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jQuery toggle won't work for checkbox, div remains display:block

I have an input checkbox field and when the checkbox changes (user clicks or unclicks) the div below should toggle. In my style sheet I have the div paypalInputArea as display:none and when the checkbox in clicked, it should toggle, however I can't seem to get it to work. Can anyone see what is wrong with my code?
Here is my html:
<div class="checkbox-row" id="paypalCheckbox">
<input type="checkbox" maxlength="2147483647" value="true" name="paypalPaymentCheckbox" id="paypalPaymentCheckbox" class="checkinput styled" />
<label class="paymentMethodTitle"></label>
</div>
<div class="paypalInputArea">
<isinclude template="includes/paymentmethodsinclude" />
</div>
And here is my jQuery:
$("#paypalCheckbox.checkbox-row .areaExpander").on('change', function() {
$(".paypalInputArea").toggle();
if ($('.paypalInputArea').is(':visible')) {
app.paymentAndReview.setCOContinueBtn(true);
$("#paypalPaymentCheckbox").attr('checked','true');
$('#paypalCheckbox.checkbox-row .areaExpander').addClass('open');
} else {
$("#paypalPaymentCheckbox").removeAttr('checked');
$('#paypalCheckbox.checkbox-row .areaExpander').removeClass('open');
app.paymentAndReview.setCOContinueBtn(false);
}
});
$("#paypalCheckbox.checkbox-row input").attr('checked') && app.paymentAndReview.setCOContinueBtn(true);

$("#paypalCheckbox").on('change', function() {
$(".paypalInputArea").toggle();
if ($('.paypalInputArea').is(':visible')) {
//app.paymentAndReview.setCOContinueBtn(true);
$('#paypalCheckbox.checkbox-row .areaExpander').addClass('open');
} else {
$('#paypalCheckbox.checkbox-row .areaExpander').removeClass('open');
//app.paymentAndReview.setCOContinueBtn(false);
}
});
$("#paypalCheckbox.checkbox-row input").attr('checked') && app.paymentAndReview.setCOContinueBtn(true);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="checkbox-row" id="paypalCheckbox">
<input type="checkbox" maxlength="2147483647" value="true" name="paypalPaymentCheckbox" id="paypalPaymentCheckbox" class="checkinput styled" />
<label class="paymentMethodTitle"></label>
</div>
<div class="paypalInputArea" style="display:none">
blabla
</div>
just replace the line:
$("#paypalCheckbox.checkbox-row .areaExpander").on('change', function() {
with:
$("#paypalCheckbox").on('change', function() {
As you have an ID (which has to be unique) you dont have to use other classes or else to reach it!
you can also remove those lines as the attrribute checked is set as the user clicks on the checkbox
$("#paypalPaymentCheckbox").attr('checked','true');
$("#paypalPaymentCheckbox").removeAttr('checked');
Hope this helps!

It looks like you're missing the class areaExpander from your checkbox

Add required to input of hidden div when radio is checked

What I'm trying to do is to set hidden div with inputs depended on checked radio input.
This is the logic:
If the first radio is checked the first div is shown, there I want to add hidden inputs with some values...
If the second radio is checked I want the input to be added with required..
And, it shouldn't be required if the 2nd radio isn't checked...
I've tried a few things over some time and got some effects but can't get it work as I want, Here is the code that i'm currently trying to work with, sorry but it's messed up and fails...
So Any help will be much appreciated...
/*
// this code is working but I messed the HTML while trying to get it work with the other code below...
$(document).ready(function() {
$("div.hiddendiv").hide();
check();
$("input[name$='name02']").change(check);
function check() {
var test = $("input[name$='name02']:checked").val();
$("div.hiddendiv").hide();
$("#" + test).show();
}
}
*/
// The code i'm trying to work with...
$(function() {
var radio = $("#closed");
var hidden = $("#hide");
hidden.hide();
checkbox.change(function() {
if (checkbox.is(':checked')) {
hidden.show();
//add required
$('#name02').prop('required', true);
} else {
hidden.hide();
//clear when hidden checked
$("#name02").val("");
//remove required
$('#name02').prop('required', false);
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="radio" id="closed" value="01"> Closed
<input type="radio" id="open" value="02"> Open
<div name="01" class="hiddendiv">
<input name="name01" type="hidden" value="code">
</div>
<div name="02" id="hide" class="hiddendiv">
<input name="name02" type="text" value="">
</div>
Here is the JSFiddle,

