I would like to convert a number in base 10 with fraction to a number in base 16.
var myno = 28.5;
var convno = myno.toString(16);
alert(convno);
All is well there. Now I want to convert it back to decimal.
But now I cannot write:
var orgno = parseInt(convno, 16);
alert(orgno);
As it doesn't return the decimal part.
And I cannot use parseFloat, since per MDC, the syntax of parseFloat is
parseFloat(str);
It wouldn't have been a problem if I had to convert back to int, since parseInt's syntax is
parseInt(str [, radix]);
So what is an alternative for this?
Disclaimer: I thought it was a trivial question, but googling didn't give me any answers.
This question made me ask the above question.
Another possibility is to parse the digits separately, splitting the string up in two and treating both parts as ints during the conversion and then add them back together.
function parseFloat(str, radix)
{
var parts = str.split(".");
if ( parts.length > 1 )
{
return parseInt(parts[0], radix) + parseInt(parts[1], radix) / Math.pow(radix, parts[1].length);
}
return parseInt(parts[0], radix);
}
var myno = 28.4382;
var convno = myno.toString(16);
var f = parseFloat(convno, 16);
console.log(myno + " -> " + convno + " -> " + f);
Try this.
The string may be raw data (simple text) with four characters (0 - 255) or
a hex string "0xFFFFFFFF" four bytes in length.
jsfiddle.net
var str = '0x3F160008';
function parseFloat(str) {
var float = 0, sign, order, mantissa, exp,
int = 0, multi = 1;
if (/^0x/.exec(str)) {
int = parseInt(str, 16);
}
else {
for (var i = str.length -1; i >=0; i -= 1) {
if (str.charCodeAt(i) > 255) {
console.log('Wrong string parameter');
return false;
}
int += str.charCodeAt(i) * multi;
multi *= 256;
}
}
sign = (int >>> 31) ? -1 : 1;
exp = (int >>> 23 & 0xff) - 127;
mantissa = ((int & 0x7fffff) + 0x800000).toString(2);
for (i=0; i<mantissa.length; i+=1) {
float += parseInt(mantissa[i]) ? Math.pow(2, exp) : 0;
exp--;
}
return float*sign;
}
Please try this:
function hex2dec(hex) {
hex = hex.split(/\./);
var len = hex[1].length;
hex[1] = parseInt(hex[1], 16);
hex[1] *= Math.pow(16, -len);
return parseInt(hex[0], 16) + hex[1];
}
function hex2dec(hex) {
hex = hex.split(/\./);
var len = hex[1].length;
hex[1] = parseInt(hex[1], 16);
hex[1] *= Math.pow(16, -len);
return parseInt(hex[0], 16) + hex[1];
}
// ----------
// TEST
// ----------
function calc(hex) {
let dec = hex2dec(hex);
msg.innerHTML = `dec: <b>${dec}</b><br>hex test: <b>${dec.toString(16)}</b>`
}
let init="bad.a55";
inp.value=init;
calc(init);
<input oninput="calc(this.value)" id="inp" /><div id="msg"></div>
I combined Mark's and Kent's answers to make an overloaded parseFloat function that takes an argument for the radix (much simpler and more versatile):
function parseFloat(string, radix)
{
// Split the string at the decimal point
string = string.split(/\./);
// If there is nothing before the decimal point, make it 0
if (string[0] == '') {
string[0] = "0";
}
// If there was a decimal point & something after it
if (string.length > 1 && string[1] != '') {
var fractionLength = string[1].length;
string[1] = parseInt(string[1], radix);
string[1] *= Math.pow(radix, -fractionLength);
return parseInt(string[0], radix) + string[1];
}
// If there wasn't a decimal point or there was but nothing was after it
return parseInt(string[0], radix);
}
Try this:
Decide how many digits of precision you need after the decimal point.
Multiply your original number by that power of 16 (e.g. 256 if you want two digits).
Convert it as an integer.
Put the decimal point in manually according to what you decided in step 1.
Reverse the steps to convert back.
Take out the decimal point, remembering where it was.
Convert the hex to decimal in integer form.
