Javascript Closures (Object literal Vs Constructor based) - javascript

When using Javascript Closures, is there some difference in using Object literal Vs Constructor based objects ?
Are there just syntax difference OR is there some other difference as well for Closures?
Any example explaining the 2 differences would be really helpful.

Closures are a feature of functional programming. They have nothing to do with objects or object literals.
Read the following answer - it explains closures really well: https://stackoverflow.com/a/12931785/783743
In general a closure is a function which closes over the variables in a nested function which moves out of the scope of the closure. For example:
function getCounter() {
var count = 0;
return function counter() {
return ++count;
};
}
var counter = getCounter();
counter(); // 1
counter(); // 2
counter(); // 3
Here the function getCounter becomes a closure because it closes over the variable count used in the nested function counter when the nested function is returned (moves out of the scope of getCounter).
The variable which is closed over (in this case count) is called an upvalue. Closures are important because they allow values which would otherwise go out of scope (be garbage collected) to remain alive. This is not possible in languages like C/C++ and Java.

Closure is more about the function scope of the variable. So the important thing to know is that the scope of a variable is the function it was defined in. Any function that run inside this scope will have access to its parent function per se. Parent function won't have access to a child function variable, because it's outside of that child's scope.
Therefore a variable in an object literal, would be scoped to the function that it is contained it. (If it's not in a function, then it's in the global scope). A constructor is a function so any variables that it defines, is scoped in itself and inaccessible outside. Any inner methods that are in the constructor has access to those defined variables.
Closures are created when a function has access to a variable that is outside its own scope and that variable may be changed or altered by something else...even well after the function has finished execution.
I hope that helped some what.

Related

How many closures are created in the following code? [duplicate]

I understand that every function in JavaScript is a first-class object and it has an internal property [[scope]] which hosts the binding records of the function's free variables. However, there are two special cases.
Is the function created by Function constructor also a closure? The function object created by Function constructor is special, because its [[scope]] may not refer to the lexical environments of its outer functions, but only the global context. For example,
var a = 1;
var fn = (function outer() {
var a = 2;
var inner = new Function('alert(a); ');
return inner;
})();
fn(); // will alert 1, not 2.
This is unintuitive. Is this also called closure?
If an inner function doesn't have any free variables, can we say a closure is formed when the inner function is created? For example,
// This is a useless case only for academic study
var fn = (function outer() {
var localVar1 = 1,
localVar2 = 2;
return function() {};
})();
In this case, fn refers to an empty function object which was created as an inner function. It has no free variables. In this case can we say a closure is formed?
Is the function created by Function constructor also a closure?
Yes, it closes over the global scope. That might be unintuitive because all other JavaScript closures close over their lexical scope, but it still matches our definition of a closure. In your example, a is a free variable, and resolves to the a in an other scope when the inner/fn function is called somewhere.
If an inner function doesn't have any free variables, can we still call it a closure?
Depends on whom you ask. Some say Yes, others call them "uninteresting closures", personally I say No because they don't reference an outer scope.
Note: Functions created with the Function constructor do not create
closures to their creation contexts; they always are created in the
global scope. When running them, they will only be able to access
their own local variables and global ones, not the ones from the scope
in which the Function constructor was called. This is different from
using eval with code for a function expression.
from https://developer.mozilla.org

Is it true that every function in JavaScript is a closure?

I understand that every function in JavaScript is a first-class object and it has an internal property [[scope]] which hosts the binding records of the function's free variables. However, there are two special cases.
Is the function created by Function constructor also a closure? The function object created by Function constructor is special, because its [[scope]] may not refer to the lexical environments of its outer functions, but only the global context. For example,
var a = 1;
var fn = (function outer() {
var a = 2;
var inner = new Function('alert(a); ');
return inner;
})();
fn(); // will alert 1, not 2.
This is unintuitive. Is this also called closure?
If an inner function doesn't have any free variables, can we say a closure is formed when the inner function is created? For example,
// This is a useless case only for academic study
var fn = (function outer() {
var localVar1 = 1,
localVar2 = 2;
return function() {};
})();
In this case, fn refers to an empty function object which was created as an inner function. It has no free variables. In this case can we say a closure is formed?
Is the function created by Function constructor also a closure?
Yes, it closes over the global scope. That might be unintuitive because all other JavaScript closures close over their lexical scope, but it still matches our definition of a closure. In your example, a is a free variable, and resolves to the a in an other scope when the inner/fn function is called somewhere.
If an inner function doesn't have any free variables, can we still call it a closure?
Depends on whom you ask. Some say Yes, others call them "uninteresting closures", personally I say No because they don't reference an outer scope.
Note: Functions created with the Function constructor do not create
closures to their creation contexts; they always are created in the
global scope. When running them, they will only be able to access
their own local variables and global ones, not the ones from the scope
in which the Function constructor was called. This is different from
using eval with code for a function expression.
from https://developer.mozilla.org

javascript function internal scope [closed]

