On fiddle I found a simple rotator and trying to make it work in my death-simple HTML page.
The page example is here:
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Demo</title>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<style>
img { max-height: 100px }
.rotator img { max-height: 200px; border: dashed 5px pink; }
</style>
<script>
$(document).ready(function() {
alert('aaa');
var $rotator = $(".rotator");
$rotator.find("img:gt(0)").hide();
setTimeout(Rotate, 1000);
function Rotate() {
var $current = $rotator.find("img:visible");
var $next = $current.next();
if ($next.length == 0) $next = $rotator.find("img:eq(0)");
$current.hide();
$next.show();
setTimeout(Rotate, 5000);
}
});
</script>
</head>
<body>
<img src="http://2.bp.blogspot.com/-XI9yzJrwLac/TkLKLZF_kDI/AAAAAAAACFE/PxPDRzwa4tQ/s1600/cute+cats+pictures+3.jpg"/>
<img src="http://2.bp.blogspot.com/-NOD8B0m7MEE/TrvJAVAPYWI/AAAAAAAAAuE/KoffoIdQfNk/s640/cute-kittens-in-cups-pics.jpg"/>
<img src="http://1.bp.blogspot.com/_cWcuJM9QIG4/S7rOVzM1YcI/AAAAAAAAAgQ/RJx5oR55Ekk/s640/Animal+wallpapers%252Bcat+wallpapers%252Bmobile+wallpapers%252Bpc+wallpapers%252Bmobile+themes%252Bpc+themes+15cc.jpg"/>
<div class="rotator">
<a href="http://google.com">
<img src="http://2.bp.blogspot.com/-XI9yzJrwLac/TkLKLZF_kDI/AAAAAAAACFE/PxPDRzwa4tQ/s1600/cute+cats+pictures+3.jpg"/>
</a>
<a href="http://google.com">
<img src="http://2.bp.blogspot.com/-NOD8B0m7MEE/TrvJAVAPYWI/AAAAAAAAAuE/KoffoIdQfNk/s640/cute-kittens-in-cups-pics.jpg"/>
<a>
<a href="http://google.com">
<img src="http://1.bp.blogspot.com/_cWcuJM9QIG4/S7rOVzM1YcI/AAAAAAAAAgQ/RJx5oR55Ekk/s640/Animal+wallpapers%252Bcat+wallpapers%252Bmobile+wallpapers%252Bpc+wallpapers%252Bmobile+themes%252Bpc+themes+15cc.jpg"/></a>
</div>
<label />
</body>
</html>
The simple script should regularly switch images, but instead of that are just displayed all 3 images. And the alert message is not displayed.
I've tried to debug the code and when I remove the function Rotate(), an alert message appears on the page.
Why the function Rotate() is not working?
$.next() gets the immediate element in the set. Your set only contains visible images - i.e. only one. How could there be a next element?
Working fiddle: http://jsfiddle.net/gjzd7/
All I have done is changed the $.next() call into an $.index() request and modulo-ed it by the number of images (so you'll never get a non-existent image). Let me know if you need anything else modified to it or any explanations!
You could also cache the images in a jQuery array and iterate over them like below.
var imgs = $(".slides"); // images to be rotated
var current = 0;
function rotate( ) {
// set current to next image
current = current >= imgs.length ? 0 : current + 1;
$(".rotator").prop("src", $(imgs.get(current)).prop("src") );
setTimeout( rotate, 5000 );
}
rotate();
Example here
Use this simple script to rotate image using buttons
function rotateImage(degree) {
$('#demo-image').animate({ transform: degree }, {
step: function(now,fx) {
$(this).css({
'-webkit-transform':'rotate('+now+'deg)',
'-moz-transform':'rotate('+now+'deg)',
'transform':'rotate('+now+'deg)'
});
}
});
}
<style>
#demo-image{padding:35px 15px;}
.btnRotate {padding: 15px 20px;border:1px solid #000; background-color:#999;color: #000;cursor: pointer;}
</style>
<div style="height:600px; width:800px; background-color:#CCC; border:1px solid #000; border-radius:6px; margin-left:auto; margin-right:auto;">
<div style="width:550px; margin-left:auto; margin-right:auto;">
<label>Rotate Image:</label>
<input type="button" class="btnRotate" value="30" onClick="rotateImage(this.value);" />
<input type="button" class="btnRotate" value="60" onClick="rotateImage(this.value);" />
<input type="button" class="btnRotate" value="90"onClick="rotateImage(this.value);" />
<input type="button" class="btnRotate" value="180" onClick="rotateImage(this.value);" />
<input type="button" class="btnRotate" value="-180" onClick="rotateImage(this.value);" />
<input type="button" class="btnRotate" value="360" onClick="rotateImage(this.value);" />
</div>
<div style="width:350px; margin-left:auto; margin-right:auto; margin-top:25px;"><img src="image-rotating-script-using-jquery .jpg" id="demo-image" /></div>
</div>
Related
Trying to make my first project with bunch of pictures, with a filter/search bar at the top that would filter the pictures depending on the input. For example if the input would be "Aatrox", it would show "Aatrox" and not "Jayce" and or "Senna" and so on. Script was working fine, I added a .toLowerCase() so its not case sensitive and then I added to the pictures so they are clickable and each lead to their own page. After adding these two the search bar stopped working.
