I am having some difficulty trying to get my Fade In and out effect working properly. I think I am over complicating it.
I have 4 images, however only the first 2 need to be faded out and in on hover of the image (The other 2 images come into play with some other feature on the page).
My HTML is:
<div class="square">
<div class="imageHolder">
<!--Comment out and uncomment BG image to show transitions on BG images-->
<img class="one" src="image_01.jpg" />
<img class="two" src="image_02.jpg" />
<img class="three" src="image_03.jpg" />
<img class="four" src="image_04.jpg" />
</div>
</div>
Images, two, three, four are displayed none
JS:
$('.square').mouseover(function () {
$(this).find('img').each(function () {
if ($(this).attr('class') === 'two') {
$(this).fadeIn('slow');
}
if ($(this).attr('class') === 'one') {
$(this).fadeOut('slow');
}
});
});
Any help would be much appreciated.
Thanks for the responses.
I was trying to be too clever and it didn't need it. Is there a way for the the fadein and out to happen simultaneously without the use for a plugin?
Why do the each and not just selected them?
var imgs = $(this).find("img");
imgs.filter(".one").fadeOut('slow');
imgs.filter(".two").fadeIn('slow');
or
var imgs = $(this);
imgs.find(".one").fadeOut('slow');
imgs.find(".two").fadeIn('slow');
Try to do it like this:
$(".one").fadeIn("slow", function() { $(this).fadeOut("slow") });
$(".two").fadeIn("slow", function() { $(this).fadeOut("slow") });
Update:
I misread you question and thought you want both to fade in and out. To make the first one fade in and the second fade out use something like this:
$(".one").fadeIn("slow");
$(".two").fadeOut("slow");
If you have other elements with one and two classes and don't want to affect them, you can type $(".imageHolder .one") and $(".imageHolder .two") instead of $(".one") and $(".two").
If you have multiple imageHolder elements on your page, use find() function as suggested by epascarello or sushanth reddy.
You do not need a .each loop .. Just find the img inside the div and do your operations on it
Try this instead..
$('.square').mouseover(function() {
$(this).find('.two').fadeIn('slow');
$(this).find('.one').fadeOut('slow');
});
Check FIDDLE
I think this is what you're looking for:
$('.square img')
.mouseover(function () {
$(this).fadeIn('slow');
})
.mouseout(function () {
$(this).fadeOut('slow');
});
I think you will better use jquery.hoverIntent.js. It will create a little delay time when you will move your cursor rapidly over the different images.
an example
$(document).ready(function(){
var config = {
interval: 230,
over: zoomIn,
out: zoomOut
};
$("div#clients_wrap div").hoverIntent(config);
});
zoomIn en zoomOut are functions, you could declare them with an fadein, fadeout respectively. This is just an improvement.
Basically assign a class to the group of images that need to fade in/out on hover in/out respectively
<div class="square">
<div class="imageHolder">
<!--Comment out and uncomment BG image to show transitions on BG images-->
<img class="one fadeeffect" src="image_01.jpg" />
<img class="two fadeeffect" src="image_02.jpg" />
<img class="three" src="image_03.jpg" />
<img class="four" src="image_04.jpg" />
</div>
</div>
javascript:
$('.fadeeffect')..hover(function(){
// write your code here
}
Related
I have a div called masterdiv, inside this div there are 3 other div div1, div2, and div3,
This is the html for these html:
<div id="masterdiv" class="masterdivclass">
<div id="div1"><img class="div1class" src="image1.jpg" id="div1id" /></div>
<div id="div2"><img class="div2class" src="image2.jpg" id="div2id" /></div>
<div id="div3"><img class="div3class" src="image3.jpg" id="div3id" /></div>
</div>
I also have another div:
<div id=”reload”><img src="reload.png" width="200" height="70" onclick=loadDIV();></div>
What I’m trying to do is to reload the masterdiv div whenever the reload div is clicked on. Hiding and then showing the div isn’t enough as I need the content to be reloaded when the refresh div is clicked on. I don’t want to reload the entire page, just the masterdiv which contains the 3 other div. But I’m not certain this is possible.
