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Skip to a Page on Google Forms

I'm programatically creating a Google Form using Google App Scripts right now, and my script automatically generates a page for each of the respondants that the form will be emailed out to.
Currently, the form has a dropdown at the beginning that the person uses to select their page, and then it forwards them to it, however, I'd prefer it if the email already sent out a pre-responded form that already started them on their page.
The reason I'm throwing them all into a single form is because I'm using Triggers to detect the form's submission, and since I have more than 20 people that require a form, that would break the trigger limit.
EDIT:
Example code:
the Form.getPublishedUrl() function returns the URL to respond the form, starting on the first page, however, I would like a URL to respond to the form starting on the 3rd or 4th page.
While the FormResponse.toPrefilledUrl() will allow me to autofill the correct response on the first page, it will not allow me to start the responder on the page that he would be forwarded to based on his pre-filled response on the first page.
tldr; :
How do I get a link to a specific page on a Google Form using Google App Scripts?

This should be a comment but don't have 50 rep yet...
Why do you need various HTML pages?
I think you should refactor your code so every form is on the same HTML and everything shows and hides with Jquery or Javascript. You can send the same URL but with differente URL parameters.
If this isn't your case, you should post some code of yours and detail a little bit more your question. Also, wich limit does it triggers?

Redirect using post and get the succes of the redirect

Say, I have a simple form on my website having three fields : name, password and email.
I have to get these information from the users, and keep in my database.
Then redirect to another website and send all these information using post.
I also have to know whether the user was successfully redirected to that site(HTTP STATUS 200).
Here's how I'm doing it:
For Point 1, I'm simply submitting the form.
After the data has been successfully saved in my database, I'm rendering the following form with hidden fields. This gets submitted and user gets redirected to anotherwebsite.com
<form id="form_id" action="https://www.anotherwebsite.com/form" method="POST">
<input type ="hidden" name ="name" value ="$name">
<input type ="hidden" name ="password" value ="$password">
<input type ="hidden" name ="email" value ="$email">
</form>
<script> document.getElementById('form_id').submit(); </script>
Problems:
I don't think my strategy to achieve point 1 and 2 is correct. I need a better solution. Submitting the form, then rendering a page with hidden fields and submitting it again to redirect to another site just doesn't feel right.
I have no clue to achieve the 3rd point.

Based on your question you might try this approach:
create a form with name, password, email fields in a file ( HTML ).
Submit the form to server.
On the server side get the data (including the form attribute in a variable) and save it to database.
then redirect to the given website ( using the variable you've stored in step 3 ).
You can easily know the status ( 202 or any error) using any of server side scripting language.

If you are sending the user to another website, the only way to know that the user was successfully redirected is for that website to notify you in some manner. Once the user leaves your page (and that's what a redirect is - it tells the browser "leave this URI and go to this URI instead"), the scripts on that page stop running, so they can't collect any further information.
If you just need to know that the information was submitted successfully, your script could POST the data in the background, wait for a 200 response, then redirect after the information has been submitted. But that may not meet your requirements, since you still won't know if the redirect succeeded.
Another possibility which does allow you to know whether the page on the other site loaded correctly would be to open it in a new browser window/tab instead of redirecting. This is the only way to keep your page active (and, thus, your scripts able to run) while loading another page. However, it introduces other issues, like what to do with the original page. (Leave it open in the background (likely to confuse the user) or close itself after seeing that the new URI has loaded (could cause undesirable visual artifacts as one window/tab opens and then the original one closes; destroys browser history)?)
If at all possible, having the final destination site notify you when the transaction completes is almost certainly the best way to go.

To achieve point 3 you need to use cookies if you are actually trying to implement a login-cum-membersarea system. Othewise, you simple need a redirect inside a condition statement.
my $cgi = CGI->new;
if (condition) { print $cgi->redirect('https://www.examplesite.com/file.html') }
for a general way of doing point 1-2, you can look at the tutorial here:
http://practicalperl5.blogspot.com/

