It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.
Closed 10 years ago.
Since I am into the basics of JavaScript I am able to create array, but I want to know what we might include in the parenthesis of array like test=new Array("parameter?"); so I meant what to include as parameter of that javascript array
The array constructor is overloaded and which result you get depends on how many arguments you pass and of which data type they are:
More than one argument (any type):
var arr = new Array(1,2,3,4);
Creates a new array containing the values passed to the constructor.
One argument ...
... of type number:
var arr = new Array(4);
Creates an empty array and sets its length to the number passed as argument. The array appears to have 4 elements (because its length is 4) but it does not contain any elements (e.g. arr[0] will be undefined).
... any other type:
var arr = new Array('foo');
Creates an array containing one element, the argument passed to the constructor (the same as passing multiple arguments).
Because of this ambiguity of the Array constructor function, you should avoid it and use array literals instead:
var arr = [1,2,3,4];
That said, to learn the basics, read the MDN JavaScript Guide, especially about arrays.
First, if you find yourself writing new Array, there's probably a better way to do it. But first I'll explain the Array constructor and then talk about better ways.
The Array constructor has two forms: A form that takes zero or one arguments (if that one argument is a number), and a form that takes more than one argument (or just one argument if the argument is not a number). Never use the second form, and avoid using the first one.
The first form:
var a = new Array(5);
...creates an array with a length of 5 which has no entries (JavaScript arrays are "sparse," because they're not really arrays at all — more on that below). If you don't supply any argument at all, the length is 0.
The second form:
var a = new Array(5, 6);
...creates an array with as many entries as there are arguments (so, two in this case) and uses the arguments to set the values of those entries.
Note that both the number and type of arguments is important:
var a = new Array(5); // Creates an array with length = 5 with no entries
var b = new Array("5"); // Creates an array with length = 1 and entry [0] = "5"
It's almost always much better to use array literals.
The first form above, done with an array literal instead:
var a = [];
a.length = 5;
The second form above, done with an array literal instead:
var a = [5, 6];
Using array literals is "better" (in my view) for several reasons, some of which are more subjective than others:
It's clearer, and doesn't have the ambiguity that the Array constructor has. For instance, what does this do?
var a = new Array(foo);
Answer: It depends (on what foo has it in it, a number or something else). This is just Not Goodtm.
It's not susceptible to someone overwriting the Array symbol (which they can do) with something else.
It's more concise and expressive (this is probably the most subjective of the reasons).
More reading:
The ECMAScript (JavaScript) specification on Arrays
A myth of arrays (in my blog), which explains how JavaScript arrays aren't arrays
You are in learning curve. See here. You can write array items there.
https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array (Need editorial review)
Syntax Reference
[element0, element1, ..., elementN]
new Array(element0, element1, ..., elementN)
new Array(arrayLength)
MDN Tutorial
Related
Arrays are quite something in JavaScript when compared with other programming languages and it's not without its full set of quirks.
Including this one:
// Making a normal array.
var normalArray = [];
normalArray.length = 0;
normalArray.push(1);
normalArray[1] = 2;
normalArray; // returns [1, 2]
normalArray.length // returns 2
So yes, the above is how we all know to make arrays and fill them with elements, right? (ignore the normalArray.length = 0 part for now)
But why is it that when the same sequence is applied on an object that's not purely an array, it looks a bit different and its length property is off by a bit?
// Making an object that inherits from the array prototype (i.e.: custom array)
var customArray = new (function MyArray() {
this.__proto__ = Object.create(Array.prototype);
return this
});
customArray.length = 0;
customArray.push(1);
customArray[1] = 2;
customArray; // returns [1, 1: 2]
customArray.length // returns 1
Not entirely sure what's going on here but some explanation will be much appreciated.
This may not be the perfect answer, but according to my understanding of Javascript arrays, they are a little bit different than usual objects. (Mainly due to the fact that it maintains a length property, and Objects don't).
So if we take your code for an example:
var normalArray = [];
This is the right way to create an array in Javascript. But what about the below one?
var customArray = new (function MyArray() {
this.__proto__ = Object.create(Array.prototype);
return this
});
Are they same? Let's see..