I’m trying to do it with this Javascript function:
<script type="text/javascript">
function loadDiv(){
$("<div id="masterdiv" class="masterdivclass">
<div id="div1"><img class="div1class" src="image1.jpg" id="div1id" /></div>
<div id="div2"><img class="div2class" src="image2.jpg" id="div2id" /></div>
<div id="div3"><img class="div3class" src="image3.jpg" id="div3id" /></div>
</div>").appendTo("body");
}
</script>
This isn’t working, I think maybe I'm going about this in the wrong way? Maybe I’m missing something very simple here? I’d really appreciate any help with this, thank you in advance!
UPDATE
After reconsidering my project's requirements, I need to change part of my question, I now need to randomise the images displayed in the divs, and have a new random image load every time the reload div is clicked on. I also need to remove each class that’s currently in each of the three divs and then reattach the same classes to the divs (if I don’t remove and reattach the classes then the divs just display the plain images without any class/effect applied to them, it seems like I need to reload the class every time I load an image into a div in order for the class/effect to be applied successfully).
I have 5 images, and I’m using each div’s id tag to attach a random image to each div.
First I’m assigning the 5 different images to 5 different ids:
<script>
document.getElementById('sample1').src="images/00001.jpg";
document.getElementById('sample2').src="images/00002.jpg";
document.getElementById('sample3').src="images/00003.jpg";
document.getElementById('sample4').src="images/00004.jpg";
document.getElementById('sample5').src="images/00005.jpg";
</script>
And then I’m trying to use the following Javascript to load a randomised id (and its assigned image) to each of the 3 divs when the reload div is clicked:
<script>
$(function() {
$('#reload').on('click',function(){
$("#masterdiv").find("div[id^='div']").each(function(index){
//First, remove and reattach classes “div1class”, “div2class” and “div3class”
//from “easyDIV”, “mediumDIV” and “hardDIV” respectively:
$(“#easyDIV”).removeClass('div1class');
$(“#easyDIV”).addClass('div1class');
$(“#mediumDIV”).removeClass('div2class');
$(“#mediumDIV”).addClass('div2class');
$(“#hardDIV”).removeClass('div3class');
$(“#hardDIV”).addClass('div3class');
//Get a random number between 1 and 5, then attach it to “sample”,
//so that the result will be either “sample1”, “sample2”, “sample3”, “sample4” or “sample5”,
//call this variable “variablesample”:
var num = Math.floor(Math.random() * 5 + 1);
variablesample = "sample" +num;
//Attach this randomised id to all three divs using “variablesample”:
jQuery(this).prev("easyDIV").attr("id",variablesample);
jQuery(this).prev("mediumDIV").attr("id",variablesample);
jQuery(this).prev("hardDIV").attr("id",variablesample);
});
var p = $("#masterdiv").parent();
var el = $("#masterdiv").detach();
p.append(el);
});
});
</script>
I’m trying to make it so that all 3 divs will show the same randomised picture (that’s why they’re all sharing the variable “variablesample”), and each div will reload its own class/effect (div1class, div2class and div3class) but it’s not working. I’m not sure if it’s correct to use jQuery inside a Javascript function, or if my syntax for updating the ids of the divs is incorrect.
Perhaps my logic to solving this problem is all wrong? I’d really appreciate any more help with this problem. Thanks again in advance!
