I'm trying to get a large logo (in the header of my site) to fall down into the header area on load. And so this is the only jquery function that I can find that seems to fit the idea.
http://jsfiddle.net/apHLu/279/
var $dropDiv = $('#dropDiv');
$('#holder a').on('click', function() {
// get position of the element we clicked on
var offset = $(this).offset();
// get width/height of click element
var h = $(this).outerHeight();
var w = $(this).outerWidth();
// get width/height of drop element
var dh = $dropDiv.outerHeight();
var dw = $dropDiv.outerWidth();
// determine middle position
var initLeft = offset.left + ((w/2) - (dw/2));
// animate drop
$dropDiv.css({
left: initLeft,
top: $(window).scrollTop() - dh,
opacity: 0,
display: 'block'
}).animate({
left: initLeft,
top: offset.top - dh,
opacity: 1
}, 300, 'easeOutBounce');
});
I basically want to know, is it possible to switch the click trigger to an onload call? I don't want to be muddling around trying to get it to work if it's not possible.
Thank you.
Here is an updated Fiddle. $(function() { ... }); is short for 'Document is ready'. I also wrapped the function in setTimeout();, because it was firing a little quick to see the full effect. Change the second parameter in setTimeout to adjust the time it waits to fire...
Updated (per #coby suggestion): If you do have a large amount of images you could change $(function() { to window.onload(function() {. Ready doesn't wait for all the images to be completely loaded.
Related
I want to display the popup on the top of element if there is no proper space on the top. Currently it hides inside the window as seen in the image below:
I can update the top position but I only want when there is no proper space otherwise it is ok.
Please let me know how to determine if the clicked position in near window edges.
JSFiddle Link :http://jsfiddle.net/g4g4negf/
Code I am using to get the position:
$(document).ready( function() {
$('.clickme').on('click', function(e) {
$('#popup').offset({ top: e.pageY, left: e.pageX}).fadeIn();
});
Check out this JSFiddle
To check if clicked position is near window edge, you have to get window's height ($(window).height()) and scroll position (window.pageYOffset). By adding these two values, you can find the scrolled position of the window. Then compare this sum with e.pageY+$("#popup").height() (this is the sum of the clicked position's height and the popup's height). If the latter is less than the former, it means the popup can be shown. If (e.pageY+$("#popup").height())>($(window).height()+window.pageYOffset) it means the popup will overflow the window's bottom border, then its top offset should be changed to e.pageY-$('#popup').height().
Here is the complete function:
$('.clickme').on('click', function(e) {
var h;
if((e.pageY+$('#popup').height())<($(window).height()+window.pageYOffset)) h=e.pageY;
else h=e.pageY-$('#popup').height();
$('#popup').offset({ top: h, left: e.pageX}).fadeIn();
});
Considering your popup height is 100px, you can try this...
$(document).ready( function() {
var h = window.innerHeight;
$('.clickme').on('click', function(e) {
alert(h + ", " + e.pageY);
if( h - e.pageY < 125) {
$('#popup').offset({ top: h-125, left: e.pageX}).fadeIn();
}
else {
$('#popup').offset({ top: e.pageY, left: e.pageX}).fadeIn();
}
});
});
Hey I have this really annoying issue thats probably got a simple solution but for the life of me i cant find away to fix it.
Basically i have two images both 50% with of it's container now the goal is the both images to slide in (left/right) on the basis of the scroll position and once it get to the top of the container both images will sit is place.
Now i got that working to that point the only issue is when i resize the page the position of both images are wrong. I obviously did a resize() function with the same logic as the scroll() function but still i got nowhere. Here's my code
var page_width = $(document).outerWidth(),
page_height = $(document).outerHeight(),
left_image = $('.split-screen.youth'),
right_image = $('.split-screen.elite'),
offset = (page_width) / page_height;
left_image.css({'left':'0px'});
right_image.css({'right':'0px'});
$(window).on('scroll', null, function(){
var scrollTop = $(window).scrollTop(),
calc = -(scrollTop*offset);
left_image.css({
'margin-left': 'calc(100% + '+calc+'px)'
});
right_image.css({
'margin-right': 'calc(100% + '+calc+'px)'
});
});
$(window).resize(function(){
// something ???
});
Here is a jsFiddle of the issue although it doesn't look entirely accurate but you get the picture. When you resize the scroll position changes and i need the margin-left/margin-right values to be correct.