Divide the result by the the appropriate power of 16 (16^n, where n is the number of digits after the decimal point you took out in step 1).
A simple example:
Convert decimal 23.5 into hex, and want one digit after the decimal point after conversion.
23.5 x 16 = 376.
Converted to hex = 0x178.
Answer in base 16: 17.8
Now convert back to decimal:
Take out the decimal point: 0x178
Convert to decimal: 376
Divide by 16: 23.5
I'm not sure what hexadecimal format you wanted to parse there. Was this something like: "a1.2c"?
Floats are commonly stored in hexadecimal format using the IEEE 754 standard. That standard doesn't use any dots (which don't exist in pure hexadecimal alphabet). Instead of that there are three groups of bits of predefined length (1 + 8 + 23 = 32 bits in total ─ double uses 64 bits).
I've written the following function for parsing such a numbers into float:
function hex2float(num) {
var sign = (num & 0x80000000) ? -1 : 1;
var exponent = ((num >> 23) & 0xff) - 127;
var mantissa = 1 + ((num & 0x7fffff) / 0x7fffff);
return sign * mantissa * Math.pow(2, exponent);
}
Here is a size-improvement of Mark Eirich's answer:
function hex2dec(hex) {
let h = hex.split(/\./);
return ('0x'+h[1])*(16**-h[1].length)+ +('0x'+h[0]);
}
function hex2dec(hex) {
let h = hex.split(/\./);
return ('0x'+h[1])*(16**-h[1].length)+ +('0x'+h[0]);
}
function calc(hex) {
let dec = hex2dec(hex);
msg.innerHTML = `dec: <b>${dec}</b><br>hex test: <b>${dec.toString(16)}</b>`
}
let init = "bad.a55";
inp.value = init;
calc(init);
<input oninput="calc(this.value)" id="inp" /><div id="msg"></div>
private hexStringToFloat(hexString: string): number {
return Buffer.from(hexString, 'hex').readFloatBE(0);
}
Someone might find this useful.
bytes to Float32
function Int2Float32(bytes) {
var sign = (bytes & 0x80000000) ? -1 : 1;
var exponent = ((bytes >> 23) & 0xFF) - 127;
var significand = (bytes & ~(-1 << 23));
if (exponent == 128)
return sign * ((significand) ? Number.NaN : Number.POSITIVE_INFINITY);
if (exponent == -127) {
if (significand === 0) return sign * 0.0;
exponent = -126;
significand /= (1 << 22);
} else significand = (significand | (1 << 23)) / (1 << 23);
return sign * significand * Math.pow(2, exponent);
}
Related
in JavaScript, the typical way to round a number to N decimal places is something like:
function roundNumber(num, dec) {
return Math.round(num * Math.pow(10, dec)) / Math.pow(10, dec);
}
function roundNumber(num, dec) {
return Math.round(num * Math.pow(10, dec)) / Math.pow(10, dec);
}
console.log(roundNumber(0.1 + 0.2, 2));
console.log(roundNumber(2.1234, 2));
However this approach will round to a maximum of N decimal places while I want to always round to N decimal places. For example "2.0" would be rounded to "2".
Any ideas?
I think that there is a more simple approach to all given here, and is the method Number.toFixed() already implemented in JavaScript.
simply write:
var myNumber = 2;
myNumber.toFixed(2); //returns "2.00"
myNumber.toFixed(1); //returns "2.0"
etc...
I found a way. This is Christoph's code with a fix:
function toFixed(value, precision) {
var precision = precision || 0,
power = Math.pow(10, precision),
absValue = Math.abs(Math.round(value * power)),
result = (value < 0 ? '-' : '') + String(Math.floor(absValue / power));
if (precision > 0) {
var fraction = String(absValue % power),
padding = new Array(Math.max(precision - fraction.length, 0) + 1).join('0');
result += '.' + padding + fraction;
}
return result;
}
Read the details of repeating a character using an array constructor here if you are curious as to why I added the "+ 1".
That's not a rounding ploblem, that is a display problem. A number doesn't contain information about significant digits; the value 2 is the same as 2.0000000000000. It's when you turn the rounded value into a string that you have make it display a certain number of digits.
