I've created a kendo grid, and need to insert kendo drop down into one of the columns. I need to get the data for the drop down from another data source. It kind of works, however, the problem is when I have chosen a value from the drop down and the drop down closes, instead of displaying that value it goes into editable mode. Only when I click outside of the dropdown, it displays the correct value. Here is a gif of the issue:
https://media2.giphy.com/media/KyMGB7FmFQMVTChFA7/giphy.gif
How could this issue be solved?
I have successfully created a kendo grid with a drop down list already. The only difference seems to be that there only one data source is used, but here two are used. Here is some of the code for the drop down:
title: "Type",
field: "productType.name", //this property is from the data source used for grid
template: "<kendo-drop-down-list k-value=\"dataItem.productType.id\"
k-options=\"productTypeOptions\" ng-change=\"productTypeChanged(dataItem, 'productType')\"
ng-model=\"dataItem.productType.id\"></kendo-drop-down-list>"
}...];
$scope.productTypes = {
data: [{ name: "Value 1", id: "1" }, { name: "Value 2", id: "2" }]
}
$scope.productTypeDataSource = new kendo.data.DataSource({
schema: {
data: "data",
model: {
fields: {
id: { type: "number" },
name: { type: "string" }
}
}
},
data: $scope.productTypes,
serverPaging: true,
serverSorting: true,
serverFiltering: true
});
$scope.productTypeOptions = {
dataSource: $scope.productTypeDataSource,
dataTextField: "name",
dataValueField: "id"
};
$scope.productTChanged = function (dataItem, field, productArray, dataSource) {
var index = dataSource.indexOf(dataItem);
var c = productArray.data[index];
if (c == null) return;
c[field] = dataItem[field];
return c;
};
$scope.productTypeChanged = function (dataItem, field) {
$scope.productTChanged(dataItem, field, $scope.products, $scope.productDataSource);
};```
I have a BootstrapTable select box. I know you can use a function to populate the values in the select box. I'd like that function to change which array it provides based on the value of a second column (called Text_example).
So in my example, if Text_example for that row is 1, the select box should have the following data: [{1:1}]. if Text_example for that row is 2, the select box should have the following data: [{2:2}]
I think my problem is that I don't know how to pass just the row's data to the function get_values as my method seems not to be working.
Full Fiddle: http://jsfiddle.net/goxe6ehg/
var data = [{"Text_example": 1},{"Text_example": 2}];
function get_values(data) {
if (data['Text_Example'] === 1) {
return [{1:1}];
}
else {
return [{2: 2}]
}
}
$('#table').bootstrapTable({
columns: [
{
field: 'Select_example',
title: 'Select_example',
editable: {
type: 'select',
source: get_values($('#table').bootstrapTable('getData'))
}
},
{
field: 'Text_example',
title: 'Text_example'
}
],
data: data
});
EDIT: I over-simplified my example. Rather than having a static field for text_example I need it to be a select box, where the value for select_example changes based on what the user has selected in text_example.
Updated JSFiddle: http://jsfiddle.net/4wwv18Lq/4/
You can use the oninit handler on the bootstraptable library.And add the editables by iterating through the data object.
var data = [{"Text_example": 1},{"Text_example": 2}];
$('#table').on('editable-init.bs.table', function(e){
var $els = $('#table').find('.editable');
$els.each(function(index,value){
$(this).editable('option', 'source', data[index])
});
});
$('#table').bootstrapTable({
columns: [
{
field: 'Select_example',
title: 'Select_example',
editable: {
type: 'select'
}
},
{
field: 'Text_example',
title: 'Text_example'
}
],
data: data
});
JSfiddle link
http://jsfiddle.net/km10z2xe/
I'm fairly new to kendo UI but some how I managed to render a kendo grid with drag and drop feature Where users can drag and place rows.In my case I have three columns id,name,sequence
So I need to keep sequence column data unchanged while id and name data changed when a drag and drop of a row.
Ex id=1 Name=David Sequnce=0
id=2 Name=Mark Sequnce=1
Now I'm going to drag row 1 to 2 while data of the sequence column remain unchanged new data like this,
Ex id=2 Name=Mark Sequnce=0
id=1 Name=David Sequnce=1
In my case every row is getting changed. I need to implement this solution.