Ajax Messaging system Questions

I'm working on a messaging system like Facebook. I do have on left a list of conversation, and on right a box where i load the messages, just like facebook does.
The basic system is complete (PHP/MySQL), and here some information on how it is structured:
messages.php - Main page, based on url parameters. Rewrited with.htaccess:
Examples:
URL = http://www.domain.com/messages/ - Right Box: Display form to send new message.
URL = http://www.domain.com/messages/Username - Ajax call to getUserMessages.php to load Messages between Logged in user and
Username and show them on the Right Box.
getUserMessages.php - Get from database messages between Logged in user and user selected. It does Output HTML ready to be displayed.
Now the system is partially Ajaxified, and i want it to be, just like Facebook does.
At the moment the Ajaxified part is:
When a user is vieweing a conversation, it display automatically new messages, and also update the conversation list with the last message.
If the user is not viewing a conversation, it does get new messages received and update the conversation list.
This is done with a PUSH service, to give Real Time experience to users.
I want to improve this, and make it to act like that:
The user click on the Conversation List, and it load the messages on the right Box, and also change the URL on the Address Bar, withut reload the entire page.
I can easily do the part to load messages when user click a conversation, but before i start i have two question:
1. How i do change the Address URL while displaying a User Conversation WITHOUT reload the page?
I found the answer.
2. How i do cache the conversations ? So if a user switch between two conversation, it does not call again the php file and query the database for all the messages, but appending only new messages (Maybe via another php File to fetch only Unread Messages)
EDIT
I comed up with a solution:
When a user open a conversation, i cache the entire Ajax response (that is HTML) in a variable, like messages-n, Where n is the user_id of the conversation selected, then if the user click again on that conversation, i check if messages-n is set, if it is, i print it and run an ajax request to get only unread message and append them.
That's only in my mind i didn't made it to actual code.
Could work well?

Solved 1/2 :
1. To change Address URL i'm using the HTML5 .pushState() event.
Since HTML5 Browsers implement the pushState method in different way, to have a Cross-Browser solution, and have support for HTML4 browsers with hash Fallback, i used Hystory.js.
2. To cache messages, i haven't found a solution yet, nor i tried to do it for now.
But as #Christopher suggested, i changed the Ajax response from HTML to Json.
If i find it i will update my answer.

Getting an answer from a page postback with HTML\JS

I have an HTML "Contact us" form which I plant on my client's HTML page,this form has an 'action' property with value that leads to my production system.
When my production system gets the form , it runs a vital code that arranges the type of request by type of request and perform some other QA at the code behind..
In case that the page has an error within our production system, we would like to notify the user that completed the form at our clients side that there was an error.
The problem is that when the form was sent we have no way to get back to the first form as a post was fired.
My question is , if there is any way to come back to the same page where the post was sent to the original page so we can notify the error AFTER the page was sent?
In other words, I need the form to be sent to the a address at the action property , and still make the browser stay at the same page.
Thanks.

You could embed a ReturnURL as part of the post data, that would identify where the post came from. Or perhaps embedding a customer code would be a better idea, that way you are not blindly redirecting to a URL (which could be hacked).

Webpage source code incomplete: hidden code?

I'm trying to understand how this login page works by looking at the source from my browser (Chrome).
The source links to some CSS, pictures, and generic JavaScript libraries. Apart from a little jQuery at the very start (for changing the language), I don't see why the page isn't more than just dead HTML elements.
For example, if I click "LOGIN" with an empty username and password, the message "The username or password you entered is incorrect." appears. But I can't see anywhere in source where such behaviour is defined.
What am I missing?

The activity you are observing is one of the core functions of <form> elements. When a form is submitted, the user's browser is directed to the page defined by the action attribute in the form. In addition to directing the user to this page, all of the inputs included in the form are passed to the web server as variables.
One way of submitting a form is by including an input element of type submit within the form, which is what the web designer has done here. When that submit element is invoked (via a click, for example), the form is submitted.

The message you see is not shown by jQuery / Javascript.
Notice that when you click the "LOGIN" button, the page submits your request.
That means it Server Side code starts to run, code that you cant see.
This Server Side code handles your input and generates the Error Message that you see.

When you click the LOGIN button, the form is submitted to the server,which returns a new HTML containing the message. The logic for that is defined in server-side code, which you can't see from outside. 'View source' will only display what the server outputs.

I think the page is simply refreshing.
You can confirm this by opening the network tab in chrome console and watching it as you submit the empty form.
Thanks to http asset caching, this seems as if the page did not refresh - but chrome's network tab confirms it does.