You could just add zeroes after the number, something like:
var s = number.toString();
if (s.indexOf('.') == -1) s += '.';
while (s.length < s.indexOf('.') + 4) s += '0';
(Note that this assumes that the regional settings of the client uses period as decimal separator, the code needs some more work to function for other settings.)
There's always a better way for doing things. Use toPrecision -
var number = 51.93999999999761;
I would like to get four digits precision: 51.94
just do:
number.toPrecision(4);
the result will be: 51.94
This works for rounding to N digits (if you just want to truncate to N digits remove the Math.round call and use the Math.trunc one):
function roundN(value, digits) {
var tenToN = 10 ** digits;
return /*Math.trunc*/(Math.round(value * tenToN)) / tenToN;
}
Had to resort to such logic at Java in the past when I was authoring data manipulation E-Slate components. That is since I had found out that adding 0.1 many times to 0 you'd end up with some unexpectedly long decimal part (this is due to floating point arithmetics).
A user comment at Format number to always show 2 decimal places calls this technique scaling.
Some mention there are cases that don't round as expected and at http://www.jacklmoore.com/notes/rounding-in-javascript/ this is suggested instead:
function round(value, decimals) {
return Number(Math.round(value+'e'+decimals)+'e-'+decimals);
}
PHP-Like rounding Method
The code below can be used to add your own version of Math.round to your own namespace which takes a precision parameter. Unlike Decimal rounding in the example above, this performs no conversion to and from strings, and the precision parameter works same way as PHP and Excel whereby a positive 1 would round to 1 decimal place and -1 would round to the tens.
var myNamespace = {};
myNamespace.round = function(number, precision) {
var factor = Math.pow(10, precision);
var tempNumber = number * factor;
var roundedTempNumber = Math.round(tempNumber);
return roundedTempNumber / factor;
};
myNamespace.round(1234.5678, 1); // 1234.6
myNamespace.round(1234.5678, -1); // 1230
from Mozilla Developer reference for Math.round()
Hopefully working code (didn't do much testing):
function toFixed(value, precision) {
var precision = precision || 0,
neg = value < 0,
power = Math.pow(10, precision),
value = Math.round(value * power),
integral = String((neg ? Math.ceil : Math.floor)(value / power)),
fraction = String((neg ? -value : value) % power),
padding = new Array(Math.max(precision - fraction.length, 0) + 1).join('0');
return precision ? integral + '.' + padding + fraction : integral;
}
I think below function can help
function roundOff(value,round) {
return (parseInt(value * (10 ** (round + 1))) - parseInt(value * (10 ** round)) * 10) > 4 ? (((parseFloat(parseInt((value + parseFloat(1 / (10 ** round))) * (10 ** round))))) / (10 ** round)) : (parseFloat(parseInt(value * (10 ** round))) / ( 10 ** round));
}
usage : roundOff(600.23458,2); will return 600.23
function roundton(num, n) {
return Number(num.toFixed(n));
}
This uses JS's built-in method Number.prototype.toFixed which is meant for formatting strings but allows us to round to a specific number of digits. the Number() call converts it back to a number object cleanly
Ideally, we wouldn't need to convert it to a string, but toFixed is written in native C++ doing basic cstring operations so it's likely still fast.
If you do not really care about rounding, just added a toFixed(x) and then removing trailing 0es and the dot if necessary. It is not a fast solution.
function format(value, decimals) {
if (value) {
value = value.toFixed(decimals);
} else {
value = "0";
}
if (value.indexOf(".") < 0) { value += "."; }
var dotIdx = value.indexOf(".");
while (value.length - dotIdx <= decimals) { value += "0"; } // add 0's
return value;
}
I need to convert this hex "46b76833" to float, and I need to get this value 23476.1
I written a code to get hex and everything else but this step I don't know how to do, can someone help me? Thanks in advance!
I tried something like this but it doesn't work.
function hexToFloat(hex) {
var s = hex >> 31 ? -1 : 1;
var e = (hex >> 23) & 0xFF;
var rez = s * (hex & 0x7fffff | 0x800000) * 1.0 / Math.pow(2, 23) * Math.pow(2, (e - 127));
return rez
}
You're nearly there, we just need to convert the hex string to a number before we tranform to a float.
