I am trying to send a div to some mouse coords I get when the mouse is clicked. The first part, where I get the mouse coords works fine - I am just having difficulty creating the animate part.
$("#container").click(function(e){
var parentOffset = $(this).parent().offset();
var relX = e.pageX - parentOffset.left;
var relY = e.pageY - parentOffset.top;
console.log (relX);
console.log (relY);
$("#move").animate({left: 'relX', top: 'relY'});
});
CSS:
#container {
width: 500px;
height 500px;
}
#move {
width: 20px;
height: 20px;
background-color: #000;
position : absolute;
}
If anyone could point me in the right direction that would be awesome! Thanks
change
$("#move").animate({left: 'relX', top: 'relY'});
to
$("#move").animate({left: relX, top: relY});
Like guys mentioned, I add example on jsFiddle:
http://jsfiddle.net/E64TK/
also in css you forgot ":"
#container {
width: 500px;
height{here} 500px;
}
Related
I am trying to to get a mousemove function to display a custom cursor element i created when the mouse is moved inside the specific div. The custom cursor is an absolute positioned div within the div i want it to appear in. The wierd thing i am seeing is i can see from the developer tools that it is infact working but the custom cursor doesnt actually show. If i however move the custom cursor div outside of the div i want it in and into the main body it displays fine.
I know this must be a simple error on my part but i cant see it! Appreciate any advice.
let customCursor = document.querySelector('.custom-cursor');
const section2 = document.querySelector('.section2');
section2.addEventListener('mousemove', function(e) {
customCursor.classList.add('active');
customCursor.setAttribute("style", "top:" + (e.pageY) + "px; left: " + e.pageX + "px;");
});
section2.addEventListener('mouseleave', function() {
customCursor.classList.remove('active');
});
.section {
position: relative;
}
.section1 {
height: 500px;
}
.section2 {
height: 500px;
}
.custom-cursor {
width: 50px;
height: 50px;
background: black;
border-radius: 50%;
display: none;
position: absolute;
}
.custom-cursor.active {
display: block;
}
<body>
<section class="section1 section">Section 1</section>
<section class="section2 section">Section 2
<div class="custom-cursor"></div>
</section>
</body>
Like #Titus comment, you can use CSS with cursor.
But if you implemeting it with JS that need to track position of your mouse relative to section2, you will need to subtract the section2 element offset left and top, then subtract half of the cursor width and height to center the cursor:
let customCursor = document.querySelector('.custom-cursor');
const section2 = document.querySelector('.section2');
section2.addEventListener('mousemove', function(e) {
customCursor.classList.add('active');
customCursor.setAttribute("style", "top:" + (e.pageY - section2.offsetTop - (customCursor.offsetWidth/2) ) + "px; left: " + (e.pageX - section2.offsetLeft - (customCursor.offsetHeight/2)) + "px;");
});
section2.addEventListener('mouseleave', function() {
customCursor.classList.remove('active');
});
.section {
position: relative;
}
.section1 {
height: 500px;
}
.section2 {
height: 500px;
}
.custom-cursor {
width: 50px;
height: 50px;
background: black;
border-radius: 50%;
display: none;
position: absolute;
}
.custom-cursor.active {
display: block;
}
<body>
<section class="section1 section">Section 1</section>
<section class="section2 section">Section 2
<div class="custom-cursor"></div>
</section>
</body>
position: absolute
is relative to the parent if the parent has
position:relative
so in order to have the correct position within your section2, you need to use e.layerY and e.layerX instead of e.pageY and e.pageX since those are based on the top left corner of your screen. e.layerY and e.layerX is relative to the container that the mouseevent is attached to.
Try this: https://jsfiddle.net/42kq1w8m/9/
Is there any way to get the current position of an element relative to the window,
not document
offset get the current position of an element relative to the document
To calculate where the element is positioned relative to the top edge of the viewport, you can use a combination of:
getClientBoundingRect() (to determine the position of the element within the document); and
window.scrollY (to determine the vertical scroll position of the window).
Then, simply subtract the second value from the first:
var button = document.getElementsByTagName('button')[0];
var div = document.getElementsByTagName('div')[0];
var divRect = div.getBoundingClientRect();
function alertCurrentPosition() {
var windowVerticalScroll = window.scrollY;
window.alert('The top of the red square is ' + (divRect.top - windowVerticalScroll) + ' pixels below the top of the viewport');
}
button.addEventListener('click', alertCurrentPosition, false);
body {
height: 1200px;
}
button {
position: fixed;
top: 6px;
left: 6px;
}
div {
position: absolute;
top: 300px;
left: 50%;
width: 100px;
height: 100px;
background-color: rgb(255,0,0);
}
<button>Scroll the Viewport and Click Me</button>
<div></div>
See this fiddle.
