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Google Fastbutton not working on mobile Safari?

I'm trying to implement Google's Fastbuttons described here for tables with a two-row layout.
The fastbuttons get bound on the table-rows with:
var buttons = document.getElementsByClassName('evtFastbutton');
for (var i = 0; i < buttons.length; i++) {
var fastbutton = new FastButton(buttons[i], function () {
var urlstr = 'xyz';
window.location.href = (urlstr);
});
}
If one of the rows is clicked it should change the background-color of either the previous or the next row and itself and open a new page.
While using Chrome or Firefox on Android or PC it all works great.
In Safari on the IPhone it is not changing the background-color but opens the new page.
I am not sure what is not working, the change of the background-color or the fastbutton.
Does anybody have had similar issues or a possible solution for this?
You can find the full code in this fiddle:
http://jsfiddle.net/tofeld/9Lu54yrr/1/
PS: I already tried the solutions suggested at this question: Google FastButton clicks twice on iOS

I found the solution of my problem.
As described here the rendering was not done before the javascript to change the page was executed.
So if anybody experiences a similar issue, try to do:
window.setTimeout(function(){window.location.href=('new/location');},0);
instead of
window.location.href=('new/location');

using onmouseover to change text hyperlink into an image hyperlink?

Please bear with me I am brand new to learning javascript (self taught)! I am usually one to find answers on my own from just web browsing but so far I haven't found any resources explaining how to accomplish the following:
So, basically all I want to do is change this (HTML):
SPEAKERS
to an image by using javascript.
The image is kept in the same folder as the html and the js.
Here is as far as I know to go with the javascript:
function showImage()
{
picture = new Image(100,100);
picture.src = "icon2.png";
document.getElementById("speakers").innerHTML = picture.src;
}
function goBack()
{
document.getElementById("speakers").innerHTML="SPEAKERS";
}
For clarity, all I would like to do is change the text ("SPEAKERS") to an image using 'onmouseover' while using the same hyperlink in the process.
It seems like a very simple problem but I don't know enough to determine if what I want to do is even possible. If it's not possible that's fine, I would just like to know either way ;P. Thanks ahead of time!

If you're ok with using jquery, you could use .html() and .hover()
http://jsfiddle.net/u8fsU/

Try something like this to get you started (not a complete nor tested solution):
var showImage = function(){
var picture = document.createElement("img");
picture.src = "icon2.png";
picture.href = "link.html";
var speakers = document.getElementById("speakers");
speakers.parentNode.replaceChild(speakers, picture);
}
Please see https://developer.mozilla.org/en-US/docs/Gecko_DOM_Reference for a good reference to some of the available DOM properties and methods.

onmouseover fails in chrome when posting or leaving page

I have onmouseover and onmouseout attributes on pictures on page. When submitting onmouseover and onmouseout cause images to fail (returns image source not found icon)
<input type="image" src="../../Content/Resources/save.png" onmouseover="mouseOverForImage('save', '../../Content/Resources/save_mouse_over.png')"
onmouseout = "mouseOverForImage('save', '../../Content/Resources/save.png')" id="save"
title = "Save" />
And Javascript:
function mouseOverForImage(imgId, imgSrcs) {
document.getElementById(imgId).src = imgSrcs;
}

I've made a page on jsfiddle to test your issue (note that you need to run the page in order to see the images with relative paths, that's a jsfiddle issue happening in all browsers).
Hover the [+] image button (it will turn into [?]) and click it. While the page is being loaded you can mouseover/out/over/out/over... as many times as you want and it will work: the image will change and no 404 will occur.
I am using Chrome 20.
This leads me to the following questions:
What's your Chrome version and can you reproduce the issue in Safari? I recall Webkit had a bug that displayed images quite randomly...
Have you posted the code exactly? Are you 100% sure that there's no missing quote, or "0" instead of "o", or some issue with letter case?
When you submit the form, does your page's (or iframe's) URL change at the same time? If so - your relative paths won't work anymore and you'll get your 404. Can you test it by setting a full path to the image's src? Maybe also log the current url?
Can some other code (onsubmit event?) interfere with your form? Can you post more code or create a jsfiddle that reproduces your issue?
Do we/I understand your problem correctly? :)
Thanks.

You can try something like this
function mouseOverForImage(imgId, imgSrcs) {
var image = new Image();
image.src = imgSrcs;
image.onload = function() {
document.getElementById(imgId).src = imgSrcs;
};
}

In place of using mouseover and mouseout events try using mouseenter and mouseleave. It usually works in these types of problem.

Only load the background-image when it has been fully loaded?