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Consider the following code:
function nepaliBuddha() {
var a = 20;
return function buddhaNepal() {
console.log(a);
}
}
var closure = nepaliBuddha();
closure(); // logs 20
Now when we invoke closure output is 20. This proves that the internal scope property ([[scope]]) was assigned to the inner function where it was defined or say when declared.If this wasn't assigned at declaration ,there was no way to log 20 as it gets invoked in different context
Invoking closure() the scope chain of a function context is created at function call and consists of the activation object or VO of the current context and the internal [[scope]] property of this function.
Invocation also creates [[scope]] property , this means that internal scope property is created at declaration as well as at execution isn't it?
Usually the definition says the [[scope]] property gets created at run time or at function call but this isn't true as [[scope]] property is already assigned at declaration as well.
What I think is the [[scope]] property might get updated after execution of function, is it? Please give clear definition of [[scope]] internal property. How and when it is created at declaration time or at execution time or at both time.
Wow, aren't you thoroughly confused. Alright, I'll try to explain closures as simply as possible.
First, we'll start with scopes. There are two types of scopes:
Block scopes
Function scopes
A block scope begins immediately when it occurs in the program. A function scope on the other hand does not begin until the function is called. Hence multiple calls to the same function result in multiple scopes being created.
JavaScript does not have block scopes. It only has function scopes. Hence to emulate a block scope we need to create a function expression and immediately execute it. This patttern is called an immediately invoked function expression (IIFE) and it looks like this:
(function () {
// this is the JS equivalent of a block scope
}());
Beside block scopes and function scopes there's another way to classify scopes. Hence we also have:
Lexical scopes
Dynamic scopes
This distinction only applies to function scopes because block scopes are always lexically scoped. JavaScript only has lexical scopes.
To understand the difference between lexical scopes and dynamic scopes we need to understand the difference between free and bound variables.
A free variable is a variable which is used within a function but which is not declared within that function.
A variable which is declared within a function is said to be bound to that function.
Consider the following program:
function add(x, y) {
return x + y; // x and y are bound to add
}
In the above program the variables x and y are bound to the function add because they are declared within add.
On the other hand the variables x and y in the following program are free within the function add because they are not declared within add but they are used within add:
function add() {
return x + y; // x and y are free within add
}
Now free variables are a problem. They need to be mapped to some value, but which value? This is where lexical and dynamic scopes come into picture. I won't go into the major details, but you can read about it on Wikipedia.
Scopes are a lot like prototypal inheritance. When a new scope begins it inherits from a parent scope forming a chain of scopes much like prototype chains in JavaScript.
Lexical scopes and dynamic scopes differ with respect to which parent scope a new scope inherits form.
In lexical scoping a new function scope inherits from the scope in which that function was defined (i.e. its lexical environment).
In dynamic scoping a new function scope inherits from the scope in which that function was called (i.e. the calling scope).
Since JavaScript only has lexical scoping we won't bother with dynamic scoping. Consider the following program:
var count = 0;
function incrementCount() {
return ++count;
}
(function () {
var count = 100;
alert(incrementCount()); // 1
}());
Here the function incrementCounter has one free variable - count. Since JavaScript has lexical scoping count will be mapped to the global variable count instead of the local count declared within the IIFE. Hence incrementCount returns 1 and not 101.
Now closures only work in languages which have lexical scoping. Consider the following program:
function getCounter() {
var count = 0;
return function () {
return ++count;
};
}
var counter = getCounter();
alert(counter()); // 1
alert(counter()); // 2
alert(counter()); // 3
In the above program the function returned by getCounter is a closure with respect to the variable count because:
The variable count is free within the returned function (i.e. counter).
The function is moved outside of the scope within which count is declared.
Both these conditions are necessary for a function to be called a closure. For more information read the following answer: https://stackoverflow.com/a/12931785/783743
Now the important thing to understand here is that the function counter will still be called a closure even though it may never be invoked. A closure is simply a function which closes over a variable (which is called the upvalue of the closure).
When we invoke getCounter we create a new scope (let's call this scope A), and each time we invoke the function returned by getCounter (i.e. counter) we create a new scope which inherits from scope A. That's all. No new closure is created.
A closure is a special kind of object that combines two things: a function, and the environment in which that function was created. The environment consists of any local variables that were in-scope at the time that the closure was created.
function makeFunc() {
var name = "Mozilla";
function displayName() {
alert(name);
}
return displayName;
}
Now call makeFunc()
var myFunc = makeFunc();
myFunc();
In this case, myFunc is a closure that incorporates both the displayName function and the "Mozilla" string that existed when the closure was created, MDN.
So, the scope created exactly when I called var myFunc = makeFunc(); and myFunc() (the result of the makeFunc() call) is now a closure. So, go to the first line where
A closure is a special kind of object that combines two things: a
function, and the environment in which that function was created.
Now consider these
function nepaliBuddha() {
var a = 1;
return function buddhaNepal() {
a = a+1;
console.log(a);
}
}
var closure1 = nepaliBuddha(); // An individual scope
var closure2 = nepaliBuddha(); // An individual scope
closure1(); // 1
closure1(); // 2
closure2(); // 1
closure2(); // 2
closure2(); // 3
Demo.
Which means, closure1() and closure2() are closures and both have their personal scope/environment and they have access to their own scope once they get it (in this case, every time you call nepaliBuddha you are creating a closure and giving/saving it to a variable).
Scope defines the area, where functions, variables and such are available. So, when you defined/declared the function buddhaNepal (inner function) inside the nepaliBuddha (outer function) the buddhaNepal (inner function) has been just separated from the global scope and nothing else. It can't access anything in the global scope but it has it's own scope, that's it. The nepaliBuddha (outer function) is the boundary of the buddhaNepal (inner function) and in this case the nepaliBuddha outer function's local scope/environment is the global scope for the buddhaNepal (inner function).
in JavaScript, this is known as Lexical Scopeing it defines how variable names are resolved in nested functions. Other names of Lexical Scope are Static Scoping or Closure. It means that the scope of an inner function contains the scope of a parent function.