Can somebody help me out on this.
Cheers,
Chinthaka
Try this,
Script
<script type="text/javascript">
$(document).ready(function () {
var data = [
{ id: 1, text: "David ", Sequnce: 0 },
{ id: 2, text: "Mark ", Sequnce: 1 }
]
var dataSource = new kendo.data.DataSource({
data: data,
schema: {
model: {
id: "id",
fields: {
id: { type: "number" },
text: { type: "string" },
Sequnce: { type: "number" }
}
}
}
});
var grid = $("#grid").kendoGrid({
dataSource: dataSource,
scrollable: false,
columns: ["id", "text", "Sequnce"]
}).data("kendoGrid");
grid.table.kendoDraggable({
filter: "tbody > tr",
group: "gridGroup",
hint: function (e) {
return $('<div class="k-grid k-widget"><table><tbody><tr>' + e.html() + '</tr></tbody></table></div>');
}
});
grid.table/*.find("tbody > tr")*/.kendoDropTarget({
group: "gridGroup",
drop: function (e) {
var target = dataSource.get($(e.draggable.currentTarget).data("id"));
dest = $(e.target);
if (dest.is("th")) {
return;
}
dest = dataSource.get(dest.parent().data("id"));
//not on same item
if (target.get("id") !== dest.get("id")) {
//reorder the items
var tmp = target.get("Sequnce");
target.set("Sequnce", dest.get("Sequnce"));
dest.set("Sequnce", tmp);
dataSource.sort({ field: "Sequnce", dir: "asc" });
}
}
});
});
</script>
View
<div id="grid">
</div>
Demo: http://jsfiddle.net/nmB69/710/
I'm going to implement drag and drop behaviour with kendo grid which is populated using template. How can I achieve draggable rows and reordering with kendo grid.
.Orderable()
Works a treat. Maybe try ".Dragable()" I'm a bit unsure about that though.
Take a look at following my demo code and try it to implement.
var data = [
{ id: 1, text: "text 1", position: 0 },
{ id: 2, text: "text 2", position: 1 },
{ id: 3, text: "text 3", position: 2 }
]
var dataSource = new kendo.data.DataSource({
data: data,
schema: {
model: {
id: "id",
fields: {
id: { type: "number" },
text: { type: "string" },
position: { type: "number" }
}
}
}
});
var grid = $("#grid").kendoGrid({
dataSource: dataSource,
scrollable: false,
columns: ["id", "text", "position"]
}).data("kendoGrid");
grid.table.kendoDraggable({
filter: "tbody > tr",
group: "gridGroup",
hint: function(e) {
return $('<div class="k-grid k-widget"><table><tbody><tr>' + e.html() + '</tr></tbody></table></div>');
}
});
grid.table/*.find("tbody > tr")*/.kendoDropTarget({
group: "gridGroup",
drop: function(e) {
var target = dataSource.get($(e.draggable.currentTarget).data("id")),
dest = $(e.target);
if (dest.is("th")) {
return;
}
dest = dataSource.get(dest.parent().data("id"));
//not on same item
if (target.get("id") !== dest.get("id")) {
//reorder the items
var tmp = target.get("position");
target.set("position", dest.get("position"));
dest.set("position", tmp);
dataSource.sort({ field: "position", dir: "asc" });
}
}
});
put .Dragable()
but make sure that you sit it in the right place, the ordering is required. Some times you may not get the expected result and that may happen due to not paying attention to the order.
I've got an ExtJS (4.0.7) GridPanel that I'm populating from a store. The values that I display in the GridPanel's column need to have a different view depending on the type of data that's in the record.
The ultimate goal is that records with "double" or "integer" value for the record's type property present a slider to the user that they can adjust, and a type of "string" just renders some read-only text.
I've created a custom Column to do this. It inspects the type in the renderer and determines what to render.
I've got the "string" working fine with the code below, but struggling with how I can dynamically create and render the more complicated slider control in the column.
This simplified example is just trying to render a Panel with a date control in it as if I can get that going, I can figure out the rest of the slider stuff.