Array.isArray(normalArray); // true -> [object Array]
Array.isArray(customArray); // false -> [object Object]
So it is clear that although you inherit from the array prototype, it doesn't really create an object with Array type. It just creates a plain JS object, but with the inherited array functions. That's the reason why it updates the length when you set the value with customArray.push(1);.
But since your customArray is only a regular object and for a regular JS object, [] notation is used to set a property, it doesn't update the length (because Objects don't have a length property)
Hope it's clear :)
The array you are trying to create is not a pure array (as you are perhaps aware). Its basically a JavaScript object and is supposed to behave like an object.
While treating an object like an array, its up to you to maintain all it's array like features.
You specifically have to assign a length property to it and you did it correctly.
Next, the push method from Array.prototype is supposed to insert an element to the array and increment the length property (if any), so it did increment 0 to 1. There you go, the length now is 1.
Next you used the literal notation of property assignment to Object, which is similar to something like customArray['someProperty'] = 1.
While using literal notation, no method from Array.Prototype is being invoked and hence the customArray object never knows that it has to behave like an Array and its length property remains unaffected. It simply behaves like an object and you get what you got.
Remember the length is just a property on Array class and this property is appropriately incremented and decremented by every method on Array.
Note: Array like objects are not recommended and its up to you entirely to maintain the index and other Array stuff for such objects.
From what I can see, you have a problem with your function:
return this
This should be
return (this);
Just fixes any potential errors you might have. Another thing is you're not using the var keyword to declare customArray. These errors might be breaking your code.
This question already has answers here:
How can I create a two dimensional array in JavaScript?
(56 answers)
Closed 9 years ago.
I use no add in libraries so what i'm looking for is a pure JavaScript solution.
This is not a duplicate of the thread offered. I want this thread opened up as the people that locked it didn't completely read what I was looking for. Offering some trivial function to initialize a dense array is NOT what I'm after. Read what I wrote.
I'm looking for a constructor, not some function that operates on an array of a known dimension. I'm looking for something that "just happens" when a multidimensional array is touched, and that something has to be an honest to goodness constructor that runs in the "background"to create the array elements on demand with no effort on the part of the programmer in the "foreground".
Correct me if I'm wrong, but when using a two dimensional array, one must first initialize the second dimension before attempting to use it.
It would be something like:
myArray[123] = [];
myArray[123][456] = 'Hi';
Is there some way to create a constructor to do that extra initialization automatically that wouldn't trash the existing functionality for a 1D array?
Alternatively, is there a way to create a new 2DArray object that will automatically allow one to use both dimensions with no prep work?
When the application has no foreknowledge of what the subscripts can be is when this issue becomes problematic.
See that question: Is there a more concise way to initialize empty multidimensional arrays?
Solution:
function createArray(length) {
var arr = new Array(length || 0),
i = length;
if (arguments.length > 1) {
var args = Array.prototype.slice.call(arguments, 1);
while(i--) arr[i] = createArray.apply(this, args);
}
return arr;
}
Simply call with an argument for the length of each dimension. Usage examples:
var multiArray = createArray(100,100); Gives a 2-dimensional array of size 100x100
Sorry for asking a noob question but if I have an array:
MyArray["2cd"]="blah1";
MyArray["3cx"]="blah3";
MyArray["8cz"]="blah2";
And a string myStr="2cd";
And then I use MyArray[myStr] to get the value of blah, how can I get the number I am accessing in the object/array or 0 in this case?
If I may read between the lines, it sounds like you're thinking that the code you posted:
MyArray["2cd"] = "blah1";
MyArray["3cx"] = "blah3";
MyArray["8cz"] = "blah2";
will automatically become the equivalent of:
MyArray[0] = MyArray["2cd"] = "blah1";
MyArray[1] = MyArray["3cx"] = "blah3";
MyArray[2] = MyArray["8cz"] = "blah2";
and therefore you can get the string "blah1" either of these two ways:
var foo = MyArray[0]; // sets foo to "blah1"
var bar = MyArray["2cd"] // also sets bar to "blah1"
But that's not how JavaScript works.
You certainly can set things up so you can use my MyArray[0] and MyArray["2cd"] to fetch the same value, but you have to do it explicitly as in my example.