An object constructor that takes parameters but has no "vars" inside the constructor body, where is the data?

Where is the data supplied by the argument being stored? Is a var first being created implicitly?
function Student(first){
this.getFirst = function(){
return first;
}
}
Tested with:
var myStudent = new Student("ross");
console.log(myStudent); // Student { getFirst=function() }
console.log(myStudent.getFirst()); // ross
console.log(first); // reference error, first not defined
console.log(myStudent.first); // undefined
for(var x in myStudent){
console.log(x);
} // getFirst
My second question is if I understand these correctly:
What happens with "var" variables inside a JavaScript Constructor?
“var” variables, "this" variables and "global" variables - inside a JavaScript Constructor
...is the getFirst function creates a closure and saves the state of the constructor's parameter value, if I use a var first in the constructor body is it okay to think of that as 'encapsulation'? Additionally, any inner function saves all the parameter values in a "closure state" or just the one's referenced by the inner function?
Thank you very much for your thoughts. This is my first question on S.O. but use the site almost daily as a reference, so thank you for that. My programming knowledge is limited so pardon if I've used crappy terms, happy to clarify where needed.
The first parameter is stored locally to the function that is your constructor, so anywhere inside Student() it will be in scope.
More interestingly, the the anonymous inner function that you're assigning to this.getFirst is closing over that value. Because of that, the inner function maintains a reference to the first variable even after the constructor is finished executing.
This works for regular functions too, not just constructors:
function makeCounter() {
var count = 1;
return function() { return count++; };
}
var counter = makeCounter();
console.log(counter()); // 1
console.log(counter()); // 2
console.log(counter()); // 3
When used the right way, this approach can be used to achieve "private" variables in JavaScript, in the sense that the values captured in the closure are inaccessible from the outside.
Because of that, it turns out not to matter whether a closure captures all the variables in its scope or just the ones it uses, since you can't "reach inside" to those closed-over variables anyway. (Though in practice generally only the used values are captured, so that the runtime can garbage collect the rest, as they're unneeded.)
To get a little further into what you're asking, it's not about creating a var, but rather in your instance the function also keeps the arguments array.
Your functions can happily create closures over both.
By returning functions from your function, those returned functions (or objects with functions as methods) have access to any and all vars and arguments, as long as you don't overwrite those functions.
The magic of closures.