The MSB is the sign, the following 8 bits are the exponent, then the last 23 bits represent the fraction of the number.
This is an IEEE Single Precision floating point number, there are more details here
function hexStringToFloat(hexString) {
const hex = parseInt(hexString, 16);
const sign = hex >> 31 ? -1 : 1;
const exponent = (hex >> 23) & 0xFF;
return sign * (hex & 0x7fffff | 0x800000) * 1.0 / Math.pow(2, 23) * Math.pow(2, (exponent - 127));
}
console.log("Result:", hexStringToFloat("46b76833"));
Is there any way I can read bytes of a float value in JS? What I need is to write a raw FLOAT or DOUBLE value into some binary format I need to make, so is there any way to get a byte-by-byte IEEE 754 representation? And same question for writing of course.
You can do it with typed arrays:
var buffer = new ArrayBuffer(4);
var intView = new Int32Array(buffer);
var floatView = new Float32Array(buffer);
floatView[0] = Math.PI
console.log(intView[0].toString(2)); //bits of the 32 bit float
Or another way:
var view = new DataView(new ArrayBuffer(4));
view.setFloat32(0, Math.PI);
console.log(view.getInt32(0).toString(2)); //bits of the 32 bit float
Not sure what browser support is like though
I've created an expansion of Miloš's solution that should be a bit faster, assuming TypedArrays are not an option of course (in my case I'm working with an environment where they're not available):
function Bytes2Float32(bytes) {
var sign = (bytes & 0x80000000) ? -1 : 1;
var exponent = ((bytes >> 23) & 0xFF) - 127;
var significand = (bytes & ~(-1 << 23));
if (exponent == 128)
return sign * ((significand) ? Number.NaN : Number.POSITIVE_INFINITY);
if (exponent == -127) {
if (significand == 0) return sign * 0.0;
exponent = -126;
significand /= (1 << 22);
} else significand = (significand | (1 << 23)) / (1 << 23);
return sign * significand * Math.pow(2, exponent);
}
Given an integer containing 4 bytes holding an IEEE-754 32-bit single precision float, this will produce the (roughly) correct JavaScript number value without using any loops.
Koolinc's snippet is good if you need a solution that powerful, but if you need it for limited use you are better off writing your own code. I wrote the following function for converting a string hex representation of bytes to a float:
function decodeFloat(data) {
var binary = parseInt(data, 16).toString(2);
if (binary.length < 32)
binary = ('00000000000000000000000000000000'+binary).substr(binary.length);
var sign = (binary.charAt(0) == '1')?-1:1;
var exponent = parseInt(binary.substr(1, 8), 2) - 127;
var significandBase = binary.substr(9);
var significandBin = '1'+significandBase;
var i = 0;
var val = 1;
var significand = 0;
if (exponent == -127) {
if (significandBase.indexOf('1') == -1)
return 0;
else {
exponent = -126;
significandBin = '0'+significandBase;
}
}
while (i < significandBin.length) {
significand += val * parseInt(significandBin.charAt(i));
val = val / 2;
i++;
}
return sign * significand * Math.pow(2, exponent);
}
There are detailed explanations of algorithms used to convert in both directions for all formats of floating points on wikipedia, and it is easy to use those to write your own code. Converting from a number to bytes should be more difficult because you need to normalize the number first.
I had a similar problem, I wanted to convert any javascript number to a Buffer and then parse it back without stringifying it.
function numberToBuffer(num) {
const buf = new Buffer(8)
buf.writeDoubleLE(num, 0)
return buf
}
Use example:
// convert a number to buffer
const buf = numberToBuffer(3.14)
// and then from a Buffer
buf.readDoubleLE(0) === 3.14
This works on current Node LTS (4.3.1) and up. didn't test in lower versions.
