I'm developing a website where I have to display a picture (not a problem).
But, I have to display it as this link: http://buildinternet.com/project/supersized/slideshow/3.2/demo.html
So, On resizing, I have to zoom on the picture to never scale it.
Does some on know how to do it?
Here is what I have:
html:
<div id="container_images">
<ul>
<li><img src="images/desktop/myimage.jpg" alt="An awesome image"></li>
</ul>
</div>
CSS:
#container_images{
display: block;
position: fixed;
left: 0;
top: 0;
overflow: hidden;
z-index: -999;
height: 100%;
width: 100%;
}
#container_images li{
display: block;
list-style: none;
z-index: -30;
position: fixed;
overflow: hidden;
top: 0;
left: 0;
width: 100%;
height: 100%;
opacity:1;
}
#container_images li img{
width: 100%;
height: 100%;
display: block;
}
If I understood correctly you don't need the browser's inbuilt zooming (ctrl+), you just want to make the picture fill in the whole window of the browser when the window is resized.
You will need 2 things for that.
First, you need some javascript to execute on window resize event, then you will need some simple maths to calculate the center of the picture taking into account the new window size and set left/top margin of the picture to new values.
You can easily do that with jQuery:
$(window).resize(function() {
var h = $(window).height();
var w = $(window).width();
var pic = $('#container_images img');
var pic_width = pic.width(), pic_height = pic.height();
$(pic).css('margin-left': (w - pic_width)/2).css('margin-top': (h - pic_height)/2);
});
One thing to remember is that if your picture's width/height is already changed from its original size, you will get that new size from width() and height() functions.
So you either should make sure the original is not touched, or use one of the solution out there for grabbing the original picture size (e.g. How do I get actual image width and height using jQuery?).
Also the above snippet is to just get you started, you should grab the picture and its parameters in some init function and only recalculate/modify css on resize event.
Related
I am trying to create a page that has before and after images that use a slider based on mouse movement to show both images. I need to have multiple sliders on the page and can not seem to get them to work. Below are a couple of different examples I have found and the challenges I am having.
http://codepen.io/dudleystorey/pen/JDphy - This works well with mobile but I can not seem to add a second version without adding css for every image since the background image is embedded in the css.
div#inked-painted {
position: relative; font-size: 0;
-ms-touch-action: none;
-webkit-touch-callout: none;
-webkit-user-select: none;
}
div#inked-painted img {
width: 100%; height: auto;
}
div#colored {
background-image: url(https://s3-us-west2.amazonaws.com/s.cdpn.io/4273/colored-panel.jpg);
position: absolute;
top: 0; left: 0; height: 100%;
width: 50%;
background-size: cover;
}
http://codepen.io/ace/pen/BqEer - Here is the other example that does not work as well with mobile. I can add the second image but the slider works all the images simultaneously and not individually when a second image is added.
Can anyone help with adding the second image. I am sure both of these are very workable but I am missing something in my css/javascript knowledge that is not allowing multiple images.
You need to loop though all classes to be able set the eventhandlers individual. Your codepen example could be change to this to work with individual images at once:
var blackWhiteElements= document.getElementsByClassName("black_white");
for (i = 0; i < blackWhiteElements.length; i++) {
initCode($(blackWhiteElements[i]));
}
function initCode($black_white) {
var img_width = $black_white.find('img').width();
var init_split = Math.round(img_width/2);
$black_white.width(init_split);
$black_white.parent('.before_after_slider').mousemove(function(e){
var offX = (e.offsetX || e.clientX - $black_white.offset().left);
$black_white.width(offX);
});
$black_white.parent('.before_after_slider').mouseleave(function(e){
$black_white.stop().animate({
width: init_split
},1000)
});
}
codepen here: http://codepen.io/anon/pen/mJPmKV
Your first attempt is near sufficient.
Assign the background-image inline in the html to avoid extra classes
<div id="colored" style="background-image: url(https://s3-us-west-2.amazonaws.com/s.cdpn.io/4273/colored-panel.jpg);"></div>
change background-size on #colored to background-size: auto 100%; to reduce the "shaky" effect
background-size: auto 100%;
I 'm trying to do kind of slideshow on the background using two img tags. I have a couple of random images, so I have a javascript function to get a random name. But the main problem is: when I zoom or resize window first two slides crop well and display without any problem, but after that every slide is changing if I try to resize the window or zoom in-out.