Ext.define('MyApp.view.MyColumn', {
extend: 'Ext.grid.column.Column',
alias: ['widget.mycolumn'],
stringTemplate: new Ext.XTemplate('code to render {name} for string items'),
constructor: function(cfg){
var me = this;
me.callParent(arguments);
me.renderer = function(value, p, record) {
var data = Ext.apply({}, record.data, record.getAssociatedData());
if (data.type == "string") {
return me.renderStringFilter(data);
} else if (data.type == "double" || data.type == "integer") {
return me.renderNumericFilter(data);
} else {
log("Unknown data.type", data);
};
},
renderStringFilter: function(data) {
// this works great and does what I want
return this.stringTemplate.apply(data);
},
renderNumericFilter: function(data) {
// ***** How do I get a component I "create" to render
// ***** in it's appropriate position in the gridpanel?
// what I really want here is a slider with full behavior
// this is a placeholder for just trying to "create" something to render
var filterPanel = Ext.create('Ext.panel.Panel', {
title: 'Filters',
items: [{
xtype: 'datefield',
fieldLabel: 'date'
}],
renderTo: Ext.getBody() // this doesn't work
});
return filterPanel.html; // this doesn't work
}
});
My problem really is, how can I Ext.create a component, and have it render into a column in the gridpanel?
There are a few ways that I have seen this accomplished. Since the grid column is not an Ext container it can not have Ext components as children as part of any configuration the way other container components can. Post grid-rendering logic is required to add Ext components to cells.
This solution modifies your custom column render so that it puts a special css class on the rendered TD tag. After the grid view is ready, the records are traversed and the custom class is found for appropriate special columns. A slider is rendered to each column found.
The code below is a modified version of the ext js array grid example provided in the Sencha examples. The modification mixes in the custom column renderer and the post grid rendering of sliders to TD elements.
This example only includes enough modification of the Sencha example to show the implementation ideas. It lacks separated view and controller logic.
This is modified from here
Ext.require([
'Ext.grid.*',
'Ext.data.*',
'Ext.util.*',
'Ext.data.Model'
]);
Ext.onReady(function() {
// sample static data for the store
Ext.define('Company', {
extend: 'Ext.data.Model',
fields: ['name', 'price', 'change', 'pctChange', 'lastUpdated', 'type']
});
var myData = [
['3m Co', 71.72, 2, 0.03, '9/1/2011', 'integer'],
['Alcoa Inc', 29.01, 4, 1.47, '9/1/2011', 'string'],
['Altria Group Inc', 83.81, 6, 0.34, '9/1/2011', 'string'],
['American Express Company', 52.55, 8, 0.02, '9/1/2011', 'string'],
['American International Group, Inc.', 64.13, 2, 0.49, '9/1/2011', 'integer'],
['AT&T Inc.', 31.61, 4, -1.54, '9/1/2011', 'integer'],
['Boeing Co.', 75.43, 6, 0.71, '9/1/2011', 'string'],
['Caterpillar Inc.', 67.27, 8, 1.39, '9/1/2011', 'integer'],
['Citigroup, Inc.', 49.37, 1, 0.04, '9/1/2011', 'integer'],
['E.I. du Pont de Nemours and Company', 40.48, 3, 1.28, '9/1/2011', 'integer'],
['Exxon Mobil Corp', 68.1, 0, -0.64, '9/1/2011', 'integer'],
['General Electric Company', 34.14, 7, -0.23, '9/1/2011', 'integer']
];
// create the data store
var store = Ext.create('Ext.data.ArrayStore', {
model: 'Company',
data: myData
});
// existing template
stringTemplate = new Ext.XTemplate('code to render {name} for string items');
// custom column renderer
specialRender = function(value, metadata, record) {
var data;
data = Ext.apply({}, record.data, record.getAssociatedData());
if (data.type == "string") {
return stringTemplate.apply(data);;
} else if (data.type == "double" || data.type == "integer") {
// add a css selector to the td html class attribute we can use it after grid is ready to render the slider
metadata.tdCls = metadata.tdCls + 'slider-target';
return '';
} else {
return ("Unknown data.type");
}
};
// create the Grid
grid = Ext.create('Ext.grid.Panel', {
rowsWithSliders: {},
store: store,
stateful: true,
stateId: 'stateGrid',
columns: [{
text: 'Company',
flex: 1,
sortable: false,
