I have two divs
<div id = "first">some details111</div>
and
<div id = "second">some details222</div>
I want to create:
<div id ="New">some details111 some details222</div>
What is the best and the fast way to do it?
Using jQuery you could do that:
$(document).ready(function(){
$("body").append("<div id='New'></div>");
$("#New").text($("#first").text() + " " +$("#second").text());
});
Some vanilla JS for kicks and giggles:
// grab the content from our two divs
var content1 = document.getElementById('one').innerHTML;
var content2 = document.getElementById('two').innerHTML;
// create our new div, pop the content in it, and give it an id
var combined = document.createElement('div');
combined.innerHTML = content1 + " " + content2; // a little spacing
combined.id = 'new';
// 'container' can be whatever your containing element is
document.getElementById('container').appendChild(combined);
Try the below :
Fiddle Example : http://jsfiddle.net/RYh7U/99/
If you already have a DIV with ID "NEW" then try like below:
$('#New').html($('#first').html() + " " + $('#second').html())
If you want to Create a div and then add the Content then try like below.
$("body").append("<div id ='New'></div>")
$('#New').html($('#first').html() + " " + $('#second').html())
Well, using jQuery you can do by this way:
$("body").append(
$('<div/>')
.attr("id","New")
.html(
$("#first).html() + $("#second").html()
)
);
$("<div></div>").attr("id", "New").html($("#first").html() + $("#second").html()).appendTo($("body"));
Related
I am trying to edit the div's text, but when i use my function to update the rowcount, everytime the text vanihes completely. Would by nice if you could also explain why.
Thanks in advance.
My update function:
var rowCountF = $('#tablef tr').length;
var rowCountV = $('#tablev tr').length;
var ftext = "Teilnehmer (" + String(rowCountF) + ")";
var vtext = "Teilnehmer (" + String(rowCountV) + ")";
$("#divf").html(ftext);
$("#divv").html(vtext);
My div layer:
<div id="divf"class="tableheader"> <h2>Teilnehmer</h2> </div>
Code for divf:
<div id="divf"class="tableheader"> <h2>Teilnehmer</h2> </div>
You are actually replacing the contents of the div itself with your text. This means the heading disappears and there is only plain text.
Probably you wanted to replace the heading contents:
$("#divf h2").html(ftext);
$("#divv h2").html(vtext);
This will select the h2 elements inside the divs and hence will update only the text inside the headings.
The result will look like the following:
<div id="divf"class="tableheader"> <h2>Teilnehmer (987)</h2> </div>
<div id="divf"class="tableheader"> <h2>Teilnehmer (123)</h2> </div>
.html() sets the HTML, meaning it replaces anything that's currently there. If you want to add to the HTML, you'll need to set the HTML to what's already there plus what you're adding, like so:
var rowCountF = $('#tablef tr').length;
var rowCountV = $('#tablev tr').length;
var ftext = "Teilnehmer (" + rowCountF + ")";
var vtext = "Teilnehmer (" + rowCountV + ")";
//Get already-existing HTML
var divfHtml = $("#divf").html();
var divvHtml = $("#divv").html();
//Set the new HTML to the existing + the new text
$("#divf").html(divfHtml + ftext);
$("#divv").html(divvHtml + vtext);
If you only want to replace the heading, then just target the <h2> as Martin Zikmund suggested in his answer.
You need to reference the h2 for the div. using .html() will replace ALL of the html inside the #divf which in this case means it will replace the h2
$("#divf h2").html(ftext);
$("#divv h2").html(vtext);
Example: https://jsfiddle.net/qhef0toc/3/
I am bringing a big html string inside an ajax call that I want to modify before I use it on the page. I am wondering if it is possible to edit the string if i store it in a variable then use the newly edited string. In the success of the ajax call this is what I do :
$.each(data.arrangement, function() {
var strHere = "";
strHere = this.htmlContent;
//add new content into strHere here
var content = "<li id=" + this.id + ">" + strHere + "</li>";
htmlContent is the key for the chunk of html code I am storing in the string. It has no problem storing the string (I checked with an alert), but the issue is I need to target a div within the stored string called .widgteFooter, and then add some extra html into that (2 small divs). Is this possible with jquery?
Thanks
Convert the string into DOM elements:
domHere = $("<div>" + strHere + "</div>");
Then you can update this DOM with:
$(".widgetFooter", domHere).append("<div>...</div><div>...</div>");
Then do:
var content = "<li id=" + this.id + ">" + domHere.html() + "</li>";
An alternative way to #Barmar's would be:
var domHere = $('<div/>').html( strHere ).find('.widgetFooter')
.append('<div>....</div>');
Then finish with:
var content = '<li id="' + this.id + '">' + domHere.html() + '</li>';
You can manipulate the string, but in this case it's easier to create elements from it and then manipulate the elements:
var elements = $(this.htmlContent);
elements.find('.widgteFooter').append('<div>small</div><div>divs</div>');
Then put the elements in a list element instead of concatenating strings:
var item = $('<li>').attr('id', this.id).append(elements);
Now you can append the list element wherever you did previously append the string. (There is no point in turning into a string only to turn it into elements again.) Example:
$('#MyList').append(item);
If i have some basic html that is saved in a variable $html and I want to use an each (jQuery) statement on it before appending to the page and I want to look in this string for each instance of a class and ammend $html.