Here is the snippet of the script
<script>
function search(){
var searchText = (document.getElementById("searchInput").value).toLowerCase();
var images = document.querySelectorAll(".image_container > img");
if(searchText.length > 0){
images.forEach((image) => {
image.classList.add("hide");
if((image.dataset.tags).toLowerCase().indexOf(searchText) > -1){
image.classList.remove("hide");
}
});
}else{
images.forEach((image) => {
image.classList.remove("hide");
});
}
}
</script>
Here is the HTML part
<head>
<title> Counterpicks </title>
<meta charset="utf-8">
<link rel="stylesheet" href="style.css">
</head>
<body>
<h1> Counterpicks pro debily </h1>
<div class="container">
<div class="searchbox_container">
<div class="searchbox">
<input type="text" name=" " placeholder="Search" class="search" id="searchInput" onkeyup="search()">
</div>
</div>
<div class="image_container">
<img data-tags="aatrox" src="aatrox.webp" alt="Aatrox" class="actionimages">
<img data-tags="ahri" src="ahri.webp" alt="Ahri" class="actionimages">
</div>
I input only few of the lines because they are just repeating for 130 lines.
And here is the CSS
.container {
background: rgba(0,0,0,0);
text-align: center;
margin-left: 20%;
margin-right: 20%;
}
.searchbox {
text-align: center;
margin-left: 20%;
margin-right: 20%;
margin-bottom: 20px;
}
.image_container {
clear:both;
}
.hide {
display:none;
This is my first project with JavaScript so I will be happy for any constructive criticism.
Replace:
var images = document.querySelectorAll(".image_container > img");
with:
var images = document.querySelectorAll(".image_container > a > img");
I'm looking to add a gif loading onclick or to delete "changing text on click" with an animation with the same button characteristics and a gif overlayed (eg. Searchbox from airbnb.com) How can i do it?
Thank you!
<input onclick="change()" type="submit" class="submit-form" value="Log in" id="myButton1">
<script type="text/javascript">
function change()
document.getElementById("myButton1").value = "Logging in...";
}
</script>
try with this below code which is having loading image and text as well.
$('#myButton1').click(function(){
$('#myButton1').hide();
$('.load').addClass('loading');
setTimeout(function () {
$('.load').removeClass('loading');
$('#myButton1').show();
}, 2000);
});
.loading{
background-image : url('http://www.fotos-lienzo.es/media/aw_searchautocomplete/default/loading.gif');
background-repeat:no-repeat;
}
.loading:after {
content: "Logging in...";
text-align : right;
padding-left : 25px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<input type="submit" class="submit-form" value="Log in" id="myButton1">
<div class="load"></div>
<script type="text/javascript">
function change() {
document.getElementById("myButton1").style.background='#000000';
}
</script>
As I can see from your question tags you using JQuery
function change()
$("#myButton1").css({
background-image:url('PATH/TO/LOADING/IMAGE.gif')
});
}
and after finish loading you can create a function to stop loading
function stopLoading()
$("#myButton1").css({
background-image:'none'
});
}
Sorry for the image, it's background is not transparent. I just hope atleast it will give you an idea.
https://jsfiddle.net/3pmpqpwj/
HTML
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" integrity="sha384-1q8mTJOASx8j1Au+a5WDVnPi2lkFfwwEAa8hDDdjZlpLegxhjVME1fgjWPGmkzs7" crossorigin="anonymous">
<img src='http://www.arabianbusiness.com/skins/ab.main/gfx/loading_spinner.gif' id='overlay' style="display:none;" />
<button id="searchbtn" class="btn btn-default" type="button" onclick="change(); alert('test');">Log In</button>
CSS
#overlay{
position: absolute;
width: 30px;
height: 30px;
top: 2px;
z-index: 3;
left: 32px;
}
JS
$('#searchbtn').click(function(){
$(this).html("Logging in...").prop('disabled',true);
$("#overlay").show();
});
So I have been able to make some progress with my problem but have encountered something a little unexpected/confusing. I have been able to add my script to my web page, however, the two do not work together. Without the script, the page appears as I would like. With the script, the script runs and overrides the web page. What happens is a random picture shows up in the top left corner of the screen, but nothing from the html file appears. I have included all my code (html, javascript, css) and if anyone can provide some guidance it would be really greatly appreciated.