dataIndex: 'name'
}, {
text: 'Price',
width: 75,
sortable: true,
renderer: 'usMoney',
dataIndex: 'price'
}, {
text: 'Change',
width: 75,
sortable: true,
dataIndex: 'change',
renderer: specialRender,
width: 200
}, {
text: '% Change',
width: 75,
sortable: true,
dataIndex: 'pctChange'
}, {
text: 'Last Updated',
width: 85,
sortable: true,
renderer: Ext.util.Format.dateRenderer('m/d/Y'),
dataIndex: 'lastUpdated'
}],
height: 350,
width: 600,
title: 'Irm Grid Example',
renderTo: 'grid-example',
viewConfig: {
stripeRows: true
}
});
/**
* when the grid view is ready this method will find slider columns and render the slider to them
*/
onGridViewReady = function() {
var recordIdx,
colVal,
colEl;
for (recordIdx = 0; recordIdx < grid.store.getCount(); recordIdx++) {
record = grid.store.getAt(recordIdx);
sliderHolder = Ext.DomQuery.select('.slider-target', grid.view.getNode(recordIdx));
if (sliderHolder.length) {
colEl = sliderHolder[0];
// remove div generated by grid template - alternative is to use a new template in the col
colEl.innerHTML = '';
// get the value to be used in the slider from the record and column
colVal = record.get('change');
// render the slider - pass in the full record in case record data may be needed by change handlers
renderNumericFilter(colEl, colVal, record)
}
}
}
// when the grids view is ready, render sliders to it
grid.on('viewready', onGridViewReady, this);
// modification of existing method but removed from custom column
renderNumericFilter = function(el, val, record) {
var filterPanel = Ext.widget('slider', {
width: 200,
value: val,
record: record,
minValue: 0,
maxValue: 10,
renderTo: el
});
}
});
I did something like this when I needed to render a small chart (essentially a spark chart) in a grid column. This solution is similar to sha's, but it's more robust and delegates the rendering to the component being rendered rather than the Column, which doesn't really have a render chain.
First, the column class:
Ext.define("MyApp.view.Column", {
extend: "Ext.grid.column.Column",
// ...
renderer: function (value, p, record) {
var container_id = Ext.id(),
container = '<div id="' + container_id + '"></div>';
Ext.create("MyApp.view.Chart", {
type: "column",
// ...
delayedRenderTo: container_id
});
return container;
}
});
Note the delayedRenderTo config option. Just like renderTo, this will be the DOM ID of the element that the chart component will render to, except that it doesn't need to be present in the DOM at the time of creation.
Then the component class:
Ext.define("MyApp.view.Chart", {
extend: "Ext.chart.Chart",
// ...
initComponent: function () {
if (this.delayedRenderTo) {
this.delayRender();
}
this.callParent();
},
delayRender: function () {
Ext.TaskManager.start({
scope: this,
interval: 100,
run: function () {
var container = Ext.fly(this.delayedRenderTo);
if (container) {
this.render(container);
return false;
} else {
return true;
}
}
});
}
});
So during initComponent(), we check for delayed render and prepare that if necessary. Otherwise, it renders as normal.
The delayRender() function itself schedules a task to check every so often (100ms in this case) for the existence of an element with the given ID — i.e., to check whether the column has rendered. If not, returns true to reschedule the task. If so, renders the component and returns false to cancel the task.
We've had good luck with this in the field, so I hope it works for you too.
By the way, I was developing this as a part of answering my own question about ExtJS charting. That thread has the results of my performance testing. I was rendering 168 chart components in grid columns in 3-4s across most browsers and OSes. I imagine your sliders would render much faster than that.
Try something like this:
renderNumericFilter: function () {
var id = Ext.id();
Ext.defer(function () {
Ext.widget('slider', {
renderTo: id,
width: 200,
value: 50,
increment: 10,
minValue: 0,
maxValue: 100,
});
}, 50);
return Ext.String.format('<div id="{0}"></div>', id);
}
But I must say whatever you're trying to do - it doesn't sound right :) I don't think a bunch of sliders inside the grid will look good to the user.