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In Javascript how can i get todays date in this format yyyymmdd

Like i need to get todays date in format like 20120924 (yyyymmdd).How can i get this in javascript.

You could add a method to the date prototype, so you can use it on any date object:
Date.prototype.toMyString = function () {
function padZero(obj) {
obj = obj + '';
if (obj.length == 1)
obj = "0" + obj
return obj;
}
var output = "";
output += this.getFullYear();
output += padZero(this.getMonth()+1);
output += padZero(this.getDate());
return output;
}
var d = new Date();
alert(d.toMyString()); // Today
var otherDate = new Date(2012,0,1);
alert(otherDate.toMyString());​ //Jan 1 2012
Fiddle: http://jsfiddle.net/johnkoer/4rk7K/10/

This worked for me.
var rDate = (new Date()).toISOString().slice(0, 10).replace(/-/g, "");

Try this.
​var date = new Date();
var year = date.getFullYear().toString();
var month = date.getMonth().toString();
var day = date.getDate().toString();
if (parseInt(month) < 10) month = "0" + month;
if (parseInt(day) < 10) day = "0" + day;
var parsedDate = year + month + day;
(edit)
Improved this function by making the day equate to the day of the month, rather than the day of the week.

How about
date = new Date().toJSON().substr(0,10).split("-")
date = date[0] + date[1] + date[2]
Edit:
This will return the UTC date, not local date...
For local date, you could use:
date = new Date().toLocaleDateString().split("/"); // "M/D/YYYY"
date[0] = date[0].length == 1 ? "0" + date[0] : date[0];
date[1] = date[1].length == 1 ? "0" + date[1] : date[1];
date = date[2] + date[0] + date[1];

var d = new Date();
var curr_date = d.getDate();
var curr_month = d.getMonth();
var curr_year = d.getFullYear();
document.write(curr_year + curr_month + curr_date);
That should give the right date:)

JavaScript Date / Time Conversion

I have dates and times in a database in the following format:
2011-08-02T00:00:00-00:00
What is the easiest way to convert them to something like 8-2-2011?
Thanks,

var date = "2011-08-02T00:00:00-00:00".split('T')[0].split('-').reverse();
var month = date[0], day = date[1];
//remove 0 in the beginning if not necessary
if (+month < 10) {
month = month.slice(1);
}
if (+day < 10) {
day = day.slice(1);
}
//swap between the two
date[0] = day;
date[1] = month;
date.join('-');
Or you can use the boring Date way.

Here's the code:
x=new Date("2011-08-02T00:00:00-00:00")
str=(x.getUTCMonth()+1)+"-"+x.getUTCDate()+"-"+x.getUTCFullYear()
Or:
x="2011-08-02T00:00:00-00:00"
x=/^(\d+)\-(\d+)\-(\d+)/.exec(x)
if(x){
str=(parseInt(x[2],10)+"-"+parseInt(x[3],10)+"-"+parseInt(x[1],10))
}

This format will work in the Javascript Date constructor:
var d = new Date("2011-08-02T00:00:00-00:00");
var month = d.getUTCMonth() + 1;
var day = d.getUTCDate();
var year = d.getUTCFullYear();
var output = month + "-" + day + "-" + year;

one way could be to split up the date part
var date = "2011-08-02T00:00:00-00:00";
var dpart = (date.substr(0,10)).split("-");
var odate = parseInt(dpart[1],10)+"-"+parseInt(dpart[2],10)+"-"+dpart[0];

Javascript date - Leading 0 for days and months where applicable

Is there a clean way of adding a 0 in front of the day or month when the day or month is less than 10:
var myDate = new Date();
var prettyDate =(myDate.getFullYear() +'-'+ myDate.getMonth()) +'-'+ myDate.getDate();
This would output as:
2011-8-8
I would like it to be:
2011-08-08

The format you seem to want looks like ISO. So take advantage of toISOString():
var d = new Date();
var date = d.toISOString().slice(0,10); // "2014-05-12"