Would this snippet help?
var parser = new BinaryParser
,forty = parser.encodeFloat(40.0,2,8)
,twenty = parser.encodeFloat(20.0,2,8);
console.log(parser.decodeFloat(forty,2,8).toFixed(1)); //=> 40.0
console.log(parser.decodeFloat(twenty,2,8).toFixed(1)); //=> 20.0
I expect you could figure it out (blech), but I assume you're asking if there's something built-in. Not as far as I've ever heard; see sections 8.5 and 15.7 of the spec.
64-bit IEEE 754 float to its binary representation and back:
// float64ToOctets(123.456) -> [64, 94, 221, 47, 26, 159, 190, 119]
function float64ToOctets(number) {
const buffer = new ArrayBuffer(8);
new DataView(buffer).setFloat64(0, number, false);
return [].slice.call(new Uint8Array(buffer));
}
// octetsToFloat64([64, 94, 221, 47, 26, 159, 190, 119]) -> 123.456
function octetsToFloat64(octets) {
const buffer = new ArrayBuffer(8);
new Uint8Array(buffer).set(octets);
return new DataView(buffer).getFloat64(0, false);
}
// intToBinaryString(8) -> "00001000"
function intToBinaryString(i, length) {
return i.toString(2).padStart(8, "0");
}
// binaryStringToInt("00001000") -> 8
function binaryStringToInt(b) {
return parseInt(b, 2);
}
function octetsToBinaryString(octets) {
return octets.map((i) => intToBinaryString(i)).join("");
}
function float64ToBinaryString(number) {
return octetsToBinaryString(float64ToOctets(number));
}
function binaryStringToFloat64(string) {
return octetsToFloat64(string.match(/.{8}/g).map(binaryStringToInt));
}
console.log(float64ToBinaryString(123.123))
console.log(binaryStringToFloat64(float64ToBinaryString(123.123)))
console.log(binaryStringToFloat64(float64ToBinaryString(123.123)) === 123.123)
This is a slightly modified version this MIT-licensed code: https://github.com/bartaz/ieee754-visualization/blob/master/src/ieee754.js
Is there any way I can read bytes of a float value in JS? What I need is to write a raw FLOAT or DOUBLE value into some binary format I need to make, so is there any way to get a byte-by-byte IEEE 754 representation? And same question for writing of course.
You can do it with typed arrays:
var buffer = new ArrayBuffer(4);
var intView = new Int32Array(buffer);
var floatView = new Float32Array(buffer);
floatView[0] = Math.PI
console.log(intView[0].toString(2)); //bits of the 32 bit float
Or another way:
var view = new DataView(new ArrayBuffer(4));
view.setFloat32(0, Math.PI);
console.log(view.getInt32(0).toString(2)); //bits of the 32 bit float
Not sure what browser support is like though
I've created an expansion of Miloš's solution that should be a bit faster, assuming TypedArrays are not an option of course (in my case I'm working with an environment where they're not available):
function Bytes2Float32(bytes) {
var sign = (bytes & 0x80000000) ? -1 : 1;
var exponent = ((bytes >> 23) & 0xFF) - 127;
var significand = (bytes & ~(-1 << 23));
if (exponent == 128)
return sign * ((significand) ? Number.NaN : Number.POSITIVE_INFINITY);
if (exponent == -127) {
if (significand == 0) return sign * 0.0;
exponent = -126;
significand /= (1 << 22);
} else significand = (significand | (1 << 23)) / (1 << 23);
return sign * significand * Math.pow(2, exponent);
}
Given an integer containing 4 bytes holding an IEEE-754 32-bit single precision float, this will produce the (roughly) correct JavaScript number value without using any loops.
Koolinc's snippet is good if you need a solution that powerful, but if you need it for limited use you are better off writing your own code. I wrote the following function for converting a string hex representation of bytes to a float:
function decodeFloat(data) {
var binary = parseInt(data, 16).toString(2);
if (binary.length < 32)
binary = ('00000000000000000000000000000000'+binary).substr(binary.length);
var sign = (binary.charAt(0) == '1')?-1:1;
var exponent = parseInt(binary.substr(1, 8), 2) - 127;
var significandBase = binary.substr(9);
var significandBin = '1'+significandBase;
var i = 0;
var val = 1;
var significand = 0;
if (exponent == -127) {
if (significandBase.indexOf('1') == -1)
return 0;
else {
exponent = -126;
significandBin = '0'+significandBase;
}
}
while (i < significandBin.length) {
significand += val * parseInt(significandBin.charAt(i));
val = val / 2;
i++;
}
return sign * significand * Math.pow(2, exponent);
}
There are detailed explanations of algorithms used to convert in both directions for all formats of floating points on wikipedia, and it is easy to use those to write your own code. Converting from a number to bytes should be more difficult because you need to normalize the number first.
