCaseC'] = '1.2.3.4-1.2.3.4';
//should not work
testCases['testCaseD'] = '1.257.3.4';
testCases['testCaseE'] = '1.2.3.4/1.2.3.356';
testCases['testCaseF'] = '1.2.3.4-1.2.3.4I';
var results = '<table><tr><th>Cases</th><th>Inputs</th><th>Outputs</th></tr>';
$.each(testCases, function(k, v) {
results += '<tr><td>' + k + ' </td><td>' + v + ' </td><td>' + pattern.test(v) + '</td>';
});
document.write(results + '</table>');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
I'm working with a Google API that returns IDs in the below format, which I've saved as a string. How can I write a Regular Expression in javascript to trim the string to only the characters after the last slash in the URL.
var id = 'http://www.google.com/m8/feeds/contacts/myemail%40gmail.com/base/nabb80191e23b7d9'
Don't write a regex! This is trivial to do with string functions instead:
var final = id.substr(id.lastIndexOf('/') + 1);
It's even easier if you know that the final part will always be 16 characters:
var final = id.substr(-16);
A slightly different regex approach:
var afterSlashChars = id.match(/\/([^\/]+)\/?$/)[1];
Breaking down this regex:
\/ match a slash
( start of a captured group within the match
[^\/] match a non-slash character
+ match one of more of the non-slash characters
) end of the captured group
\/? allow one optional / at the end of the string
$ match to the end of the string
The [1] then retrieves the first captured group within the match
Working snippet:
var id = 'http://www.google.com/m8/feeds/contacts/myemail%40gmail.com/base/nabb80191e23b7d9';
var afterSlashChars = id.match(/\/([^\/]+)\/?$/)[1];
// display result
document.write(afterSlashChars);
Just in case someone else comes across this thread and is looking for a simple JS solution:
id.split('/').pop(-1)
this is easy to understand (?!.*/).+
let me explain:
first, lets match everything that has a slash at the end, ok?
that's the part we don't want
.*/ matches everything until the last slash
then, we make a "Negative lookahead" (?!) to say "I don't want this, discard it"
(?!.*) this is "Negative lookahead"
Now we can happily take whatever is next to what we don't want with this
.+
YOU MAY NEED TO ESCAPE THE / SO IT BECOMES:
(?!.*\/).+
this regexp: [^\/]+$ - works like a champ:
var id = ".../base/nabb80191e23b7d9"
result = id.match(/[^\/]+$/)[0];
// results -> "nabb80191e23b7d9"
This should work:
last = id.match(/\/([^/]*)$/)[1];
//=> nabb80191e23b7d9
Don't know JS, using others examples (and a guess) -
id = id.match(/[^\/]*$/); // [0] optional ?
Why not use replace?
"http://google.com/aaa".replace(/(.*\/)*/,"")
yields "aaa"
I would like to match a path in a Url, but ignoring the querystring.
The regex should include an optional trailing slash before the querystring.
Example urls that should give a valid match:
/path/?a=123&b=123
/path?a=123&b=123
So the string '/path' should match either of the above urls.
I have tried the following regex: (/path[^?]+).*
But this will only match urls like the first example above: /path/?a=123&b=123
Any idea how i would go about getting it to match the second example without the trailing slash as well?
Regex is a requirement.
No need for regexp:
url.split("?")[0];
If you really need it, then try this:
\/path\?*.*
EDIT Actually the most precise regexp should be:
^(\/path)(\/?\?{0}|\/?\?{1}.*)$
because you want to match either /path or /path/ or /path?something or /path/?something and nothing else. Note that ? means "at most one" while \? means a question mark.
BTW: What kind of routing library does not handle query strings?? I suggest using something else.
http://jsfiddle.net/bJcX3/
var re = /(\/?[^?]*?)\?.*/;
var p1 = "/path/to/something/?a=123&b=123";
var p2 = "/path/to/something/else?a=123&b=123";
var p1_matches = p1.match(re);
var p2_matches = p2.match(re);
document.write(p1_matches[1] + "<br>");
document.write(p2_matches[1] + "<br>");
Any working Regex to find image url ?
Example :
var reg = /^url\(|url\(".*"\)|\)$/;
var string = 'url("http://domain.com/randompath/random4509324041123213.jpg")';
var string2 = 'url(http://domain.com/randompath/random4509324041123213.jpg)';
console.log(string.match(reg));
console.log(string2.match(reg));
I tied but fail with this reg
pattern will look like this, I just want image url between url(" ") or url( )
I just want to get output like http://domain.com/randompath/random4509324041123213.jpg
http://jsbin.com/ahewaq/1/edit
I'd simply use this expression:
/url.*\("?([^")]+)/
This returns an array, where the first index (0) contains the entire match, the second will be the url itself, like so:
'url("http://domain.com/randompath/random4509324041123213.jpg")'.match(/url.*\("?([^")]+)/)[1];
//returns "http://domain.com/randompath/random4509324041123213.jpg"
//or without the quotes, same return, same expression
'url(http://domain.com/randompath/random4509324041123213.jpg)'.match(/url.*\("?([^")]+)/)[1];
If there is a change that single and double quotes are used, you can simply replace all " by either '" or ['"], in this case:
/url.*\(["']?([^"')]+)/
Try this regexp:
var regex = /\burl\(\"?(.*?)\"?\)/;
var match = regex.exec(string);
console.log(match[1]);
The URL is captured in the first subgroup.
If the string will always be consistent, one option would be simply to remove the first 4 characters url(" and the last two "):
var string = 'url("http://domain.com/randompath/random4509324041123213.jpg")';
// Remove last two characters
string = string.substr(0, string.length - 2);
// Remove first five characters
string = string.substr(5, string.length);
Here's a working fiddle.
Benefit of this approach: You can edit it yourself, without asking StackOverflow to do it for you. RegEx is great, but if you don't know it, peppering your code with it makes for a frustrating refactor.