This is my code :
var myStr = "/private_images/last-edit/image-work-med.png";
and I'd like to replace the last 7 chars (med.png) with big.png. Or, as you can see, the last occurence after a - split.
How can I do it? I think about regex, but I'm not a champion with them. Tried :
myStr = myStr .replace(/-([^-]*)$/, "big" + '$1');
but it replace the last -, not the last occurence. So the result is /private_images/last-edit/image-workbigmed.png
I'll make a confession: I'm not so great with regexes either.
How about splitting up using split? Less concise, but easier to understand.
var myStr = "/private_images/last-edit/image-work-med.png";
var strs = myStr.split('-');
// Change the last element.
strs[strs.length - 1] = "big.png";
// And put back the right string.
myStr = strs.join('-');
You could use a regex, or you could use a few string methods and make your intentions clear.
var idx = myStr.lastIndexOf("-");
var newStr = myStr.substring(0, idx) + "big.png";
Without using RegExp you could use:
var str = "/private_images/last-edit/image-work-med.png"
,replace = 'big.png'
,nwstr = str.slice(0,str.lastIndexOf('-')+1)+replace;
//=> nwstr now "/private_images/last-edit/image-work-big.png"
More 'functional':
var nwstr = function(s){
return s.replace(s.substr(-7),'');}(
'/private_images/last-edit/image-work-med.png'
)+'big.png'
var url = "/private_images/last-edit/image-work-med.png";
var index = url.lastIndexOf('-');
url = url.substring(0, index+1);
var url2 = "big.png";
var output = url.concat(url2); alert(output);
Check this
Just add '-' to your regex and to the replacement string:
myStr = myStr .replace(/-([^-]*)\.png$/, "-big.png");
Or if you want the file extension to be variable:
myStr = myStr .replace(/-([^-]*)\.([a-z]+)$/, "-big.$2");
Why not just use replace:
var myStr = "/private_images/last-edit/image-work-med.png";
var newStr = myStr.replace("med.png", "big.png");
According to the requirements specified in your question this would suffice.
If you know it will be a .png file:
var ex = new Regex(#"-\w*.png$");
var myStr = "/private_images/last-edit/image-work-med.png";
myStr = ex.Replace(myStr, "-big.png");
It works but if its a jpg it wont...
If you want to use string functions -
var myStr = "/private_images/last-edit/image-work-med.png";
var cleanedupStr = myStr.slice(0, myStr.lastIndexOf("-"));
String.slice
Related
I have a string look like:
var str = https://sharengay.com/movie13.m3u8?pid=144.21.112.0&tcp=none
I want to remove at start ?pid= to end. The result look like:
var str = https://sharengay.com/movie13.m3u8
I tried to:
str = str.replace(/^(?:?pid=)+/g, "");
But it show error like:
Invalid regular expression: /^(?:?pid=)+/: Nothing to repeat
If you really want to do this at the string level with regex, it's simply replacing /\?pid=.*$/ with "":
str = str.replace(/\?pid=.*$/, "");
That matches ?pid= and everything that follows it (.*) through the end of the string ($).
Live Example:
var str = "https://sharengay.com/movie13.m3u8?pid=144.21.112.0&tcp=none";
str = str.replace(/\?pid=.*$/, "");
console.log(str);
You can use split
var str = "https://sharengay.com/movie13.m3u8?pid=144.21.112.0&tcp=none"
var result = str.split("?pid=")[0];
console.log(result);
You can simply use split(), which i think is simple and easy.
var str = "https://sharengay.com/movie13.m3u8?pid=144.21.112.0&tcp=none";
str = str.split("?pid");
console.log(str[0]);
You may create a URL object and concatenate the origin and the pathname:
var str = "https://sharengay.com/movie13.m3u8?pid=144.21.112.0&tcp=none";
var url = new URL(str);
console.log(url.origin + url.pathname);
You have to escape the ? and if you want to remove everything from that point you also need a .+:
str = str.replace(/\?pid=.+$/, "")
You can use split function to get only url without query string.
Here is the example.
var str = 'https://sharengay.com/movie13.m3u8?pid=144.21.112.0&tcp=none';
var data = str.split("?");
alert(data[0]);
For a given URL,
/disconnect/<backend>/foo/<association_id>/
I'd like to get
/disconnect/:backend/foo/:association_id/
There could be any number of <pattern>s in a path.