Original question was edited many times, so here is the correct answer for the latest edit. Answer to the question; "How to use random image, but same image on all 3, and 3 class on/off switching":
$(function() {
var imageArray = [
'https://via.placeholder.com/40x40',
'https://via.placeholder.com/80x40',
'https://via.placeholder.com/120x40',
'https://via.placeholder.com/160x40',
'https://via.placeholder.com/200x40'];
reloadImages(imageArray);
$('#reload').on('click',function(){
$( "#masterdiv img[id^='div']" ).each(function(index){
$(this).removeClass("div"+(index+1)+"class");
$(this).fadeOut( "slow", function() {
if(index==0) {
reloadImages(imageArray);
}
$(this).addClass("div"+(index+1)+"class");
$(this).fadeIn();
});
});
});
});
function shuffleArray(array) {
for (var i = array.length - 1; i > 0; i--) {
var j = Math.floor(Math.random() * (i + 1));
var temp = array[i];
array[i] = array[j];
array[j] = temp;
}
return array;
}
function reloadImages(array){
shuffleArray(array);
for(var i=0;i<3;i++){
// places the first image into all divs, change 0 to i if you want different images in each div
document.getElementById('div'+(i+1)+'id').src=array[0];
}
}
.div1class {
border:2px dashed #0F0;
}
.div2class {
border:2px dashed yellow;
}
.div3class {
border:2px dashed red;
}
#reload {
background-color:blue;
color:white;
width:100px;
height:30px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div id='reload'>Click here</div>
<div id="masterdiv" class="masterdivclass">
<div id="div1">
<img src="https://via.placeholder.com/20x40" class="div1class" id="div1id" />
</div>
<div id="div2">
<img src="https://via.placeholder.com/20x40" class="div2class" id="div2id" />
</div>
<div id="div3">
<img src="https://via.placeholder.com/20x40" class="div3class" id="div3id" />
</div>
</div>
Line breaks and un-escaped quotes are why the functions is not working.
function loadDiv(){
$('#masterdiv').remove();
$("<div id='masterdiv' class='masterdivclass'><div id='div1'><img class='div1class' src='image1.jpg' id='div1id' /></div><div id='div2'><img class='div2class' src='image2.jpg' id='div2id' /></div><div id='div3'><img class='div3class' src='image3.jpg' id='div3id' /></div></div>").appendTo("body");
}
try:
function loadDiv(){
$("#masterdiv").load(location.href + " #masterdiv");
}
Here's the code pen demo:
http://codepen.io/anon/pen/xwgRWm
If content of container is not being changed dynamically then there is no point reloading it. appendTo wiil append DOM in existing DOM structure, you will need html() here which will replace the content inside container. Also note you had typo here onclick=loadDiv();
HTML:
<div id="masterdiv" class="masterdivclass">
<div id="div1"><img class="div1class" src="image1.jpg" id="div1id"/></div>
<div id="div2"><img class="div2class" src="image2.jpg" id="div2id"/></div>
<div id="div3"><img class="div3class" src="image3.jpg" id="div3id"/></div>
</div>
<div id="reload"><img src="reload.png" width="200" height="70" onclick=loadDiv();></div>
JS:
function loadDiv() {
$("#masterdiv").html('<div id="div1"><img class="div1class" src="image1.jpg" id="div1id" /></div>\
<div id="div2"><img class="div2class" src="image2.jpg" id="div2id" /></div>\
<div id="div3"><img class="div3class" src="image3.jpg" id="div3id" /></div>');
}
EDIT: I WANT MY SLIDER TO BE EASY TO YOU AND ONCE A LINK IS CLICKED THE IMAGE THAT CORRELATES WITH LINK SHOWS.
I'm looking to make a really simple "slider" that if you click a link, the img shows that correlates with it. I've been trying to find something for a bit now and things are either too flash or don't suit my needs. This came close: http://jsfiddle.net/bretmorris/ULNa2/7/
I would something a little simpler that can be applied easily to multiple images for different divs.
This is what my code looks like with just a plain img tag to it:
<div id="adobe_content" class="hdiv"><button class="x">X</button>
<img src="images/adobefront.png"><br>
<img src="images/adobeinside.png"><br>
<img src="images/adobeback.png"><br>
<h5>Adobe Brochure</h5>
<p>
I wanted to make something functional and out the box that Adobe might consider giving out. It's clean like their work and sparks interest in opening the brochure with the cut out in the center. The front flap is able to slide into a slot on the right side for a neat logo. They're now more interested in their cloud, but the information is inside is still relevant!
</p>
<b>Programs used: Adobe Illustrator, InDesign and Photoshop.</b>
</div>
The code doesn't work for me because, well I partially don't understand it, and I'm not sure how to make it suit my needs (especially if I got up to multiple images) like correlating with an image.