No, there is no nice way to do it. You have to resort to something like:
var myDate = new Date();
var year = myDate.getFullYear();
var month = myDate.getMonth() + 1;
if(month <= 9)
month = '0'+month;
var day= myDate.getDate();
if(day <= 9)
day = '0'+day;
var prettyDate = year +'-'+ month +'-'+ day;

var myDate = new Date();
var m = myDate.getMonth() + 1;
var d = myDate.getDate();
m = m > 9 ? m : "0"+m;
d = d > 9 ? d : "0"+d;
var prettyDate =(myDate.getFullYear() +'-'+ m) +'-'+ d;
...and a sample: http://jsfiddle.net/gFkaP/

You can try like this
For day:
("0" + new Date().getDate()).slice(-2)
For month:
("0" + (new Date().getMonth() + 1)).slice(-2)
For year:
new Date().getFullYear();

You will have to manually check if it needs a leading zero and add it if necessary...
var m = myDate.getMonth();
var d = myDate.getDate();
if (m < 10) {
m = '0' + m
}
if (d < 10) {
d = '0' + d
}
var prettyDate = myDate.getFullYear() +'-'+ m +'-'+ d;

Yes, get String.js by Rumata and then use:
'%04d-%02d-%02d'.sprintf(myDate.getFullYear(),
myDate.getMonth() + 1,
myDate.getDate());
NB: don't forget the + 1 on the month field. The Date object's month field starts from zero, not one!
If you don't want to use an extra library, a trivial inline function will do the job of adding the leading zeroes:
function date2str(d) {
function fix2(n) {
return (n < 10) ? '0' + n : n;
}
return d.getFullYear() + '-' +
fix2(d.getMonth() + 1) + '-' +
fix2(d.getDate());
}
or even add it to the Date prototype:
Date.prototype.ISO8601date = function() {
function fix2(n) {
return (n < 10) ? '0' + n : n;
}
return this.getFullYear() + '-' +
fix2(this.getMonth() + 1) + '-' +
fix2(this.getDate());
}
usage (see http://jsfiddle.net/alnitak/M5S5u/):
var d = new Date();
var s = d.ISO8601date();

For Month,
var month = ("0" + (myDate.getMonth() + 1)).slice(-2);
For Day,
var day = ("0" + (myDate.getDate() + 1)).slice(-2);

Unfortunately there's no built-in date-format in javascript. Either use a existing library (example http://blog.stevenlevithan.com/archives/date-time-format) or build your own method for adding a leading zero.
var addLeadingZeroIfNeeded = function addLeadingZeroIfNeeded(dateNumber) {
if (String(dateNumber).length === 1) {
return '0' + String(dateNumber);
}
return String(dateNumber);
},
myDate = new Date(),
prettyDate;
prettyDate = myDate.getFullYear() + '-' + addLeadingZeroIfNeeded(myDate.getMonth()) + '-' + addLeadingZeroIfNeeded(myDate.getDate());
EDIT
As Alnitak said, keep in mind that month i JavaScript starts on 0 not 1.

The easiest way to do this is to prepend a zero and then use .slice(-2).
With this function you always return the last 2 characters of a string.
var month = 8;
var monthWithLeadingZeros = ('0' + month).slice(-2);
Checkout this example:
http://codepen.io/Shven/pen/vLgQMQ?editors=101

How do I get Month and Date of JavaScript in 2 digit format?

When we call getMonth() and getDate() on date object, we will get the single digit number.
For example :
For january, it displays 1, but I need to display it as 01. How to do that?

("0" + this.getDate()).slice(-2)
for the date, and similar:
("0" + (this.getMonth() + 1)).slice(-2)
for the month.