try this code
give same name of radio button so it will work as a group and
also set id of input tag as name02 so its use as a #name02 in jquery
so it will work
$(function() {
var radio = $("#closed");
var hidden = $("#hide");
hidden.hide();
$(this).click(function() {
if ($('#closed').is(':checked')) {
hidden.show();
$('#name02').prop('required', true);
} else {
hidden.hide();
//clear when hidden checked
$("#name02").val("");
//remove required
$('#name02').prop('required', false);
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="radio" name='btn' id="closed" value="01"> Closed
<input type="radio" name='btn' id="open" value="02"> Open
<div name="01" class="hiddendiv">
<input name="name01" type="hidden" value="code">
</div>
<div name="02" id="hide" class="hiddendiv">
<input name="name02" id="name02" type="text" value="">
</div>

Part of your problem is that you need to set the name attribute of your radio buttons to be the same value, otherwise the HTML won't know that they belong to the same group.
I've updated the JSfiddle here
https://jsfiddle.net/hba4d83k/2/
What i have done is add a change event handler to your the radio group and then did some conditional logic to show/hide the relevant inputs.

JQuery - show second checkbox when ticking first

This is my simple example I'm currently stuck on. I'm trying to get a 2nd checkbox to appear, if I click on the first one.
In the example below (demo: https://jsfiddle.net/d2ykzjvg/1/) you can see that both checkboxes appear when the page loads.
If I click the red one saying "1st" then nothing happens. If I remove the tick from the first checkbox, the blue "2nd" box is hidden.
If I then tick the red one again, the blue one appears, and toggles on and off when I toggle the red checkbox.
I don't know how to get the blue checkbox to be hidden when the page first loads.
HTML
<form action="#" method="post">
<div class="label label-danger">
<label for="rev"><input id="rev" type="checkbox" name="rev" id="rev" value="y"> 1st</label>
</div>
<div class="label label-primary" id="r2">
<label for="rev_inc"><input type="checkbox" name="rev_inc" id="rev_inc" value="y"> 2nd</label>
</div>
</form>
Javascript
$(function() {
$('#rev').change(function() {
if($(this).is(":checked")) {
$('#r2').show();
}
else{
$('#r2').hide();
}
});
});
JSFiddle: https://jsfiddle.net/d2ykzjvg/1/

You should use style="display:none" like this:
<label for="rev_inc"><input type="checkbox" name="rev_inc" id="rev_inc" value="y" style="display:none;"> 2nd</label>
In order to hide it on page-load

You need to hide first your 2nd checkbox
$(document).ready(function(){
$('#r2').hide();
$('#rev').change(function() {
if($(this).is(":checked")) {
$('#r2').show();
}
else {
$('#r2').hide();
}
});
});

Simple. Just add $('#r2').hide(); this on page load function.
OR add this css below:
#r2{
display:none;
}

Put an inline style in your second div like this
<div class="label label-primary" id="r2" style="display:none;">
<label for="rev_inc"><input type="checkbox" name="rev_inc" id="rev_inc" value="y"> 2nd</label>
</div>
Updated fiddle : https://jsfiddle.net/d2ykzjvg/2/

You can hide the div on "documentReady" or you can add style ( display : none )
$(function() {
$('#r2').hide();
$('#rev').change(function() {
if ($(this).is(":checked")) {
$('#r2').show();
} else {
$('#r2').hide();
}
});
});
or
<style>
#r2 { display:none; }
</style>

hide a checkbox in function another and disabled all elements to the checkbox disabled

<script type="text/javascript">
function CheckBox(checkerbox, div) {
if (checkerbox.checked) {
document.getElementById(div, Urbanoo).style.display = "block"
} else {
document.getElementById(div, Rurall).style.display = "none"
$("#Rurall").find("*").prop("disabled", true);
}
}
function CheckBox1(checkerbox1, div) {
if (checkerbox1.checked) {
document.getElementById(div, Rurall).style.display = "block"
} else {
document.getElementById(div, Urbanoo).style.display = "none"
$("#Urbanoo").find("*").prop("disabled", true);
}
}
</script>
How to hide a checkbox in function another and disabled all elements to the checkbox disabled?
<input name="Rural" type="checkbox" onclick="CheckBox1(this,'Rurall');" />
<input name="Urbano" type="checkbox" onclick="CheckBox(this,'Urbanoo');" /> Urbanoo </center>
<div id="Urbanoo" style="display:none" >
<g:render template="../DomUrbano/form"/>
</div>
The problem is that when I turn on a check box not the other box is not disabled
<div id="Rurall" style="display:none">
</br>
<g:render template="../DomRural/form"/>
</div>