Perhaps understanding what is going on would maybe get you on the right track, so here is an explanation:
$('a.prev').click(function() {
prevSlide($(this).parents('.slideshow').find('.slides'));
});
//clicking image goes to next slide
$('a.next, .slideshow img').click(function() {
nextSlide($(this).parents('.slideshow').find('.slides'));
});
This part is relatively straightforward, when you click on the previous or next links, call the prevSlide or nextSlide function, passing the collection of slides as an argument.
//initialize show
iniShow();
function iniShow() {
//show first image
$('.slideshow').each(function() {
$(this).find('img:first').fadeIn(500);
})
}
Initialize the slideshow by finding each slideshow on the page and fading in the first image. $(this) refers to the <div class="slideshow"> parent, find all child image tags and take the first, fade that element in (and do it in 500 milliseconds).
function prevSlide($slides) {
$slides.find('img:last').prependTo($slides);
showSlide($slides);
}
function nextSlide($slides) {
$slides.find('img:first').appendTo($slides);
showSlide($slides);
}
The prevSlide and nextSlide functions both rearrange the order of images, this line in particular:
$slides.find('img:first').appendTo($slides);
Is moving the first image to the end of the images, so:
<img src="http://placekitten.com/300/500" width="300" height="500" />
<img src="http://placekitten.com/200/400" width="200" height="400" />
<img src="http://placekitten.com/400/400" width="500" height="400" />
becomes:
<img src="http://placekitten.com/200/400" width="200" height="400" />
<img src="http://placekitten.com/400/400" width="500" height="400" />
<img src="http://placekitten.com/300/500" width="300" height="500" />
$slides.find('img:last').prependTo($slides); does the inverse and moves the last image to the beginning.
function showSlide($slides) {
//hide (reset) all slides
$slides.find('img').hide();
//fade in next slide
$slides.find('img:first').fadeIn(500);
}
Finally, showSlide accepts the collection of images, hides all of them and then fades in the first image (since the collection is reordered each time, the first is a different image).
Now, if you want a link for each image that will display a corresponding image, you could do something as simple as:
<a class="image" data-src="http://placekitten.com/300/500">Kitten 1</a>
<a class="image" data-src="http://placekitten.com/200/400">Kitten 2</a>
<a class="image" data-src="http://placekitten.com/400/500">Kitten 3</a>
<div id="image-container">
<img src="http://placekitten.com/300/500" />
</div>
and something like the following:
$('.image').on('click', function() {
var imageSrc = $(this).data('src');
$('#image-container img').prop('src', imageSrc);
});
Which will update the child image tag of <div id="image-container"> with the data-src attribute value in the clicked link.
http://jsfiddle.net/9sxt6n0t/
Hope this helps.
just a quick function to slide
function slideIt(images , prev , next){
$('.slideshow img:nth-child(1)').show();
var imagesLength = $(images).length;
var i = 1;
$(prev).click(function() {
$(images).hide();
if(i !== 1){
$(images + ':nth-child('+ (i - 1) +')').show();
i--;
}else{
$(images +':nth-child('+imagesLength +')').show();
i = imagesLength;
}
});
//clicking image goes to next slide
$(''+next+','+images+'').on('click',function() {
$(images).hide();
if(i !== imagesLength){
$(images + ':nth-child('+ (i + 1) +')').show();
i++;
}else{
$(images + ':nth-child(1)').show();
i = 1;
}
});
}
and use like that slideIt(Images , prevArrow , nextArrow)
slideIt('.slideshow img','a.prev' , 'a.next');
DEMO HERE
Please see this fiddle http://jsfiddle.net/rabelais/Fzs7u/
I have thumbnails and titles that toggle when a mouseover function occurs. How can I make the title remain from the last hovered thumbnail? Should I use something other than toggle? Perhaps target the css display rule?