Javascript Closures

I'm quite still confused with the concept of closure in JavaScript. I get the point that closure is the ability of the inner function to access the variable created within its mother function after the mother function has returned.
But I'm still confused why do we have to create inner function to protect the local variable if we could just create a variable inside the function?
We need to create an inner function so that the variables in the outer function have some existence after the outer function returns.
Consider a simple function:
function f() {
var x = 0;
return ++x; // x=1
} // Once the function has exited then "x" no longer exists.
Note that the variable "x" is only "active" (alive, existent) when control of the program flows from the start of the "f()" function to the end of it. But if we enclose "x" in an inner function then x will live as long as the inner function does:
function g() {
var x = 0;
return function() {
// Now "x" will live for as long as this function.
return ++x;
}
};
var counter = g();
counter(); // => 1
counter(); // => 2
counter(); // => 3
Now when we call "g()" we get another function, and "x" is active for as long as that function is referenced by a variable.
Why use closure?
(function(){
var current_page = 1;
function previous_page() {
current_page--;
// update interface
}
function next_page() {
current_page++;
// update interface
}
// a bit of jQuery, ok?
$('#previous').click(previous_page);
$('#next').click(next_page);
})();
Look: we have no global variables, not even any function defined in the global space... yet, we have attached a behaviour to the click events of "#previous" and "#next" buttons for a paging feature. How would you do it without closures? How would you do it defining current_page variable inside the functions?
You just answered your question, the inner function protects it's variable. jsFiddle
(function outer(){
var foo = 'bar';
function inner(){
var foo = 'OMG NO!';
}
alert(foo);//alerts 'bar'
})()
FROM MDN CLOSURES
why to use:
A closure lets you associate some data (the environment) with a function that operates on that data. This has obvious parallels to object oriented programming, where objects allow us to associate some data (the object's properties) with one or more methods.
when not to use
It is unwise to unnecessarily create functions within other functions if closures are not needed for a particular task as it will negatively affect script performance both in terms of processing speed and memory consumption.
For instance, when creating a new object/class, methods should normally be associated to the object's prototype rather than defined into the object constructor. The reason is that whenever the constructor is called the methods would get reassigned (that is, for every object creation).
The reason you need to create the inner function with scoped variables is object oriented encapsulation. It's essentially private variables.
The variables are "closed over".
// constructor function
var myObject = function(message) {
// private - scope is function level. It's CLOSED OVER the the inner function (closure).
// not delcared as a JSON property so not visible externally
var value = 0;
// constructor returns JSON object with public methods
// always constructed from the myObject var so it always hands back the same instance
// of the public methods
return {
// nested functions have access to outer function variables.
increment: function (inc) {
value ++;
},
getValue: function() {
return value;
},
// the inner function even has access to the outer function's args!
getMessage: message
}
};
Look at the return statement. It returns the public interface - some methods that have access to the private variable because they are in the inner function. It's using JavaScripts function scoped variable to create object oriented encapsulation.
After that I can it like:
var obj = myObject('Hello World');
obj.increment();
obj.increment();
console.log(obj.getValue());
console.log(obj.getMessage);
// should be undefined
console.log(obj.value);
Note at this point the consumer does not have access to the protected/encapsulated value or message.
Now, here's the kicker - the object is mutable so the caller can add methods or even replace methods. So, you would think someone could add a method that exposes the internals. But, they can't because of function scope (closure - they're closed over). Only the nested function has access to the variables of the outer function. So, if the caller adds a method to return the internal, they can't get access and it will be undefined.
The code above outputs:
2
Hello World
undefined
As a side note, I'm running the javascript with node.js
Here's a good blog post on the module pattern using closures:
http://www.yuiblog.com/blog/2007/06/12/module-pattern/
The point is that the variable is shared between the two functions. If you declared the variable in the inner function, then the outer function would not be able to access it, so it wouldn't be shared.
If you declared the variable in the inner function, then each call to the inner function would create a new variable: any modifications made by a previous call are lost.
But if the variable is declared in the outer function then multiple calls to the inner function would see the same variable and one call would see the modifications of a previous call so long as they were both scoped to the same version of the outer function.
There are alot of right answers out there about closures, but it always seems to get really technical while many people asking might be looking for a higher level simple explanation first.
I like to think of it like a car. When you drive a car, there are many many complex processes going on, but the average person doesn't need to know about these on an average day. Think of all those complexities as "private" variables hidden away by closures which makes the gas pedal, the break, the shifter, the steering wheel, and so on a lot easier to use.
So what is the purpose of a closure? To hide away all the complex variables and such to make a script much more usable. If you had to worry about every variable in a script everytime you wanted to use any function in the script, well that could quickly get very difficult. YAY CLOSURES!

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