This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, visit the help center.
Closed 10 years ago.
jQuery AJAX seems to be sending two requests. As I'm using a two-factor authentication method, based on time, the second request is failing hence the original request is "failing".
The first is a post request, that's fine, but then there's a GET request, which isn't fine.
Here's the javascript I'm using to generate the query.
$('#form').live('submit', function(event) {
var target = $('#ajax');
var url = '/ajax/user/authenticateLevel3';
$.ajax({
type: "POST",
url: url,
data: $('#form').serialize(),
dataType: 'json',
success: function(data, status) {
$.getJSON(url, function(data) {
if (!data.resultCode) {
$('#ajax').html($.base64.decode(data.html));
$('#ajax').modal();
} else {
location.reload();
}
});
}
});
event.preventDefault();
});
Any ideas how I can work around this?
That is because you are doing 2 ajax calls (.ajax and .getJSON)
Try doing this instead (using document event delegation instead of .live):
$(document).on('submit', '#form', function(event) {
var target = $('#ajax');
var url = '/ajax/user/authenticateLevel3';
$.ajax({
type: "POST",
url: url,
data: $('#form').serialize(),
dataType: 'json',
success: function(data, status) {
if (!data.resultCode) {
$('#ajax').html($.base64.decode(data.html));
$('#ajax').modal();
} else {
location.reload();
}
}
});
event.preventDefault();
});
You are sending 2 requests. One with .ajax and another with .getJson.
Remove the .getJson request. With no dataType property passed to .ajax, jquery will attempt to guess the response type. You may also specify the dataType as json to force the conversion. The 'data' parameter of the success callback should be converted to a javascript object for both of these options.
getJSON is an AJAX method for retrieving JSON from a server, not for processing the data returned by another ajax method. Just remove it.
$('#form').live('submit', function(event) {
var target = $('#ajax');
var url = '/ajax/user/authenticateLevel3';
$.ajax({
type: "POST",
url: url,
data: $('#form').serialize(),
dataType: 'json',
success: function(data, status) {
if (!data.resultCode) {
$('#ajax').html($.base64.decode(data.html));
$('#ajax').modal();
} else {
location.reload();
}
}
});
event.preventDefault();
});
Since you mentioned you are switching over to .on, the syntax will be like this:
$(parent).on('submit', '#form', function(event) {
/*
* ...
*/
});
where parent is the nearest static parent element of #form.
Related
is it possible to call a page of another website from an ajax call ?
my guess is that is possible since connection is not denied , but i can't figure out how to make my ajax call works , I am calling a list of TV Channels of a website , but I am getting no results , would you please see if my script contains any errors
function showValues(){
var myUrl="http://www.nilesat.com.eg/en/Home/ChannelList";
var all = 1;
$.ajax({
url: myUrl+"&callback=?",
data: "channelType="+all,
type: 'POST',
success: function(data) {
$('#showdata').html(data);
},
error: function(e) {
alert('Error: '+data);
}
});
}
showValues();
html div for results
<div id="showdata" name ="showdata">
</div>
Ajax calls are not valid across different domains.you can use JSONP. JQuery-ajax-cross-domain is a similar question that may give you some insight. Also, you need to ensure thatJSONP has to also be implemented in the domain that you are getting the data from.
Here is an example for jquery ajax(), but you may want to look into $.getJSON():
$.ajax({
url: 'http://yourUrl?callback=?',
dataType: 'jsonp',
success: processJSON
});
Another option is CORS (Cross Origin Resource Sharing), however, this requires that the other server to enable CORS which most likely will not happen in this case.
You can try this :
function showValues(){
var myUrl="http://www.nilesat.com.eg/en/Home/ChannelList";
var all = 1;
$.ajax({
url: myUrl,
data: channelType="+all,
type: 'POST',
success: function (data) {
//do something
},
error: function(e) {
alert('Error: '+e);
}
});
}
This question already has answers here:
Abort Ajax requests using jQuery
(18 answers)
How to cancel/abort jQuery AJAX request?
(8 answers)
Closed 8 years ago.