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8" />
<link href="mplstyles.css" rel="stylesheet" type="text/css" />
<title>Monroe Public Library</title>
</head>
<body>
<div id="pageContent">
<div id="head">
<img src="mpl.jpg" alt="Monroe Public Library" />
</div>
<div id="links">
<ul class = "nav">
<span>Quick Links</span>
<li>Home Page</li>
<li>Online Catalog</li>
<li>Friends of MPL</li>
<li>New Books and Other Good Reading</li>
<li>Ohio Virtual Library</li>
<li>Internet Public Library</li>
<li>Services and Collection</li>
<li>Adult Programs</li>
<li>Teen Central</li>
<li>Children's Room</li>
<li>Computers at MPL</li>
<li>Computer Rules and Procedures</li>
<li>Staff Directory</li>
<li>Library Records</li>
</ul>
</div>
<div id="main">
<h2>Library Records</h2>
<p>To view the library records, enter your username and password.</p>
<form id="login" method="post" action="">
<p>
<label for="username" class="center" id="input"> Username:</label>
<input type="text" id="username" name="username" size="20" />
</p>
<p>
<label for="password" class="center" id="input"> Password:</label>
<input type="password" id="password" name="password" size="20" />
</p>
<p>
<label for="captcha" id="input">As a final security check, enter the 5 numbers you see displayed below.</label>
<input type="text" id="captcha" name="captcha" size="6" />
</p>
<p id="login"> </p>
<p id="login">
</p>
<script src="mpl.js"></script>
<p align="center"><img src="" alt="" name="number1" width="70" height="100" id="number1"><img src="" alt="" name="number2" width="70" height="100" id="number2"><img src="" alt="" name="number3" width="70" height="100" id="number3"><img src="" alt="" name="number4" width="70" height="100" id="number4"><img src="" alt="" name="number5" width="70" height="100" id="number5"></p>
<div id="images">
</div>
<p align="center">
<input type="submit" value="View Library Records" />
</p>
</form>
</div>
<div id="address">
<span class="addressBold">Monroe Public Library</span>
580 Main Street, Monroe, OH 45050
<span class="addressBold">Phone</span>(513) 555-0211
<span class="addressBold">Fax</span>(513) 555-0241
</div>
</div>
</body>
</html>
window.onload = function ()
{
//http://www.java-scripts.net/javascripts/Random-Image-Script.phtml
var pictureNumbers=new Array()
//specify random images below. You can have as many as you wish
pictureNumbers[1]="0.jpg"
pictureNumbers[2]="1.jpg"
pictureNumbers[3]="2.jpg"
pictureNumbers[4]="3.jpg"
pictureNumbers[5]="4.jpg"
pictureNumbers[6]="5.jpg"
pictureNumbers[7]="6.jpg"
pictureNumbers[8]="7.jpg"
pictureNumbers[9]="8.jpg"
pictureNumbers[10]="9.jpg"
var randomNumber = Math.floor(Math.random()*pictureNumbers.length)
if (randomNumber==0)
{
randomNumber=1
document.write('<img src="'+pictureNumbers[randomNumber]+'" border=0>')
}
else if (randomNumber==1)
{
document.write('<img src="'+pictureNumbers[randomNumber]+'" border=0>')
}
else if (randomNumber==2)
{
document.write('<img src="'+pictureNumbers[randomNumber]+'" border=0>')
}
else if (randomNumber==3)
{
document.write('<img src="'+pictureNumbers[randomNumber]+'" border=0>')
}
else if (randomNumber==4)
{
document.write('<img src="'+pictureNumbers[randomNumber]+'" border=0>')
}
else if (randomNumber==5)
{
document.write('<img src="'+pictureNumbers[randomNumber]+'" border=0>')
}
else if (randomNumber==6)
{
document.write('<img src="'+pictureNumbers[randomNumber]+'" border=0>')
}
else if (randomNumber==7)
{
document.write('<img src="'+pictureNumbers[randomNumber]+'" border=0>')
}
else if (randomNumber==8)
{
document.write('<img src="'+pictureNumbers[randomNumber]+'" border=0>')
}
else if (randomNumber==9)
{
document.write('<img src="'+pictureNumbers[randomNumber]+'" border=0>')
}
else if (randomNumber==10)
{
document.write('<img src="'+pictureNumbers[randomNumber]+'" border=0>')
}
}
#charset "UTF-8";
/* CSS Document */
body
{
margin-top:0;
font-family:Georgia, "Times New Roman", Times, serif;
background-color:#FFC;
}
#head
{
background-color:orange;
}
#page
{
width: auto;
margin" 0 auto;
background-color: white;
border-top: none;
}
#links
{
position:absolute;
width:10em;
border: 1px solid blue;
top: 72px;
background-color: white;
}
#main
{
margin-left: 12em;
}
#login
{
padding-top: 1em;
padding-left: 2em;
padding-bottom: 5em;
border: 1px solid blue;
}
#address
{
padding-top: 2em;
padding-left: 2em;
border-top: 1px solid blue;
}
#pageContent #main h2 {
color: #00F;
}
#input
{
background-color: orange;
padding-right: 20%;
}
Your problem is document.write. You should either be creating an element and appending it to a parent element in the DOM, or changing the src attribute of an existing element.