This is what I was thinking...
$('.flipper', $html).each(function(){
var frontContent = $(this).find('.front > .content');
var backContent = $(this).find('.back > .content');
$(this).append('<div class="background"><div class="content">' + frontContent.html() + '<div class="back">' + backContent.html() + '</div></div></div>');
console.log($html);
});
this doesnt run - i guess because i am trying to update an element on the page rather than one stored in a variable
can I still use the each ?
Cheers
Looks like $html is a string, not a dom element reference... in that case changes made to the elements in the loop will not be reflected in the original string.
Try something like
var html = '';
var $html = $(html);
$('.flipper', $html).each(function () {
var frontContent = $(this).find('.front > .content');
var backContent = $(this).find('.back > .content');
$(this).append('<div class="background"><div class="content">' + frontContent.html() + '<div class="back">' + backContent.html() + '</div></div></div>');
});
console.log($html[0].outerHTML);
Demo: Fiddle
Try this:
$($html).find('.flipper').each(....);
I'm having some problems when trying to add a class to a variable and then append this to another div. When I do this, the text appears but without the class I am trying to add to it. I am doing all of this with jQuery.
This is the code:
var names = $(this).attr('name');
var description = $(this).attr('description');
var url = $(this).attr('url');
$(names).addClass("nam");
$(div1).append( names + " " + description + " " + url);
});
I guess I am doing something wrong but can't see where.
You are creating a jQuery wrapper for name and adding a class to it but then you are appending the previous string reference instead of the jQuery wrapper to which the class was added.
Also you can't add class to a text node so try wrapping it with a span element(if name is not a html content like <span>some name</span>)
var names = $('<span />', {
text : $(this).attr('name'),
'class' : 'nam'
})
var description = $(this).attr('description');
var url = $(this).attr('url');
$(div1).append( names).append( " " + description + " " + url);
});
First off for this answer I am assuming we're using an xml string of the format you provided in your comment on op. Note - I did correct the syntax of the string to remove the extraneous semi colons.
var xmlstring = '<Blogs> <blog name="number1" description="1" url=" 1.com/"/> <blog name="number2" description="2" url="2.com/"/> <blog name="number3" description="3" url="3.com;" />" </Blogs>'
Now we can parse this string as expected into a jQuery object and use mostly as expected:
var $doc = $($.parseXML(xmlstring));
I'm assuming in your original example that this blog refers to one of these sub blogs so I'm going to say for my example:
var $this = $doc.find("blog:eq(2)");//the blog name=number3 in your example
//OR
var $this = $(this);//useful so we dont keep rewrapping
Okay so now we have our blog ($this) and we can append the contents to div1 as follows:
var names = $("<span>", {text:$this.attr('name'), 'class': 'nam'});
var description = $this.attr('description');
var url = $this.attr('url');
$(div1).append( names, description + " " + url);//as names is a span element
I tested this on an empty div and it produced the following outerhtml:
"<div><span class="nam">number3</span>3 3.com;</div>"
Hope this helped, I tried to explain steps because I'm not sure where what you're doing was deviating.
I am trying to load pictures name from a xml object and append to div. I am getting confuse with append typing layout, not able to find where im doing typing mistake.
This is working
$("#nn").append("<img id='theImg' src='/pic/jas/pic1.jpg'/>");
This not working
$("#nn").append("<img id='theImg' src='/pic/jas/'" + customer.find("pic_name") + "/>");
My jquery script part is
function OnSuccess(response) {
var xmlDoc = $.parseXML(response.d);
var xml = $(xmlDoc);
pageCount = parseInt(xml.find("PageCount").eq(0).find("PageCount").text());
var pic_infoVar = xml.find("pic_info");
pic_infoVar.each(function () {
var customer = $(this);
$("#picDiv").append("<img id='theImg' src='/pic/jas/'" + customer.find("pic_name") + "/>");
});
$("#loader").hide();
}
Html Div tag
<div id="picDiv">
LoadPic
</div>
Provded that pic_name is infact an element in an XML data structure (ex: <pic_name>pic1.jpg</pic_name>), the code that will do what you want is:
$("#nn").append("<img id='theImg' src='/pic/jas/" + customer.find("pic_name").text() + "'/>");
This is how i used to do
document.getElementById('nn').innerHTML +='<img src="'+customer.find(\"pic_name\")+'"/>';