Here you can see that bug: cullycross.github.io(nevermind about big images, im gonna resize them)
Here is my code:
function randomBackground () {
var active = $('#background .active');
var next = ($('#background .active').next().length > 0) ? $('#background .active').next() : $('#background img:first');
next.attr('src', getRandomName());
var imgHeight = next.height();
var windowHeight = $(window).height();
var diff = imgHeight - windowHeight;
if(diff > 0) {
next.css('top', -diff*0.6);
}
next.css('z-index', 2);
active.fadeOut(1500, function() {
active.css('z-index', 1).show().removeClass('active');
next.css('z-index', 3).addClass('active');
})
}
window.onload = function() {
$('#background .active').attr('src', getRandomName());
$('#background').fadeIn(1500);
setInterval(randomBackground, 5000)
}
Here is css:
#background {
padding: 0;
margin: 0;
width: 100%;
height: 100%;
position: absolute;
top: 0;
left: 0;
z-index: -1;
overflow: hidden;
}
#background img {
position: absolute;
z-index: 1;
float: left;
bottom: 0px;
left: 0px;
top: 0px;
height: auto;
width: 100%;
}
#background img.active {
z-index: 3;
}
Here is part of html:
<div id="background">
<img id="current-image" class="active" />
<img id="next-image" />
</div>
It seem to affect only the images loaded after first run.
Try adding images directly into html, using a
<ul><li><img ...></li></ul>
structure, and get the image from there.
You should decrease the fadeout delay. The problem is caused from the browser since the delay is big it can't handle both fadeout and zoom in/out
active.fadeOut(300, function() {
active.css('z-index', 1).show().removeClass('active');
next.css('z-index', 3).addClass('active');
})
And try to use light size pictures, with the same aspect ratio
I didn't found an answer, but I found a library, that makes possible that thing, that I want. Thx to https://github.com/srobbin/jquery-backstretch
Having a problem in trying to copy the height of a responsive image to my mask on first load and on every time the window is resized. I've tried a few js scripts, but still I cant make it happen.
It is really a responsive image slider with a div(mask) exactly over it whatever the viewport screen size is.
this is my jQuery script:
function maskInit(){
var offsetDots = $("#slide").offset().top + $("#slide").height() + "px";
$("#mask").height() = offsetDots;
}
$(document).ready(function() {
maskInit();
});
$(window).resize(function(){
maskInit();
});
and my CSS:
#slide{
height: 10vw; /* to simulate a responsive image */
width: 100%;
margin: 0;
padding: 0;
background: red;
z-index: 0;
}
#mask{
position: absolute;
z-index: 1;
top: 0;
right: 0;
left: 0;
background: gray;
opacity: 0.8;
}
I've setup a jsFiddle here to simulate my problem
There is something wrong with your script.
You are NOT setting the mask height with this:
$("#mask").height() = offsetDots;
Check jQuery .height()
Instead use it this way:
$("#mask").height(offsetDots);
or you can set via css:
$("#mask").css({"height":offsetDots});
Here's your updated jsFIDDLE demo
.height() is a function so you can not do $("#mask").height() = offsetDots; use $("#mask").height(offsetDots); or by .css({"height":offsetDots}) to set height.
Ok, so i want to have a series of divs which are the exact width and height of the user's browser window, regardless of the screen size. I can easily make the divs stretch horizontally with "width: 100%;" but i cant work out how to make the height stretch itself. I am guessing that i need to use some bit of javascript to judge the height, and then another piece to resize the seperate divs. Unfortunately I am a complete javascript n00b and after two hours of seemingly fruitless searching and coming up with about 100 "solutions" this was as far as id gotten (Im sure that at some point I have probably been closer to the answer):
var viewportHeight = "height:" + document.documentElement.clientHeight;
getElementById('section-1').setAttribute('style', viewportHeight);
<div class="section" id="section-1"></div>
<div class="section" id="section-2"></div>
<div class="section" id="section-3"></div>
edit:
ah i should be more clear, im attempting to have all three divs take up the entire screen, so you have to scroll down to see each one - almost like seperate slides. The idea is that each one takes up the entire screen so you cant see the next section until you scroll down, rather than having three divs which take up a third of the screen.
If you haven't already tried it, you'll want to look at parent:child inheritance of elements within the DOM by way of using CSS.
What I want to STRESS is that everyone giving you JS hacks to accomplish this is not only providing you with overkill (YOU did ask for a JavaScript solution, so they gave it to you!), but it's also a deviation from standards. HTML is for structure, CSS is for presentation, and JavaScript is for behavioral aspects... setting a div to the width of the viewport on load is a PRESENTATION aspect and should be done in CSS... not JavaScript. If you were trying to change the width based on events or user interaction, then yes JavaScript is your friend... but stick with just HTML and CSS for now.
The trick is that most elements have an undefined height - and height is later defined by the content that the element holds.
If you want to 'trick' an element into having a height other than what it wants to default to, you'll have to explicitly define it. Since you want to inherit your height from the viewport, you'll have to define the height at the top and bring it down...
You might be in luck and can avoid JavaScript altogether (unnecessary). Just use CSS.
Try something like:
html, body {
height: 100%;
width: 100%;
}
Now, when you try to set your div's later on, specify width: 100% and the height gets inherited from the html --> body --> div.
Try that and see if that solves your problem - if not, point us to a website, a pastebin, or a SOMETHING with code in it that we can just show you how to do it (whereas what you posted for code was an attempt in JavaScript which is only 1 part of the code - post the full thing either to a server or temp site like pastebin).