I think I see what you are attempting but frankly it's less than super clear.
SO what I think you want is;
Hide other checkboxes if I check one
If I do uncheck a box, show the other one again
Show a "partner" area if I check a box
Disable other NOT partner area inputs if I check a box
I modified your markup some to make it easier and also added some additional to clearly show what is happening. I also added a data element for the partner to the input so we can make this all simpler and only have one function; now called via an event handler and NOT with inline code in markup.
Revised markup:
<span class="myinputs"><input class="mycheck" name="Rural" type="checkbox" data-partner="#Rurall" /> Rurall</span>
<span class="myinputs"><input class="mycheck" name="Urbano" type="checkbox" data-partner="#Urbanoo" /> Urbanoo</span>
<div id="Urbanoo" class="hidden others">the Urbannoo
<g:render template="../DomUrbano/form" />
<input type="textbox"/>
</div>
<div id="Rurall" class="hidden others">the Rurall
<g:render template="../DomRural/form" />
<input type="textbox"/>
</div>
Code:
$('.mycheck').on('change', function() {
var amIChecked = $(this)[0].checked;
$(this).parent().siblings('.myinputs').toggle(!amIChecked);
var pt = $(this).data('partner');// get the partner selector
$(pt).toggle(amIChecked);// show the partner in the others list
//do the enable in the partner
$('.others').filter(pt).toggle(amIChecked).find("*").prop("disabled", !amIChecked);
//do the disable in the othes list not the partner
$('.others').not(pt).find("*").prop("disabled", amIChecked);
});
Play with it all here: https://jsfiddle.net/MarkSchultheiss/cLyb103x/1/

How to hide a div on unchecking the checkbox

I have a checkbox ,when the checkbox clicks it will display a div ,if unchecked the div has to hide,I have tried this code but it is not working properly,oncheck it is showing the div but it's not hiding
Code:
<div style="clear:both;" class="tab">
<input type="checkbox" id="schedulecheck" name="schedulecheck" value="red" /> Schedule Campaign
<div id="datediv" class="red boxs" style="display: none">
<!--<label>You can schedule campaigns only after 3 hours from now.</label></br>-->
<label>Select date & time to schedule</label></br>
<input type="text" id="scheduledatetime" name="scheduledatetime"/><label id="schedule_error" class="error"> </label>
<!--<input type="text" id="datepickerad"/>-->
</div>
</div>
And the JS code:
$('#schedulecheck').on('ifChecked', function(event){
// alert();
if($(this).attr("value")=="red"){
$(".red").show();
}
});
$('#schedulecheck').on('unChecked', function(event){
if($(this).attr("value")=="red"){
$(".red").hide();
}
});

$('#schedulecheck').click(function () {
$(".red").toggle(this.checked);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div style="clear:both;" class="tab">
<input type="checkbox" id="schedulecheck" name="schedulecheck" value="red" />Schedule Campaign
<div id="datediv" class="red boxs" style="display:none" >
<!--<label>You can schedule campaigns only after 3 hours from now.</label></br>-->
<label>Select date & time to schedule</label>
</br>
<input type="text" id="scheduledatetime" name="scheduledatetime" />
<label id="schedule_error" class="error"></label>
<!--<input type="text" id="datepickerad"/>-->
</div>

You can rather use .change() function for listening change event. and use .toggle(flag) with flag being true/false based on checked value for making show/hide decision:
$('#schedulecheck').change(function(){
$(".red").toggle(this.checked);
});
Working Demo

Ty this code
$('#schedulecheck').on('click',function () {
if($(this).is(':checked'))
$(".red").show();
else
$(".red").hide();
});

Use this:
$("#schedulecheck").on("click", function () {
$(".red").toggle($(this).is(":checked"));
});
This is "the cross-browser-compatible way to determine if a checkbox is checked" as jQuery recomands it (see http://api.jquery.com/prop/#prop1 for more details).