In phonegap how to cancel an ajax request in program, I would like to set cancel button for control the request when it's too slow
$.ajax({
type: "GET",
url: url,
success: function(m) {
alert( "success");
}
});
hi it's similar as Abort Ajax requests using jQuery,anyway This can help you
var ab = $.ajax({ type: "GET", url: url, success: function(m) { alert( "success"); } });
//kill the request
ab.abort()
Store the promise interface returned from ajax request in a global variable and abort it on cancel click
var result = $.ajax({ type: "GET", url: url, success: function(m) { alert( "success"); } });
$('#cancel').click(function() {
result.abort();
});
var request= $.ajax({ type: "GET", url: url, success: function(m) { alert( "success"); } });
$('#cancel').click(function() {
request.abort();
});
this will abort the request from the client(browser) side but note : if the server has already received the request, it may continue processing the request (depending on the platform of the server) even though the browser is no longer listening for a response. There is no reliable way to make the web server stop processing a request that is in progress.
I am building a chatroom-type app using the Parse Javascript API. The task is to get some data from Parse, display it, add user input to the messages, and send it right back to parse.
The problem is I am not being able to see the data from parse, and receive a 502 error. I am a bit newer to javascript, so any advice on how to accomplish this, or any mistakes you may see in my code, would be fantastic. I also commented out my code the best I could. Thanks for the help.
Here is my code;
$(document).ready(function(){
delete Chat.display;
delete Chat.send;
delete Chat.fetch;
var my_messages = $('ul.messages')
//fetches data from parse
var myChat = function() {
$.ajax({
url: "https://api.parse.com/1/classes/chats",
dataType: "json",
success: console.log("Success"),
function message(a) {
my_messages.append('<ul>' + a +'</ul>'); //adds ul 'text' to messages
};
});
};
myChat(); // call mychat
$('button.send').on('click', function() { // when user clicks send
// send post to
$.ajax({
type: "POST",
url: "https://api.parse.com/1/classes/chats",
data: JSON.stringify({text: $('input.draft').val()}), // stringify the text on value input.draft
function(message){
window.location.reload(1) //refresh every 3 seconds
});
});
});
</script>
you have syntax error in both of your success functions of $.ajax calls. In the first ajax call you have places console.log, which should be inside the success callback. In the second one u haven't even added success: callback.
Try below updated code
$(document).ready(function(){
delete Chat.display;
delete Chat.send;
delete Chat.fetch;
var my_messages = $('ul.messages');
var myChat = function() {
$.ajax({
url: "https://api.parse.com/1/classes/chats",
dataType: "json",
success:function message(a) {
console.log("Success")
$.each(a,function(i,item){
my_messages.append('<ul>' + item.username +'</ul>'); //adds ul 'text' to messages
});
}
});
};
myChat(); // call mychat
$('button.send').on('click', function() { // when user clicks send
// send post to
$.ajax({
type: "POST",
url: "https://api.parse.com/1/classes/chats",
data: JSON.stringify({text: $('input.draft').val()}), // stringify the text on value input.draft
success:function(message){
window.location.reload(1) //refresh every 3 seconds
}
});
});
});
My Script to call ajax
<script language="javascript">
function search_func(value)
{
$.ajax({
type: "GET",
url: "sample.php",
data: {'search_keyword' : value},
dataType: "text",
success: function(msg){
//Receiving the result of search here
}
});
}
</script>
HTML
<input type="text" name="sample_search" id="sample_search" onkeyup="search_func(this.value);">
Question: while onkeyup I am using ajax to fetch the result. Once ajax result delay increases problem occurs for me.
For Example
While typing t keyword I receive ajax result and while typing te I receive ajax result
when ajax time delay between two keyup sometime makes a serious issue.
When I type te fastly. ajax search for t keyword come late, when compare to te. I don't know how to handle this type of cases.
Result
While typing te keyword fastly due to ajax delays. result for t keyword comes.
I believe I had explained up to reader knowledge.
