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Javascript - one button call ajax and one button submit form using html5 form validation

I have a form that I want to use the required attribute, which I believe is from html5 to make sure the user puts in a name before running the ajax to send and email and stays on this page (index.php). The form below works. My problem is that I can't figure out how to a a button called pay that submits the form to pay.php like a regular form submit so the user ends up on pay.php when they click "pay" and I want the form validation to still occur when they click pay and on pay.php I can grab the contactName from the post.
<form id="contactForm" method="post" class="tm-contact-form">
Name: <input type="text" id="contactName" name="contactName" class="form-control" placeholder="Name" required/>
<button type="submit" id="inquire-button" class="btn btn-primary">Inquire</button>
<div id="mail-status"> </div>
</form>
<script type="text/javascript">
$("inquire-button").on('click',function(e){
e.preventDefault();
});
$("#contactForm").on('submit',function(e){
sendContact();
e.preventDefault();
});
function sendContact() {
jQuery.ajax({
url: "mailer.php",
data:'contactName='+$("#contactName").val(),
type: "POST",
success:function(data){
$("#mail-status").html(data);
},
error:function (){}
});
}
</script>

EITHER don't use the click, but only the submit event
$("#contactForm").on('submit', function(e) {
const $btn = $(document.activeElement);
if ($btn.is("#inquire")) {
console.log("Inquire clicked")
e.preventDefault();
jQuery.ajax({
url: "mailer.php",
data: 'contactName=' + $("#contactName").val(),
type: "POST",
success: function(data) {
$("#mail-status").html(data);
},
error: function() {}
});
}
else console.log("Pay clicked")
})
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<form id="contactForm" method="post" class="tm-contact-form">
Name: <input type="text" id="contactName" name="contactName" class="form-control" placeholder="Name" required/>
<button type="submit" id="inquire-button" class="btn btn-primary">Inquire</button>
<button type="submit" id="pay" class="btn btn-primary">Pay</button>
<div id="mail-status"> </div>
</form>
OR use a button
$("#contactForm").on('submit', function(e) {
console.log("Submitted (pay)")
})
$("#inquire-button").on("click", function() {
if (!this.form.checkValidity()) {
this.form.reportValidity()
return
}
console.log("Inquire clicked")
jQuery.ajax({
url: "mailer.php",
data: 'contactName=' + $("#contactName").val(),
type: "POST",
success: function(data) {
$("#mail-status").html(data);
},
error: function() {}
});
})
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<form id="contactForm" method="post" class="tm-contact-form">
Name: <input type="text" id="contactName" name="contactName" class="form-control" placeholder="Name" required/>
<button type="button" id="inquire-button" class="btn btn-primary">Inquire</button>
<button type="submit" id="pay" class="btn btn-primary">Pay</button>
<div id="mail-status"> </div>
</form>

Submit HTML forms that contain dynamic IDs

I have 2 HTML forms that contain dynamic ID attributes. What I want is to store data with AJAX call from each HTML form separately. Currently AJAX call works only for one HTML form when I use static ID name "surveyImage".
I don't know how I can with jQuery to call method submit() individually for each form. Is there any way to resolve this issue?
Form with id="surveyImage13"
<form method="POST" action="http://localhost/1/467/survey" accept-charset="UTF-8" id="surveyImage13" role="form" class="form-material m-t-40" novalidate="novalidate">
<div class="row">
<div class="col-lg-12">
<input name="questionnaire_pivot_id" id="questionnaire_pivot_id13" class="questionnaire_pivot_id" type="hidden" value="13">
<input name="questionnaire_id" id="questionnaire_id" class="questionnaire_id" type="hidden" value="1">
<input name="survey_image_id" id="survey_image_id" class="survey_image_id" type="hidden" value="467">
...
<div class="row" style="margin-bottom: 5%;">
<div class="col-xl-2 col-lg-3 col-md-3">
<button id="add" class="btn btn-default btn-md-6" type="submit" style="margin-top: 11%;">Save</button>
</div>
</div>
</form>
Form with ID="surveyImage18"
<form method="POST" action="http://localhost/2/467/survey" accept-charset="UTF-8" id="surveyImage18" role="form" class="form-material m-t-40" novalidate="novalidate">
<div class="row">
<div class="col-lg-12">
<input name="questionnaire_pivot_id" id="questionnaire_pivot_id18" class="questionnaire_pivot_id" type="hidden" value="18">
<input name="questionnaire_id" id="questionnaire_id" class="questionnaire_id" type="hidden" value="2">
<input name="survey_image_id" id="survey_image_id" class="survey_image_id" type="hidden" value="467">
...
</div>
</div>
<div class="row" style="margin-bottom: 5%;">
<div class="col-xl-2 col-lg-3 col-md-3">
<button id="add" class="btn btn-default btn-md-6" type="submit" style="margin-top: 11%;">Save</button>
</div>
</div>
</form>
AJAX call
<script type="text/javascript">
$("#surveyImage13").validate({
rules: {
'responses[]': {
required:true
}
},
// change name of error class that is assigned to input fields
errorClass: 'error_validate',
errorPlacement: function (label, element) {
// default
if (element.is(':radio')) {
label.insertAfter(element.parent('.form-check-inline'));
}
else {
label.insertAfter(element);
}
}
});
</script>
<script type="text/javascript">
$("#surveyImage13").submit(function(e) {
e.preventDefault();
var route=$('#surveyImage13').attr('action');
var pivot_id = $("#questionnaire_pivot_id").val();
// Get values of checked checkboxes
var responses = $('.form-check-inline input').filter(':checked').map(function() {
return this.value;
}).get();
var isFormValid = $("#surveyImage13").valid();
if(isFormValid){
$.ajax({
type: "POST",
url: route,
data: {'responses': responses, 'pivot_id': pivot_id},
success: function(response){
$("#surveyImageForm").css("display", "none");
$("#surveyImageAjax").css("display", "block");
$('#SurveyTableAjaxColumn1').append(response[1]);
$('#SurveyTableAjaxColumn2').append(response[0]);
},
error: function(){
console.log('Error');
}
})
}
});
</script>

