I have a problem replace certain words started with #. I have the following code
var x="#google",
eval("var pattern = /" + '\\b' + x + '\\b');
txt.replace(pattern,"MyNewWord");
when I use the following code it works fine
var x="google",
eval("var pattern = /" + '\\b' + x + '\\b');
txt.replace(pattern,"MyNewWord");
it works fine
any suggestion how to make the first part of code working
ps. I use eval because x will be a user input.
The problem is that \b represents a boundary between a "word" character (letter, digit, or underscore) and a "non-word" character (anything else). # is a non-word character, so \b# means "a # that is preceded by a word character" — which is not at all what you want. If anything, you want something more like \B#; \B is a non-boundary, so \B# means "a # that is not preceded by a word character".
I'm guessing that you want your words to be separated by whitespace, instead of by a programming-language concept of what makes something a "word" character or a "non-word" character; for that, you could write:
var x = '#google'; // or 'google'
var pattern = new RegExp('(^|\\s)' + x);
var result = txt.replace(pattern, '$1' + 'MyNewWord');
Edited to add: If x is really supposed to be a literal string, not a regex at all, then you should "quote" all of the special characters in it, with a backslash. You can do that by writing this:
var x = '#google'; // or 'google' or '$google' or whatever
var quotedX = x.replace(/[^\w\s]/g, '\\$&');
var pattern = new RegExp('(^|\\s)' + quotedX);
var result = txt.replace(pattern, '$1' + 'MyNewWord');
Make you patter something like this:
/(#)?\w*/
If you want to make a Regular Expression, try this instead of eval:
var pattern = new RegExp(x);
Btw the line:
eval("var pattern = /" + '\\b' + x + '\\b');
will make an error because of no enclose pattern, should be :
eval("var pattern = /" + '\\b' + x + '\\b/');
How about
var x = "#google";
x.match(/^\#/);
Related
I want to search and replace special characters of markdown (viz \`*_{}[]()#+.!|-) from the given string.
I am able to make it work in C# easily since there is verbatim # but Javascript not getting what's the issue. It seems something to do with /g , I read in another post which asked to use replaceAll but I could not find that method for string
C# version
string test = #"B
*H*
C
**AB**";
Console.WriteLine ("Input " + test);
var pattern = #"[\\`*_{}\[\]()#+-.!]";
var _1 = Regex.Replace (test, "\r?\n", "<br/>");
var out_ = Regex.Replace (_1, pattern, m => #"\" + m.Value);
Console.WriteLine ("Output " + out_);
Typescript Version
const regexM = new RegExp(/[\\\`\*\_\{\}\[\]\(\)#\+-\.!\|]/g, 'm');
var input = `B
*H*
C
**AB**`;
var inputString = input.replace(regexM, function (y: any) { return "\\" + y; });
if (/\r|\n/.exec(inputString))
{
inputString = inputString .replace(/\r?\n/g, "<br/>");
}
inputString = inputString.replace(regexM, function (x: any)
{
return "\\" + x;
});
Expected: B <br/>\*H\*<br/>C<br/>\*\*AB\*\*
I am getting B <br/>\*H*<br/>C<br/>**AB**
You may use
const regexM = /[\\`*_{}[\]()#+.!|-]/g;
var input = `B
*H*
C
**AB**`;
var inputString = input.replace(regexM, "\\$&");
inputString = inputString.replace(/\r?\n/g, "<br/>");
console.log(inputString);
// => B <br/>\*H\*<br/>C<br/>\*\*AB\*\*
NOTE:
The - in the regexM regex forms a range, you need to either escape it or - as in the code above - put it at the end of the character class
Rather than using callback methods, in order to reference the whole match, you may use the $& placeholder in a string replacement pattern
When you define the regex using a regex literal, there is only one backslash needed to form a regex escape, so const regexM = /[\\`*_{}[\]()#+.!|-]/g is equal to const regexM = new RegExp("[\\\\`*_{}[\\]()#+.!|-]", "g")
There is no need to check if there is a line break char or not with if (/\r|\n/.exec(inputString)), just run .replace.
There is some text, exp: "The string class is an instantiation of the basic_string class template that uses char".
I need to find the text - "basic_string", but if there is no word "the" in front of him.
If use negative lookbehind, it was be:
(?<!\sthe)\s+basic_string
But javascript not understand negative lookbehind, what to do?
If the only allowed character between "the" and "basic_string" is the white-space:
([^e\s]|[^h]e|[^t]he)\s+basic_string
You can use xregexp library to get advanced regex features like lookbehind in Javascript.
Alternatively you can use alternation and capture group as a workaround:
var s = 'The string class is an instantiation of the basic_string class template that uses char';
var kw = s.match(/\bthe basic_string\b|(\bbasic_string\b)/)[1];
// undefined
s = 'instantiation of basic_string class template'
kw = s.match(/\bthe basic_string\b|(\bbasic_string\b)/)[1]
//=> "basic_string"
In this regex, captured group #1 will only be populated if bbasic_string isn't preceded by word the.