Creating Elements and appending them
var parent = document.getElementById("parent"),
img = document.createElement("img")
img.setAttribute("src","your-file-name.jpg")
parent.appendChild(img)
Example
Here is a simplified example of what you are doing.
Fiddle: http://jsfiddle.net/L3WYH/1/
HTML
<div id="picture-frame"></div>
JS
var pictureNumbers = [],
pictureCount = 10
for ( var i = 1; i <= pictureCount; i++ )
pictureNumbers[i] = i + ".jpg"
var randomNumber = Math.ceil(Math.random()*(pictureNumbers.length - 1)),
element = document.getElementById("picture-frame"),
image = document.createElement("img")
image.setAttribute("src", pictureNumbers[randomNumber])
element.appendChild(image)
To expand on #Gary's comment to the original post:
The calls to document.write(...) are what's causing your problem. Upon firing the 'onload' event, the browser closes the document for writing. Any subsequent calls to document.write will literally overwrite the whole page.
To fix this, you will need to do one of two things:
Make your calls to document.write outside of the window.onload event
Do as #MBottens mentioned in his answer, where you append new <img> elements to a DIV tag.
I have a number of buttons in my html. Each button referring to a particular DIV. I want an easy way to hide the previously open DIV when another button is clicked. So far I have written a code in jquery, but I have a strange feeling that am putting in a lot of code into a simply achievable task. Is there a simpler way to do this than what I have tried to accomplish?
Here is what I have done so far.
My HTML:
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>TODO supply a title</title>
<meta name="viewport" content="width=device-width"/>
<script src='http://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js'></script>
</head>
<body>
<div id="body">
<input type="button" name="division1" value="div1" class="buttons" id="button1"/>
<input type="button" name="division2" value="div2" class="buttons" id="button2"/>
<input type="button" name="division3" value="div3" class="buttons" id="button3"/>
<input type="button" name="division4" value="div4" class="buttons" id="button4"/>
<input type="button" name="division5" value="div5" class="buttons" id="button5"/>
<input type="button" name="division6" value="div6" class="buttons" id="button6"/>
<div id="div1" class="divs"></div>
<div id="div2" class="divs"></div>
<div id="div3" class="divs"></div>
<div id="div4" class="divs"></div>
<div id="div5" class="divs"></div>
<div id="div6" class="divs"></div>
</div>
</body>
</html>
My CSS:
#body{
position: absolute;
left: 0;
top: 0;
width: 100%;
height: 100%;
background-color: #000;
}
.buttons{
width: 10%;
height: 5%;
position: relative;
left: 10%;
cursor: pointer;
z-index: 500;
}
.divs{
position: absolute;
left: 0;
top: 0;
width: 100%;
height: 100%;
display: none;
}
#div1{
background-color: #377D9F;
}
#div2{
background-color: #02B0E6;
}
#div3{
background-color: #4b9500;
}
#div4{
background-color: #aaa;
}
#div5{
background-color:#aa0000;
}
#div6{
background-color: aquamarine;
}
My Jquery:
$(document).ready(function () {
$("#button1").click(function () {
$('#div1').toggle(100);
$("#div2,#div3,#div4,#div5,#div6").hide();
});
$("#button2").click(function () {
$("#div2").toggle(100);
$("#div1,#div3,#div4,#div5,#div6").hide();
});
$("#button3").click(function () {
$("#div3").toggle(100);
$("#div1,#div2,#div4,#div5,#div6").hide();
});
$("#button4").click(function () {
$("#div4").toggle(100);
$("#div1,#div2,#div3,#div5,#div6").hide();
});
$("#button5").click(function () {
$("#div5").toggle(100);
$("#div1,#div2,#div3,#div4,#div6").hide();
});
$("#button6").click(function () {
$("#div6").toggle(100);
$("#div1,#div2,#div3,#div4,#div5").hide();
});
});
I kind of have around 50 DIV's in my html like the above ones. And I think using the above JQUERY is a waste of coding lines. I know there will be a better way to do this. My code seems to work well, but is there any way in jquery to just hide the previous DIV, no matter which button user clicks?