Why not give your forms a common class
$('.myClass').validate({ ...
})
$('.myClass').submit(...

Based on your provided configuration, it should not be possible for jQuery to perform the submit action. The jQuery selector is #surveyImage, which does not match any id attributes in the provided HTML.
<form id="surveyImage13">...</form>
<form id="surveyImage18">...</form>
$("#surveyImage").submit...
I think you may be able to resolve the issue by using a different query selector string.
$('#surveyImage13 #surveyImage18').submit...
or...
$('form[id^="surveyImage"]').submit...

1.Instead of submit event use button click event
2.Get form id and store it
3.use this variable where you need id
$(".btn").click(function(e) {
e.preventDefault();
var formId = '#'+ $(this).parents('form').attr('id');
var route=$(formId).attr('action');
var pivot_id = $("#questionnaire_pivot_id").val();
// Get values of checked checkboxes
var responses = $('.form-check-inline input').filter(':checked').map(function() {
return this.value;
}).get();
var isFormValid = $(formId).valid();
if(isFormValid){
$.ajax({
type: "POST",
url: route,
data: {'responses': responses, 'pivot_id': pivot_id},
success: function(response){
$("#surveyImageForm").css("display", "none");
$("#surveyImageAjax").css("display", "block");
$('#SurveyTableAjaxColumn1').append(response[1]);
$('#SurveyTableAjaxColumn2').append(response[0]);
},
error: function(){
console.log('Error');
}
})
}
});

Thanks for all answers but I found solution. Im working in LARAVEL therefore I used foreach loop based on which i was able to assign dynamic ID on HTML forms.
#foreach($questionnaire_by_images as $t)
<form id="surveyImage{{$t->id}}">...</form>
<form id="surveyImage{{$t->id}}">...</form>
#endforeach
script
#foreach($questionnaire_by_images as $t)
<script type="text/javascript">
$( document ).ready(function() {
$("#surveyImage{{$t->id}}").validate({
rules: {
'responses[]': {
required:true
}
},
// change name of error class that is assigned to input fields
errorClass: 'error_validate',
errorPlacement: function (label, element) {
// default
if (element.is(':radio')) {
label.insertAfter(element.parent('.form-check-inline'));
}
else {
label.insertAfter(element);
}
}
});
$("#surveyImage{{$t->id}}").submit(function(e) {
e.preventDefault();
var route=$('#surveyImage{{$t->id}}').attr('action');
var survey_image_pivot = $("#survey_image_pivot{{$t->id}}").val();
// Get values of checked checkboxes
var responses = $('.form-check-inline .radio{{$t->id}}').filter(':checked').map(function() {
return this.value;
}).get();
var isFormValid = $("#surveyImage{{$t->id}}").valid();
if(isFormValid){
$.ajax({
type: "POST",
url: route,
data: {'responses': responses, 'survey_image_pivot': survey_image_pivot},
success: function(response){
$("#surveyImageForm{{$t->id}}").css("display", "none");
$("#surveyImageAjax{{$t->id}}").css("display", "block");
$('#SurveyTableAjaxColumn1{{$t->id}}').append(response[1]);
$('#SurveyTableAjaxColumn2{{$t->id}}').append(response[0]);
},
error: function(){
console.log('Error');
}
})
}
});
});
</script>
</script>
#endforeach