You can use RegExp /(the)(?\sbasic_string)/ or new RegExp("(" + before + ")(?=" + match + ")") to match "the" if followed by " basic_string", .match() to retrieve .index of matched string, .slice() to get "basic_string"
var str = "The string class is an instantiation of the basic_string class template that uses char";
var before = "the";
var match = " basic_string";
var index = str.match(new RegExp("(" + before + ")(?=" + match + ")")).index
+ before.length + 1;
console.log(str.slice(index, index + match.length));
The easiest way to emulate the negative lookbehind is via an optional capturing group, and check if the group participated in the match:
/(\bthe)?\s+basic_string/g
^^^^^^^^
See this JS demo:
var s = 'The string class is an instantiation of the basic_string class template that uses char, not basic_string.';
var re = /(\bthe)?(\s+basic_string)/gi;
var res = s.replace(re, function(match, group1, group2) {
return group1 ? match : "<b>" + group2 + "</b>";
});
document.body.innerHTML = res;
I am trying to only allow alphanumeric entry or these characters:'()-_. (with the "." included)
Using regexpal.com I entered this regular expression: [^a-zA-Z0-9()\.'\-\_ ]
It is correctly identifying * and # as a match. What's baffling is that I have that same exact expression in my javascript on an .aspx page and it is not catching * or #. I have confirmed that is indeed entering that function and that the expression evaluates. Here is that code:
$(".validateText").keyup(function (e) {
var matchPattern = "[^a-zA-Z0-9()\.'\-\_ ]";
var regEx = new RegExp(matchPattern);
console.log("Regex: " + regEx + "\nValue of " + e.target.id + " is: " + e.target.value);
if (regEx.test(e.target.value)) {
console.log("Found invalid data.");//I don't get here with # or *
var failingChar = e.target.value.length - 1;
e.target.value = e.target.value.substring(0, failingChar);
}
});
Rather than using string literals to define regexes, use regex literals.
var regEx = /[^a-zA-Z0-9()\.'\-\_ ]/;
String literals interpret backslashes as escape characters, so they need to be escaped. Regex literals don't require this.
As per Bergi's suggestion, you wouldn't even need to escape all those characters.
/[^a-zA-Z0-9().'_ -]/
You could probably even use the general \w character.
/[^\w().' -]/
var matchPattern = "[^a-zA-Z0-9()\\.'\\-\\_ ]";
Would work.
I want to replace a markdown image pattern with the given filename in the textarea with an empty string.
So the pattern is 
This is the code I have now:
var content = target.val();
var fileName = someDynamicValue;
var regex = new RegExp(RegExp.escape('![') + '.*' + RegExp.escape(']') + RegExp.escape('(') + '.*' + RegExp.escape(fileName) + RegExp.escape(')'), 'i');
var found = regex.exec(content);
var newContent = content.replace(regex, "");
target.val(newContent);
RegExp.escape= function(s) {
return s.replace(/[-\/\\^$*+?.()|[\]{}]/g, '\\$&')
};
For example var fileName = filename.jpg. Then I need to match  and replace it with an empty string.
Everything works great if the content includes one image. But if there are more then one, for example:
Some text  some text  more text.
then var found includes , but I need to match only .
What regex I need in this case?
Use non-greedy quantifiers will do:
!\[(.*?)\]\((.*?)\)
You can check it out online: https://regex101.com/r/kfi8qI
Not sure how you are trying to put the strings together but
'.*' is greedily matching up to the last filename.
So, it should probably be '.*?'.
However, if the filenames are different then it shouldn't have matched.
Another thing is you should in general stop it from running past the next [alt] with
something like '[^\[\]]*'
Edit:
RegExp.escape('![') + '.*' + RegExp.escape(']') + RegExp.escape('(') + '.*' + RegExp.escape(fileName) + RegExp.escape(')'), 'i');
is the culprit.
Try
RegExp.escape('![') + '[^\]]*' + RegExp.escape(']') + RegExp.escape('(') + '[^\[\]]*?' + RegExp.escape(fileName) + RegExp.escape(')'), 'i');
I have a dynamic pattern that I have been using the code below to find
var matcher = new RegExp("%" + dynamicnumber + ":", "g");
var found = matcher.test(textinput);
I need the pattern to have a new requirement, which is to include an additional trailing 5 characters of either y or n. And then delete it or replace it with a '' (nothing).
I tried this syntax for the pattern, but obviously it does not work.
var matcher = new RegExp("%" + dynamicnumber + ":" + /([yn]{5})/, "g");
Any tip is appreciated
TIA.
You should only pass the regex string into the RegExp c'tor :
var re = new RegExp("%" + number + ":" + "([yn]{5})", "g");
var matcher = new RegExp("(%" + number + ":)([yn]{5})", "g");
Then replace it with the contents of the first capture group.
Use quotes instead of slashes:
var matcher = new RegExp("%" + number + ":([yn]{5})", "g");
Also, make sure that dynamicnumber or number are valid RegExps. special characters have to be prefixed by a double slash, \\, a literal double slash has to be written as four slashes: \\\\.