You should check if the value has changed over time:
var searchRequest = null;
$(function () {
var minlength = 3;
$("#sample_search").keyup(function () {
var that = this,
value = $(this).val();
if (value.length >= minlength ) {
if (searchRequest != null)
searchRequest.abort();
searchRequest = $.ajax({
type: "GET",
url: "sample.php",
data: {
'search_keyword' : value
},
dataType: "text",
success: function(msg){
//we need to check if the value is the same
if (value==$(that).val()) {
//Receiving the result of search here
}
}
});
}
});
});
EDIT:
The searchRequest variable was added to prevent multiple unnecessary requests to the server.
Keep hold of the XMLHttpRequest object that $.ajax() returns and then on the next keyup, call .abort(). That should kill the previous ajax request and let you do the new one.
var req = null;
function search_func(value)
{
if (req != null) req.abort();
req = $.ajax({
type: "GET",
url: "sample.php",
data: {'search_keyword' : value},
dataType: "text",
success: function(msg){
//Receiving the result of search here
}
});
}
Try using the jQuery UI autocomplete. Saves you from many low-level coding.
First i will suggest that making a ajax call on every keyup is not good (and this why u run in this problem) .
Second if you want to use keyup then show a loading image after input box to show user its still loading (use loading image like you get on adding comment)
Couple of pointers. Firstly, language is a deprecated attribute of javascript. In HTML(5) you can leave the attribute off, or use type="text/javascript". Secondly, you are using jQuery so why do you have an inline function call when you can do that with jQuery too?
$(function(){
// Document is ready
$("#sample_search").keyup(function()
{
$.ajax({
type: "GET",
url: "sample.php",
data: {'search_keyword' : value},
dataType: "text",
success: function(msg)
{
//Receiving the result of search here
}
});
});
});
I would suggest leaving a little delay between the keyup event and calling an ajax function. What you could do is use setTimeout to check that the user has finished typing before then calling your ajax function.
Hi Am new to Jquery/ajax and need help with the final (I think) piece of code.
I have a draggable item (JQuery ui.draggable) that when placed in a drop zone updates a mysql table - that works, with this:
function addlist(param)
{
$.ajax({
type: "POST",
url: "ajax/addtocart.php",
data: 'img='+encodeURIComponent(param),
dataType: 'json',
beforeSend: function(x){$('#ajax-loader').css('visibility','visible');}
});
}
but what I cannot get it to do is "reload" another page/same page to display the updated results.
In simple terms I want to
Drag & drop
Update the database
Show loading gif
Display list from DB table with the updated post (i.e. from the drag & drop)
The are many ways of doing it. What I would probably do is have the PHP script output the content that needs to be displayed. This could be done either through JSON (which is basically data encoded in JavaScript syntax) or through raw HTML.
If you were to use raw HTML:
function addlist(param)
{
$.ajax(
{
type: 'POST',
url: 'ajax/addtocart.php',
data: 'img=' + encodeURIComponent(param),
dataType: 'html',
beforeSend: function()
{
$('#ajax-loader').css('visibility','visible');
},
success: function(data, status)
{
// Process the returned HTML and append it to some part of the page.
var elements = $(data);
$('#some-element').append(elements);
},
error: function()
{
// Handle errors here.
},
complete: function()
{
// Hide the loading GIF.
}
});
}
If using JSON, the process would essentially be the same, except you'd have to construct the new HTML elements yourself in the JavaScript (and the output from the PHP script would have to be encoded using json_encode, obviously). Your success callback might then look like this:
function(data, status)
{
// Get some properties from the JSON structure and build a list item.
var item = $('<li />');
$('<div id="div-1" />').text(data.foo).appendTo(item);
$('<div id="div-2" />').text(data.bar).appendTo(item);
// Append the item to some other element that already exists.
$('#some-element').append(item);
}
I don't know PHP but what you want is addtocart.php to give back some kind of response (echo?)
that you will take care of.
$.ajax({
type: "POST",
url: "ajax/addtocart.php",
data: 'img='+encodeURIComponent(param),
dataType: 'json',
beforeSend: function(x){$('#ajax-loader').css('visibility','visible');
success: function(response){ /* use the response to update your html*/} });