Here is some sample code I wrote (tested in Chromium):
The HTML:
<html>
<head>
<title>Test Divs at 100%</title>
<link rel="stylesheet" type="text/css" href="divtest.css"
</head>
<body>
<div class="test1">aef</div>
<div class="test2">aef</div>
<div class="test3">aef</div>
</body>
</html>
The CSS:
html, body {
width: 100%;
height: 100%;
background-color: #793434;
padding: 0;
margin: 0;
}
div {
height: 100%;
width: 100%;
}
.test1 {
background-color: #E3C42E;
}
.test2 {
background-color: #B42626;
}
.test3 {
background-color: #19D443
}
try this
div#welcome {
height: 100vh;
background: black;
color: white;
}
div#projects {
height: 100vh;
background: yellow;
}
<div id="welcome">
your content on screen 1
</div>
<div id="projects">
your content on screen 2
</div>
it should work for you, but little support in IE
A bit of jQuery should do it:
$(document).ready(function() {
var window_height = $(window).height();
$('#section-1").height(window_height);
});
And if you want to keep 100% height on window resize:
$(document).ready(function() {
function viewport_height() {
var window_height = $(window).height();
$('#section-1").height(window_height);
}
viewport_height();
$(window).resize(function() {
viewport_height();
});
});
try this
window.onload = init;
function init()
{
var viewportHeight = "height:" + document.documentElement.clientHeight+"px;";
document.getElementById('section-1').setAttribute('style', viewportHeight);
}
Here is a script free solution, just CSS. This assumes that the divs are directly in the body element or a parent with position absolute and the parent has no padding.
#section-1 {
position: absolute;
height: 100%;
width: 100%;
background: #ff0000;
}
#section-2 {
position: absolute;
width: 100%;
top: 100%;
height: 100%;
background: #00ff00;
}
#section-3 {
position: absolute;
width: 100%;
top: 200%;
height: 100%;
background: #0000ff;
}
See fiddle: http://jsfiddle.net/QtvU5/1/
I have a table with three rows. I have 1 main #container div (height 100%) and inside it is a table with 3 rows. The first and last row have fixed size content. In the second row is a #content div with 100% height and overflow:auto. (actually the table has a lot more rows and the page has more divs, but for the sake of clarity i scalled it down for this question).
If there is more content in #content than fits, a vertical scrollbar should appear next to that div's content. However, a vertical scrollbar appears at the browser window itself. When i set the #content div to a fixed size however, that vertical scrollbar does appear in the correct place.
I must be doing something wrong, or maybe misinterpreting something :) Any ideas? Maybe there's jquery/javascript out there that can monitor the page and when loading/resizing the browser, scales down that particular div?
EDIT: I just created a small example: http://wierdaonline.com/softest.html
In the ideal situation, the whole thing (table) should always be visible in the browser window, without any window scrollbar other than in the #content div.
It's much easier to create a fixed header and footer without using tables and using fixed position:
#header
{
position: fixed;
top: 0;
height: 20px;
}
#middle
{
position: fixed;
top: 20px;
bottom: 20px;
overflow: auto;
}
#footer
{
position: fixed;
bottom: 0;
height: 20px;
}
Set overflow: scroll in the div. You shouldn't need Javascript for this.
The #container 100% is 100% of the page height which can be more than the window height. Setting html and body height to 100% (=100% of the window) could help, depending on what you are trying to achieve.
Edit: these changes should work for the height, a similar thing can be done with the width if you so desire.
javascript:
window.onresize = function() {
var tehdiv = document.getElementById('content2');
if($(window).height() < 100) { tehdiv.height = 50; }
else if($(window).height() > 2000) { tehdiv.height = '100%'; }
else { tehdiv.height = ($(window).height()/2);}
};
the content div's table:
<td valign='top' id='content2'>
Would something like this work?
window.onresize = function() {
var minh = 50;
var minw = 50;
var tehh = (window.height/2);
var tehw = (window.width/2);
var tehdiv = document.getElementById('yourdiv');
tehdiv.height = (tehh > minh)? tehh : minh;
tehdiv.width = (tehw > minw)? tehw : minw;
};
That would make it scale to half the window size, as long as it can be bigger whan 50. You could also change the min to max and make it perform tehdiv.height = 100% at that point.
Well since you have no choice but to use tables, I modified the HTML, but actually left the CSS the same from the demo I posted in a comment above, check it out here - the only problem I've found is in IE7 where the header and footer table cell doesn't go 100% across:
CSS
#header, #footer {
position: absolute;
top: 0;
left: 0;
right: 0;
height: 20px;
border: #000 1px solid;
margin: 5px;
}
#footer {
top: auto;
bottom: 0;
}
#content {
position: absolute;
top: 25px;
left: 0;
bottom: 25px;
right: 0;
overflow-y: auto;
background: #ddd;
margin: 5px;
}
HTML
<table id="page">
<thead>
<tr><td id="header">Header</td></tr>
</thead>
<tfoot>
<tr><td id="footer">Footer</td></tr>
</tfoot>
<tbody>
<tr><td><div id="content">Content goes here</div></td></tr>
</tbody>
</table>
It's still better to not use tables, if you get around to switching the HTML around.