$(".thumbnail-wrapper").on("mouseover mouseout", "img", function () {
$("#" + $(this).data("title")).toggle();
});
Since you don't want to hide the caption, I'd do things a little differently:
http://jsfiddle.net/zZ6UJ/
<div class="editable title" id="title">
</div>
<div class="thumbnail-wrapper repeatable">
<img src="http://intelligen.info/images/LFW Live Show Drawings/Vivienne Westwood/2013/img012_2.jpg" alt="1" data-title="Vivienne Westwood"/>
</div>
<div class="thumbnail-wrapper repeatable">
<img src="http://intelligen.info/images/LFW Live Show Drawings/Vivienne Westwood/2013/img013_3.jpg" alt="2" data-title="Paul Smith"/>
</div>
$(".thumbnail-wrapper").on("mouseover", "img", function () {
$("#title").text($(this).data('title'));
});
http://jsfiddle.net/Fzs7u/3/
$(".thumbnail-wrapper").on("mouseover", "img", function () {
$('.title:visible').hide();
$("#" + $(this).data("title")).show();
});
I changed your .toggle() to .show(), and hid .title on mouseover, to make sure that only one title is displayed at a time. Also removed your mouseout handler.
I'm using the jquery cycle1 plugin for a slideshow with fade transitions between images, no previous or next controls. I need to layer text on top of this slider that changes color based on what slide is showing.
I'm not very fluent in jQuery so I'm having a hard time using the documentation to manipulate the available options. I've gotten this far thanks to this post and this one but the color changes slightly before or after depending on if I use before or after, obviously. How can I make the text color change at the same exact time the slide does?
Note: I have to use the cycle 1 plugin as my site uses jQuery 1.3.2 with no hope of upgrading.
here is a fiddle, and code below. Thanks in advance for any help!
here is my html:
<div id="text">this is some text over the slider</div>
<div id="switch-it">
<div id="slide1">
<a href="link1.html">
<img src="hp_hero_010114_01.jpg" height="500" width="980" border="0" />
</a>
</div>
<div id="slide2">
<a href="link2.html">
<img src="hp_hero_010114_02.jpg" height="500" width="980" border="0"/>
</a>
</div>
</div><!--//END switch-it-->
and here is the jQuery
$(document).ready(function(){
$('#switch-it').after('<div id="switch" class="switch">').cycle({
fx: 'fade',
speed: 800,
timeout: 500,
cleartypeNoBg: true,
height:'500px',
width:'980px',
pager:'#switch',
pause:1,
before: function (prev, current, opts) {
var current_id = $(current).attr('id');
if( current_id.match("slide1")){
$('#text').css('color','white');
}
else if( current_id.match("slide2")){
$('#text').css('color','red');
}
else if( current_id.match("slide3")){
$('#text').css('color','blue');
}
else if( current_id.match("slide4")){
$('#text').css('color','green');
}
},
pagerAnchorBuilder: function(index, el) {
return '•'; // whatever markup you want
}
});
});
It's not very elegant, but adding a timeout inside the before for half of your speed makes the change exactly in the middle of your transition.
setTimeout(function () { ...change text color }, 400);
JSFiddle
EDIT OR
Add a transition to your css for the #text for the same amount of time as your speed
#text {transition: color .8s linear}
JSFiddle
You might want to update to Cycle2 plugin it has what you are looking for
link
Down in "misc. bits" look for the state variable named 'busy';
I have tried plenty of things and nothing appears to be working.
I am not sure if I am using .siblings() correctly so I had to remove it and made it simple without the actual thing that I want.
Currently I have made it to be as: fade currently selected/hovered div.
$('.recent_each').hover(function () {
$(this).stop().fadeTo(300, '.5')
}, function () {
$(this).stop().fadeTo(300, '1');
});
Can anyone tell me how I can set the opacity of '.5' to all of the siblings and have the currently hovered div on opacity of '1'
I am really confused. Here's html structure tho.
echo "
<div class=\"recent_each\">
<div class=\"recent_title\">
<a href=\"http://www.youtube.com/watch?v='{$info["yt_id"]}'\">
{$info["yt_name"]}
</a>
</div>
<div class=\"recent_thumbnail\">
<a href=\"http://www.youtube.com/watch?v='{$info["yt_id"]}'\">
<img src=\"{$info["thumb"]}\" alt=\"Recently Converted Thumbnail\">
</a>
</div>
</div>
";
As of CSS, there's no opacity at all set in there.
You can use .siblings:
$('.recent_each').hover(function () {
$(this).siblings('.recent_each').stop().fadeTo(300, '.5')
}, function () {
$(this).siblings('.recent_each').stop().fadeTo(300, '1');
});