$(document).ready(function(){
$(".buttons").click(function () {
var divname= this.value;
$("#"+divname).slideToggle().siblings('.divs').hide("slow");
});
});
Going with this sentence I kind of have around 50 DIV's in my html like the above ones
This would be a lot more clean as well as convenient if you use a select tag, instead of using button to show and hide each div
Demo
HTML
<select id="show_divs">
<option>Select to show a div</option>
<option value="1">Show 1</option>
<option value="2">Show 1</option>
</select>
<div class="parent">
<div id="show1">This is the first div</div>
<div id="show2">This is the second div</div>
</div>
jQuery
$('#show_divs').change(function() { //onChange execute the function
var showDiv = $(this).val(); //Store the value in the variable
$('div.parent > div').hide(); //Hide all the div nested inside .parent
$('#show' + showDiv ).show(); //Fetch the value of option tag, concatenate it with the id and show the relevant div
});
CSS
div.parent > div {
display: none; /* Hide initially */
}
If you want to avoid using id's, you can also create your custom attribute, like data-show="1" and data-show="2" so on...
Try this
$(document).ready(function() {
$(".divs").hide();
$(".buttons").click(function() {
$(".divs").hide().eq($(this).index()).show();
});
});
DEMO
<input type="button" value="div1" class="buttons" id="button1" />
<input type="button" value="div2" class="buttons" id="button2" />
<input type="button" value="div3" class="buttons" id="button3" />
<input type="button" value="div4" class="buttons" id="button4" />
<input type="button" value="div5" class="buttons" id="button5" />
<input type="button" value="div6" class="buttons" id="button6" />
<div id="div1" class="divs">div1</div>
<div id="div2" class="divs">div2</div>
<div id="div3" class="divs">div3</div>
<div id="div4" class="divs">div4</div>
<div id="div5" class="divs">div5</div>
<div id="div6" class="divs">div6</div>
<script language="javascript">
$(document).ready(function () {
$(".buttons").click(function () {
$('.divs').hide();
$('#div'+$(this).attr('id').replace('button','')).toggle(100);
})
})
</script>
I am trying to change the color of a transparent image inside a div (using jQuery). I cannot get the left and top of the image fixed into the div while changing the color.
Could anyone help? I'm trying to have the image filled if a user clicks on any of the span colors.
test.css:
.iconWrapper .color span
{
width: 50px;
height: 58px;
display: block;
}
.color1
{
background-color: #f6f6f6;
}
.color2
{
background-color: #ffe25b;
}
.color3
{
background-color: #e35990;
}
.color4
{
background-color: #58c1d8;
}
step1.php
<link rel="stylesheet" type="text/css" href="test.css" media="screen" />
<script language="javascript" type="text/javascript">
$(function() {
$('.iconWrapper span').click(function(e){
var color=$(this).attr('class');
//alert(color);
$('#div1').removeClass().addClass(color);
$('#hiddencolor').val(color);
e.preventDefault();
});
});
</script>
</head>
<body>
<div class="iconWrapper">
<ul class="color">
<li>
<span class="color1"></span>
</li>
<li>
<span class="color2" ></span>
</li>
<li>
<span class="color3"></span>
</li>
<li>
<span class="color4"></span>
</li>
</ul>
</div>
<div id="div1" style="width:17%; height:28%;" ><img src="img/107.png" />
<form method="post" action="step3.php">
<input name="kleur" type="text" value="" id="hiddencolor" />
<input name="submit" type="submit" value="Submit" />
</form>
</div>
Change the width of the parent div from 17% to the width of img in other words 250px
Demo: http://jsfiddle.net/V9zEH/5/
$('#div1 img').removeClass().addClass(color);
Would this be what you wanted?
If what you want is the color to not spill out of the borders inside the image, the only solution I can find is to edit the image so that there is white where you don't want to see the colour - rather than transparent.
I have trouble understanding what it is exactly that you want to achieve. :|
Try:
$(function () {
$('.iconWrapper span').click(function (e) {
var $span = $(this),
color = $span.attr('class');
$('#div1 img').css('background-color', $span.css('background-color'));
$('#hiddencolor').val(color);
e.preventDefault();
});
});
Test the effect here »