I think you'll get the answer.
Here is the
[1]: http://jsfiddle.net/mk4q332q/
This code worked with me well
var offset = $("selector").offset();
var posY = offset.top - $(window).scrollTop();
var posX = offset.left - $(window).scrollLeft();
I got the answer from here stackoverflow.com/a/13930064/5695475
I'm trying to solve how to get the correct coordinates and movement of the element but find that the CSS Transformation doesn't align with the elements DOM coordinates.
I've tried to also change the properties of the element's CSS Transformation via the JS code itself.
The problem you can see in the demo is that the element doesn't reach all four corners of the #wrap div.
Is it also better to incorporate a skew or perspective property rather than rotations? I've just read Top & Left position with Transform Rotate (posted as a duplicated question), but this doesn't explain how to rotation of this example's prespective would work?
HTML
<div id="wrap">
<div id="thing"></div>
</div>
JS
$(function() {
$("#wrap").click(function(e) {
var offset = $(this).offset();
var relativeX = (e.pageX - offset.left);
var relativeY = (e.pageY - offset.top);
document.getElementById("thing").style.left = relativeX + "px";
document.getElementById("thing").style.top = relativeY + "px";
document.getElementById("thing").innerHTML = relativeX + "<br />" + relativeY;
});
});
CSS
#wrap {
height: 300px;
width: 500px;
background: green;
position: relative;
overflow: hidden;
transform: rotateX(60deg) rotateZ(-30deg);
}
#thing {
background: blue;
width: 50px;
height: 50px;
position: absolute;
transition: 1s;
left: 0;
top: 0;
}
Live: https://jsfiddle.net/h9ad4k63/
In my project, I need to show a small image in center of the visible part of the container, with respect to the window i.e .loader. Even when the user scrolls the page, the image should be visible in center of .loader.
I successfully implemented this but now I am facing a edgecase which is when user scrolls the page "up to the header" or "down to the footer", the small image is hiding. demo.
This is actually normal behaviour but in these edgecases, I want the image to stick to top/bottom end of the .loader container.
What I want:
Keep the small image always at center of .loader container. (I already implemented this)
when scrolled to any end of .loader container, the image should stick to that end instead of hiding behind the container.
Fiddle
A solution using just css is preferred. I am looking for browser support in IE9+, chrome and firefox.
.header {
height: 600px;
width: 650px;
background-color: grey;
}
.left-side {
height: 300px;
width: 150px;
float: left;
background-color: red;
}
.loader {
background-image: url('http://i.imgur.com/U2njI.jpg');
margin-left: 150px;
height: 1500px;
width: 500px;
background-position: 345px center;
background-repeat: no-repeat;
background-attachment: fixed;
background-color: cornflowerblue;
}
.footer {
height: 600px;
width: 650px;
background-color: silver;
}
<div class="header"></div>
<div class="left-side"></div>
<div class="loader"></div>
<div class="footer"></div>
Here is a working solution with javascript, I hope its behaviour is how you expect it to be. I'm unfortunately not able to test it on IE9 right now but it should work (DEMO):
document.addEventListener('DOMContentLoaded',function() {
var loader = document.querySelector('.loader'),
loaderRect = loader.getBoundingClientRect(),
loaderTop = loaderRect.top + document.body.scrollTop,
loaderBottom = loaderTop + loader.offsetHeight,
initialBgPos = loader.style.backgroundPosition,
imageHeight = 141;
function onScroll() {
var scrollTop = document.documentElement.scrollTop || document.body.scrollTop;
if(loaderTop >= (scrollTop + (window.innerHeight - imageHeight)/2)) {
loader.style.backgroundPosition='345px ' + (loaderTop - scrollTop) + 'px';
} else if(loaderBottom <= (scrollTop + (window.innerHeight + imageHeight)/2)) {
loader.style.backgroundPosition='345px ' + (loaderBottom - scrollTop - imageHeight) + 'px';
} else {
loader.style.backgroundPosition = initialBgPos;
}
}
window.addEventListener('scroll', onScroll);
onScroll();
});
To achieve what I think you want. We have to set the position of the .loader div to fixed, then it'll always stay where it's placed, regardless of whether the user scrolls the page, the div will scroll too. In here's how to set the position of loader to fixed in CSS (you may also have to get the position of your fixed div):
.loader{
position: fixed;
left: 100px;
top: 300px;
}
Here's your upadted JSFiddle: http://jsfiddle.net/Ezhb4/4/
I have divs with class="myDiv". I need to do this logic: on mouse over, I want to show a popup in the middle of the div.