jQuery - Change action and form ID and use this

Apparently in the DOM have changed the values, even changed the ID of the form with the idea that the script no longer has effect but when you click Publish, nothing happens. Searching I tried to use "prop" instead of "attr" but it still does not work. I think it's because of the "e.preventDefault ()". But I do not know how to disable it. This is my code.
As you can see once the request is sent, the input and the "send" button are deactivated and when the values are received, they change the id of the form, the id and name of the button and it is renamed "Publish".
<script>
jQuery(function($){
var pluginUrl = '<?php echo plugin_dir_url( __FILE__ ); ?>' ;
$('[id^="form-search"]').on('submit', function(e) {
e.preventDefault();
$.ajax({
type : 'POST',
url : 'http://localhost/ladoserver/getapi.php',
data : $(this).serialize(),
cache: false,
beforeSend: function(){
$('input#keyword').prop('disabled', true);
$('button#search').prop('disabled', true);
$('#resuls').html('<img src="'+pluginUrl+'../../assets/img/loading.gif" />');
}
}).done(function(data) {
$('#results').html(data);
$('input#keyword').prop('value', 'PUBLISH DATA');
$('button#search').prop({disabled: false, id:'publish', name:'publish'}).html('Publish');
$('span#help').hide();
$('[id^="form-search"]').prop('action','publish.php');
$('[id^="form-search"]').prop('id', 'form-publish');
var countResults = $('input#total_data').val();
for (var i = 1; i <= countResults; i++) {
$('#lista>select').clone().prop({ id: "cat_"+i, name: "cat_"+i}).appendTo('.category_'+i);
}
$('#lista').remove();
});
});
});
</script>
Here my html
<form action="" method="post" class="form-search" id="form-search">
<fieldset>
<!-- Form Name -->
<legend>Name</legend>
<div class="form-group">
<input id="keyword" name="keyword" required="" type="text">
<button id="search" name="search" class="btn btn-success boton">Search</button>
<span class="help-block" id="help">Help</span>
<div id="lista" style="display:none">Test</div>
</div>
</fieldset>
<div id="result"></div>
</form>
Here a fiddle showing that happened (check DOM).
JSFiddle.net

//var pluginUrl = '<?php echo plugin_dir_url( __FILE__ ); ?>' ;
// when the action is plugin url.
$(document).on('submit','[id^="form-search"]', function(e) {
e.preventDefault();
$.ajax({
type : 'POST',
url : 'http://localhost/ladoserver/getapi.php',
data : $(this).serialize(),
cache: false,
beforeSend: function(){
$('input#keyword').prop('disabled', true);
$('button#search').prop('disabled', true);
$('#resuls').html('<img src="'+pluginUrl+'../../assets/img/loading.gif" />');
}
}).done(function(data) {
$('#results').html(data);
$('input#keyword').prop('value', 'PUBLISH DATA');
$('button#search').prop({disabled: false, id:'publish', name:'publish'}).html('Publish');
$('span#help').hide();
$('[id^="form-search"]').prop('action','publish.php');
$('[id^="form-search"]').prop('id', 'form-publish');
var countResults = $('input#total_data').val();
for (var i = 1; i <= countResults; i++) {
$('#lista>select').clone().prop({ id: "cat_"+i, name: "cat_"+i}).appendTo('.category_'+i);
}
$('#lista').remove();
});
});
// when the action point to publish.php === This is what you need
$(document).on('submit','[id^="form-publish"]', function(e) {
e.preventDefault();
var url = $(this).attr('action');
$.ajax({
type : 'POST',
url : url,
data : $(this).serialize(),
cache: false,
beforeSend: function(){
// do your pre-processing
}
}).done(function(data) {
// do your post processing.
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<form action="" method="post" class="form-search" id="form-search">
<fieldset>
<!-- Form Name -->
<legend>Name</legend>
<div class="form-group">
<input id="keyword" name="keyword" required="" type="text">
<input type ="submit" id="search" name="search" class="btn btn-success boton">Search</button>
<!-- change the button type to submit type -->
<span class="help-block" id="help">Help</span>
<div id="lista" style="display:none">Test</div>
</div>
</fieldset>
<div id="result"></div>
</form>

Submit multiple forms same jquery script

I have multiple forms and I want all of them to be processed by a single jquery script, of course I have php functions that work correctly, I tried them separately.
This is my script:
function proceso_form(type_form, id_div_error){
var url = "my_url.php?form="+type_form; //functions
var response = document.getElementById(id_div_error);
response.innerHTML="<img src='img/loader.gif' style='margin-right: 5px;'/>Loading ..."; //
response.style.display='block';
$.ajax({
type: "POST",
url: url,
data: $(this).serialize(), //ID form
success: function(data)
{
if (data==1){
window.location.reload();
}else{
response.innerHTML=data; // show PHP response.
}
}
});
return false;
};
My form looks like this
<form id="contacto" name="contacto" method="post" onsubmit="proceso_form('contacto', 'cargando')">
<input type="text" name="name"class="form-control">
<input type="text" name="phone" class="form-control">
<input type="email" name="email" class="form-control">
<textarea style="height:100px;margin-bottom:0px" name="messaje" class="form-control"></textarea>
<input style="margin-top:5px" type="submit" class="btn btn-block" value="SEND">
</form>
I think my problem is that I can't put my script in the onsubmit, but honestly I have no idea.