One thing you didn't mention is how you declared MyArray itself. Is it an Array or an Object? That is, before the code you posted, did you create MyArray with:
var MyArray = {}; // or equivalently, var Array = new Object;
or:
var MyArray = []; // or equivalently, var Array = new Array;
The first example creates an Object, the second an Array.
What is a bit confusing is that JavaScript has both of these two types, which in many cases you can use somewhat interchangeably. But it's customary to use an Object when you are using arbitrary (generally but not necessarily non-numeric) keys into the object, as in your example. Conversely, it's customary to use an Array when you are primarily using strictly numeric indexes.
In fact, JavaScript's Array type inherits from the Object type. An Array is simply an Object with some additional behavior:
An Array has additional methods such as .push() which appends an item to the array.
An Array has a .length property which is automatically updated when you add elements with .push() or a direct array[123] assignment, or when you remove elements with .pop() or other methods.
What JavaScript doesn't have, as Fabrício pointed out, is an "associative array" that behaves like what you might find in some other languages. It has Objects and it has Arrays (which inherit from Objects), and you have to deal with each of those on their own terms.
I was trying to define an array (including other arrays as values) in a single javascript statement, that I can loop through to validate a form on submission.
The function I wrote to (try to) create inline arrays follows:
function arr(){
var inc;
var tempa = new Array(Math.round(arguments.length/2));
for(inc=0; inc<arguments.length; inc=inc+2) {
tempa[arguments[inc]]=arguments[inc+1];
}
return tempa;
}
This is called three times here to assign an array:
window.validArr = arr(
'f-county',arr('maxlen',10, 'minlen',1),
'f-postcode',arr('maxlen',8, 'minlen',6)
);
However in the javascript debugger the variable is empty, and the arr() function is not returning anything. Does anyone know why my expectations on what this code should do are incorrect?
(I have worked out how to create the array without this function, but I'm curious why this code doesn't work (I thought I understood javascript better than this).)
Well from what your code does, you're not really making arrays. In JavaScript, the thing that makes arrays special is the management of the numerically indexed properties. Otherwise they're just objects, so they can have other properties too, but if you're not using arrays as arrays you might as well just use objects:
function arr(){
var inc;
var tempa = {};
for(inc=0; inc<arguments.length; inc=inc+2) {
tempa[arguments[inc]]=arguments[inc+1];
}
return tempa;
}
What you're seeing from the debugger is the result of it attempting to show you your array as a real array should be shown: that is, its numerically indexed properties. If you call your "arr()" function as is and then look at (from your example) the "f-county" property of the result, you'll see something there.
Also, if you do find yourself wanting a real array, there's absolutely no point in initializing them to a particular size. Just create a new array with []:
var tempa = [];
Your code works. Just inspect your variable, and you will see that the array has the custom keys on it. If not expanded, your debugger shows you just the (numerical) indixed values in short syntax - none for you.
But, you may need to understand the difference between Arrays and Objects. An Object is just key-value-pairs (you could call it a "map"), and its prototype. An Array is a special type of object. It has special prototype methods, a length functionality and a different approach: to store index-value-pairs (even though indexes are still keys). So, you shouldn't use an Array as an associative array.
Therefore, their literal syntax differs:
var array = ["indexed with key 0", "indexed with key 1", ...];
var object = {"custom":"keyed as 'custom'", "another":"string", ...};
// but you still can add keys to array objects:
array.custom = "keyed as 'custom'";
Namely, how does the following code:
var sup = new Array(5);
sup[0] = 'z3ero';
sup[1] = 'o3ne';
sup[4] = 'f3our';
document.write(sup.length + "<br />");
output '5' for the length, when all you've done is set various elements?
My 'problem' with this code is that I don't understand how length changes without calling a getLength() or a setLength() method. When I do any of the following:
a.length
a['length']
a.length = 4
a['length'] = 5
on a non-array object, it behaves like a dict / associative array. When I do this on the array object, it has special meaning. What mechanism in JavaScript allows this to happen? Does JavaScript have some type of property system which translates
a.length
a['length']
into "get" methods and
a.length = 4
a['length'] = 5
into "set" methods?