Below is a regex to use with replace method
var str = '/disconnect/<backend>/foo/<association_id>/',
reg = /<([^>]+)>/g;
console.log(str.replace(reg, ":$1"));
DEMO
What about this way? Live Demo http://jsfiddle.net/d4N9s/
var mystring = "/disconnect/<backend>/foo/<association_id>/"
var middle = mystring.replace(/>/g , "")
console.log(middle.replace(/</g , ":"));
Cleaner way:
var mapO = {
'>':"",
'<':":",
};
str = mystring.replace(/<|>/gi, function(matched){
return mapO[matched];
});
console.log(str);
/<(.*?)>/g
That will match all instances of a string between < and >. You can use some simple JavaScript to replace each instance pretty easily.
http://regexr.com/3ggen
If I have a input value "a[123],b[456],c[789]" and I want to return as "a=123&b=456&c789"
I've tried below code but no luck.. Is there a correct way to implement this?
var str = "a[123],b[456],c[789]"
var string = (str).split(/\[|,|\]/);
alert(string);
One option is:
var rep = { '[': '=', ']': '', ',': '&' };
var query = str.replace(/[[,\]]/g, el => rep[el] );
The delimiters are already there, it's just a matter of replacing one delimiter with another. Replace each [ with an =, replace each , with an &, and remove all ].
var str = "a[123],b[456],c[789]"
var string = str.replace(/([a-z])\[(\d+)],?/g, '$1=$2&').slice(0, -1);
alert(string);
Brute force way im not good at Regex. Just adding my thoughts
var str = "a[123],b[456],c[789]"
str = str.replace(/],/g, '&');
str = str.replace(/\[/g, '=');
str = str.replace(/]/g,'');
alert(str);
The simple 2 line answer for this is:
str=str.replace(/,/g,"&");
str=str.replace(/(\w)\[(\d+)\]/g,"$1=$2");
12:00:00:12
How to remove 6 character from the back? the output would be 12:00, I can't use substring to get the from the front to get the 6 char, because it can be 9:00 so it's just 4 char instead of 5.
I think #ZakariaAcharki is a better solution but if you want make it by substring try this:
str = '12:00:00:12';
str.substring(0,str.length-6);
I think better if you use split() function, and take the first and second items in splited array.
var my_string ="12:00:00:12";
var array_splited = my_string.split(':');
console.log( array_splited[0] + ':' + array_splited[1] ); //12:00
If you want it in single line, e.g :
my_string.split(':')[0] + ':' + my_string.split(':')[1];
Hope this helps.
You can determine the length and than go back 6 chars e.g.
str = '12:00:00:12'
str = str.substring(0,str.length - 6);
But you may better match with
str = '12:00:00:12'.match(/^[0-9]+:[0-9]+/)[0]
A regular expression with .match() method will do:
var str1 = '12:00:00:12';
var str2 = '9:40:00:12';
var regex = /(\d+)+:+(\d\d)/g;
var newStr1 = str1.match(regex)[0];
var newStr2 = str2.match(regex)[0];
document.querySelector('#one').textContent = JSON.stringify(newStr1);
document.querySelector('#two').textContent = JSON.stringify(newStr2);
'12:00:00:12' <pre id='one'></pre>
<hr>
'9:40:00:12' <pre id='two'></pre>
var str = "12:00:00:12";
var newStrArr = str.split(":");
newStrArr.pop();
newStrArr.pop();
newStrArr.join(":");
If the time will always be in the form (0-12):(00-59);(00-59) then you could use regex and the function .match() to get the time in the format you would like:
current_time = '12:00:00'
time_formatted = current_time.match(/\d+:\d+/)
Try using split and join.
EG 1:
var num = "12:00:00:12";
console.log(num.split(':', 2).join(':'));
EG 2:
var num = "9:00:00:12";
console.log(num.split(':', 2).join(':'));
Simple and best solution:
Use slice() function.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
$(function(){
var str = '12:00:00:12';
alert(str.slice(0,-6));
});
Output: 12:00
JSFiddle Demo
I want to extract the date and the username from string using .split() in this particular string:
var str ='XxSPMxX on 08/30/2012';
I want XxSPMxX in one variable and 08/30/2012 in the other.
Using just split:
var x = str.split('</a> on ');
var name = x[0].split('>')[1];
var date = x[1];
Demo: http://jsfiddle.net/Guffa/YUaAT/
I don't think split is the right tool for this job. Try this regex:
var str ='XxSPMxX on 08/30/2012',
name = str.match(/[^><]+(?=<)/)[0],
date = str.match(/\d{2}\/\d{2}\/\d{4}/)[0];
Here's the fiddle: http://jsfiddle.net/5ve7Y/
Another way would be to match using a regular expression, build up a small array to get the parts of the anchor, and then use substring to grab the date.
var str = 'XxSPMxX on 08/30/2012';
var matches = [];
str.replace(/[^<]*(<a href="([^"]+)">([^<]+)<\/a>)/g, function () {
matches.push(Array.prototype.slice.call(arguments, 1, 4))
});
var anchorText = matches[0][2];
var theDate = str.substring(str.length - 10, str.length);
console.log(anchorText, theDate);
working example here: http://jsfiddle.net/dkA6D/