Well, the title pretty much describes my question:
How to load the background-image dynamically after it has been fully loaded? Sometimes, I must use backgrounds that are so big that it can take a while for the browser to download it. I'd rather 'load it in the background' and let it fade in when it has been fully loaded.
I think jQuery would be best to be using, but I also want my background to appear if JavaScript has been disabled. If this really isn't possible, so be it, but I think it is?
Best regards,
Aart
........
EDIT:
Thanks a bunch, guys! I've been bugged with this for ages and just couldn't think of a nice and easy way.
I converted Jeffrey's Javascript-solution into a jQuery one, just because jQuery's built-in fade looks so awesome.
I'll just post it here in case anyone else has the same issue:
<script type='text/javascript' src='http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js'></script>
<script type='text/javascript'>
$(document).ready(function() {
$('#img').css('opacity','0').load(function() {
$(this).animate({
opacity: 1
}, 500);
});
});
</script>
<img src='yourimage.jpg' id='img'/>

If the image is included with an img element:
<img src="bg.jpg" id="img" onload="this.style.opacity='1'">
<script>
document.getElementById("img").style.opacity="0";
</script>
That should load the image normally if JavaScript is disabled, but show it only once it loads assuming it's enabled.
One thing to note (that I overlooked): some browsers will not even attempt to load an image if its display property is none. That's why this method uses the opacity attribute.

You can't do it when JS is disabled. However, what you can do is set the background image in CSS and then use the following script (assuming the element has the ID myelem).
(function() {
var elm = document.getElementById('myelem'),
url = 'background image URL here';
elm.style.backgroundImage = "none";
var tmp = new Image();
tmp.onload = function() {
elm.style.backgroundImage = "url('"+url+"')";
// or insert some other special effect code here.
};
tmp.src = url;
})();
EDIT: Although, make sure your background images are optimal. If they are PNG, try having them Indexed with as small a colour table as possible, or make sure the alpha channel is removed if there is no transparency. If they are JPEG, try adjusting the compression.

Check the example on this page:
http://www.w3schools.com/jsref/event_img_onload.asp
Using "image.onload" will start your code only when the image is ready

Without javascript you can't have events, so you won't be able to know if the image is loaded, at least for the first rendering.
You can also use a css preload (put the image as a background in a hidden div), but that would work better in your first refresh and not while loading.

You can set a variable to the image, and when it loads, set it to the body background:
var my_bg = new Image();
my_bg.src = "url(mybackground.png)";
document.style.backgroundImage = my_bg;

What you are looking for is an image onLoad method. If you set the image with a display:none it wont be visible. To get around the possible lack of javascript, you do the following:
<body style="background-image:url(image.png);">
<img src="image.png" style="display:none" onLoad="changeBackground();" />
</body>
<script>
document.body.style.backgroundImage = "";
function changeBackground(){
document.body.style.backgroundImage = "url(image.png)";
}
</script>
This way, if javascript isnt enabled, the bg will load as normal. If it is, it will display at the end

Customize OpenLayers Control

How can I easily customize OpenLayers map controls? Or at least, how can I minimize the controls' height?
Thank you.
PS. Is there any CSS override?

You can sub-class any of the openLayers controls. I just made a 'zoom-slider' by sub-classing PanZoomBar (panZoomBar.js), overriding the draw() method and commenting out all the button elements, just leaving the zoom slider.. like this:
function zoomSlider(options) {
this.control = new OpenLayers.Control.PanZoomBar(options);
OpenLayers.Util.extend(this.control,{
draw: function(px) {
// initialize our internal div
OpenLayers.Control.prototype.draw.apply(this, arguments);
px = this.position.clone();
// place the controls
this.buttons = [];
var sz = new OpenLayers.Size(18,18);
var centered = new OpenLayers.Pixel(px.x+sz.w/2, px.y);
this._addButton("zoomin", "zoom-plus-mini.png", centered.add(0, 5), sz);
centered = this._addZoomBar(centered.add(0, sz.h + 5));
this._addButton("zoomout", "zoom-minus-mini.png", centered, sz);
return this.div;
}
});
return this.control;
}
var panel = new OpenLayers.Control.Panel();
panel.addControls([
new zoomSlider({zoomStopHeight:11}),
new OpenLayers.Control.LayerSwitcher({'ascending':false}),
]);
map.addControl(panel);

There is a CSS file that comes with can controls all of the CSS commands for within openlayers generally .olZoombar { here}
It is probably the easiest way to edit those sorts of things otherwise you can edit the actual .js file for the control.

If you are talking about the PanZoomBar or ZoomBar, as has been mentioned, you need to edit the zoomStopHeight. However, You do not need to edit OpenLayers.js.
new OpenLayers.Control.PanZoomBar({zoomStopHeight: 7})
You could consider trying PanZoom, which has no bar.

To minimize the ZoomBar search for zoomStopHeight in OpenLayers.js and edit it as you wish.
Further reference: Link.

Take a look here - http://geojavaflex.blogspot.com/
I am in the process of showing how to do an involved customization of the LayerSwitcher. This might give you ideas on how to do what you are after.
There is a map on the page that shows how the control works, and subsequent posts will discuss the code in detail.
If you are just interested in code see the source of the page and look for the link to CustomLayerSwitcher.js for the customized version of the switcher.