If you want a format like "YYYY-MM-DDTHH:mm:ss", then this might be quicker:
var date = new Date().toISOString().substr(0, 19);
// toISOString() will give you YYYY-MM-DDTHH:mm:ss.sssZ
Or the commonly used MySQL datetime format "YYYY-MM-DD HH:mm:ss":
var date2 = new Date().toISOString().substr(0, 19).replace('T', ' ');

Why not use padStart ?
padStart(targetLength, padString) where
targetLength is 2
padString is 0
// Source: https://stackoverflow.com/a/50769505/2965993
var dt = new Date();
year = dt.getFullYear();
month = (dt.getMonth() + 1).toString().padStart(2, "0");
day = dt.getDate().toString().padStart(2, "0");
console.log(year + '/' + month + '/' + day);
This will always return 2 digit numbers even if the month or day is less than 10.
Notes:
This will only work with Internet Explorer if the js code is transpiled using babel.
getFullYear() returns the 4 digit year and doesn't require padStart.
getMonth() returns the month from 0 to 11.
1 is added to the month before padding to keep it 1 to 12.
getDate() returns the day from 1 to 31.
The 7th day will return 07 and so we do not need to add 1 before padding the string.

Example for month:
function getMonth(date) {
var month = date.getMonth() + 1;
return month < 10 ? '0' + month : '' + month; // ('' + month) for string result
}
You can also extend Date object with such function:
Date.prototype.getMonthFormatted = function() {
var month = this.getMonth() + 1;
return month < 10 ? '0' + month : '' + month; // ('' + month) for string result
}

The best way to do this is to create your own simple formatter (as below):
getDate() returns the day of the month (from 1-31)
getMonth() returns the month (from 0-11) < zero-based, 0=January, 11=December
getFullYear() returns the year (four digits) < don't use getYear()
function formatDateToString(date){
// 01, 02, 03, ... 29, 30, 31
var dd = (date.getDate() < 10 ? '0' : '') + date.getDate();
// 01, 02, 03, ... 10, 11, 12
var MM = ((date.getMonth() + 1) < 10 ? '0' : '') + (date.getMonth() + 1);
// 1970, 1971, ... 2015, 2016, ...
var yyyy = date.getFullYear();
// create the format you want
return (dd + "-" + MM + "-" + yyyy);
}

I would do this:
var date = new Date(2000, 0, 9);
var str = new Intl.DateTimeFormat('en-US', {
month: '2-digit',
day: '2-digit',
year: 'numeric'
}).format(date);
console.log(str); // prints "01/09/2000"

The following is used to convert db2 date format
i.e YYYY-MM-DD using ternary operator
var currentDate = new Date();
var twoDigitMonth=((currentDate.getMonth()+1)>=10)? (currentDate.getMonth()+1) : '0' + (currentDate.getMonth()+1);
var twoDigitDate=((currentDate.getDate())>=10)? (currentDate.getDate()) : '0' + (currentDate.getDate());
var createdDateTo = currentDate.getFullYear() + "-" + twoDigitMonth + "-" + twoDigitDate;
alert(createdDateTo);

Just another example, almost one liner.
var date = new Date();
console.log( (date.getMonth() < 9 ? '0': '') + (date.getMonth()+1) );

function monthFormated(date) {
//If date is not passed, get current date
if(!date)
date = new Date();
month = date.getMonth();
// if month 2 digits (9+1 = 10) don't add 0 in front
return month < 9 ? "0" + (month+1) : month+1;
}

If it might spare some time I was looking to get:
YYYYMMDD
for today, and got along with:
const dateDocumentID = new Date()
.toISOString()
.substr(0, 10)
.replace(/-/g, '');

function monthFormated() {
var date = new Date(),
month = date.getMonth();
return month+1 < 10 ? ("0" + month) : month;
}

This was my solution:
function leadingZero(value) {
if (value < 10) {
return "0" + value.toString();
}
return value.toString();
}
var targetDate = new Date();
targetDate.setDate(targetDate.getDate());
var dd = targetDate.getDate();
var mm = targetDate.getMonth() + 1;
var yyyy = targetDate.getFullYear();
var dateCurrent = leadingZero(mm) + "/" + leadingZero(dd) + "/" + yyyy;