I had a similar problem, I wanted to convert any javascript number to a Buffer and then parse it back without stringifying it.
function numberToBuffer(num) {
const buf = new Buffer(8)
buf.writeDoubleLE(num, 0)
return buf
}
Use example:
// convert a number to buffer
const buf = numberToBuffer(3.14)
// and then from a Buffer
buf.readDoubleLE(0) === 3.14
This works on current Node LTS (4.3.1) and up. didn't test in lower versions.
Would this snippet help?
var parser = new BinaryParser
,forty = parser.encodeFloat(40.0,2,8)
,twenty = parser.encodeFloat(20.0,2,8);
console.log(parser.decodeFloat(forty,2,8).toFixed(1)); //=> 40.0
console.log(parser.decodeFloat(twenty,2,8).toFixed(1)); //=> 20.0
I expect you could figure it out (blech), but I assume you're asking if there's something built-in. Not as far as I've ever heard; see sections 8.5 and 15.7 of the spec.
64-bit IEEE 754 float to its binary representation and back:
// float64ToOctets(123.456) -> [64, 94, 221, 47, 26, 159, 190, 119]
function float64ToOctets(number) {
const buffer = new ArrayBuffer(8);
new DataView(buffer).setFloat64(0, number, false);
return [].slice.call(new Uint8Array(buffer));
}
// octetsToFloat64([64, 94, 221, 47, 26, 159, 190, 119]) -> 123.456
function octetsToFloat64(octets) {
const buffer = new ArrayBuffer(8);
new Uint8Array(buffer).set(octets);
return new DataView(buffer).getFloat64(0, false);
}
// intToBinaryString(8) -> "00001000"
function intToBinaryString(i, length) {
return i.toString(2).padStart(8, "0");
}
// binaryStringToInt("00001000") -> 8
function binaryStringToInt(b) {
return parseInt(b, 2);
}
function octetsToBinaryString(octets) {
return octets.map((i) => intToBinaryString(i)).join("");
}
function float64ToBinaryString(number) {
return octetsToBinaryString(float64ToOctets(number));
}
function binaryStringToFloat64(string) {
return octetsToFloat64(string.match(/.{8}/g).map(binaryStringToInt));
}
console.log(float64ToBinaryString(123.123))
console.log(binaryStringToFloat64(float64ToBinaryString(123.123)))
console.log(binaryStringToFloat64(float64ToBinaryString(123.123)) === 123.123)
This is a slightly modified version this MIT-licensed code: https://github.com/bartaz/ieee754-visualization/blob/master/src/ieee754.js
in JavaScript, the typical way to round a number to N decimal places is something like:
function roundNumber(num, dec) {
return Math.round(num * Math.pow(10, dec)) / Math.pow(10, dec);
}
function roundNumber(num, dec) {
return Math.round(num * Math.pow(10, dec)) / Math.pow(10, dec);
}
console.log(roundNumber(0.1 + 0.2, 2));
console.log(roundNumber(2.1234, 2));
However this approach will round to a maximum of N decimal places while I want to always round to N decimal places. For example "2.0" would be rounded to "2".
Any ideas?
I think that there is a more simple approach to all given here, and is the method Number.toFixed() already implemented in JavaScript.
simply write:
var myNumber = 2;
myNumber.toFixed(2); //returns "2.00"
myNumber.toFixed(1); //returns "2.0"
etc...
I found a way. This is Christoph's code with a fix:
function toFixed(value, precision) {
var precision = precision || 0,
power = Math.pow(10, precision),
absValue = Math.abs(Math.round(value * power)),
result = (value < 0 ? '-' : '') + String(Math.floor(absValue / power));
if (precision > 0) {
var fraction = String(absValue % power),
padding = new Array(Math.max(precision - fraction.length, 0) + 1).join('0');
result += '.' + padding + fraction;
}
return result;
}
Read the details of repeating a character using an array constructor here if you are curious as to why I added the "+ 1".