Your html must look like
<form id="contacto" name="contacto" method="post" onsubmit="return proceso_form(this, 'cargando')">
...
</form>
And inside the function:
function proceso_form(form, id_div_error){
var $form = $(form);
var url = "my_url.php?form="+$form.attr('id'); //functions
var response = document.getElementById(id_div_error);
response.innerHTML="<img src='img/loader.gif' style='margin-right: 5px;'/>Loading ..."; //
response.style.display='block';
$.ajax({
type: "POST",
url: url,
data: $form.serialize(), //ID form
success: function(data)
{
if (data==1){
window.location.reload();
}else{
response.innerHTML=data; // show PHP response.
}
}
});
return false;
};
By passing this to the function you passing the whole form reference.
Hope it will help.

First, it should be:
<form id="contacto" name="contacto" method="post" onsubmit="return proceso_form('contacto', 'cargando')">
The return keyword there is important.
Next, data: $(this).serialize(), //ID form should be:
data: $('#'+type_form).serialize(), //ID form
So, your script should look like this:
<script type="text/javascript" src="/path/to/jquery.min.js"></script>
<form id="contacto" name="contacto" method="post" onsubmit="return proceso_form('contacto', 'cargando')">
<input type="text" name="name" class="form-control">
<input type="text" name="phone" class="form-control">
<input type="email" name="email" class="form-control">
<textarea style="height:100px;margin-bottom:0px" name="messaje" class="form-control"></textarea>
<input style="margin-top:5px" type="submit" class="btn btn-block" value="SEND">
</form>
<div id="cargando"></div>
<script>
function proceso_form(type_form, id_div_error){
var url = "my_url.php?form="+type_form; //functions
var response = document.getElementById(id_div_error);
response.innerHTML="<img src='img/loader.gif' style='margin-right: 5px;'/>Loading ..."; //
response.style.display='block';
$.ajax({
type: "POST",
url: url,
data: $('#'+type_form).serialize(), //ID form
success: function(data)
{
if (data==1){
window.location.reload();
}else{
response.innerHTML=data; // show PHP response.
}
}
});
return false;
};
</script>

Form serialize issue

Here is my form's markup
<form name="contactForm" id="contactForm" role="form">
<div style="width: 190px">
<div class="form-group">
<input type="text" placeholder="fullname" name="fullname" id="formFullname" class="form-control">
</div>
<div class="form-group">
<input type="email" placeholder="email" name="email" id="fromEmail" class="form-control">
</div>
<div class="form-group">
<input type="text" placeholder="company" name="company" id="fromCompany" class="form-control">
</div>
</div>
<div class="clear"></div>
<div class="form-group">
<textarea placeholder="message" name="message" id="formMessage" rows="3" class="form-control"></textarea>
</div>
<button class="btn btn-success" type="submit" name="submit" id="formSubmit">send</button>
</form>
Using jquery 1.10.2
And here is JS
var form = $('#contactForm');
form.submit(function () {
console.log("form ", $(this).serialize());
$.ajax({
type: "POST",
url: url + "ajax/sendmail",
data: $(this).serialize(),
success: function (response) {
console.log(response);
}
});
return false;
});
I know that function fires, tested with alert. But console.log doesnt return anything, and during ajax call I don't see anything in POST (Watching with firebug's XHR).
BTW: role="form" is because i'm using Twitter Bootstrap framework
What am I doing wrong?
UPDATE
data: $(form).serialize() didn't help also

If you try this :
form.submit(function () {
console.log("form ", $(this).serialize());
return false;
});
it works just fine. So I think the problem
form.on('submit',function () {
event.preventDefault();
console.log("form ", $(this).serialize());
$.ajax({
type: "POST",
url: url + "ajax/sendmail",
data: $("form").serialize(),
success: function (response) {
console.log(response);
}
});
return false;
});
Because $(this) in your code doesn't refer to the form but instead refers to jQuery on which the ajax method is called

Try the following code, but first modify your form HTML so that is has an "action" attribute. The nice thing about this code is that it can be used on any form which has a submit button and an action attribute. (i.e. it is not coupled to any specific IDs)
$(function() {
$('input[type="submit"]').click(function(event) {
event.preventDefault();
var form = $(this).closest('form');
var url = form.attr('action');
var data = form.serialize();
$.post(url, data)
.done(function() {
alert('Yay! your form was submitted');
})
.fail(function() {
alert('Uh oh, something went wrong. Please try again');
});
});
Cheers.