Using Moment.js it can be done like that:
moment(new Date(2017, 1, 1)).format('DD') // day
moment(new Date(2017, 1, 1)).format('MM') // month

const today = new Date().toISOString()
const fullDate = today.split('T')[0];
console.log(fullDate) //prints YYYY-MM-DD

Not an answer but here is how I get the date format I require in a variable
function setDateZero(date){
return date < 10 ? '0' + date : date;
}
var curr_date = ev.date.getDate();
var curr_month = ev.date.getMonth() + 1;
var curr_year = ev.date.getFullYear();
var thisDate = curr_year+"-"+setDateZero(curr_month)+"-"+setDateZero(curr_date);
Hope this helps!

Ternary Operator Solution
A simple ternary operator can add a "0" before the number if the month or day is less than 10 (assuming you need this information for use in a string).
let month = (date.getMonth() < 10) ? "0" + date.getMonth().toString() : date.getMonth();
let day = (date.getDate() < 10) ? "0" + date.getDate().toString() : date.getDate();

The more modern approach perhaps, using "padStart"
const now = new Date();
const day = `${now.getDate()}`.padStart(2, '0');
const month = `${now.getMonth()}`.padStart(2, '0');
const year = now.getFullYear();
then you can build as a template string if you wish:
`${day}/${month}/${year}`

Tip from MDN :
function date_locale(thisDate, locale) {
if (locale == undefined)
locale = 'fr-FR';
// set your default country above (yes, I'm french !)
// then the default format is "dd/mm/YYY"
if (thisDate == undefined) {
var d = new Date();
} else {
var d = new Date(thisDate);
}
return d.toLocaleDateString(locale);
}
var thisDate = date_locale();
var dayN = thisDate.slice(0, 2);
var monthN = thisDate.slice(3, 5);
console.log(dayN);
console.log(monthN);
http://jsfiddle.net/v4qcf5x6/

new Date().getMonth() method returns the month as a number (0-11)
You can get easily correct month number with this function.
function monthFormatted() {
var date = new Date(),
month = date.getMonth();
return month+1 < 10 ? ("0" + month) : month;
}

I would suggest you use a different library called Moment https://momentjs.com/
This way you are able to format the date directly without having to do extra work
const date = moment().format('YYYY-MM-DD')
// date: '2020-01-04'
Make sure you import moment as well to be able to use it.
yarn add moment
# to add the dependency
import moment from 'moment'
// import this at the top of the file you want to use it in
Hope this helps :D

How it easy?
new Date().toLocaleString("en-US", { day: "2-digit" })
Another options are available such:
weekday
year
month
More info here.
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date/toLocaleDateString#using_options

function GetDateAndTime(dt) {
var arr = new Array(dt.getDate(), dt.getMonth(), dt.getFullYear(),dt.getHours(),dt.getMinutes(),dt.getSeconds());
for(var i=0;i<arr.length;i++) {
if(arr[i].toString().length == 1) arr[i] = "0" + arr[i];
}
return arr[0] + "." + arr[1] + "." + arr[2] + " " + arr[3] + ":" + arr[4] + ":" + arr[5];
}

And another version here https://jsfiddle.net/ivos/zcLxo8oy/1/, hope to be useful.
var dt = new Date(2016,5,1); // just for the test
var separator = '.';
var strDate = (dt.getFullYear() + separator + (dt.getMonth() + 1) + separator + dt.getDate());
// end of setup
strDate = strDate.replace(/(\b\d{1}\b)/g, "0$1")

The answers here were helpful, however I need more than that: not only month, date, month, hours & seconds, for a default name.
Interestingly, though prepend of "0" was needed for all above, " + 1" was needed only for month, not others.
As example:
("0" + (d.getMonth() + 1)).slice(-2) // Note: +1 is needed
("0" + (d.getHours())).slice(-2) // Note: +1 is not needed