That's not a rounding ploblem, that is a display problem. A number doesn't contain information about significant digits; the value 2 is the same as 2.0000000000000. It's when you turn the rounded value into a string that you have make it display a certain number of digits.
You could just add zeroes after the number, something like:
var s = number.toString();
if (s.indexOf('.') == -1) s += '.';
while (s.length < s.indexOf('.') + 4) s += '0';
(Note that this assumes that the regional settings of the client uses period as decimal separator, the code needs some more work to function for other settings.)
There's always a better way for doing things. Use toPrecision -
var number = 51.93999999999761;
I would like to get four digits precision: 51.94
just do:
number.toPrecision(4);
the result will be: 51.94
This works for rounding to N digits (if you just want to truncate to N digits remove the Math.round call and use the Math.trunc one):
function roundN(value, digits) {
var tenToN = 10 ** digits;
return /*Math.trunc*/(Math.round(value * tenToN)) / tenToN;
}
Had to resort to such logic at Java in the past when I was authoring data manipulation E-Slate components. That is since I had found out that adding 0.1 many times to 0 you'd end up with some unexpectedly long decimal part (this is due to floating point arithmetics).
A user comment at Format number to always show 2 decimal places calls this technique scaling.
Some mention there are cases that don't round as expected and at http://www.jacklmoore.com/notes/rounding-in-javascript/ this is suggested instead:
function round(value, decimals) {
return Number(Math.round(value+'e'+decimals)+'e-'+decimals);
}
PHP-Like rounding Method
The code below can be used to add your own version of Math.round to your own namespace which takes a precision parameter. Unlike Decimal rounding in the example above, this performs no conversion to and from strings, and the precision parameter works same way as PHP and Excel whereby a positive 1 would round to 1 decimal place and -1 would round to the tens.
var myNamespace = {};
myNamespace.round = function(number, precision) {
var factor = Math.pow(10, precision);
var tempNumber = number * factor;
var roundedTempNumber = Math.round(tempNumber);
return roundedTempNumber / factor;
};
myNamespace.round(1234.5678, 1); // 1234.6
myNamespace.round(1234.5678, -1); // 1230
from Mozilla Developer reference for Math.round()
Hopefully working code (didn't do much testing):
function toFixed(value, precision) {
var precision = precision || 0,
neg = value < 0,
power = Math.pow(10, precision),
value = Math.round(value * power),
integral = String((neg ? Math.ceil : Math.floor)(value / power)),
fraction = String((neg ? -value : value) % power),
padding = new Array(Math.max(precision - fraction.length, 0) + 1).join('0');
return precision ? integral + '.' + padding + fraction : integral;
}
I think below function can help
function roundOff(value,round) {
return (parseInt(value * (10 ** (round + 1))) - parseInt(value * (10 ** round)) * 10) > 4 ? (((parseFloat(parseInt((value + parseFloat(1 / (10 ** round))) * (10 ** round))))) / (10 ** round)) : (parseFloat(parseInt(value * (10 ** round))) / ( 10 ** round));
}
usage : roundOff(600.23458,2); will return 600.23
function roundton(num, n) {
return Number(num.toFixed(n));
}
This uses JS's built-in method Number.prototype.toFixed which is meant for formatting strings but allows us to round to a specific number of digits. the Number() call converts it back to a number object cleanly
Ideally, we wouldn't need to convert it to a string, but toFixed is written in native C++ doing basic cstring operations so it's likely still fast.
If you do not really care about rounding, just added a toFixed(x) and then removing trailing 0es and the dot if necessary. It is not a fast solution.
function format(value, decimals) {
if (value) {
value = value.toFixed(decimals);
} else {
value = "0";
}
if (value.indexOf(".") < 0) { value += "."; }
var dotIdx = value.indexOf(".");
while (value.length - dotIdx <= decimals) { value += "0"; } // add 0's
return value;
}