I am attempting to create a circle with a height of 10% the browser window. If I also make the width 10%, and you scale the browser, you get a misshapen or squished circle. I want to try to create the width of the circle with jquery to change in proportion with the height. so if 10% converts to 200px height, the width would be changed to 200px. I have tried a few solutions, but keep getting a width of 0px in return.
assuming you are using jQuery and your circle is an HTML element you could do this:
var $window = $(window),
$el = $('#someElement');
$window.on('resize', function () {
var size = $window.height() * 0.1;
$el.width(size).height(size);
});
Get the width and the height of the window and then simply check which one of them is the smallest. Get 10% of that value and use this as the circle's radius.
Little experiment using a transparent square image which is the direct child of <body>:
http://jsfiddle.net/2S3xU/3/
<html><body><img src="transparent-square.gif">
img {
border-radius: 99999px;
position: absolute;
top: 0; left: 0;
height: 100%; /* width will follow height to keep image undistorted*/
max-width: 100%;
max-height: 10%;
}
/* Opera fix*/
body, html {
width: 100%;
height: 100%;
}
Related
After 4 hours of trial and errors, I cannot find a way to get the width of the circle that is defined by a percent and convert it to pixels and make the circles height the same size as the width in pixels. Below is what I have right now. (I have tried many variations of this but cannot figure it out) Right now it only works on my screen. I try it on other devices and the height is just not right. This button is created onload.
Example: Circle Width = 12% , the Pixel Value of 12% on a screen is "70px". So somehow make Circle Height = 70px.
<!DOCTYPE html>
<head>
<title>Circle Test</title>
<meta charset='UTF-8'>
<script type="text/javascript" src="/js/fs"></script>
</head>
<body>
</body>
</html>
// Creates a button
var mainButton = document.createElement("button");
mainButton.style.width = "10%";
// Get the Screens Avaliable Width and Get 10% of it and convert it to pixels
var wad = screen.availWidth * .1 + "px";
// Thinking this would return the pixel amount the circle button is, but it only works on the regular screen and not when resized. It also does not work for mobile.
console.log(wad);
mainButton.style.height = wad;
You set the width of your button to 10% of its containing block's width, and the height to 10% of the width of one of
The available area of the rendering surface of the output device, in CSS pixels.
The area of the output device, in CSS pixels.
The area of the viewport, in CSS pixels.
It's very likely that these are measurements of two different things, or that resizing the window will affect one but not the other. Fortunately, CSS has a unit for "percentage of the window's width": vw. Set your button's height and width in vw units, and you don't need any JavaScript:
button {
width: 10vw;
height: 10vw;
border-radius: 50%;
}
<button>Go</button>
If you really meant that the button is 10% as wide as its container, even if its container isn't as wide as the whole window, you can use the padding-bottom technique detailed in this answer. Unlike height, percentages in padding refer to the width of the containing block:
.wrapper {
width: 40%; /* here I use 40% instead of 10% for aesthetics */
padding-bottom: 40%; /* should match width */
position: relative;
}
.wrapper > button {
display: block;
position: absolute;
width: 100%;
top: 0;
bottom: 0;
border-radius: 50%;
}
/* the rest is just to make figuring out
the exact width of the button difficult */
body {
display: flex;
align-items: stretch;
height: 90vh;
}
body > div {
flex: 1 1 0;
background: rebeccapurple;
margin: 0 4px;
}
<div>
<div class="wrapper"><button>Go</button></div>
</div>
<div></div>
<div></div>
And finally, just for completeness, if you really must get the computed width from JavaScript, you can use window.getComputedStyle:
let button = document.querySelector('button');
let width = window
.getComputedStyle(button)
.getPropertyValue('width');
console.log(button.style.height = /* DO NOT DO THIS */ width);
button {
width: 40%;
border-radius: 50%;
}
/* the rest is just to make figuring out
the exact width of the button difficult */
body {
display: flex;
align-items: stretch;
height: 90vh;
}
body > div {
flex: 1 1 0;
background: rebeccapurple;
margin: 0 4px;
}
<div>
<button>Go</button>
</div>
<div></div>
<div></div>
If you try putting that into a resize handler, though, performance will suffer.
In bootstrap I have a fixed top nav bar and fixed bottom nav bar. I want to show a large image in the background between the space of those two nav bars and I also want to cover the width of the window. How can I dynamically get the height between the navbars and the width of the window? The window size may change depending on device.So I need it dynamic
Requires jquery:
var viewport = {
width : $(window).width(),
height : $(window).height()
};
//can access dimensions like this:
//viewport.height
Though you won't always get perfect results, different devices behave differently and this gives the viewport dimensions, not the screen dimensions.