My solution:
function addLeadingChars(string, nrOfChars, leadingChar) {
string = string + '';
return Array(Math.max(0, (nrOfChars || 2) - string.length + 1)).join(leadingChar || '0') + string;
}
Usage:
var
date = new Date(),
month = addLeadingChars(date.getMonth() + 1),
day = addLeadingChars(date.getDate());
jsfiddle: http://jsfiddle.net/8xy4Q/1/

var net = require('net')
function zeroFill(i) {
return (i < 10 ? '0' : '') + i
}
function now () {
var d = new Date()
return d.getFullYear() + '-'
+ zeroFill(d.getMonth() + 1) + '-'
+ zeroFill(d.getDate()) + ' '
+ zeroFill(d.getHours()) + ':'
+ zeroFill(d.getMinutes())
}
var server = net.createServer(function (socket) {
socket.end(now() + '\n')
})
server.listen(Number(process.argv[2]))

if u want getDate() function to return the date as 01 instead of 1, here is the code for it....
Lets assume Today's date is 01-11-2018
var today = new Date();
today = today.getFullYear()+ "-" + (today.getMonth() + 1) + "-" + today.getDate();
console.log(today); //Output: 2018-11-1
today = today.getFullYear()+ "-" + (today.getMonth() + 1) + "-" + ((today.getDate() < 10 ? '0' : '') + today.getDate());
console.log(today); //Output: 2018-11-01

I wanted to do something like this and this is what i did
p.s. i know there are right answer(s) on top, but just wanted to add something of my own here
const todayIs = async () =>{
const now = new Date();
var today = now.getFullYear()+'-';
if(now.getMonth() < 10)
today += '0'+now.getMonth()+'-';
else
today += now.getMonth()+'-';
if(now.getDay() < 10)
today += '0'+now.getDay();
else
today += now.getDay();
return today;
}

If you'll check smaller than 10, you haven't to create a new function for that. Just assign a variable into brackets and return it with ternary operator.
(m = new Date().getMonth() + 1) < 10 ? `0${m}` : `${m}`

currentDate(){
var today = new Date();
var dateTime = today.getFullYear()+'-'+
((today.getMonth()+1)<10?("0"+(today.getMonth()+1)):(today.getMonth()+1))+'-'+
(today.getDate()<10?("0"+today.getDate()):today.getDate())+'T'+
(today.getHours()<10?("0"+today.getHours()):today.getHours())+ ":" +
(today.getMinutes()<10?("0"+today.getMinutes()):today.getMinutes())+ ":" +
(today.getSeconds()<10?("0"+today.getSeconds()):today.getSeconds());
return dateTime;
},

Get date for every Thursday in the year Javascript

Given a day of the week (var day) the code below will print the date of each
day in the year starting from today. Since 4 = Thursday, I will get a list
of all the Thursdays left in the year. I was just curious if there was some
'neater' way to accomplish this?
var day = 4;
var date = new Date();
var nextYear = date.getFullYear() + 1;
while(date.getDay() != day)
{
date.setDate(date.getDate() + 1)
}
while(date.getFullYear() < nextYear)
{
var yyyy = date.getFullYear();
var mm = (date.getMonth() + 1);
mm = (mm < 10) ? '0' + mm : mm;
var dd = date.getDate();
dd = (dd < 10) ? '0' + dd : dd;
console.log(yyyy + '-' + mm + '-' + dd)
date.setDate(date.getDate() + 7);
}
Output:
2011-02-10
2011-02-17
2011-02-24
2011-03-03
2011-03-10
..etc

Well, it would look a lot prettier if you used Datejs.
var thursday = Date.today().next().thursday(),
nextYear = Date.next().january().set({day: 1}),
format = 'yyyy-MM-dd';
while (thursday.isBefore(nextYear))
{
console.log(thursday.toString(format));
thursday = thursday.add(7).days();
}
See also http://code.google.com/p/datejs/.