For that I have the following:
$(".myDiv").mouseover(function () {
positionDiv($(this).position().left + $(this).width() / 2, $(this).position().top + $(this).height() / 2);
});
function positionDiv(xPosition ,yPosition ) {
$("#popupWindow").css("left", xPosition + "px");
$("#popupWindow").css("top", yPosition + "px");
$("#popupWindow").show();
}
The CSS:
.popupWindow{
position:absolute;
width:313px;
height:383px;
display:none;
}
This will position the popup window in the middle of the div on mouse over. Everything works great at this point.
However, if the website is zoomed in (using the browser zoom functionality), tHe position will get messed up. The popup window no longer appears in the middle of myDiv.
Any idea what might be the problem?
Edit:
For more info, if it is created and I zoom it, it is fine. But when I move my mouse to another myDiv and the new popup appears in a weird position. The left and top attribute of the Div are messing up.
You don't need JS for this:
http://jsfiddle.net/coma/6VUpS/1/
The key is to play with CSS and avoid JS calculations. The container div (myDiv) should be position: relative, the popup must be inside and position: absolute, top and left to 50% and using negative margins to center it (http://www.css-101.org/negative-margin/06.php).
Try avoiding JS for visual fanciness, only CSS ensures the correct position even on zoom since it's rendered by the browser.
HTML
<div class="myDiv">
Hi!
<div class="popupWindow">you are welcome!</div>
</div>
CSS
div.myDiv {
padding: 10px;
background-color: #eee;
margin: 50px 0;
position: relative;
}
div.popupWindow {
position: absolute;
top: 50%;
left: 50%;
margin: -50px 0 0 -100px;
width: 200px;
line-height: 100px;
background-color: #111;
color: #fff;
text-align: center;
display: none;
pointer-events: none;
}
div.myDiv:hover > div.popupWindow {
display: block;
}
Bonus track using a checkbox to click/tap/toggle popup and some fade in:
http://jsfiddle.net/coma/6VUpS/3/
More hacky:
http://jsfiddle.net/coma/6VUpS/
More complex example:
http://jsfiddle.net/coma/dHTHG/
I understand your problem and my solution is to put every object containing a pop up in pos relative and then set your pop up with those CSS :
.myPopUp{
position:absolute;
display : none;
width:400px;
height : 100px;
margin-top : -50px;
margin-left:-200px;
background-color: red;
top : 50%;
left: 50%;
}
It will alway be centered.
Now i understand you have only 1 pop up for all your hoverable div. My trick is to save the pop up in a var and remove it from its parent container to append it in the hovered div like this :
var popUp = $('.myPopUp');
$('.myDiv').mouseover(appendPopUp);
$('.myDiv').mouseout(function(){popUp.css('display', 'none')});
function appendPopUp(){
console.log(popUp.parent(), $(this))
if(popUp.parent()[0] != $(this)[0]){
popUp.remove();
$(this).append(popUp);
}
popUp.css('display', 'block')
}
That should work, here's my fiddle : http://jsfiddle.net/7EEZT/
$(window).on('resize', function(){
var $md = $('.myDiv');
positionDiv($md.position().left + $md.width() / 2, $md.position().top + $(this).height() / 2);
});
I have a simple css solution if you have a div with known height and width you can do same task with help of css only
.popupWindow {
position:absolute;
width:313px;
height:383px;
left:50%;
top:50%;
margin-left:-156px;/*half of width*/
margin-top:-191px;/*half of height*/
display:none;
}
Go with position:relative and try this. It will solved your problem relate to position.
$(".myDiv").mouseover(function () {
positionDiv( $(this).width() / 2, $(this).height() / 2);
});
function positionDiv(xPosition ,yPosition ) {
$("#popupWindow").css("left","-" + xPosition + "px");
$("#popupWindow").css("top", "-" + yPosition + "px");
$("#popupWindow").show();
}
The CSS:
.popupWindow{
position:relative;
width:313px;
height:383px;
display:none;
}
http://jsfiddle.net/kishan6446/PdNkg/13/