Alternatively you could check the width of a data-role="page" element to find the device-width (since it's set to 100% of the device-width):
var deviceWidth = 0;
$(window).bind('resize', function () {
deviceWidth = $('[data-role="page"]').first().width();
}).trigger('resize');
$(window).resize(function() {
var top_nav_height = $("#id_of_top_nav").height();
var bottom_nav_height = $("#id_of_bottom_nav").height();
var window_height = $(window).height();
var height_of_open_space = window_height - (top_nav_height+bottom_nav_height);
$("#id_of_img").css({
height:height_of_open_space+'px';
});
});
this will be fine with if 0px padding and margin, if not also get that values and subtract from height_of_open_space before applying to img height
It is a bit hard to tell without seeing any of your markup, but it should be feasable with pure css. I set up a very basic example to demonstrate:
http://codepen.io/anon/pen/XbGJJO
HTML:
<div class='top'>
top navbar
</div>
<div class='content'>
<p> some content </p>
</div>
<div class='bottom'>
bottom navbar
</div>
CSS:
.top, .bottom {
height: 40px;
background: red;
position: fixed;
width: 100%;
}
.top {
top: 0;
}
.bottom {
bottom: 0;
}
.content {
margin: 40px 0;
min-height: calc(100vh - 80px);
background: green; /* background goes here */
}
The trick lies in the following line:
min-height: calc(100vh - 80px);
This tells your content to at least take up 100% of the vertical height, minus the height of the top and bottom bar. Let me know if you want me to explain further.
I have grid like this and my sidebar take 4 of 12 col near to 33.3% and my sidebar is parent element
$susy: (
columns : 12,
gutters : 1/1.618033989/1.618033989/1.618033989,
math : fluid,
output : float,
gutter-position : inside,
);
#include border-box-sizing;
.sidebar {
height: 100vh;
#include span(4);
}
and I have div tag in my side bar and width of child is 100% of parent, now I want height of child be width of parent*number
I have tried some thing like this
width: 33.3333vw;
height:20.601112354vw;
but that work when we are out of grid when there is no parent element
and I have tried this
#container {
display: inline-block;
position: relative;
width: 50%;
}
#dummy {
margin-top: 75%; /* 4:3 aspect ratio */
}
#element {
position: absolute;
top: 0;
bottom: 0;
left: 0;
right: 0;
background-color: silver /* show me! */
}
but there is many bugs in this method like you put 2 or more div tag in child and working with this should be full of tricks
I want some method that simply get width of parent and multiply that and make that height of child element.so when we resizing browser when width of parent get change -> height of child get change
var width = $('.child').width();
var parentWidth = $('.sidebar').width();
var ratio = parentWidth/1.618033989;
$(".child").height(ratio);
$( window ).resize(function() {
var width = $('.child').width();
var parentWidth = $('.sidebar').width();
var ratio = parentWidth/1.618033989;
$(".child").height(ratio);
I've got a background video playing on a web page, and this CSS;
#video_background {
position: fixed;
width: 100%;
height: 100%;
margin: 0px;
padding: 0px;
top: 0px;
left: 0px;
z-index: -1000;
overflow: hidden;
}
..is keeping it centered, like I want it to, but it's keeping all of the edges within the browser window, rather than always being full-bleed. I'm trying to replicate what this site is doing;
http://marisapassos.com/#home
This site appears to have two sets of rules, one on a div that contains the video, and one on the video itself. Could someone explain to me why that works and what I'm doing doesn't? Is there also js working to keep the video on the linked site centered?
Yes, look at the video_background.js in the source of the website you linked to, specifically at the $(window).resize function:
$(window).resize(function() {
var windowWidth = $(window).width();
var windowHeight = $(window).height();
var width;
var height;
//size
width = windowWidth;
height = width*formH/formW;
if(height<windowHeight){
height = windowHeight;
width = formW*height/formH;
}
$div_holder.css("width", width);
$div_holder.css("height", height);
$div_holder.css("left", windowWidth/2-width/2);
$div_holder.css("top", windowHeight/2-height/2);
});
Left and top are defined in terms of both the windowWidth and (video) width which keeps the video centered.
Is there a way (without binding to the window.resize event) to force a floating DIV to re-center itself when the browser window is resized?
To help explain, I imagine the pseudocode would look something like:
div.left = 50% - (div.width / 2)
div.top = 50% - (div.height / 2)
UPDATE
My query having been answered below, I wanted to post the final outcome of my quest - a jQuery extension method allowing you to center any block element - hope it helps someone else too.
jQuery.fn.center = function() {
var container = $(window);
var top = -this.height() / 2;
var left = -this.width() / 2;
return this.css('position', 'absolute').css({ 'margin-left': left + 'px', 'margin-top': top + 'px', 'left': '50%', 'top': '50%' });
}
Usage:
$('#mydiv').center();
This is easy to do with CSS if you have a fixed-size div:
.keepcentered {
position: absolute;
left: 50%; /* Start with top left in the center */
top: 50%;
width: 200px; /* The fixed width... */
height: 100px; /* ...and height */
margin-left: -100px; /* Shift over half the width */
margin-top: -50px; /* Shift up half the height */
border: 1px solid black; /* Just for demo */
}
The problem, of course, is that fixed-size elements aren't ideal.
The simplest way would be with the following CSS code:
#floating-div {
width: 50%;
border: 1px solid gray;
margin: 0 auto;
}
The key line of CSS code above is the "margin: 0 auto;" which tells the browser to automatically set the left/right margins to keep the div centered on the page, even when you resize the browser window.
Try this little article about Horizontal and Vertical centering. It is a little old and has a few hacks but you should be able to work out some test code from it.