Everything in JavaScript is an object. In the case of an Array, the length property returns the size of the internal storage area for indexed items of the array. Some of the confusion may come into play in that the [] operator works for both numeric and string arguments. For an array, if you use it with a numeric index, it returns/sets the expected indexed item. If you use it with a string, it returns/sets the named property on the array object - unless the string corresponds to a numeric value, then it returns the indexed item. This is because in JavaScript array indexes are coerced to strings by an implicit toString() call. Frankly, this is just one more of those things that makes you scratch your head and say "JavaScript, this, this is why they laugh at you."
The actual underlying representation may differ between browsers (or it may not). I wouldn't rely on anything other than the interface that is supplied when working with it.
You can find out more about JavaScript arrays at MDN.
Characteristics of a JavaScript array
Dynamic - Arrays in JavaScript can grow dynamically .push
Can be sparse - for example, array[50000] = 2;
Can be dense - for example, array = [1, 2, 3, 4, 5]
In JavaScript, it is hard for the runtime to know whether the array is going to be dense or sparse. So all it can do is take a guess. All implementations use a heuristic to determine if the array is dense or sparse.
For example, code in point 2 above, can indicate to the JavaScript runtime that this is likely a sparse array implementation. If the array is initialised with an initial count, this could indicate that this is likely a dense array.
When the runtime detects that the array is sparse, it is implemented in a similar way to an object. So instead of maintaining a contiguous array, a key/value map is built.
For more references, see How are JavaScript arrays implemented internally?
This really depends on what you intend to do with it.
[].length is "magical".
It doesn't actually return the number of items in the array. It returns the largest instated index in the array.
var testArr = []; testArr[5000] = "something"; testArr.length; // 5001
But the method behind the setter is hidden in the engine itself.
Some engines in some browsers will give you access to their implementations of those magic-methods.
Others will keep everything completely locked down.
So don't rely on defineGetter and defineSetter methods, or even, really, __proto__ methods, unless you know which browsers you know you're targeting, and which you aren't.
This will change in the future, where opt-in applications written in ECMAScript Next/6 will have access to more.
ECMAScript 5-compliant browsers are already starting to offer get and set magic methods in objects and there's more to come... ...but it's probably a while away before you can dump support for oldIE and a tonne of smartphones, et cetera...
It is important to know that when you do sup['look'] = 4; you are not using an associative array, but rather modify properties on the object sup.
It is equivalent to sup.look = 4; since you can dynamically add properties on JavaScript objects at any time. sup['length'] would for an instance output 5 in your first example.
To add to tvanfosson's answer: In ECMA-262 (the 3.0 specification, I believe), arrays are simply defined as having this behavior for setting properties (See 15.4.5.1). There's no general mechanism underlying it (at least as of now) - this is just how it's defined, and how JavaScript interpreters must behave.
As other people have mentioned, a property in JavaScript can basically act as both as getter and a setter of your array (or string or other inputs).
As a matter of fact, you might try this yourself:
const test = [1, 2, 3, 4, 5]
test.length = 3
console.log(test) // [1, 2, 3]
test.length = 5
console.log(test) // Guess what happens here!
As far as I know, arrays in JavaScript do not work exactly like associative arrays and you have elements which are put in memory as contiguously as possible (given that you can have arrays of mixed objects), depending on the JavaScript engine you are considering.
As a side note, I am a bit baffled that the most voted answer keeps spreading the over-simplified myth (or half-truth) of "everything being an object in JavaScript"; that is not exactly true, otherwise you will never study primitives, for example.
Try to do this:
const pippi = "pippi"
pippi.cat = "cat"
console.log(pippi.cat) // Will it work? Throw an error? Guess why again
Spoiler: the string is wrapped in a throwaway object for that specific operation on the second line, and then in the following one you are just going to access a property of the primitive which is not there (provided you did not play with String.prototype or the like), so you get undefined.
Array object inherits caller, constructor, length, and name properties from Function.prototype.
A JavaScript array is an object just like any other object, but JavaScript gives it special syntax.
arr[5] = "yo"
The above is syntactic sugar for
arr.insert(5,"yo")
which is how you would add stuff to a regular object. It's what is inside the insert method that changes the value of arr.length
See my implementation of a customArray type here: http://jsfiddle.net/vfm3vkxy/4/