I think your problem is that you're still using the old offset value. Just update your global values first, than it works for me (see: https://jsfiddle.net/a7tfmp37/2/):
$(window).resize(function(){
page_width = $(document).outerWidth(),
page_height = $(document).outerHeight(),
offset = (page_width) / page_height;
var scrollTop = $(window).scrollTop(),
calc = -(scrollTop*offset);
left_image.css({
'margin-left': 'calc(100% + '+calc+'px)'
});
right_image.css({
'margin-right': 'calc(100% + '+calc+'px)'
});
});
So I am trying to show a tooltip like box as I scroll my webpage and I would like it to follow the scrollbar along the right side of the page.
I looked around and found something to attempt to accomplish that as shown below:
function returnPercentHeight(){
var a = document.getElementById('rightPanel').scrollTop;
var b = document.getElementById('rightPanel').scrollHeight - document.getElementById('rightPanel').clientHeight;
return ((a/b) * 100);
}
I then append a % to the end and set the top margin of the tooltip to that returned value. This works pretty well (sort of) I have to adjust the return((a/b) * x) part (x) to make it follow the scrollbar based on the size of the browser window. Is there a better way to accomplish what I am trying to do? (NOTE: I can only use javascript, no JQuery please.)
EDIT:
Only the div given an ID of 'RightPanel' is scrolling, I am not using the scrollbar on the browser, but a scrollbar on an inner div.
There are three ways to do so:
First:
is to use the fixed position as following;
Position: Fixed;
Second:
With jQuery;
$(function(){
$(window).on('scroll', function() {
var scrollPOS = $(document).scrollTop();
$('.scroll').css({
top: scrollPOS
});
}).scroll();
});
Third:
Same as the previous, only animated;
$(window).on('scroll', function() {
$("#div").stop().animate({
"marginTop": ($(window).scrollTop()) + "px",
"marginLeft":($(window).scrollLeft()) + "px"}, "slow" );
});
Although IE doesn't support, this is the coolest I've seen:
// get
var x = window.scrollX,
y = window.scrollY;
// set
window.scrollTo(1, 2);
I have this bit of script here that takes some position:absolute elems and scrolls them along the x-axis only. It works but is super slow. Any way to speed up the performance?
(function() {
var $menu = $('.gallery-nav ul'),
$headA = $("header .home"),
leftOffset1 = parseInt($menu.css('left')),
leftOffset2 = parseInt($headA.css('left'));
$(window).scroll(function(){
$menu.css({
'left': $(this).scrollLeft() + leftOffset1
});
$headA.css({
'left': $(this).scrollLeft() + leftOffset2
});
});
})();
UPDATE: http://jsfiddle.net/davidpm/LeTEX/2/
I don't get your approach here since there is a perfect and very very speedy way only using CSS for that task.
You can simply set your element's position to fixed which means that they'll STAY AT THE POSITION regardless of document width/height or scrolling.
myElement{ position: fixed; left: 0; }
See DA new FIDDLE
The site in question is this one:
http://www.pickmixmagazine.com/wordpress/
When you click on one of the posts (any of the boxes) an iframe will slide down from the top with the content in it. Once the "Home" button in the top left hand corner of the iframe is clicked, the iframe slides back up. This works perfectly the first 2 times, on the 3rd click on of a post, the content will slide down, but when the home button is clicked, the content slides back up normally but once it has slid all the way up to the position it should be in, the iframe drops straight back down to where it was before the home button was clicked, I click it again and then it works.
Here is the code I've used for both sliding up and sliding down functions:
/* slide down function */
var $div = $('iframe.primary');
var height = $div.height();
var width = parseInt($div.width());
$div.css({ height : height });
$div.css('top', -($div.width()));
$('.post').click(function () {
$('iframe.primary').load(function(){
$div.animate({ top: 0 }, { duration: 1000 });
})
return false;
});
/* slide Up function */
var elm = parent.document.getElementsByTagName('iframe')[0];
var jelm = $(elm);//convert to jQuery Element
var htmlElm = jelm[0];//convert to HTML Element
$('.homebtn').click(function(){
$(elm).animate({ top: -height }, { duration: 1000 });
return false;
})
Have you considered using Ajax, like load(), ready() in jquery to control them better?
I am also not sure what you are trying to do with this.
var height = $div.height();
$div.css({ height : height });
may be you want to get the height of the current window? Where you can get it this way
var $dDiv = $('iframe.primary');
var innerH = window.innerHeight;
$dDiv.height(innerH);
Also try avoiding naming your custom var with default names like height, width, div, etc... You will confuse yourself and make debugging a pain.